product
-----------
product_id
product_name
product_description
price
size
productpictures
--------------
product_id
picture_id
pictures
---------
picture_id
picture_name
every product has 2 pictures but i only need the name, size, description and price once but i need both the pictures.
i used:
SELECT
product.product_description,
product.product_name,
product.price,
product.size,
pictures.picture_name
FROM product
LEFT OUTER JOIN productpictures
ON product.product_id = productpictures.product_id
LEFT OUTER JOIN bilde
ON productpictures.picture_id = pictures.picture_id
WHERE product.product_id = 1
But I get two rows with double up name, price, size and description, but the picture names are different, but how can i insert both picture names into my php file so it shows the information about the product and both pictures?
i tried printing the row picture name but that only gave me the first name but not the second.
size product_name price picture_name
50x70cm Sandvasket silke 399 Elfenben.PNG
50x70cm Sandvasket silke 399 SVElfenben.JPG
this is my current ressult with my current sql statement. basically whan i want in php is to echo the size name and price in a p tag, thats no problem but i also want to echo both the picture_names in a img tag
With just exactly two pictures per product, one solution is to use aggregation:
SELECT
pr.product_description,
pr.product_name,
pr.price,
pr.size,
MAX(pi.picture_name) picture_name1,
MIN(pi.picture_name) picture_name2
FROM product pr
LEFT JOIN productpictures pp ON pr.product_id = pp.product_id
LEFT JOIN pictures pi ON pp.picture_id = pi.picture_id
WHERE pr.product_id = 1
GROUP BY
pr.product_id,
pr.product_description,
pr.product_name,
pr.price,
pr.size
PS: I added table aliases to your query, they make the query easier to read and maintain (and allow self-JOINing when necessary...).
Related
Background
Products can be sold as bundles. Following tables are present: products, bundles, bundles_products, orders, orders_products.
An order would be said to "contain" a bundle if it contains all the bundle's products.
Problem
How would one go about counting orders for bundles?
Example
products table
id name
1 broom
2 mug
3 spoon
4 candle
bundles table
id name
1 dining
2 witchcraft
bundles_products table
bundle_id product_id
1 2
1 3
2 1
2 4
orders_products table
order_id product_id
1000 1
1000 3
1001 1
1001 2
1001 3
The query would return the following table:
bundle orders
dining 1
witchcraft 0
Notes
The example intentionally misses the orders table as it is not relevant what it contains.
Of course, this could be approached imperatively, by writing some code and gathering the data, but I was hoping there is a declarative, SQL way of querying for this kind of things?
One idea I had was to use a GROUP_CONCAT to concatenate all the products of a bundle and somehow compare that with products of each order. Still, a long way from clear.
One way is to use two Derived Tables (subqueries). In first subquery, we will fetch the total number of unique products for every bundle. In the second subquery, we will fetch the total products in an order, for a combination of order and bundle.
We will LEFT JOIN them on bundle_id as well as matching the total count of products per bundle in them. Eventually, we will do a grouping on bundle, and count the number of orders matching successfully.
SELECT dt1.id AS bundle_id,
dt1.name AS bundle,
Count(dt2.order_id) AS orders
FROM (SELECT b.id,
b.name,
Count(DISTINCT bp.product_id) AS total_bundle_products
FROM bundles AS b
JOIN bundles_products AS bp
ON bp.bundle_id = b.id
GROUP BY b.id,
b.name) AS dt1
LEFT JOIN (SELECT op.order_id,
bp.bundle_id,
Count(DISTINCT op.product_id) AS order_bundle_products
FROM orders_products AS op
JOIN bundles_products AS bp
ON bp.product_id = op.product_id
GROUP BY bp.bundle_id,
op.order_id) AS dt2
ON dt2.bundle_id = dt1.id
AND dt2.order_bundle_products = dt1.total_bundle_products
GROUP BY dt1.id,
dt1.name
SQL Fiddle DEMO
Here's the brief example, which lacks some parts, I omitted because I don't know precise database structure. Logic is such:
Temp table is generated, which consists of 3 rows - order, count of
products related to bundle, count of products in bundle
Then we select only orders from this table in which we have those last two
variables equal
select count(order_id) from orders
left join(
select count(*) from bundles_products as bundle_amount,
sum(case when orders_products in (
select names from bundles_products where bundle_id='1') then 1 else 0) as order_total,
orders.order_id
left join product on bundle_products.product_id = products.product_id
left join orders on products.product_id = orders_products.product_id
where bundle_products.bundle_id ='1'
) as my_table
on orders.order_name = my_table.orders
where my_table.bundle_amount = my_table.order_total
Edit: I posted this as a response to previous version of the question, without detailed explanation.
Edit2: fixed query a bit. It can be starting point. Logic is still the same, you can get amount of orders for each bundle_id using it
Even though my question was warned as similar title, I couldn't find here any similar problem. Let me explain in details:
I've got two tables (I'm working with MySQL) with these values inserted:
table products:
id name
1 TV
2 RADIO
3 COMPUTER
table sales (product_id is A FK which references products(id)):
id quantity product_id
1 50 2
2 100 3
3 200 3
The tv's haven't been sold, radios got 1 sale (of 50 unities) and computers got two sales (one of 100 e other of 200 unities);
Now I must create a query where I can show the products and its sales, but there are some conditions that make that task difficult:
1 - If there's no sales, show obviously NULL;
2 - If there's 1 sale, show that sale;
3 - If there's more than 1 sale, show the latest sale (which I've tried to use function MAX(id) to make it simple, and yet didn't worked);
In the tables example above, I expect to show this, after a proper SQL Query:
products.NAME sales.QUANTITY
TV NULL
RADIO 50
COMPUTER 200
I've been trying lots of joins, inner joins, etc., but couldn't find the result I expect. Which SQL query can give the answer I expect?
Any help will be very appreciated.
Thanks.
Hope the below query works.
SELECT products.name, sl.quantity
FROM products LEFT JOIN (
SELECT product_id, max(quantity) as quantity FROM sales GROUP BY product_id) sl
ON products.id = sl.product_id
In MySQL 8.0 you can do:
with m (product_id, max_id) as ( -- This is a CTE
select product_id, max(id) from sales group by product_id
)
select
p.name,
s.quantity
from products p
left join m on m.product_id = p.id
left join sales s on s.id = m.max_id
If you have an older MySQL, you can use a Table Expression:
select
p.name,
s.quantity
from products p
left join ( -- This is a table expression
select product_id, max(id) as max_id from sales group by product_id
) m on m.product_id = p.id
left join sales s on s.id = m.max_id
For the sake of clarity and this question i will rename the tables so it is a bit clearer for everybody and explain what i want to achieve:
There is an input form with options that return categories ID's. If a 'Product' has 'Category', i want to return/find the 'Product' which lets say has multiple categories(or just 1) and all of its categories are inside the array that is passed from the form.
Products table
ID Title
1 Pizza
2 Ice Cream
Categories table
ID Title
1 Baked food
2 Hot food
ProductsCategories table
ID ProductId CategoryId
1 1 1
2 1 2
So if i pass [1,2] the query should return Product with id 1 since all ProductsCategories are inside the requested array, but if i pass only 1 or 2, the query should return no results.
Currently i have the following query which works, but for some reason if i create a second Product and create a ProductCategory that has a CategoryId same as the first product, the query returns nulll...
SELECT products.*
FROM products
JOIN products_categories
ON products_categories.product_id= products.id
WHERE products_categories.category_id IN (1, 2)
HAVING COUNT(*) = (select count(*) from products_categories pc
WHERE pc .product_id = products.id)
All help is deeply appretiated! Cheers!
In order to match all values in IN clause, you just need to know in addition the number of passed categories which you must use it in HAVING clause:
SELECT
p.*,
GROUP_CONCAT(c.title) AS categories
FROM
Products p
INNER JOIN ProductsCategories pc ON pc.productId = p.ID
INNER JOIN Categories c ON c.ID = pc.categoryId
WHERE
pc.categoryId IN (1,2)
GROUP BY
p.id
HAVING
COUNT(DISTINCT pc.categoryId) = 2 -- this is # of unique categories in IN clause
So in case IN (1,2) result is:
+----+-------+---------------------+
| id | title | categories |
+----+-------+---------------------+
| 1 | Pizza | Baked Food,Hot Food |
+----+-------+---------------------+
1 row in set
In case IN (1,3) result is Empty set (no results).
#mitkosoft, thanks for your answer, but sadly the query is not producing the needed results. If the product's categories are partially in the passed categories the product is still returned. Additionally i might not know how many parameters are sent by the form.
Luckily I managed to create the query that does the trick and works perfectly fine (at least so far)
SELECT products.*,
COUNT(*) as resultsCount,
(SELECT COUNT(*) FROM products_categories pc WHERE pc.product_id = products.id) as categoriesCount
FROM products
JOIN products_categories AS productsCategories
ON productsCategories.product_id= products.id
WHERE productsCategories.category_id IN (7, 15, 8, 1, 50)
GROUP BY products.id
HAVING resultsCount = categoriesCount
ORDER BY amount DESC #optional
That way the query is flexible and gives me exactly what I needed! - Only those products that have all their categories inside the search parameters(not partially).
Cheers! :)
This are my tables:
Part table:
Part_id name
1 Case
2 Pen
3 Chicken
(Between table)table:
Part_id product_id
2 10
2 10
3 30
Product table:
product_id Name
10 Phone
20 Camera
30 Mouse
I want to search on the product name and get the product name back + the linked part name. But if i search on part name i want to get the part name and product name back.
I don't know how to join the tables but don't know how to preform an search like that.
Select part.name, product.name
from part
left join betweentable on part.part_id = betweentable.part_id
But i don't know how to join the next table. And than search to it.
Let me see if I understand this correctly... you have a name, which may be a product name or a part name, and you want to search for that, and return the linked parts if it's a product, or the linked products if it's a part.
If that's what you're asking, you can use the following query:
Select part.name, product.name
from part
left join betweentable on part.part_id = betweentable.part_id
left join product on product.id = betweentable.product_id
where part.name = <input_name>
union
Select part.name, product.name
from product
left join betweentable on product.id = betweentable.product_id
left join part on part.part_id = betweentable.part_id
where product.name = <input_name>;
< input_name > is the name you're searching for.
Simply add an other join:
Select part.name, product.name
from part
left join betweentable on part.part_id = betweentable.part_id
left join product on product.id = betweentable.product_id
Hi I want to get opposite of intersect from two tables.
I have a sale table and purchase table. What I want to do is get all purchases ids where not included in the sales table.
sale table
sale_id (pk)
product_id (fk)
purchase_id (fk)
purchase table
product_id (fk)
purchase_id (pk)
SELECT DISTINCT purchase_id
, product_id
FROM
purchase
INNER JOIN sale
USING (purchase_id, product_id);
Here is an example:
If I run the above code, this will be the result.
purchase_id product id
1 1
1 2
1 4
2 1
2 3
Now I want to get:
purchase_id product id
1 3
2 2
In short I want to get inverse of above code. Thanks in advance.
Okay, I think I understand better now.
This should return any entry in purchase that have no matching entry in sales.
SELECT
`purchase`.`purchase_id`, `purchase`.`product_id`
FROM `purchase`
LEFT JOIN `sale` ON `sale`.`purchase_id` = `purchase`.`purchase_id` AND `sale`.`product_id` = `purchase`.`product_id`
WHERE
`sale`.`sale_id` IS NULL
ORDER BY
`purchase`.`purchase_id`, `purchase`.`product_id`
If you want to get all the purchases that have no related values in the sales table, you can use a LEFT JOIN:
select
p.purchase_id
from
purchase as p
left join sale as s on p.purchase_id = s.purchase_id
where
s.purchase_id is null;
"Unilateral" joins (LEFT JOIN, RIGHT JOIN) are useful when you want to get data from a table even if data in another related table does not exist. Of course, that means that you can filter data from one table when there's no related data in a second table.
Hope this helps.
Looking at your updated question and your comment, I think that you want all the possible combinations not used.
You'll need to split this in two steps:
First you need all the possible combinations of purchase_id and sale_id values (the "cartesian product" of both the sets).
Then you need to get all the combinations already used.
Finally you need to exclude all the combinations already used.
This can be done using subqueries.
Step 1.
select distinct p.purchase_id, s.product_id from purchase as p, sale as s;
Step 2. (Your query)
select distinct
purchase_id, product_id
from
purchase as p
inner join sale as s
on (p.purchase_id = s.purchase_id and p.product_id = s.product_id);
Step 3. Put it all together
select
a.*
from
(select distinct p.purchase_id, s.product_id from purchase as p, sale as s) as a
left join (
select distinct
purchase_id, product_id
from
purchase as p
inner join sale as s
on (p.purchase_id = s.purchase_id and p.product_id = s.product_id)
) as e on (a.purchase_id = e.purchase_id and a.product_id = e.product_id)
where
e.purchase_id is null and e.product_id is null;