SQL server like statement for second word - sql-server-2008

I'm trying to do a WHERE myColumn like -Second Word is "is"-.
Since I can't use regular expressions, I'm not how I can do this. '% is' returns results that have the word is later on... Is this even possible ?


It's not particularly elegant, but this will work :
select * from MyTable
where MyColumn like '%[ ]SearchTerm%' and
CHARINDEX(' ', MyColumn, 0) + 1 = CHARINDEX('SearchTerm', MyColumn, 0)
This assumes a table called MyTable, a column to look in called MyColumn and a string to look for of "SearchTerm"


Here you go:
SELECT *
FROM TestTB
WHERE SUBSTRING(TestColumn, CHARINDEX('-', TestColumn, 1), CHARINDEX('-', TestColumn, 1) + 1) LIKE '%Val%'
Sql Fiddle Demo

Related

Convert a string with operation to int using sql query

persons is a tinytext field and can contain "4 + 2", "4+2", "4 +2", "5" or "" and so on.
I would like to select and int like 6, 6, 6, 5 and 0 from that MySQL 5.6 Table.
Tried this without success:
SELECT CAST(persons AS INT) FROM Table
SELECT CONVERT(INT, persons ) FROM Table

If + is the only operator and it appears once, then:
select (case when col like '%+%'
then substring_index(col, '+', 1) + substring_index(replace(col, ' ', ''), '+', -1)
else col + 0
end) as added_value

use SUBSTRING_INDEX
select SUBSTRING_INDEX(col , "+", 1)+ SUBSTRING_INDEX(col , "+", -1) as col1
from cte where col like '%+%'
union all
select SUBSTRING_INDEX(col , "+", 1) from cte where col not like '%+%'
output
col1
6
6
6
5
the upper solution will work only for your sample data
demo link

What database are you using? You may need to use something db specific. e.g. in oracle you can do:
select dbms_aw.eval_number ('4+2') from dual
It will return 6.
Generally speaking - using dynamic SQL you can easily achieve this.

How to write a sql query to find a word in a para?

("select * from table where column like ?", ['%' + var1 + '%'])
shows results like "cabcd a", "xyabcd xyz", " xyz abc", "x abc","abc y". But i only want the output to be like "xyz abc", "x abc", "abc y". And abc is stored in var1

I would suggest:
where concat(' ', column, ' ') like "% abc %"
This will find the word anywhere in the column, assuming the only valid separator is a space.
Note: In SQLite, you would use || instead of concat(). Also, if you want performance, look into full text indexes.
EDIT:
The code if the value is stored in a variable looks like:
"select * from table where concat(' ', column, ' ') like ?", ['% ' + var1 + ' %'])

SELECT *
FROM #temp1
WHERE name LIKE '% abc%'
OR name LIKE 'abc_%'

Try this:
SELECT * FROM table_name
WHERE column LIKE "% abc%" OR column LIKE "%abc %" OR column="abc";

You can use REGEXP and the [[:<:]] and [[:>:]] word-boundary markers:
SELECT * FROM table WHERE column REGEXP "[[:<:]]abc[[:>:]]";

you have to declare the variable
DECLARE #Pattern_Val AS CHAR(7)
SET #Pattern_Val = '% abc %'
SELECT * FROM table WHERE column LIKE #Pattern_Val
CAUTION: Pay attention to the length of the CHAR - Definition!!

Since your String is saved in a variable try something like this:
SELECT * FROM table WHERE (column LIKE CONCAT('% ', var1, '%') OR column LIKE CONCAT(var1,' %'));
Extra parentheses are to avoid confusion if you add more constraints (AND operators have precedence over OR).

How about searching with spaces on either side:
select * from table where column like "% abc%" or column like "%abc %"

SQL: select unique substrings from the table by mask

There is a SQL table mytable that has a column mycolumn.
That column has text inside each cell. Each cell may contain "this.text/31/" or "this.text/72/" substrings (numbers in that substrings can be any) as a part of string.
What SQL query should be executed to display a list of unique such substrings?
P.S. Of course, some cells may contain several such substrings.
And here are the answers for questions from the comments:
The query supposed to work on SQL Server.
The prefered output should contain the whole substring, not the numeric part only. It actually could be not just the number between first "/" and the second "/".
And it is varchar type (probably)
Example:
mycolumn contains such values:
abcd/eftthis.text/31/sadflh adslkjh
abcd/eftthis.text/44/khjgb ljgnkhj this.text/447/lhkjgnkjh
ljgkhjgadsvlkgnl
uygouyg/this.text/31/luinluinlugnthis.text/31/ouygnouyg
khjgbkjyghbk
The query should display:
this.text/31/
this.text/44/
this.text/447/

How about using a recursive CTE:
CREATE TABLE #myTable
(
myColumn VARCHAR(100)
)
INSERT INTO #myTable
VALUES
('abcd/eftthis.text/31/sadflh adslkjh'),
('abcd/eftthis.text/44/khjgb ljgnkhj this.text/447/lhkjgnkjh'),
('ljgkhjgadsvlkgnl'),
('uygouyg/this.text/31/luinluinlugnthis.text/31/ouygnouyg'),
('khjgbkjyghbk')
;WITH CTE
AS
(
SELECT MyColumn,
CHARINDEX('this.text/', myColumn, 0) AS startPos,
CHARINDEX('/', myColumn, CHARINDEX('this.text/', myColumn, 1) + 10) AS endPos
FROM #myTable
WHERE myColumn LIKE '%this.text/%'
UNION ALL
SELECT T1.MyColumn,
CHARINDEX('this.text/', T1.myColumn, C.endPos) AS startPos,
CHARINDEX('/', T1.myColumn, CHARINDEX('this.text/', T1.myColumn, c.endPos) + 10) AS endPos
FROM #myTable T1
INNER JOIN CTE C
ON C.myColumn = T1.myColumn
WHERE SUBSTRING(T1.MyColumn, C.EndPos, 100) LIKE '%this.text/%'
)
SELECT DISTINCT SUBSTRING(myColumn, startPos, EndPos - startPos)
FROM CTE

Having a table named test with the following data:
COLUMN1
aathis.text/31/
this.text/1/
bbbthis.text/72/sksk
could this be what you are looking for?
select SUBSTR(COLUMN1,INSTR(COLUMN1,'this.text', 1 ),INSTR(COLUMN1,'/',INSTR(COLUMN1,'this.text', 1 )+10) - INSTR(COLUMN1,'this.text', 1 )+1) from test;
result:
this.text/31/
this.text/1/
this.text/72/
i see your problem:
Assume the same table as above but now with the following data:
this.text/77/
xxthis.text/33/xx
xthis.text/11/xxthis.text/22/x
xthis.text/1/x
The following might help you:
SELECT SUBSTR(COLUMN1, INSTR(COLUMN1,'this.text', 1 ,1), INSTR(COLUMN1,'/',INSTR(COLUMN1,'this.text', 1 ,1)+10) - INSTR(COLUMN1,'this.text', 1 ,1)+1) FROM TEST
UNION
SELECT CASE WHEN (INSTR(COLUMN1,'this.text', 1,2 ) >0) THEN
SUBSTR(COLUMN1, INSTR(COLUMN1,'this.text', 1,2 ), INSTR(COLUMN1,'/',INSTR(COLUMN1,'this.text', 1 ,2),2) - INSTR(COLUMN1,'this.text', 1,2 )+1) end FROM TEST;
it will generate the following result:
this.text/1/
this.text/11/
this.text/22/
this.text/33/
this.text/77/
The downside is that you need to add a select statement for every occurance you might have of "this.text". If you might have 100 "this.text" in the same cell it might be a problem.

SQL> select SUBSTR(column_name,1,9) from tablename;
column_name
this.text

SELECT REGEXP_SUBSTR(column_name,'this.text/[[:digit:]]+/')
FROM table_name

MySql: updating a column with the column's content plus something else

I'm don't have a lot of knowledge of MySql (or SQL in general) so sorry for the noobness.
I'm trying to update a bunch of String entries this way:
Lets say we have this:
commands.firm.pm.Stuff
Well I want to convert that into:
commands.firm.pm.print.Stuff
Meaning, Add the .print after pm, before "Stuff" (where Stuff can be any Alphanumerical String).
How would I do this with a MySql Query? I'm sure REGEXP has to be used, but I'm not sure how to go about it.
Thanks

Try something like this. It finds the last period and inserts your string there:
select insert(s, length(s) - instr(reverse(s), '.') + 1, 0, '.print')
from (
select 'commands.firm.pm.Stuff' as s
) a
To update:
update MyTable
set MyColumn = insert(MyColumn, length(MyColumn) - instr(reverse(MyColumn), '.') + 1, 0, '.print')
where MyColumn like 'commands.firm.pm.%'

Perhaps use a str_replace to replace commands.firm.pm to commands.firm.pm.print
$original_str = "commands.firm.pm.15hhkl15k0fak1";
str_replace("commands.firm.pm", "commands.firm.pm.print", $original_str);
should output: commands.firm.pm.print.15hhkl15k0fak1
then update your table with the new value...How to do it all in one query (get column value and do the update), I do not know. All I can think of is you getting the column value in one query, doing the replacement above, and then updating the column with the new value in a second query.

To update rows that end in '.Stuff' only:
UPDATE TableX
SET Column = CONCAT( LEFT( CHAR_LENGTH(Column) - CHAR_LENGTH('.Stuff') )
, '.print'
, '.Stuff'
)
WHERE Column LIKE '%.Stuff'
To update all rows - by appending .print just before the last dot .:
UPDATE TableX
SET Column = CONCAT( LEFT( CHAR_LENGTH(Column)
- CHAR_LENGTH(SUBSTRING_INDEX(Column, '.', -1))
)
, 'print.'
, SUBSTRING_INDEX(Column, '.', -1)
)
WHERE Column LIKE '%.%'

Search for text between delimiters in MySQL

I am trying to extract a certain part of a column that is between delimiters.
e.g. find foo in the following
test 'esf :foo: bar
So in the above I'd want to return foo, but all the regexp functions only return true|false,
is there a way to do this in MySQL

Here ya go, bud:
SELECT
SUBSTR(column,
LOCATE(':',column)+1,
(CHAR_LENGTH(column) - LOCATE(':',REVERSE(column)) - LOCATE(':',column)))
FROM table
Yea, no clue why you're doing this, but this will do the trick.
By performing a LOCATE, we can find the first ':'. To find the last ':', there's no reverse LOCATE, so we have to do it manually by performing a LOCATE(':', REVERSE(column)).
With the index of the first ':', the number of chars from the last ':' to the end of the string, and the CHAR_LENGTH (don't use LENGTH() for this), we can use a little math to discover the length of the string between the two instances of ':'.
This way we can peform a SUBSTR and dynamically pluck out the characters between the two ':'.
Again, it's gross, but to each his own.

This should work if the two delimiters only appear twice in your column. I am doing something similar...
substring_index(substring_index(column,':',-2),':',1)

A combination of LOCATE and MID would probably do the trick.
If the value "test 'esf :foo: bar" was in the field fooField:
MID( fooField, LOCATE('foo', fooField), 3);

I don't know if you have this kind of authority, but if you have to do queries like this it might be time to renormalize your tables, and have these values in a lookup table.

With only one set of delimeters, the following should work:
SUBSTR(
SUBSTR(fooField,LOCATE(':',fooField)+1),
1,
LOCATE(':',SUBSTR(fooField,LOCATE(':',fooField)+1))-1
)

mid(col,
locate('?m=',col) + char_length('?m='),
locate('&o=',col) - locate('?m=',col) - char_length('?m=')
)
A bit compact form by replacing char_length(.) with the number 3
mid(col, locate('?m=',col) + 3, locate('&o=',col) - locate('?m=',col) - 3)
the patterns I have used are '?m=' and '&o'.

select mid(col from locate(':',col) + 1 for
locate(':',col,locate(':',col)+1)-locate(':',col) - 1 )
from table where col rlike ':.*:';

If you know the position you want to extract from as opposed to what the data itself is:
$colNumber = 2; //2nd position
$sql = "REPLACE(SUBSTRING(SUBSTRING_INDEX(fooField, ':', $colNumber),
LENGTH(SUBSTRING_INDEX(fooField,
':',
$colNumber - 1)) + 1)";

This is what I am extracting from (mainly colon ':' as delimiter but some exceptions), as column theline255 in table loaddata255:
23856.409:0023:trace:message:SPY_EnterMessage (0x2003a) L"{#32769}" [0081] WM_NCCREATE sent from self wp=00000000 lp=0023f0b0
This is the MySql code (It quickly did what I want, and is straight forward):
select
time('2000-01-01 00:00:00' + interval substring_index(theline255, '.', 1) second) as hhmmss
, substring_index(substring_index(theline255, ':', 1), '.', -1) as logMilli
, substring_index(substring_index(theline255, ':', 2), ':', -1) as logTid
, substring_index(substring_index(theline255, ':', 3), ':', -1) as logType
, substring_index(substring_index(theline255, ':', 4), ':', -1) as logArea
, substring_index(substring_index(theline255, ' ', 1), ':', -1) as logFunction
, substring(theline255, length(substring_index(theline255, ' ', 1)) + 2) as logText
from loaddata255
and this is the result:
# LogTime, LogTimeMilli, LogTid, LogType, LogArea, LogFunction, LogText
'06:37:36', '409', '0023', 'trace', 'message', 'SPY_EnterMessage', '(0x2003a) L\"{#32769}\" [0081] WM_NCCREATE sent from self wp=00000000 lp=0023f0b0'

This one looks elegant to me. Strip all after n-th separator, rotate string, strip everything after 1. separator, rotate back.
select
reverse(
substring_index(
reverse(substring_index(str,separator,substrindex)),
separator,
1)
);
For example:
select
reverse(
substring_index(
reverse(substring_index('www.mysql.com','.',2)),
'.',
1
)
);

you can use the substring / locate function in 1 command
here is a mice tutorial:
http://infofreund.de/mysql-select-substring-2-different-delimiters/
The command as describes their should look for u:
**SELECT substr(text,Locate(' :', text )+2,Locate(': ', text )-(Locate(' :', text )+2)) FROM testtable**
where text is the textfield which contains "test 'esf :foo: bar"
So foo can be fooooo or fo - the length doesnt matter :).