I am having a mysql problem I am trying to find both the most current payment value, and, for a particular month (in this query I'm using April). Link to the sqlfillde is here
(case when max(py.pay_date)and month(py.pay_date)= 4 then amount else 0 end) max_pay_april,
This is what I have but it doesn't seem to be working. The most current payment value is: (5, '2012-04-20', 90,) therefore it would be 90 I would really appreciate some help please.
How about this:
select p.name,
v.v_name,
sum(case when Month(py.pay_date) = 4 then amount end) april_amount,
max(case
when month(py.pay_date)= 4
and py.pay_date = (select max(pay_date)
from payment
where month(pay_date) =4 )
then amount else 0 end) max_pay_april,
sum(case
when Month(py.pay_date) = Month(curdate())
then amount end) current_month_amount,
sum(case
when Month(py.pay_date) = Month(curdate())-1
then amount end) previous_month_amount
from persons p
left join vehicle v
on p.id = v.person_veh
left join payment py
on p.id = py.person_id
group by p.name,
v.v_name
see SQL Fiddle with demo
Related
Dears,
I tried to create a view that sumarize transaction per category (row) and months (columns) on one year as this :
SELECT counterpart.id_category as catid, category AS Category, (
SELECT COALESCE(SUM(amount), 0)
FROM transaction
INNER JOIN counterpart
ON transaction.id_counterpart = counterpart.id_counterpart
WHERE YEAR(date) = YEAR(now())
AND MONTH(date) = 1
AND id_category = catid
) AS Jan, [...]
FROM transaction
INNER JOIN counterpart
ON transaction.id_counterpart = counterpart.id_counterpart
INNER JOIN category
ON counterpart.id_category = category.id_category
WHERE transaction.id_user = 2
AND YEAR(date) = YEAR(now())
GROUP BY category
I don't know if it's a good way or not, at least it works as single command but not as view.
On view, the WHERE id_category = catid for subquery doesn't work properly.
Thank you.
I suspect conditional aggregation would be more appropriate and quicker than a lot of sub queries.
for example
SELECT counterpart.id_category as catid, category AS Category,
sum(case when month(date) = 1 then 1 else 0 end) as Jan,
sum(case when month(date) = 2 then 1 else 0 end) as feb,
sum(case when month(date) = 3 then 1 else 0 end) as Mar
FROM transaction
INNER JOIN counterpart
ON transaction.id_counterpart = counterpart.id_counterpart
INNER JOIN category
ON counterpart.id_category = category.id_category
WHERE transaction.id_user = 2
AND YEAR(date) = YEAR(now())
GROUP BY counterpart.id_category,category
I would like to join 3 tables.
The result is one of the field - SUM from the other table like this image, please help
You don't need to join tblwork as you can get all required fields from other 2 tables.
Following query should work:
select t1.nmstudent,
sum(case when t2.idwork = 'w001' then t2.trprice else 0 end) as w001,
sum(case when t2.idwork = 'w002' then t2.trprice else 0 end) as w002,
sum(case when t2.idwork = 'w003' then t2.trprice else 0 end) as w003,
sum(case when t2.idwork = 'w004' then t2.trprice else 0 end) as w004
from tblstudent t1
inner join tblTrans t2
on t1.idstudent = t2.idstudent
group by t1.idstudent;
Hope it helps!
I am trying to return multiple counts and averages from multiple tables sorting by gender and am getting incorrect data. I understand that the following is incorrect, but I am unsure of how to fix it. (Edit: Problem with group by gender. See below.)
Here is the query:
SELECT c.gender AS 'Gender',
COUNT(DISTINCT mr.mailing_recipient_id) AS 'Mailing Recipients',
(SELECT COUNT(DISTINCT CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) ) AS 'Open Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) AS 'Avg Open',
(SELECT COUNT(DISTINCT CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) ) AS 'Click Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) AS 'Avg Click',
COUNT(DISTINCT ca.cons_action_contribution_id) AS Donations,
AVG(ca.transaction_amt) AS 'Avg Donation Amt'
FROM ((mailing m
LEFT JOIN mailing_recipient mr ON m.mailing_id = mr.mailing_id)
LEFT JOIN mailing_recipient_click mrc ON mr.mailing_recipient_id = mrc.mailing_recipient_id
LEFT JOIN cons_action_contribution ca ON mr.cons_id = ca.cons_id
LEFT JOIN cons c ON c.cons_id = ca.cons_id)
WHERE m.mailing_id = 1
AND gender IS NOT NULL
GROUP BY c.gender;
Here is the table which would be correct if the totals in the fields were correct:
GENDER Mailing Recipient Open Total Avg Open Click Total Avg Click Donations Avg Amt
F 105 2 0.5000 2 0.5000 105 22.5000
M 98 2 0.5000 2 0.5000 98 18.8780
EDIT: Here is an example of what I am hoping to achieve. I am certain that the above values are being repeated. The below values are just examples of what I am expecting:
GENDER Mailing Recipient Open Total Avg Open Click Total Avg Click Donations Avg Amt
F 105 8 0.0761 4 0.0380 2 22.5000
M 98 2 0.0204 1 0.0102 1 18.8000
Edit:
After playing around a bit, I thought that I had discovered that the joining the cons table was what is giving me problematic returns, but the problem is with GROUP BY when using gender. To illustrate, this query (which is grouped by mailing name instead of gender) works beautifully.
select m.mailing_name AS 'mailing',
COUNT(DISTINCT mr.mailing_recipient_id) AS 'Mailing Recipients',
SUM(CASE
when mrc.mailing_recipient_click_type_id = 2 THEN 1
END)
AS 'Open Total',
AVG(CASE
WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1
ELSE 0
END) AS 'Avg Open',
SUM(CASE
WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1
END)
AS 'Click Total',
AVG(CASE
WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1
ELSE 0
END) AS 'Avg Click',
COUNT(ca.cons_action_contribution_id) AS Donations,
AVG(ca.transaction_amt) AS 'Avg Donation Amt'
FROM
mailing m
LEFT JOIN mailing_recipient mr ON m.mailing_id = mr.mailing_id
LEFT JOIN mailing_recipient_click mrc
ON mr.mailing_recipient_id = mrc.mailing_recipient_id
LEFT JOIN cons_action_contribution ca ON mr.cons_id = ca.cons_id
LEFT JOIN cons c ON mr.cons_id = c.cons_id
WHERE m.mailing_id = 1
GROUP BY m.mailing_name;
The statement is identical with the exception of the first and last lines.
Try this:
I'm not sure what you mean by Avg Open and Avg Click.
SELECT c.gender AS 'Gender',
COUNT(DISTINCT mr.mailing_recipient_id) AS 'Mailing Recipients',
SUM(CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) AS 'Open Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) AS 'Avg Open',
SUM(CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) AS 'Click Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) AS 'Avg Click',
COUNT(DISTINCT ca.cons_action_contribution_id) AS Donations,
AVG(ca.transaction_amt) AS 'Avg Donation Amt'
FROM mailing m
LEFT JOIN mailing_recipient mr ON m.mailing_id = mr.mailing_id
LEFT JOIN mailing_recipient_click mrc ON mr.mailing_recipient_id = mrc.mailing_recipient_id
LEFT JOIN cons_action_contribution ca ON mr.cons_id = ca.cons_id
LEFT JOIN cons c ON c.cons_id = ca.cons_id
WHERE m.mailing_id = 1
AND gender IS NOT NULL
GROUP BY c.gender;
I also think that mrc.mailing_recipient_click_type_id = 2 means open and mrc.mailing_recipient_click_type_id = 1 mean click seems strange to me. I would expect this data to be exclusive and stored in two different fields.
Using the following sqlfiddle here How would I find the most recent payment made between the months of 2012-04-1 and 2012-03-31 using the case statement as in the previous queries
I tried this:
max(case when py.pay_date >= STR_TO_DATE(CONCAT(2012, '-04-01'),'%Y-%m-%d') and py.pay_date <= STR_TO_DATE(CONCAT(2012, '-03-31'), '%Y-%m-%d') + interval 1 year then py.amount end) CURRENT_PAY
However the answer I am getting is incorrect, where the actual answer should be:(12, '2012-12-12', 20, 1)
Please Provide me with some assistance, thank you.
Rather than a CASE inside your MAX() aggregate, that condition belongs in the WHERE clause. This joins against a subquery which pulls the most recent payment per person_id by joining on MAX(pay_date), person_id.
SELECT payment.*
FROM
payment
JOIN (
SELECT MAX(pay_date) AS pay_date, person_id
FROM payment
WHERE pay_date BETWEEN '2012-04-01' AND DATE_ADD('2012-03-31', INTERVAL 1 YEAR)
GROUP BY person_id
) maxp ON payment.person_id = maxp.person_id AND payment.pay_date = maxp.pay_date
Here is an updated fiddle with the ids corrected in your table (since a bunch of them were 15). This returns record 18, for 2013-03-28.
Update
After seeing the correct SQL fiddle... To incorporate the results of this query into your existing one, you can LEFT JOIN against it as a subquery on p.id.
select p.name,
v.v_name,
sum(case when Month(py.pay_date) = 4 then py.amount end) april_amount,
(case when max(py.pay_date)and month(py.pay_date)= 4 then py.amount else 0 end) max_pay_april,
sum(case
when Month(py.pay_date) = Month(curdate())
then py.amount end) current_month_amount,
sum(case
when Month(py.pay_date) = Month(curdate())-1
then py.amount end) previous_month_amount,
maxp.pay_date AS last_pay_date,
maxp.amount AS last_pay_amount
from persons p
left join vehicle v
on p.id = v.person_veh
left join payment py
on p.id = py.person_id
/* LEFT JOIN against the subquery: */
left join (
SELECT MAX(pay_date) AS pay_date, amount, person_id
FROM payment
WHERE pay_date BETWEEN '2012-04-01' AND DATE_ADD('2012-03-31', INTERVAL 1 YEAR)
GROUP BY person_id, amount
) maxp ON maxp.person_id = p.id
group by p.name,
v.v_name
Right now I have 3 tables, the first one for users, the second for group of users and the third one for points (and other ones, if you want one I could create it for you :P).
Table users:
user_id
|
fname
|
active
Table user_groups:
id
|
group_id
|
user_id
|
active
Table user_points:
id
|
point_type
|
point_units
|
active
Each user of a group could earn points for different activities. So, I want to show the points that the users have earned for their different activities, with a grand total at the end.
Here's the query that I have so far:
SELECT
u.user_id AS `ID`,
u.fname AS `Name`,
SUM(case when up.point_type = 'Referrals' then up.point_units else 0 end) AS `Referrals`,
SUM(case when up.point_type = 'Email' then up.point_units else 0 end) AS `Email`,
SUM(case when up.point_type = 'Facebook' then up.point_units else 0 end) AS `Facebook`,
SUM(case when up.point_type = 'Twitter' then up.point_units else 0 end) AS `Twitter`,
SUM(case when up.point_type = 'Extra' then up.point_units else 0 end) AS `Extra`,
SUM(case when up.point_type = 'Discount' then up.point_units else 0 end) AS `Discount`,
SUM(case when u.user_id = up.user_id then up.point_units else 0 end) AS `Total`
FROM users AS u, user_groups AS uc, user_points AS up
WHERE u.user_id = uc.user_id
AND u.user_id = up.user_id
AND u.active = 1
AND uc.active = 1
AND up.active = 1
AND uc.group_id = up.group_id
AND uc.group_id = 65
ORDER BY u.fname;
The problem that I have is that the query only shows one user and the total sum of the points of all the users in each column.
I know that this isn't the right approach, but I don't know how to put everything into a query. Also, I'm giving this query to PHPExcel, so it could generate a nice friendly report.
Any ideas? :-)
You need a GROUP BY clause when using aggregate functions. Yours might look like:
GROUP BY u.user_id
In your query it would go here:
AND uc.group_id = 65
GROUP BY u.user_id
ORDER BY u.fname;