Looking for the code to make this particular shape with CSS..
Any help much appreciated!
You can do it with some rotation and perspective:
.box {
width: 150px;
height: 120px;
background: #f540a8;
margin: 20px;
transform: perspective(180px) rotateX(15deg) rotateY(20deg) rotateZ(-3deg);
}
<div class="box">
</div>
Or using SVG:
<svg viewBox="0 0 200 200" width=200>
<polygon points="20,0 150,20 170,130 0,150" fill="#f540a8" />
</svg>
And also using gradient (but without transparency):
.box {
width: 150px;
height: 120px;
background:
linear-gradient(to top right, transparent 46%,#fff 50%) right/10px 100%,
linear-gradient(to top right, transparent 46%,#fff 50%) top/100% 10px,
linear-gradient(to bottom right, transparent 46%,#fff 50%) bottom/100% 10px,
linear-gradient(to top left, transparent 46%,#fff 50%) left/10px 100%,
#f540a8;
background-repeat:no-repeat;
margin: 20px;
}
<div class="box">
</div>
You can use clip-path.
The clip-path CSS property creates a clipping region that defines
what part of an element should be displayed. More specifically, those
portions that are inside the region are shown, while those outside are
hidden.
Try this code snippet.
div{
width: 150px;
height: 150px;
-webkit-clip-path: polygon(5% 7%, 91% 14%, 98% 91%, 0% 100%);
clip-path: polygon(5% 7%, 91% 14%, 98% 91%, 0% 100%);
background: pink;
}
<div></div>
you can use:
clip-path: polygon(30px 0 , 250px 0, 200px 300px, 0 0);
Please see the example here: https://codepen.io/shakogele/pen/ZMZGGK
Related
I am trying to create a CSS gradiant based vertical progress bar as shown in the figure.
Sample Image
I want to achieve the followings:
It should only have two colors.
The gradient should be a dotted one (similar to dotted border).
I should be able to set the height of each color. For example, if I want the 30% of the height of the gradient to be gray, the rest of the 70% should be set to green. And there shouldn't be a spread of the color(not sure of the right term).
Any clues on how this can be achieved via CSS only.
I have tried the following code with no success, just pasting it for reference.
<!DOCTYPE html>
<html>
<head>
<style>
#grad1 {
height: 700px;
width: 10px;
background-image: linear-gradient(180deg, transparent, transparent 50%, #fff 50%, #fff 50%), linear-gradient(180deg, orange 25%, black 75%);
background-size: 100% 20px, 100% 700px;
}
</style>
</head>
<body>
<h1>Linear Gradient - Top to Bottom</h1>
<p>This linear gradient starts red at the top, transitioning to yellow at the bottom:</p>
<div id="grad1"></div>
</body>
</html>
You could paint the vertical line n% in lime and then 100% - n% in gray.
Then overlay that with a repeating linear gradient of transparent and white.
.line {
height: 700px;
width: 10px;
background-image: linear-gradient(transparent 0 50%, white 50% 100%), linear-gradient(lime 0 71%, gray 71% 100%);
background-size: 100% 10%, 100% 100%;
}
<div class="line"></div>
You can use mask and gradient like below:
.line {
height: 300px;
width: 20px;
-webkit-mask: radial-gradient(circle closest-side, #000 96%, #0000) 0 0/100% 10%;
background: linear-gradient(red 60%, blue 0);
}
<div class="line"></div>
Currently using this CSS for a bottom slant going up from left to right:
clip-path: polygon( 0 0, 100% 0, 100% calc(100% - 3vw), 0 100% );
It works very well for a responsive solution but having a hard time figuring out how to do this for a responsive solution for a slant at the top of the div going down from left to right.
I tried this:
clip-path: polygon( 0 0, 100% calc(100% - 29vw), 100% 100%, 0 100% );
Thank you!
You can adjust like below. You make the second point to start lower by 3vw and you put back the other one to 100%
.box {
height: 100px;
background: red;
clip-path: polygon( 0 0, 100% 3vw, 100% 100%, 0 100%);
/* (0,0) ----------------- (100%,0)
| |<---------(100%,3vw)
| |
| |
| |
(0,100%) ----------------- (100%,100%)
}
<div class="box">
</div>
And like this if you want from right to left:
.box {
height: 100px;
background: red;
clip-path: polygon( 0 3vw, 100% 0, 100% 100%, 0 100%);
}
<div class="box">
</div>
On the sides:
.box {
height: 100px;
background: red;
clip-path: polygon( 0 0, calc(100% - 3vw) 0, 100% 100%, 0 100%);
}
<div class="box">
</div>
If you want a more supported way, you can consider multiple background like below:
.box {
height: 100px;
margin:5px;
padding-top:3vw;
background:
/*a triangle shape on the padding-top area*/
linear-gradient(to bottom var(--d,left),transparent 48%,red 50%) top/100% 3.1vw no-repeat,
/*color the content and not the padding-top*/
linear-gradient(red,red) content-box;
}
<div class="box">
</div>
<div class="box" style="--d:right">
</div>
I'm struggling to find a nice way to fade a vertical gradient at its left and right sides. Basically a top-bottom gradient with the left-right ends faded to 0% opacity.
I need it to be a Transparent fade out so that it can be on top of images/videos.
Here is a quick visual of what I am aiming for:
Any suggestions?
Pretty Simple, You just need to add transparent in a linear gradient.
div {
background:linear-gradient(to right, transparent, #00F5CB, transparent);
width: 100%;
height:64px;
}
<div></div>
Use multiple backgrounds. The first one is on top.
div {
width: 100%;
height: 100px;
background-image: linear-gradient( to right, white 0%, transparent 30%, transparent 70%, white 100%),
linear-gradient( to bottom, Lightgreen, Aquamarine);
}
<div></div>
You can try multiple background like this:
.box {
width: 500px;
height: 80px;
margin:auto;
background:
radial-gradient(ellipse at top, #7ff5b0 20%, transparent 70%) top center/80% 100%,
linear-gradient( to right, transparent 0%, #19d9ef 30%, #19d9ef 70%, transparent 100%);
background-repeat:no-repeat;
color: ;
color: ;
}
body {
background:pink
}
<div class="box"></div>
I have two divs on top of each other. I need the bottom div to have a slanted angle like this:
I only need help with slant of the top of the blue div, I can handle to bottom slant myself.
I could create a psuedo element and skew it, but the issue is that the blue div has a gradient and making a psuedo element with the same gradient makes the two elements not flow together with their gradients.
I think my only solution is to create a transparent div, skew it and place it on top of the blue div. I was wondering if this is even possible to create a skewed transparent div and have it cut into the blue div, slanting the blue div while showing the image in the background.
I'm open to any other ideas to achieve this slanted div.
Ive created a simple jsfiddle with the divs for anyone to mess around with.
Here is the basic mark up:
<div class="main">
<div class="main-top">
</div>
<div class="main-bottom">
</div>
</div>
.main-top {
background: url("http://stock-wallpapers.com/wp-content/uploads/2015/01/Huawei_P7_home_wallpaper_02_.jpg") center center no-repeat;
background-size: cover;
height: 300px;
width: 600px;
}
.main-bottom {
height: 300px;
width: 600px;
background-image: -moz-linear-gradient( -51deg, rgb(28,35,80) 0%, rgb(27,31,71) 41%, rgb(25,26,62) 100%);
background-image: -webkit-linear-gradient( -51deg, rgb(28,35,80) 0%, rgb(27,31,71) 41%, rgb(25,26,62) 100%);
position: relative;
top: -150px;
}
Thanks
It is in fact very easy if you use this site
http://bennettfeely.com/clippy/
.main-top {
background: url("http://stock-wallpapers.com/wp-content/uploads/2015/01/Huawei_P7_home_wallpaper_02_.jpg") center center no-repeat;
background-size: cover;
height: 300px;
width: 600px;
}
.main-bottom {
height: 300px;
width: 600px;
background-image: -moz-linear-gradient( -51deg, rgb(28, 35, 80) 0%, rgb(27, 31, 71) 41%, rgb(25, 26, 62) 100%);
background-image: -webkit-linear-gradient( -51deg, rgb(28, 35, 80) 0%, rgb(27, 31, 71) 41%, rgb(25, 26, 62) 100%);
position: relative;
top: -150px;
-webkit-clip-path: polygon(0 0, 100% 32%, 100% 100%, 0 68%);
clip-path: polygon(0 0, 100% 32%, 100% 100%, 0 68%);
}
<div class="main">
<div class="main-top">
</div>
<div class="main-bottom">
</div>
</div>
I'm trying to re-design a website homepage.
How can I split the full screen background image currently being used into 3 sections, with a gap between each with the image only being shown within the Rhomboid shape?
I've looked around and have found the CSS + HTML to create the Rhomboid with the image inside however it's the whole image and only one of these Rhomboid shapes.
.polygon-each {
padding: 10px;
text-align: center;
}
.polygon-each-img-wrap img {
margin-bottom: 10px;
}
.polygon-each img {
display: block;
margin-left: auto;
margin-right: auto;
}
}
img {
max-width: 100%;
height: auto;
}
.polygon-clip-rhomboid {
-webkit-clip-path: polygon(0% 100%, 30% 0%, 100% 0%, 70% 100%);
clip-path: polygon(0% 100%, 30% 0%, 100% 0%, 70% 100%);
-webkit-clip-path: url("#polygon-clip-rhomboid");
clip-path: url("#polygon-clip-rhomboid");
}
<div class="polygon-each">
<div class="polygon-each-img-wrap">
<img src="/img/rules-bgrnd.png" alt="demo-clip-rhomboid" class="polygon-clip-rhomboid">
</div>
<svg class="clip-svg">
<defs>
<clipPath id="polygon-clip-rhomboid" clipPathUnits="objectBoundingBox">
<polygon points="0 1, 0.3 0, 1 0, 0.7 1" />
</clipPath>
</defs>
</svg>
</div>
A view of what is currently shown can be seen here
One way you could do this is just by utilizing a more complex clipping path that has three rhomboids in it. There are some tools that help you "draw" the path you want and generate the CSS for you, http://bennettfeely.com/clippy/ is one I was able to find, but there seem to be more as well.
Essentially, you want your path to have points positioned in a way where it looks like you're creating three different shapes, even though it's all one clip.
.polygon-each {
padding: 10px;
text-align: center;
}
.polygon-each-img-wrap img {
margin-bottom: 10px;
width:100%;
-webkit-clip-path: polygon(0% 100%, 15% 0, 33% 0%, 18% 100%, 32% 100%, 46% 0, 66% 0, 52% 100%, 68% 100%, 80% 0%, 100% 0%, 91% 100%);
clip-path: polygon(0% 100%, 15% 0, 33% 0%, 18% 100%, 32% 100%, 46% 0, 66% 0, 52% 100%, 68% 100%, 80% 0%, 100% 0%, 91% 100%);
}
.polygon-each img {
display: block;
margin-left: auto;
margin-right: auto;
}
}
img {
max-width: 100%;
height: auto;
}
https://jsfiddle.net/bjc89nkv/
There's a quick and messy demo of what I was able to "draw" to create such an effect.