I need to make a box with arrow for a tooltip but I can't use pseudo-elements because :
The box background is a little transparent
It has border
here is the example :
.box {
margin: 60px 0 0 0;
width: 250px;
height: 50px;
background-color: rgba(255, 144, 89, 0.5);
border-radius: 5px;
position: relative;
border: 2px solid #ff6e26;
}
.box:after,
.box:before {
bottom: 100%;
left: 50%;
border: solid transparent;
content: " ";
height: 0;
width: 0;
position: absolute;
pointer-events: none;
}
.box:after {
border-color: rgba(136, 183, 213, 0);
border-bottom-color: rgba(255, 144, 89, 0.5);
border-width: 10px;
margin-left: -10px;
}
.box:before {
border-color: rgba(194, 225, 245, 0);
border-bottom-color: #ff6e26;
border-width: 12px;
margin-left: -12px;
}
<div class="box"></div>
https://codepen.io/Masoudm/pen/qgvJGX
as you see when I make the background transparent it doesn't works for the arrow, because I already used ::before behind it for its border. I wonder if there is another approach which allows me to keep the box size dynamic.
Update:
the box should be something like this ( except the top curvy line)
Based on this previous answer I will adjust slightly the code to have a transparent background. There is two main tricks. Half the coloration of the pseudo element to avoid the intersection with the main element and the use of gradient on the main element to create the border top and create the hole for the pseudo element:
body {
margin:0;
background-image:linear-gradient(to right,yellow,pink);
}
.box {
border: 2px solid red;
border-top:transparent; /*make border-top transparent*/
margin: 50px;
height: 50px;
position:relative;
/* Use gradient to mimic the border top with a transparent gap */
background:
linear-gradient(red,red) left top /calc(50% - 10px*1.414) 2px,
linear-gradient(red,red) right top/calc(50% - 10px*1.414) 2px,
rgba(0,255,0,0.4);
background-repeat:no-repeat;
}
.box:before {
content: "";
position: absolute;
width: 20px;
height: 20px;
border-top: 2px solid red;
border-left: 2px solid red;
top: -11px;
left: calc(50% - 11px);
transform: rotate(45deg);
background:linear-gradient(-45deg,transparent 50%,rgba(0,255,0,0.4) 50%);
}
<div class="box">
</div>
* {
box-sizing: border-box;
font-family: inherit;
}
html {
font-size: 62.25%;
}
body {
padding: 50px;
}
.outter {
width: 200px;
height: 100px;
position: relative;
}
.box {
padding: 20px;
width: 100%;
height: 100%;
background: rgba(255, 68, 0, 0.568);
border: 3px solid orangered;
border-radius: 5px;
clip-path: polygon(0 0,45% 0,45% 10px,calc(45% + 15px) 10px,calc(45% + 15px) 0,100% 0,100% 100%,0 100%,0 0)
}
.arrow {
width: 15px;
height: 8px;
background: rgba(255, 68, 0, 0.568);
transform: translate(-67%, 100%);
position: absolute;
left: 50%;
bottom: 98%;
}
.arrow::after {
border: 3px solid transparent;
border-left-color: orangered;
border-top-color: orangered;
border-right: 0px solid transparent;
border-bottom: 0px solid transparent;
width: 11px;
height: 11px;
position: absolute;
left: 0;
bottom: 34%;
content: '';
transform: rotate(45deg);
background: linear-gradient(134deg,rgba(255, 68, 0, 0.56) 0%,rgba(255, 68, 0, 0.56) 50%,transparent 50%, transparent 100%);
}
<div class="outter">
<div class="arrow"></div>
<div class="box"></div>
</div>
Related
I'm trying to blur the left and right edges of a divider, as the line is too harsh. Is there a way to do this with CSS? This is what the right edge currently looks like:
right blur
This is my current code:
.front-name {
position: fixed;
top: 70%;
left: 50%;
transform: translate(-50%, -30%);
width: 80%;
background-color: linear-gradient(to right, transparent, rgba(148, 148, 148, 0.5));
backdrop-filter: blur(4px);
padding-top: 15px;
padding-bottom: 20px;
border-top: 2px solid #ffffff;
border-bottom: 2px solid #ffffff;
}
It'd be nice for this to be a smoother transition from the blurry part of the divider to the sharp background image.
Try with mask:
.front-name {
position: fixed;
top: 50%;
left: 50%;
transform: translate(-50%, -30%);
width: 80%;
background: #fff5;
-webkit-mask: linear-gradient(90deg, #0000, #000, #0000);
backdrop-filter: blur(4px);
padding-top: 15px;
padding-bottom: 20px;
border-top: 2px solid #ffffff;
border-bottom: 2px solid #ffffff;
}
html {
background: url(https://picsum.photos/id/1003/800/400)
}
<div class="front-name"></div>
I'm trying to create a background for a banner using css where one side has a color and on the other side has another one with a 45° cut like this
I've been able to recreate the above image except for the drop shadow that doesn't stay in the right position.
Any advice would be greatly appreciated.
This is my code code:
#container {
height: 100px;
width: 400px;
overflow: hidden;
background-color: #2962ff;
}
#triangle-topleft {
width: 0;
height: 0;
border-top: 100px solid #2196f3;
border-right: 400px solid transparent;
-webkit-box-shadow: 5px 5px 20px 0px rgba(0,0,0,0.75);
-moz-box-shadow: 5px 5px 20px 0px rgba(0,0,0,0.75);
box-shadow: 5px 5px 20px 0px rgba(0,0,0,0.75);
}
<div id="container">
<div id="triangle-topleft"></div>
</div>
The CSS triangle trick with border can not be used for this, as a shadow will still be applied to the box, and not only to the triangle.
You will have to create a pseudo element, rotate it and THEN apply shadow to it.
#container {
position: relative;
height: 200px;
width: 200px;
overflow: hidden;
background-color: grey;
}
#container:before {
content: '';
position: absolute;
left: 20%;
width: 100%;
height: 200%;
background-color: rgb(255, 255, 255); /* fallback */
background-color: rgba(255, 255, 255, 0.5);
top: 0;
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
transform: rotate(45deg);
box-shadow: inset 0 0 20px 10px #333;
}
<div id="container"></div>
Basically you create a rectangle which is larger than the parent, then rotate it and apply a shadow. You can tweak the colors and rotation-degree for your needs
Demo: http://jsfiddle.net/b5TnZ/2032/
You can add multiple color stops in Linear Gradients. Use two color set.
Gradient generated using Shapy
.canvas {
display: flex;
height: 100vh;
align-items: center;
justify-content: center;
min-height: 100%;
min-width: 100%;
}
.gradient-canvas {
max-height: 100%;
max-width: 100%;
width: 100%;
height: 100%;
background: linear-gradient(127deg, rgb(31, 163, 209) 0%, rgb(31, 163, 209) 50%, rgb(25, 64, 208) 0%, rgb(46, 101, 223) 52%) 50% 50% / 100% 100% no-repeat;
}
<div class="canvas"><div class="gradient-canvas"></div></div>
You can try gradient like below:
#container {
height: 150px;
background:
linear-gradient(135deg,#2962ff 49.8%,rgba(0,0,0,0.75) 50%, #2196f3 calc(50% + 10px));
background-color:#2196f3;
}
<div id="container">
</div>
And simply replace the deg with to bottom right if you want the diagonal result:
#container {
height: 150px;
width:50%;
background:
linear-gradient(to bottom right,#2962ff 50%,rgba(0,0,0,0.75) 50%, #2196f3 calc(50% + 10px));
background-color:#2196f3;
}
<div id="container">
</div>
I want to remove the corners of borders like this picture.
You can use ::before and ::after pseudo elements to cover (and thus, "hide") parts of the border:
.bordery {
border: 1px solid teal;
padding: 20px;
position: relative;
}
.bordery::after,
.bordery::before {
background-color: white;
content: "";
display: block;
height: 10px;
position: absolute;
width: 10px;
}
.bordery::after {
bottom: -1px;
right: -1px;
}
.bordery::before {
top: -1px;
left: -1px;
}
<div class="bordery">This is just some sample content.</div>
You can use :before and :after pseudo elements to create this.
.el {
position: relative;
width: 200px;
height: 50px;
margin: 50px;
}
.el:after,
.el:before {
content: '';
position: absolute;
height: 90%;
width: 100%;
}
.el:before {
top: -5px;
left: -5px;
border-top: 1px solid orange;
border-left: 1px solid orange;
}
.el:after {
bottom: -5px;
right: -5px;
border-bottom: 1px solid orange;
border-right: 1px solid orange;
}
<div class="el"></div>
You can use css3 linear-gradient to draw this background to just a single <div> element and without using any pseudo elements.
div {
background-image: linear-gradient(to left, transparent 20px, orange 20px),
linear-gradient(to bottom, transparent 20px, orange 20px),
linear-gradient(to right, transparent 20px, orange 20px),
linear-gradient(to top, transparent 20px, orange 20px);
background-position: 100% 0, 100% 0, 0 100%, 0 100%;
background-size: 100% 1px, 1px 100%;
background-repeat: no-repeat;
}
div {
background-color: #eee;
background-image: linear-gradient(to left, transparent 20px, orange 20px),
linear-gradient(to bottom, transparent 20px, orange 20px),
linear-gradient(to right, transparent 20px, orange 20px),
linear-gradient(to top, transparent 20px, orange 20px);
background-position: 100% 0, 100% 0, 0 100%, 0 100%;
background-size: 100% 1px, 1px 100%;
background-repeat: no-repeat;
position: relative;
margin: 0 auto;
height: 100px;
width: 80%;
}
<div></div>
You can do it by following:
#rectangle{
width:400px;
height: 200px;
border-style: solid;
color:orange;
position: absolute;
}
#eraser1{
position: absolute;
width: 50px;
height: 50px;
background-color:white;
margin: -10px 0px 0px 374px;
}
#eraser2{
position: absolute;
width: 50px;
height: 50px;
background-color:white;
margin: 175px 0px 0px -13px;
}
Use clip-path property to clip corner
div{
width: 15em;
height: 5em;
border: 2px solid red;
clip-path: polygon(0 0, 91% 0, 100% 12%, 100% 100%, 12% 100%, 0 89%);
}
<div></div>
I am trying to create right arrow with gray border with css. but I think the arrow is over lapping the left rectangle. some finishing touch is required here:
.arrow_box {
position: relative;
background: #fff;
border: 2px solid #aaa;
width: 300px;
padding: 8px 20px 8px 40px;
}
.arrow_box:after,
.arrow_box:before {
left: 100%;
top: 50%;
border: solid transparent;
content: " ";
height: 0;
width: 0;
position: absolute;
pointer-events: none;
}
.arrow_box:after {
border-color: rgba(255, 255, 255, 0);
border-left-color: #fff;
border-width: 17px;
margin-top: -17px;
}
.arrow_box:before {
border-color: rgba(170, 170, 170, 0);
border-left-color: #aaa;
border-width: 19px;
margin-top: -19px;
}
<div class="arrow_box">Consumer Customer
</div>
You can add border on specific sides except right:
.arrow_box {
position: relative;
background: #fff;
border-left: 2px solid #aaa;
border-top: 2px solid #aaa;
border-bottom: 2px solid #aaa;
width: 300px;
padding: 8px 20px 8px 40px;
box-sizing: border-box;
}
https://jsfiddle.net/2ca4aucm/1/
http://jsfiddle.net/6HyjZ/
.bookmarkRibbon{
width:0;
height:100px;
border-right:50px solid blue;
border-left:50px solid blue;
border-bottom:30px solid transparent;
}
<div class="bookmarkRibbon"></div>
I'm struggling to make a version of this shape where the ribbon is pointing right instead of down,
how can I achieve this?
Ribbon shape using CSS Clip Path:
.bookmarkRibbon {
width: 100px;
height: 60px;
background: blue;
clip-path: polygon(0% 0%, 100% 0%, calc(100% - 20px) 50%, 100% 100%, 0% 100%);
}
<div class="bookmarkRibbon"></div>
Pointing down:
.bookmarkRibbon {
width: 60px;
height: 100px;
background: blue;
clip-path: polygon(0% 0%, 100% 0%, 100% 100%, 50% calc(100% - 20px), 0% 100%, 0% 0%);
}
<div class="bookmarkRibbon"></div>
Ribbon shape using CSS border
To help you visualize the logic step-by-step, so you can apply it easily on any side:
.bookmarkRibbon {
border: 30px solid blue; /* All borders set */
border-left: 0; /* Remove left border */
border-right: 20px solid transparent; /* Right transparent */
width: 100px; /* Increase element Width */
}
<div class="bookmarkRibbon"></div>
Using the helpful accepted answer here is it with text version.
Vertical(Top to bottom) Banner with text
.ribbon-vertical {
position: absolute;
right: 10px;
border: 13px solid #e46a76; /* All borders set */
border-top: 0; /* Remove left border */
border-bottom: 10px solid transparent; /* Right transparent */
height: auto; /* Increase element Width */
width: 0;
word-wrap: break-word;
color: white;
z-index: 1;
-webkit-filter: drop-shadow(0 1px 2px rgba(0, 0, 0, 0.3));
filter: drop-shadow(0 1px 2px rgba(0, 0, 0, 0.3));
}
.ribbon-vertical div{
position: relative;
right: 5px;
padding-top: 2px;
padding-bottom: 2px;
}
<div class="ribbon-vertical"><div>BANNER</div></div>
Horizontal(Right to Left) Banner with text
.ribbon-horizontal{
position: absolute;
right: 0;
bottom: 5rem;
border: 13px solid #e46a76;
border-right: 0;
border-left: 10px solid transparent;
height: 0;
line-height: 0;
width: 100px;
color: white;
z-index: 1;
-webkit-filter: drop-shadow(0 1px 2px rgba(0, 0, 0, 0.3));
filter: drop-shadow(0 1px 2px rgba(0, 0, 0, 0.3));
letter-spacing: 3px;
}
.ribbon-horizontal span{
position: relative;
padding: 0 4px 0 10px;
text-align: center;
}
<div class="ribbon-horizontal"><span>BANNER</span></div>
.bookmarkRibbon{
width:100px;
height:0;
border-bottom:50px solid blue;
border-top:50px solid blue;
border-right:30px solid transparent;
}
If you 'rotate' the css properties, it rotates the form by 90 degrees.
.bookmarkRibbon{
width:100px;
height:0;
border-bottom:50px solid blue;
border-top:50px solid blue;
border-left:30px solid transparent;
}
http://jsfiddle.net/6HyjZ/6/
Use transform:rotate :
.bookmarkRibbon{
width:0;
height:100px;
border-right:50px solid blue;
border-left:50px solid blue;
border-bottom:30px solid transparent;
transform:rotate(7deg);
-ms-transform:rotate(7deg); /* IE 9 */
-webkit-transform:rotate(7deg); /* Opera, Chrome, and Safari */
}
Just swap what you have and you are good to go jsfiddle:
.bookmarkRibbonRight{
width:100px;
height:0px;
border-right:30px solid transparent;
border-bottom:50px solid blue;
border-top:50px solid blue;
}
You already have the shape, just use the transform property to change its angle.
Here is the code that I have added to the code you have.
transform: rotate(270deg);
Here is the fiddle, http://jsfiddle.net/6HyjZ/11/ It now points to the right (unless that's right right side)
Use the rotate css transform:
.bookmarkRibbon{
width:0;
height:100px;
border-right:50px solid blue;
border-left:50px solid blue;
border-bottom:30px solid transparent;
-webkit-transform: rotate(90deg);
-ms-transform: rotate(90deg);
transform: rotate(90deg);
}
http://jsfiddle.net/6HyjZ/13/