How can I Use Clip-Path for slanted edges? - html

Question

Currently using this CSS for a bottom slant going up from left to right:
clip-path: polygon( 0 0, 100% 0, 100% calc(100% - 3vw), 0 100% );
It works very well for a responsive solution but having a hard time figuring out how to do this for a responsive solution for a slant at the top of the div going down from left to right.
I tried this:
clip-path: polygon( 0 0, 100% calc(100% - 29vw), 100% 100%, 0 100% );
Thank you!

Answer 1

You can adjust like below. You make the second point to start lower by 3vw and you put back the other one to 100%
.box {
height: 100px;
background: red;
clip-path: polygon( 0 0, 100% 3vw, 100% 100%, 0 100%);
/* (0,0) ----------------- (100%,0)
| |<---------(100%,3vw)
| |
| |
| |
(0,100%) ----------------- (100%,100%)
}
<div class="box">
</div>
And like this if you want from right to left:
.box {
height: 100px;
background: red;
clip-path: polygon( 0 3vw, 100% 0, 100% 100%, 0 100%);
}
<div class="box">
</div>
On the sides:
.box {
height: 100px;
background: red;
clip-path: polygon( 0 0, calc(100% - 3vw) 0, 100% 100%, 0 100%);
}
<div class="box">
</div>
If you want a more supported way, you can consider multiple background like below:
.box {
height: 100px;
margin:5px;
padding-top:3vw;
background:
/*a triangle shape on the padding-top area*/
linear-gradient(to bottom var(--d,left),transparent 48%,red 50%) top/100% 3.1vw no-repeat,
/*color the content and not the padding-top*/
linear-gradient(red,red) content-box;
}
<div class="box">
</div>
<div class="box" style="--d:right">
</div>