MySQL behaves differently on 3 servers, same version - mysql

I've got this query running on two different fiddle sites, both set to use MySQL 5.6:
SELECT name, rank, position FROM(
SELECT name, position,
#rank:= IF(#prev = name, #rank + 1, 1) AS rank,
#prev:= name
FROM (SELECT * FROM drivers
LEFT JOIN results on drivers.id = results.driver_id
JOIN (SELECT #rank := 1) AS init
ORDER BY name, results.position ASC) AS temp
) AS derived WHERE rank <= 3 ORDER BY name, rank
It's supposed to give the top 3 finishing positions of each driver. The query works on fiddle #1, but not on fiddle #2 or the production server, although all three of them are running on MySQL 5.6.
Is there a setting that I'm missing?
Fiddle #1 - working
Fiddle #2 - not working

You can use the following solution:
SELECT name, rank, position FROM (
SELECT name, position,
#rank:= IF(#prev = name, #rank + 1, 1) AS rank,
#prev:= name
FROM (
SELECT *
FROM drivers LEFT JOIN results ON drivers.id = results.driver_id
JOIN (SELECT #rank := 1) AS init_rank
JOIN (SELECT #prev := '') AS init_prev
ORDER BY name, results.position ASC
) AS temp
) AS derived
WHERE rank <= 3
ORDER BY name, rank
I added the initialization for the #prev variable on a JOIN too.
different demos:
demo on db-fiddle.com
demo on sqlfiddle.com
demo on dbfiddle.uk
Since MySQL 8.0 you can use the built-in RANK window function. So you don't need the #prev or #rank variables:
SELECT name, `rank`, position FROM (
SELECT name, position, RANK() OVER (PARTITION BY name ORDER BY name, position) AS `rank`
FROM drivers LEFT JOIN results ON drivers.id = results.driver_id
) AS derived
WHERE `rank` <= 3
ORDER BY name, `rank`
demo on dbfiddle.uk

Related

Trying to put a variable into limit to find a median

I trying to use mysql to solve the following solutions:
https://www.hackerrank.com/challenges/weather-observation-station-20/problem
Understanding that a variable cannot be put into LIMIT statement (from this )
My approach>
to declare a new variable to record rowIDs, and use rowID to retrieve the record in the middle.
However, it seems that rowID is not working well.
Could anyone give me some advises?
SELECT ROUND(COUNT(LAT_N)/2,0) FROM STATION into #count;
SELECT ROUND(a.LAT_N,4) FROM (
SELECT *,#row := #row + 1 FROM STATION s, (SELECT #row := 0) r
WHERE #row <=#count
ORDER BY s.LAT_N ASC) a
ORDER BY a.LAT_N DESC LIMIT 1;`
If you are running MySQL 8.0, this is simpler done with window functions:
select round(avg(lat_n), 4) median_lat_n
from (
select s.*, row_number() over(orer by lat_n) rn
from station s
where lat_n is not null
) s
where rn * 2 in (rn - 1, rn, rn + 1)
In earlier versions, variables make it bit tricky; we need one more level of nesting to make it safe:
select round(avg(lat_n), 2) median_lat_n
from (
select s.*, #rn := #rn + 1 rn
from (select * from station order by lat_n) s
cross join (select #rn := 0) p
) s
where rn * 2 in (rn - 1, rn, rn + 1)
The logic is as follows: first enumerate the rows, ordered by lat_n. If the row count is uneven, we pick the middle row; if it is even, we take the average of the two middle values.

Mysql: "SET #Variable = 0" in one query [Java]

I have two sql queries. But in Java I can't set variables.
I tried to summarize it to one query. But that not works, because the sql syntax is wrong.
SET #rn = 0;
SELECT *
FROM (SELECT t.id, #rn := #rn + 1 AS rank
FROM stats t
ORDER BY t.points DESC) t2
WHERE t2.id = ?;
If only the SET part is the problem you can do
SELECT t.id, #rn := #rn + 1 AS rank
FROM stats t
CROSS JOIN ( SELECT #rn := 0 ) as parameters
ORDER BY t.points DESC
You can also check this tutorial http://www.mysqltutorial.org/mysql-row_number/
You need to do a join like this :
SELECT stats.id, #rn := #rn+1 AS rank
FROM stats, (SELECT #rn:=0) a
WHERE stats.id = ?
If you have mysql 8.0 you can use: ROW_NUMBER() or RANK() :
SELECT
id,
ROW_NUMBER() OVER w AS 'row_number',
RANK() OVER w AS 'rank',
FROM stats
WHERE stats.id = ?
WINDOW w AS (ORDER BY points);

What would the equivalent statement be in MySQL 5.6.39?

I recently moved to a shared host that has MySQL 5.6.39 instead of MariaDB 10.x, I was wondering what would the equivalent of the following MariaDB statement in MySQL?
SELECT rank,
total
FROM
(SELECT ROW_NUMBER() OVER (
ORDER BY `prestige` DESC, `xp` DESC) AS rank,
(SELECT COUNT(*)
FROM Modular_LS) AS total,
steamid
FROM Modular_LS) sub
WHERE sub.steamid = '%s'
I got as far as this, but now I'm stuck
SELECT rank, total FROM
(SELECT #rank := #rank +1 as rank FROM Modular_LS,
(SELECT COUNT(*) FROM Modular_LS) AS total, steamid FROM Modular_LS) sub,
(SELECT #rank := 0) r ORDER BY `prestige` DESC, `xp` DESC) t;
The table structure contains the column steamid, xp, prestige
My goal is to order by prestige descending first and then xp descending to put it in a ranking like-order, then using WHERE query to find a specific player's ranking. The output of which contains the rank (position) and the total (total amount of records)
Maybe this will get you started:
SELECT #rank := IF(player_id = #prev, #rank + 1, 1), #prev := player_id
FROM ( SELECT #rank := 1, #prev = 0 ) AS init
JOIN ( SELECT player_id
FROM Modular_LS
ORDER BY prestige DESC, SP DESC
) AS x ;
After a few hours, this is what I came up with that solved my problem.
SELECT
sub.rank
,sub.total
FROM
(
SELECT
t.id
,t.steamid
,#rownum : = #rownum + 1 AS rank
,(
SELECT
COUNT (*)
FROM
Modular_LS
) AS total
FROM
Modular_LS t JOIN (
SELECT
#rownum : = 0
) r
ORDER BY
t.prestige DESC
,t.xp DESC
) sub
WHERE
sub.steamid = '%s'

MariaDB/MySQL RANK() implementation

I am working on migration from MS SQL Server to MariaDB 10.0. I have query which use RANK() PARTITION BY. I already created some kind of RANK() implementation on my table but it's not working properly.
The original query was:
RANK() OVER (PARTITION BY visits.id_partner ORDER BY visits.updated_at DESC) AS rank
My implementation for MariaDB/MySQL:
SELECT
...,
(
CASE visits.id_partner
WHEN #currId THEN
#curRow := #curRow + 1
ELSE
#curRow := 1 AND #currId := visits.id_partner
END
) AS rank
FROM
records rec
JOIN visits ON visits.id = rec.id_visit,
(
SELECT
#curRank := 0,
#currId := NULL
) r
WHERE
...
ORDER BY visits.id_partner ASC, visits.updated_at DESC
I want to select row ranked by id_partner order by updated_at field. When id_partner is same as on row before RANK should increase by 1. When is different than before, it should reset to 1.
But my query is not working at all. I have still rank 1 on all rows. Can you help me find mistake?
Thank you for help!
It is tricky to use variables in MySQL/MariaDB. A variable should only be used and assigned in one statement (as you do correctly). However, AND can short-circuit variable assignment.
I use a construct like this for ROW_NUMBER(). RANK() is actually a bit of a pain . . . DENSE_RANK() and ROW_NUMBER() are simpler. However, this seems to be the code that you are aiming for:
SELECT ...,
(#rn := if(#currId = visits.id_partner, #rn + 1,
if(#currId := visits.id_partner, 1, 1)
)
) as rank
FROM records rec JOIN
visits
ON visits.id = rec.id_visit CROSS JOIN
(SELECT #rn := 0, #currId := NULL) params
WHERE
...
ORDER BY visits.id_partner ASC, visits.updated_at DESC;
EDIT:
In MySQL (and presumably in MariaDB), sometimes variables don't work quite right unless you use a subquery. So, try this:
SELECT . . .,
(#rn := if(#currId = visits.id_partner, #rn + 1,
if(#currId := visits.id_partner, 1, 1)
)
) as rank
FROM (SELECT ...
FROM records rec JOIN
visits
ON visits.id = rec.id_visit
WHERE
...
ORDER BY visits.id_partner ASC, visits.updated_at DESC
) t CROSS JOIN
(SELECT #rn := 0, #currId := NULL) params;

Mysql query to get the row position in a table

I have table with id (store user id) and score in different match. I want what is the position of a user.
So for i try this sql fiddle;
in this I am getting all the row but I need only user having id 3 and it position in the table.
like this:
Score Postion
26 3
Even i try to do like this but no success
MySql: Find row number of specific record
With MySQL, how can I generate a column containing the record index in a table?
I got the answer: http://sqlfiddle.com/#!2/b787a/2
select * from (
select T.*,(#rownum := #rownum + 1) as rownum from (
select sum(score) as S,id from mytable group by id order by S desc ) as T
JOIN (SELECT #rownum := 0) r
) as w where id = 3
Updated sqlfiddle and above query. Now it is working perfectly.
I think this should do the trick:
SELECT totalScore, rownum FROM (
SELECT id,sum(score) AS totalScore,(#rownum := #rownum + 1) AS rownum
FROM mytable
JOIN (SELECT #rownum := 0) r
group by id) result
WHERE result.ID = 3;
just add a where clause
select x.id,x.sum,x.rownum
from(
select id,sum(score) as sum,(#rownum := #rownum + 1) as rownum
from mytable
JOIN (SELECT #rownum := 0) r
group by id
) x
where id =3