Convert Total Sum Into Percentage - mysql

Question

I want to convert a sum result into percentage. When added it will result 100% in total. I already group it by remarks and already got the total from my query. But its still in number.
This is my query
SELECT
CASE
WHEN A.district = B.district THEN 'Delivered from store in same district'
WHEN A.city = B.city THEN 'Delivered from store in same city'
WHEN A.province = B.province THEN 'Delivered from store in same province'
ELSE 'Not delivered from nearest store'
END AS 'REMARK',
SUM(CASE
WHEN YEAR(T1.create_time) = '2019' AND MONTH(T1.create_time) = '01' THEN 1
ELSE 0
END) AS 'Jan-19',
SUM(CASE
WHEN YEAR(T1.create_time) = '2019' AND MONTH(T1.create_time) = '02' THEN 1
ELSE 0
END) AS 'Feb-19',
SUM(CASE
WHEN YEAR(T1.create_time) = '2019' AND MONTH(T1.create_time) = '03' THEN 1
ELSE 0
END) AS 'Mar-19',
SUM(CASE
WHEN YEAR(T1.create_time) = '2019' AND MONTH(T1.create_time) = '04' THEN 1
ELSE 0
END) AS 'Apr-19'
FROM
au_store_add A
INNER JOIN
(SELECT
A.id,
A.code,
A.create_time,
A.plat_create_time,
A.appoint_stcode,
A.status
FROM deli_order A
WHERE A.appoint_stcode IS NOT NULL
UNION
SELECT
B.id,
B.code,
B.create_time,
B.plat_create_time,
B.destination_code,
B.status
FROM deli_order B
WHERE B.destination_code IS NOT NULL) T1 ON T1.appoint_stcode = A.store_code
INNER JOIN
deli_order_delivery B ON B.order_id = T1.id
WHERE
YEAR(T1.plat_create_time)='2019' and T1.status = 6 and (month(T1.plat_create_time) in (1,2,3,4))
GROUP BY
CASE
WHEN A.district = B.district THEN 'Delivered from store in same district'
WHEN A.city = B.city THEN 'Delivered from store in same city'
WHEN A.province = B.province THEN 'Delivered from store in same province'
ELSE 'Not delivered from nearest store'
END
And the result is like this
REMARK | Jan-19| Feb-19| Mar-19| Apr-19|
-----------------------------------------------------------------------
Delivered from store in same city 252 198 308 283
Delivered from store in same district 114 110 163 138
Delivered from store in same province 1135 976 1387 1208
Not delivered from nearest store 3046 2518 3189 3123
I need to generate something like this for each month(without the 'Grand Total')
REMARK | Jan-19|
-----------------------------------------------
Delivered from store in same city 5.5%
Delivered from store in same district 2.5%
Delivered from store in same province 25%
Not delivered from nearest store 67%
Grand Total 4547 (100%)
What should i add to my query?

Answer 1

Given that you are using MySQL 8+, then COUNT() as an analytic function should be available to use. It comes in handy here:
SELECT
CASE
WHEN A.district = B.district THEN 'Delivered from store in same district'
WHEN A.city = B.city THEN 'Delivered from store in same city'
WHEN A.province = B.province THEN 'Delivered from store in same province'
ELSE 'Not delivered from nearest store'
END AS REMARK,
100.0 * COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-01' THEN 1 END)
/ COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-01'
THEN 1 END) OVER () `Jan-19`,
100.0 * COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-02' THEN 1 END)
/ COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-02'
THEN 1 END) OVER () `Feb-19`,
100.0 * COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-03' THEN 1 END)
/ COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-03'
THEN 1 END) OVER () `Mar-19`,
100.0 * COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-04' THEN 1 END)
/ COUNT(CASE WHEN DATE_FORMAT(create_time, '%Y-%m') = '2019-04'
THEN 1 END) OVER () `Apr-19`
FROM
au_store_add A
...
I used DATE_FORMAT above to make the check on the year and month a bit less verbose. I also used COUNT in place of SUM, which lets us use a slightly shorter conditional expression.