I have table with id (store user id) and score in different match. I want what is the position of a user.
So for i try this sql fiddle;
in this I am getting all the row but I need only user having id 3 and it position in the table.
like this:
Score Postion
26 3
Even i try to do like this but no success
MySql: Find row number of specific record
With MySQL, how can I generate a column containing the record index in a table?
I got the answer: http://sqlfiddle.com/#!2/b787a/2
select * from (
select T.*,(#rownum := #rownum + 1) as rownum from (
select sum(score) as S,id from mytable group by id order by S desc ) as T
JOIN (SELECT #rownum := 0) r
) as w where id = 3
Updated sqlfiddle and above query. Now it is working perfectly.
I think this should do the trick:
SELECT totalScore, rownum FROM (
SELECT id,sum(score) AS totalScore,(#rownum := #rownum + 1) AS rownum
FROM mytable
JOIN (SELECT #rownum := 0) r
group by id) result
WHERE result.ID = 3;
just add a where clause
select x.id,x.sum,x.rownum
from(
select id,sum(score) as sum,(#rownum := #rownum + 1) as rownum
from mytable
JOIN (SELECT #rownum := 0) r
group by id
) x
where id =3
Related
I already googled but couldn't find a solution.
I have two columns called order_id and name. I want to ORDER BY name and then SET ascending order_id.
Like this:
order_id name
1 Arya
2 Herbert
3 Paul
4 Peter
5 Tiffany
My id column is int(4) and by default value is 0. It's not PRIMARY or UNIQUE. (It'a also not the main id. Main id is of course PRIMARY.
How can I do this with SQL?
You could use ROW_NUMBER(MySQL 8.0+):
SELECT name, ROW_NUMBER() OVER(ORDER BY name) AS rn
FROM tab
ORDER BY rn;
Update:
UPDATE tab
SET order_id = (SELECT rn FROM (SELECT name,ROW_NUMBER() OVER(ORDER BY name) AS rn
FROM tab)s
WHERE s.name = tab.name); -- assuming that name is UNIQUE
DBFidde Demo
For versions < 8.0 you can use this:
select #rn := 0;
UPDATE tbl T1
JOIN (select #rn := #rn + 1 rn, `name` from tbl order by `name`) T2
ON T1.`name` = T2.`name`
SET T1.order_id = T2.rn
Demo
Useful article related to your problem: MySQL UPDATE JOIN
As your mysql version is below 8.0 so you have to manually generate orderid
below can help you
select t.*,
#rownum := #rownum + 1 AS order_id from
(
select * from
tab o order by name asc
) as t , (SELECT #rownum := 0) r
http://www.sqlfiddle.com/#!9/ae3fda/3
I have the following table on my DataBase:
TimeRank(user-id, name, time)
I would like to order the table by time and get the position of an specific ID on the table, for example:
The user nº 68 is on the 3rd position.
I only need to do a query that returns the position of the user.
MySQL don't have the function row_number, so I don't know how to do it.
SELECT x.user-id,
x.name,
x.time,
x.position
FROM (SELECT t.user-id,
t.name,
t.time,
#rownum := #rownum + 1 AS position
FROM TABLE TimeRank t
JOIN (SELECT #rownum := 0) r
ORDER BY t.time) x
WHERE x.user-id = 123
Alternative:
SELECT user-id,
(SELECT COUNT(*) FROM TimeRank WHERE time <= (SELECT time FROM TimeRank WHERE user-id = 123)) AS position,
time,
name
FROM TimeRank
WHERE user-id = 123
You can generate a position column with a variable
set #pos=0;
select pos,user_id
from (select #pos:=#pos+1 pos,user_id from TimeRank order by time) s
where user_id=68;
If indexing is a concern, you can add a column to your table and update it with
set #pos=0;
update TimeRank set position=(#pos:=#pos+1) order by time;
I've got a logs table with an ID column in it, and I want to do the following:
Select the ID and row number
Join the table to itself based on the row number
My objective is to get a specific row as well as the row before it. The SQL query below actually returns nothing. It's like it forgets the row number entirely. Joining on ID returns just fine.
Is there something that needs to be done in MySQL to support this kind of operation?
select * from
(select id, #rownum := #rownum + 1 as 'row'
from logs, (select #rownum := 0) r order by id) a
join
(select id, #rownum := #rownum + 1 as 'row'
from logs, (select #rownum := 0) r order by id) b
on a.row = b.row;
Change your variable name in second query, using same variable in both queries can produce unexpected results
select * from
(select id, #rownum := #rownum + 1 as 'row'
from logs, (select #rownum := 0) r order by id) a
join
(select id, #rownum1 := #rownum1 + 1 as 'row1'
from logs, (select #rownum1 := 0) r order by id) b
on a.row = b.row1;
I have the table with data:
And for this table I need to create pegination by productId column. I know about LIMIT N,M, but it works with rows and not with groups. For examle for my table with pegination = 2 I expect to retrieve all 9 records with productId = 1 and 2 (the number of groups is 2).
So how to create pegination by numbers of groups ?
I will be very thankfull for answers with example.
One way to do pagination by groups is to assign a product sequence to the query. Using variables, this requires a subquery:
select t.*
from (select t.*,
(#rn := if(#p = productid, #rn + 1,
if(#rn := productid, 1, 1)
)
) as rn
from table t cross join
(select #rn := 0, #p := -1) vars
order by t.productid
) t
where rn between X and Y;
With an index on t(productid), you can also do this with a subquery. The condition can then go in a having clause:
select t.*,
(select count(distinct productid)
from t t2
where t2.productid <= t.productid)
) as pno
from t
having pno between X and Y;
Try this:
select * from
(select * from <your table> where <your condition> group by <with your group>)
LIMIT number;
I have a MySQL table called "MyTable" and it basically lists usernames and points (two columns, name and points). I want to say something like "what is joe1928's rank?", which of course is based off his points. How could I do this in MySQL without having to download all that data and sort it and determine the rank myself?
The person with the highest number of points would be ranked 1.
Try getting the number of people with a higher score than your user:
select count(*) from MyTable where score > (select score from MyTable where user = 'Joe');
That will return 0 for the top user.
This page seems to describe and solve your problem.
Notes from that page:
SET #rownum := 0;
SELECT rank, correct FROM (
SELECT #rownum := #rownum + 1 AS rank, correct, uid
FROM quiz_user ORDER BY correct DESC
) as result WHERE uid=xxxxxxxx
SELECT #r AS Rank
FROM MyTable u, (SELECT #r := 0)
WHERE (#r := #r + 1) * (u.Username = 'joe1928')
ORDER BY u.Score DESC
LIMIT 1
select * from [TABLENAME] where [USERNAME] = blah order by [POINTS] desc limit 1;
Based on the link posted by #Dave your query will look like something below:
select Rank,name from
(select #rownum:=#rownum+1 AS 'Rank', p.name
from calls p, (select #rownum:=0) r
order by p.points desc) as rankResults
where name = 'joe';
This is from another stack overflow page, seems to solve your problem.
SELECT uo.*,
(
SELECT COUNT(*)
FROM users ui
WHERE (ui.points, ui.id) >= (uo.points, uo.id)
) AS rank
FROM users uo
WHERE id = #id