I have a sql query that sum and counts some registers from my db, the problem is that I'm using a lot of subquerys and all of them have the same condition, I need to find a better solution because this is causing slowness in my system.
I tried to use a simple left join but mysql returned a single row and I want that counts and sum every register on the table dbgeneralesImportacion.
I have something like this:
SELECT dbgeneralesImportacion.id,
sapito.dbgeneralesImportacion.documentosCompletos AS 'documentosCompletos',
(SELECT COUNT(c.id)
FROM sapito.dbcontenedores c
WHERE c.operacion = dbgeneralesImportacion.id ) AS 'ContadorContenedores',
(SELECT SUM(IF(c.estatus = 1, 1, 0))
FROM sapito.dbcontenedores c
WHERE c.operacion = dbgeneralesImportacion.id ) AS 'ContadorDespachos',
(SELECT SUM(IF(c.estatus = 2, 1, 0))
FROM sapito.dbcontenedores c
WHERE c.operacion = dbgeneralesImportacion.id ) AS 'ContadorCompletado',
(SELECT SUM(IF(c.desconsolidacion = 1, 1, 0))
FROM sapito.dbcontenedores c
WHERE c.operacion = dbgeneralesImportacion.id ) AS 'DesconsolidacionPuerto',
(SELECT SUM(c.bultos) FROM sapito.dbcontenedores c WHERE c.operacion = dbgeneralesImportacion.id) AS 'bultos'
FROM dbgeneralesImportacion
And my idea was to do this but counts all register and return a single row:
SELECT dbgeneralesImportacion.id AS 'id',
COUNT(c.id) AS 'ContadorContenedores',
SUM(IF(c.estatus = 1, 1, 0)) AS 'ContadorDespachos',
SUM(IF(c.estatus = 2, 1, 0)) AS 'ContadorCompletado',
SUM(IF(c.desconsolidacion = 1, 1, 0)) AS 'DesconsolidacionPuerto',
SUM(c.bultos) AS 'bultos'
FROM dbgeneralesImportacion
LEFT JOIN dbcontenedores c ON c.operacion = dbgeneralesImportacion.id
Thank you everyone
You could use a join a and group by
SELECT a.id
, a.documentosCompletos
, COUNT(c.id) ContadorContenedores
, SUM(IF(c.estatus = 1, 1, 0)) ContadorDespachos
, SUM(IF(c.estatus = 2, 1, 0)) ContadorCompletado
, SUM(IF(c.desconsolidacion = 1, 1, 0)) DesconsolidacionPuerto
, SUM(c.bultos) bultos
FROM dbgeneralesImportacion a
INNER JOIN sapito.dbcontenedores c ON c.operacion = a.id
GRUP BY a.id, a.documentosCompletos
Not positive, but couldn't you do something like this
SELECT dbgeneralesImportacion.id,
sapito.dbgeneralesImportacion.documentosCompletos AS 'documentosCompletos',
COUNT(c.id) AS 'ContadorContenedores',
SUM(IF(c.estatus = 1, 1, 0)) AS 'ContadorDespachos',
SUM(IF(c.estatus = 2, 1, 0)) AS 'ContadorCompletado',
SUM(IF(c.desconsolidacion = 1, 1, 0)) AS 'DesconsolidacionPuerto',
SUM(c.bultos) AS 'bultos'
FROM dbgeneralesImportacion, sapito.dbcontenedores c
WHERE c.operacion = dbgeneralesImportacion.id
GROUP BY dbgeneralesImportacion.id
You need a GROUP BY, but you can also simplify the query:
SELECT gi.id AS id,
COUNT(c.id) AS ContadorContenedores,
SUM( c.estatus = 1 ) AS ContadorDespachos,
SUM( c.estatus = 2 ) AS ContadorCompletado,
SUM( c.desconsolidacion = 1 ) AS DesconsolidacionPuerto,
SUM(c.bultos) AS bultos
FROM dbgeneralesImportacion LEFT JOIN
dbcontenedores c
ON c.operacion = gi.id
GROUP BY gi.id;
MySQL treats boolean values as numbers in a numeric context, with true being 1 and false being 0. This makes it easy to count up matching values.
Also, only use single quotes for string and date constants. Using them for column aliases can lead to hard-to-debug problems.
Related
i want to calculate the balance of 3 accounts.
I have 2 tables:
accounts with id, name and start-balance
transactions with value, charge-account, type and paid
To calculate the balance i have to add the start-balance (from accounts) with alle the transaction-values where charge-account = account-id, paid = 1 and type = 1. Then i have to subtract (correct word?) all the transaction-values where charge-account = account-id, paid = 1 and type = 0
At the end, if everything would work i just want to see what balance the accounts have right now.
i tried this query but i get wrong results, it looks like it adds the start-balance multiple times...
SELECT
SUM(IF(a.id = 1, IF(t.type = 1 AND t.charge_account = 1, t.value, 0) - IF(t.type = 0 AND t.charge_account = 1, t.value, 0), 0) + a.start-balance) as "balanc_1",
SUM(IF(a.id = 2, IF(t.type = 1 AND t.charge_account = 2, t.value, 0) - IF(t.type = 0 AND t.charge_account = 2, t.value, 0), 0) + a.start-balance) as "balance_2",
SUM(IF(a.id = 3, IF(t.type = 1 AND t.charge_account = 3, t.value, 0) - IF(t.type = 0 AND t.charge_account = 3, t.value, 0), 0) + a.start-balance) as "balance_3"
FROM test.transactions t, test.accounts a
WHERE t.paid = 1;
transactions:
accounts:
how it should be like:
SELECT a.id,
MAX ( a.`start-balance` ) +
SUM ( CASE WHEN t.type = 1 then t.value
WHEN t.type = 2 then -t.value
ELSE 0
END ) as balance
FROM accounts a
JOIN transactions t
ON a.id = t.`charge-account`
WHERE a.id IN (1,2,3)
AND t.paid = 1
GROUP BY id
You need to use UNION and then group by account id
select accountid, sum(amount ) as amount from (
select accountid, startamount as amount from accounts
union
select accountid, transactionamount from transactions WHERE ....
) t
group by accountid
I made a query that has 3 tables: 1 with current year, last year and name of the country
As you can see the results of current year and last year are the same and that is the problem here. I want to use like. I want to make 1 query with one that has current year and one with last year.
I can use this for last year YEAR(o.date_add) = YEAR(NOW() - INTERVAL 1 YEAR)
And from current year i can use this for example: YEAR(o.date_add) = YEAR(CURRENT_DATE())
My query:
SELECT
IFNULL(SUM(DISTINCT o.total_paid_tax_excl), 0) AS CurrentYEAR,
IFNULL(SUM(DISTINCT o.total_paid_tax_excl), 0) AS LastYEAR,
IFNULL(CONCAT(l.name), 0) AS name
FROM
expoled.ps_orders o
LEFT JOIN
expoled.ps_address a ON o.id_address_delivery = a.id_address
INNER JOIN
expoled.ps_country c ON a.id_country = c.id_country
INNER JOIN
expoled.ps_country_lang l ON c.id_country = l.id_country
WHERE
l.id_lang = 7
AND o.current_state IN (3 , 4, 5, 9, 13, 15, 20, 22, 23, 24, 25, 121)
AND l.name NOT IN ('Netherlands')
GROUP BY (l.name)
I can make seperate query but i want it in 1 query how can i archief this?
I did try Union but the results stayed the same.
I want to have it like this(this one does not work!! just for example[photoshop]
I think I need to change this part of the query
SELECT
IFNULL(SUM(o.total_paid_tax_excl), 0) AS CurrentYEAR,
IFNULL(SUM(o.total_paid_tax_excl), 0) AS LastYEAR,
IFNULL(CONCAT(l.name), 0) AS name
FROM
And add this to my query
For CurrentYEAR = YEAR(o.date_add) = YEAR(CURRENT_DATE())
For LastYEAR = YEAR(o.date_add) = YEAR(NOW() - INTERVAL 1 YEAR)
I think you can try something like this (I added CASE for fields with SUM and a Where condition to extract only relevant years):
SELECT
IFNULL(SUM( CASE WHEN YEAR(CURRENT_DATE)-YEAR(o.date_date) =0 THEN o.total_paid_tax_excl ELSE 0 END), 0) AS CurrentYEAR,
IFNULL(SUM( CASE WHEN YEAR(CURRENT_DATE)-YEAR(o.date_date) =1 THEN o.total_paid_tax_excl ELSE 0 END), 0) AS LastYEAR,
IFNULL(CONCAT(l.name), 0) AS name
FROM
expoled.ps_orders o
LEFT JOIN
expoled.ps_address a ON o.id_address_delivery = a.id_address
INNER JOIN
expoled.ps_country c ON a.id_country = c.id_country
INNER JOIN
expoled.ps_country_lang l ON c.id_country = l.id_country
WHERE
l.id_lang = 7
AND o.current_state IN (3 , 4, 5, 9, 13, 15, 20, 22, 23, 24, 25, 121)
AND l.name NOT IN ('Netherlands')
AND YEAR(o.date_date) IN (YEAR(CURRENT_DATE()), YEAR(CURRENT_DATE)-1)
GROUP BY (l.name)
You can use a conditional expression (if() function or case statement) within the sum() aggregate function to add only those values that fit the criteria:
SELECT
IFNULL(SUM(DISTINCT if(YEAR(o.date_add) = YEAR(CURRENT_DATE()),o.total_paid_tax_excl, 0)), 0) AS CurrentYEAR,
IFNULL(SUM(DISTINCT if(YEAR(o.date_add) = YEAR(CURRENT_DATE())-1,o.total_paid_tax_excl, 0)), 0) AS LastYEAR,
IFNULL(l.name, '') AS name
FROM
expoled.ps_orders o
LEFT JOIN
expoled.ps_address a ON o.id_address_delivery = a.id_address
INNER JOIN
expoled.ps_country c ON a.id_country = c.id_country
INNER JOIN
expoled.ps_country_lang l ON c.id_country = l.id_country
WHERE
l.id_lang = 7
AND o.current_state IN (3 , 4, 5, 9, 13, 15, 20, 22, 23, 24, 25, 121)
AND l.name NOT IN ('Netherlands')
GROUP BY IFNULL(l.name, '')
I also simplified the expression for the name field and made the group by clause consistent with it.
I did not change any other parts of the query, although I do not really agree with the distinct within the sum(), since you could have the same value paid as tax, but it is your data.
If your table has older data than the previous year's, then consider adding a where criteria to restrict the records for which the calculations are run.
I'm trying to count the result of tc.personnel_id if there's more than 1 result, then the output is 1. And then finally, it will get the sum. But I am getting an "Invalid use of group function" error when i execute this code. Any help will be appreciated.
SELECT tv.id,
tv.vesselName,
SUM(IF(tpi.returningCrew = 0, 1,
IF(
COUNT(tc.personnel_id) > 1, 1, 0)
)
) AS ex_crew,
SUM(IF(tpi.returningCrew = 1, 1, 0)) AS new_hire
FROM tbl_vessels AS tv
LEFT JOIN tbl_personnel_info AS tpi
ON tv.id = tpi.lastJoinedVsl
LEFT JOIN tbl_contracts AS tc
ON tpi.id = tc.personnel_id
LEFT JOIN tbl_management AS tm
ON tm.id = tv.management
WHERE tpi.emp_status = 'ON-BOARD'
AND tc.status = 'ACTIVE'
AND tv.trade_route = 'WORLD WIDE'
AND tm.management = 'TOKYO'
GROUP BY vesselName;
Aggregate functions can not be nested. So something like SUM(.. COUNT(..) ..) is not possible. You might try something like this:
SELECT tv.id,
tv.vesselName,
CASE WHEN COUNT(tc.personnel_id) > 1
THEN SUM(IF(tpi.returningCrew = 0, 1, 1)
ELSE SUM(IF(tpi.returningCrew = 0, 1, 0)
END AS ex_crew,
SUM(IF(tpi.returningCrew = 1, 1, 0)) AS new_hire
FROM [..]
SUM(IF(tpi.returningCrew = 0, 1, 1) can be rewriten to SUM(1) or to COUNT(*).
SUM(IF(tpi.returningCrew = 0, 1, 0) cann also be rewritten to SUM(tpi.returningCrew = 0)
And SUM(IF(tpi.returningCrew = 1, 1, 0)) to SUM(tpi.returningCrew = 1)
So the final select could be:
SELECT tv.id,
tv.vesselName,
CASE WHEN COUNT(tc.personnel_id) > 1
THEN COUNT(*)
ELSE SUM(tpi.returningCrew = 0)
END AS ex_crew,
SUM(tpi.returningCrew = 1) AS new_hire
FROM [..]
I'm trying the query below and MySQL gave me this error: Invalid use of group function
SELECT C.`some_name`,
SUM(IF(A.`med_type` = 1, SUM(A.`med_qty`), 0)) AS total,
SUM(IF(A.`is_rejected` = 4, 1 , 0)) AS approved,
SUM(IF(A.`is_rejected` = 2, 1 , 0)) AS qeue,
SUM(IF(A.`is_rejected` = 3, 1 , 0)) AS rejected,
SUM(IF(A.`is_rejected` = 1, 1 , 0)) AS fresh
FROM `ne_media` A
INNER JOIN `ne_member` B ON A.`mem_id` = B.`mem_id`
INNER JOIN `ne_some` C ON B.`some_id` = C.`some_id`
GROUP BY C.`some_id`;
I want to sum med_qty just if med_type = 1.
How do I do it?
Use:
SUM(CASE WHEN (A.`med_type` = 1) THEN A.`med_qty` ELSE 0 END)) AS total,
or:
SUM(IF(A.`med_type` = 1, A.`med_qty`, 0)) AS total,
You can't do aggregates on aggregates like you tried to in the original.
I have written a fairly complex SQL query to get some statistics about animals from an animal sampling database. This query includes a number of subqueries and I would now like to see if it is possible to rewrite this query in any way to use joins instead of subqueries. I have a dim idea that this might reduce query time. (it's now about 23s on a mac mini).
Here's the query:
SELECT COUNT(DISTINCT a.AnimalID), TO_DAYS(a.VisitDate) AS day,
DATE_FORMAT(a.VisitDate, '%b %d %Y'), a.origin,
(
SELECT COUNT(DISTINCT a.AnimalID)
FROM samples AS a
JOIN
custom_animals AS b
ON a.AnimalID = b.animal_id
WHERE
b.organism = 2
AND
TO_DAYS(a.VisitDate) = day
) AS Goats,
(
SELECT COUNT(DISTINCT a.AnimalID)
FROM samples AS a
JOIN custom_animals AS b
ON a.AnimalID = b.animal_id
WHERE
b.organism = 2
AND
b.sex = 'Female'
AND
TO_DAYS(a.VisitDate) = day
) AS GF,
(
SELECT COUNT(DISTINCT a.AnimalID)
FROM samples AS a
JOIN custom_animals AS b
ON a.AnimalID = b.animal_id
WHERE
b.organism = 3
AND
b.sex = 'Female'
AND
TO_DAYS(a.VisitDate) = day
) AS SF
FROM
samples AS a
JOIN custom_animals AS b
ON a.AnimalID = b.animal_id
WHERE
project = 5
AND
AnimalID LIKE 'AVD%'
GROUP BY
TO_DAYS(a.VisitDate);
Thanks to ksogor my query is now way faster at;
SELECT DATE_FORMAT(s.VisitDate, '%b %d %Y') AS date,
s.origin,
SUM(IF(project = 5 AND s.AnimalID LIKE 'AVD%', 1, 0)) AS sampled_animals,
SUM(IF(ca.organism = 2, 1, 0)) AS sampled_goats,
SUM(IF(ca.organism = 2 AND ca.sex = 'Female', 1, 0)) AS female_goats,
SUM(IF(ca.organism = 3 AND ca.sex = 'Female', 1, 0)) AS female_sheep
FROM samples s JOIN custom_animals ca ON s.AnimalID = ca.animal_id
GROUP BY date;
I would still need to make this query select distinct s.AnimalID though as right now it counts the samples we have taken from these animals instead of the animals themselves. Anyone got any idea?
After some more help from ksogor I now have a great query:
SELECT DATE_FORMAT(s.VisitDate, '%b %d %Y') AS date,
s.origin,
SUM(IF(project = 5 AND s.AnimalID LIKE 'AVD%', 1, 0)) AS sampled_animals,
SUM(IF(ca.organism = 2, 1, 0)) AS sampled_goats,
SUM(IF(ca.organism = 2 AND ca.sex = 'Female', 1, 0)) AS female_goats,
SUM(IF(ca.organism = 3 AND ca.sex = 'Female', 1, 0)) AS female_sheep
FROM (
SELECT DISTINCT AnimalID AS AnimalID,
VisitDate,
origin,
project
FROM samples
) s
JOIN custom_animals ca ON s.AnimalID = ca.animal_id
GROUP BY date;
You can just use if or case statements, like this:
SELECT SUM(if(project = 5 AND AnimealID LIKE 'AVD%', 1, 0)) AS countbyproj,
TO_DAYS(s.VisitDate) AS day,
DATE_FORMAT(s.VisitDate, '%b %d %Y') AS date,
s.origin,
SUM(if(ca.organism = 2, 1, 0)) AS countGoats,
SUM(if(ca.organism = 2 AND ca.sex = 'Female', 1, 0)) AS countGF,
SUM(if(ca.organism = 3 AND ca.sex = 'Female', 1, 0)) AS countSF
FROM samples s JOIN custom_animals ca ON s.AnimalID = ca.animal_id
GROUP BY TO_DAYS(a.VisitDate);
I can't check query, I don't know what result you're expected and which tables/relations you have, so this is only example with idea.
If you need count unque AnimealID's for each day:
SELECT SUM(byproj) AS countbyproj,
day,
date,
origin,
SUM(Goats) AS countGoats,
SUM(GF) AS countGF,
SUM(SF) AS countSF
FROM (
SELECT s.AnimealID,
if(project = 5 AND AnimealID LIKE 'AVD%', 1, 0) AS byproj,
TO_DAYS(s.VisitDate) AS day,
DATE_FORMAT(s.VisitDate, '%b %d %Y') AS date,
s.origin,
if(ca.organism = 2, 1, 0)) AS Goats,
if(ca.organism = 2 AND ca.sex = 'Female', 1, 0) AS GF,
if(ca.organism = 3 AND ca.sex = 'Female', 1, 0) AS SF
FROM samples s JOIN custom_animals ca ON s.AnimalID = ca.animal_id
) dataset
GROUP BY dataset.day, dataset.AnimealID;