persons is a tinytext field and can contain "4 + 2", "4+2", "4 +2", "5" or "" and so on.
I would like to select and int like 6, 6, 6, 5 and 0 from that MySQL 5.6 Table.
Tried this without success:
SELECT CAST(persons AS INT) FROM Table
SELECT CONVERT(INT, persons ) FROM Table
If + is the only operator and it appears once, then:
select (case when col like '%+%'
then substring_index(col, '+', 1) + substring_index(replace(col, ' ', ''), '+', -1)
else col + 0
end) as added_value
use SUBSTRING_INDEX
select SUBSTRING_INDEX(col , "+", 1)+ SUBSTRING_INDEX(col , "+", -1) as col1
from cte where col like '%+%'
union all
select SUBSTRING_INDEX(col , "+", 1) from cte where col not like '%+%'
output
col1
6
6
6
5
the upper solution will work only for your sample data
demo link
What database are you using? You may need to use something db specific. e.g. in oracle you can do:
select dbms_aw.eval_number ('4+2') from dual
It will return 6.
Generally speaking - using dynamic SQL you can easily achieve this.
Related
I have taken reference from the internet about one user-defined function to locate 'nth occurrence of a string to do the sort column name in the database. I am using MySQL 5.5 version, not the latest version. Here is my sample database link https://dbfiddle.uk/?rdbms=mysql_5.5&fiddle=bcb32a6b47d0d5b061fd401d0888bdc3
My problem is I want to sort column name in the database follow the prefix number, but I am using below the SQL query, it doesn't work.
select t.id,t.name
from
(
select t.*, cast((case when col1_col2_ref > 0
then
substring_index(modified_name,'-',1)
else
modified_name
end
) as unsigned) col1
, cast((case when col1_col2_ref > 0
and col3_ref > 0
then
substr(modified_name,(col1_col2_ref + 1),(col3_ref - (col1_col2_ref + 1)))
when col1_col2_ref > 0
then
substr(modified_name,(col1_col2_ref + 1))
end) as unsigned) col2
, cast((case when col3_ref > 0
and col4_ref > 0
then
substr(modified_name,(col3_ref + 1),(col4_ref - (col3_ref + 1)))
when col3_ref > 0
then
substr(modified_name,(col3_ref + 1))
end) as unsigned) col3
, cast((case when col4_ref > 0
then
substr(modified_name,(col4_ref + 1))
end) as unsigned) col4
from
(
select t.*,substring_index(name,' ',1) modified_name
,locate('-',name,1) col1_col2_ref
,locate('/',name,1) col3_ref
,locate('/',name,locate('/',name,1)+1) col4_ref
from filing_code_management t
) t
) t
order by col1,col2,col3,col4
It shows me below the result, it cannot sort properly.
Output 1
Actually I want the output sample like below:
Output 2
Output 3
This is before I can sort the column name link, https://dbfiddle.uk/?rdbms=mysql_5.5&fiddle=6b12a4d42359cb30f27a5bfb9d0c8210. After I am inserted into new data, it cannot work for me. Maybe an example in new data like this error (R)100-6-2-2 Mesyuarat Majlis Kerajaan Negeri (MMKN) JKK if I put () in front. Or in new data like this error 100-1-1 Penggubalan/Penyediaan/Pindaan Undang-Undang/Peraturan if I put / in between the word.
Hope someone can guide me to solve this problem. Thanks.
You should be able to adapt the following code to your needs (tested at your DB Fiddle!). I've used the file_name column instead of the name column to slightly simplify building the sort fields, as it seems the file name is always repeated in the first part of the name field anyway.
This would be quite a bit simpler using regular expression support, but I note that the version of MySQL you are using doesn't have this feature (I think it arrives in SQL 8.0, if I'm not mistaken).
SELECT id,
num_hyphens,
CAST(SUBSTRING_INDEX(CONCAT(file_name_adj,'-'), '-', 1) AS UNSIGNED) AS sort1,
CAST(CASE WHEN num_hyphens = 0
THEN '0'
ELSE SUBSTRING_INDEX(SUBSTRING_INDEX(file_name_adj,'-', 2), '-',-1)
END AS UNSIGNED) AS sort2,
CAST(CASE WHEN num_hyphens <= 1
THEN '0'
ELSE SUBSTRING_INDEX(SUBSTRING_INDEX(file_name_adj,'-', 3), '-',-1)
END AS UNSIGNED) AS sort3,
CAST(CASE WHEN num_hyphens <= 2
THEN '0'
ELSE SUBSTRING_INDEX(file_name_adj, '-', -1)
END AS UNSIGNED) AS sort4,
file_name,
name
FROM (
SELECT id, name, MID(file_name, instr(file_name, ')') + 1) AS file_name_adj, file_name,
LENGTH(file_name) - LENGTH(REPLACE(file_name, '-', '')) AS num_hyphens
FROM filing_code_management
) t1
ORDER BY sort1, sort2, sort3, sort4
Please take a look at a table below:
I need "the last part" of "what I have" to be number if it's all number and string if it contains character.
In Excel I've achieved this with the following function (as shown above):
=IFERROR(VALUE(TEXT(D2;"0"));TEXT(D2;"0"))
However I want to do this in mySQL in order to compute more effectively.
I've "floated" somwhere around CASE with CAST or CONVERT and also TRIM functions, but I haven't been able to put up something sensical.
A nice "bonus" would be to extract "the part part" by looking for the last "" character (so first "" from right of the string) but no idea at all how to achieve that.
Use SUBSTRING_INDEX.
Query
SELECT
CASE
WHEN SUBSTRING_INDEX(records.data, '_', -1) > 1 # is int check '00004949' returns 1
THEN SUBSTRING_INDEX(records.data, '_', -1) + 0 # converts '00004949' to 4949
ELSE SUBSTRING_INDEX(records.data, '_', -1)
END
AS word
FROM (
SELECT "TRA_PL_NWL_EMA_NWLY_DAI_000_20170610_IN1_01P002bc" AS DATA
UNION
SELECT "TRA_PL_NWL_EMA_NWLY_DAI_000_2017_0909_JET_00004949" AS DATA
) records
Result
word
----------
01P002bc
4949
Following query will somewhat achieve the task:
SELECT
case
when SUBSTRING_INDEX(value, "_", -1) REGEXP('(^[0-9]+$)')
then Trim(Leading 0 from SUBSTRING_INDEX(value, "_", -1))
else SUBSTRING_INDEX(value, "_", -1)
end as Value
From yourtable;
Click here for Demo
Hope it helps!
I hope this is what u want.
At least it does what you have asked for.
SELECT
CASE
WHEN (
CONVERT(
substring(
txt,
LENGTH(txt) - LOCATE('_', REVERSE(txt))+2,
length(txt)
)
, signed integer
)
) = 0
THEN substring(
txt,
LENGTH(txt) - LOCATE('_', REVERSE(txt))+2,
length(txt)
)
ELSE CONVERT(
substring(
txt,
LENGTH(txt) - LOCATE('_', REVERSE(txt))+2,
length(txt)
)
, signed integer
)
END as NUMBER
from test.test
This is my test Table and result of SQL:
txt NUMBER
DA_DA_ADAD_ADAD_ADAD_asd123 asd123
DA_DA_ADAD_ADAD_ADAD_000123 123
DA_DA_ADAD_ADAD_ADAD_444 444
DA_DA_ADAD_ADAD_ADAD_bsd123 bsd123
DA_DA_ADAD_ADAD_ADAD_csd123 csd123
DA_DA_ADAD_ADAD_ADAD_dsd123 dsd123
I need to find the frequency of a string in a column, irrespective of its case and any white spaces.
For example, if my string is My Tec Bits and they occur in my table like this, as shown below :
061 MYTECBITS 12123
102 mytecbits 24324
103 MY TEC BITS 23432
247 my tec bits 23243
355 My Tec Bits 23424
454 My Tec BitS 23432
Then, the output should be 6, because, with whites pace removed and irrespective of case, all those strings are identical.
Is there any grep() equivalent in SQL as there is in R?
If your concern is only with the SPACE and the CASE, then you need two functions:
REPLACE
UPPER/LOWER
For example,
SQL> WITH DATA AS(
2 SELECT 'MYTECBITS' STR FROM DUAL UNION ALL
3 SELECT 'mytecbits' STR FROM DUAL UNION ALL
4 SELECT 'MY TEC BITS' STR FROM DUAL UNION ALL
5 SELECT 'my tec bits' STR FROM DUAL UNION ALL
6 SELECT 'MY TEC BITS' STR FROM DUAL UNION ALL
7 SELECT 'MY TEC BITS' STR FROM DUAL
8 )
9 SELECT UPPER(REPLACE(STR, ' ', '')) FROM DATA
10 /
UPPER(REPLA
-----------
MYTECBITS
MYTECBITS
MYTECBITS
MYTECBITS
MYTECBITS
MYTECBITS
6 rows selected.
SQL>
Then, the output should be 6
So, based on that, you need to use it in the filter predicate and COUNT(*) the rows returned:
SQL> WITH DATA AS(
2 SELECT 'MYTECBITS' STR FROM DUAL UNION ALL
3 SELECT 'mytecbits' STR FROM DUAL UNION ALL
4 SELECT 'MY TEC BITS' STR FROM DUAL UNION ALL
5 SELECT 'my tec bits' STR FROM DUAL UNION ALL
6 SELECT 'MY TEC BITS' STR FROM DUAL UNION ALL
7 SELECT 'MY TEC BITS' STR FROM DUAL
8 )
9 SELECT COUNT(*) FROM DATA
10 WHERE UPPER(REPLACE(STR, ' ', '')) = 'MYTECBITS'
11 /
COUNT(*)
----------
6
SQL>
NOTE The WITH clause is only to build the sample table for demonstration purpose. In our actual query, remove the entire WITH part, and use your actual table_name in the FROM clause.
So, you just need to do:
SELECT COUNT(*) FROM YOUR_TABLE
WHERE UPPER(REPLACE(STR, ' ', '')) = 'MYTECBITS'
/
You could use something like
UPPER(REPLACE(userString, ' ', ''))
to check for upper case only and to remove white space.
You could cast your statements to LOWER() before comparing them eg.
LOWER(column_name) = LOWER(variable)
more specific:
LOWER(First_name) = LOWER('JoHn DoE')
would become first name = 'john doe'
For the spacing you should use replace, the format for that is:
REPLACE(yourstring, ' ' , '')
' ' = a space character replace it by an empty string = ''
So you would do
WHERE LOWER(REPLACE(fieldname, ' ', '') = 'mytecbits'
You need to use count to bring back the number affected, Lower will place the data into lower case so that when you make a comparison you can make it lower case.
To remove spaces you then use Replace and replace the space with an empty string for your comparison:
Select COUNT(ColumnA)
from table
where Lower(Replace(ColumnB, ' ', '')) = 'mytecbits'
If you are looking for the number of instances of one specific string, irrespective of case / whitespace, then you need to do the following -
ignore whitespace
ignore case
count the number of instances of the string
So you want a query like the following -
SELECT
COUNT(field)
FROM
table
WHERE
UPPERCASE(REPLACE(field, ' ', '')) = UPPERCASE(REPLACE(userstring, ' ', ''))
This counts the number of rows in your table where field is the same as the userstring, when case is ignored (all set to the same case using UPPERCASE, so it is effecitvely ignored), and spaces are ignored (spaces are removed from the field and the userstring using REPLACE)
Since REGEXP is case insensitive, you can obtain a match by making the spaces optional, example:
SELECT count(field) FROM yourtable WHERE field REGEXP "MY *TEC *BITS";
Note: if needed, you can add a space or a [[:<:]] (word boundary) before "MY" and a space or a [[:>:]] after "BITS" to avoid false positive.
I'm trying to do a WHERE myColumn like -Second Word is "is"-.
Since I can't use regular expressions, I'm not how I can do this. '% is' returns results that have the word is later on... Is this even possible ?
It's not particularly elegant, but this will work :
select * from MyTable
where MyColumn like '%[ ]SearchTerm%' and
CHARINDEX(' ', MyColumn, 0) + 1 = CHARINDEX('SearchTerm', MyColumn, 0)
This assumes a table called MyTable, a column to look in called MyColumn and a string to look for of "SearchTerm"
Here you go:
SELECT *
FROM TestTB
WHERE SUBSTRING(TestColumn, CHARINDEX('-', TestColumn, 1), CHARINDEX('-', TestColumn, 1) + 1) LIKE '%Val%'
Sql Fiddle Demo
There is a SQL table mytable that has a column mycolumn.
That column has text inside each cell. Each cell may contain "this.text/31/" or "this.text/72/" substrings (numbers in that substrings can be any) as a part of string.
What SQL query should be executed to display a list of unique such substrings?
P.S. Of course, some cells may contain several such substrings.
And here are the answers for questions from the comments:
The query supposed to work on SQL Server.
The prefered output should contain the whole substring, not the numeric part only. It actually could be not just the number between first "/" and the second "/".
And it is varchar type (probably)
Example:
mycolumn contains such values:
abcd/eftthis.text/31/sadflh adslkjh
abcd/eftthis.text/44/khjgb ljgnkhj this.text/447/lhkjgnkjh
ljgkhjgadsvlkgnl
uygouyg/this.text/31/luinluinlugnthis.text/31/ouygnouyg
khjgbkjyghbk
The query should display:
this.text/31/
this.text/44/
this.text/447/
How about using a recursive CTE:
CREATE TABLE #myTable
(
myColumn VARCHAR(100)
)
INSERT INTO #myTable
VALUES
('abcd/eftthis.text/31/sadflh adslkjh'),
('abcd/eftthis.text/44/khjgb ljgnkhj this.text/447/lhkjgnkjh'),
('ljgkhjgadsvlkgnl'),
('uygouyg/this.text/31/luinluinlugnthis.text/31/ouygnouyg'),
('khjgbkjyghbk')
;WITH CTE
AS
(
SELECT MyColumn,
CHARINDEX('this.text/', myColumn, 0) AS startPos,
CHARINDEX('/', myColumn, CHARINDEX('this.text/', myColumn, 1) + 10) AS endPos
FROM #myTable
WHERE myColumn LIKE '%this.text/%'
UNION ALL
SELECT T1.MyColumn,
CHARINDEX('this.text/', T1.myColumn, C.endPos) AS startPos,
CHARINDEX('/', T1.myColumn, CHARINDEX('this.text/', T1.myColumn, c.endPos) + 10) AS endPos
FROM #myTable T1
INNER JOIN CTE C
ON C.myColumn = T1.myColumn
WHERE SUBSTRING(T1.MyColumn, C.EndPos, 100) LIKE '%this.text/%'
)
SELECT DISTINCT SUBSTRING(myColumn, startPos, EndPos - startPos)
FROM CTE
Having a table named test with the following data:
COLUMN1
aathis.text/31/
this.text/1/
bbbthis.text/72/sksk
could this be what you are looking for?
select SUBSTR(COLUMN1,INSTR(COLUMN1,'this.text', 1 ),INSTR(COLUMN1,'/',INSTR(COLUMN1,'this.text', 1 )+10) - INSTR(COLUMN1,'this.text', 1 )+1) from test;
result:
this.text/31/
this.text/1/
this.text/72/
i see your problem:
Assume the same table as above but now with the following data:
this.text/77/
xxthis.text/33/xx
xthis.text/11/xxthis.text/22/x
xthis.text/1/x
The following might help you:
SELECT SUBSTR(COLUMN1, INSTR(COLUMN1,'this.text', 1 ,1), INSTR(COLUMN1,'/',INSTR(COLUMN1,'this.text', 1 ,1)+10) - INSTR(COLUMN1,'this.text', 1 ,1)+1) FROM TEST
UNION
SELECT CASE WHEN (INSTR(COLUMN1,'this.text', 1,2 ) >0) THEN
SUBSTR(COLUMN1, INSTR(COLUMN1,'this.text', 1,2 ), INSTR(COLUMN1,'/',INSTR(COLUMN1,'this.text', 1 ,2),2) - INSTR(COLUMN1,'this.text', 1,2 )+1) end FROM TEST;
it will generate the following result:
this.text/1/
this.text/11/
this.text/22/
this.text/33/
this.text/77/
The downside is that you need to add a select statement for every occurance you might have of "this.text". If you might have 100 "this.text" in the same cell it might be a problem.
SQL> select SUBSTR(column_name,1,9) from tablename;
column_name
this.text
SELECT REGEXP_SUBSTR(column_name,'this.text/[[:digit:]]+/')
FROM table_name