laravel query building with a lot of joins - mysql

my sql query is
$q = "SELECT
file,
roleId,
page,
type,
userType,
COUNT(DISTINCT($a)) as 'a',
COUNT(DISTINCT($b)) as 'b'
FROM table_name
WHERE
course IN ($type)
AND date BETWEEN '$startDate' AND '$endDate'
AND (course_1 is NULL OR course_1 NOT IN ('ABCD'))
AND deleted IS NULL
AND type LIKE '%Professor%'
AND action = 'submit'
GROUP BY file, roleId";
I want to convert that query into laravel query builder like
$orders = DB::table('table_name')
->select('file', 'roleId', 'page', 'type', userType DB::raw('COUNT(DISTINCT(($a)) as 'a'))
->groupBy('file', 'roleId')
->get();
Do understand how to add the other COUNT into it and how and where to chain the ->where() ?

<?php
$orders = DB::table('table_name')
->whereIn('course', $courseTypes)
->whereBetween('date', [$startDate, $endDate])
->where(function($q){
return $q->whereNull('course_1')
->orWhereNotIn('course_1', $courseArrayToFilter);
})
->whereNull('deleted')
->where('type', 'like', '%Professor%')
->where('action', 'submit')
->groupBy('file', 'roleId')
->select(
'file',
'roleId',
'page',
'type',
'userType',
\DB::raw("COUNT(DISTINCT($a)) as a"),
\DB::raw("COUNT(DISTINCT($b) as b")
)
->get();

Maybe in a cleanest way doing this:
Use the Model instance in inspite of invoke the DB facade
Use whereRaw to pass complex or pure SQL queries
Use selectRaw() to process pure SQL queries for instance functions like COUNT
Use Multiple WHERE to emulate AND operator
Use whereIn to filter ranges of data
You need to GROUP BY all columns in your SELECT you have an error at this point, I mean your query is wrong
Code
$data = Model::select('file', 'roleId', 'page', 'type', 'userType')
->selectRaw('COUNT(DISTINCT($a)) as a')
->selectRaw('COUNT(DISTINCT($b)) as b')
->whereRaw('type IN $type')
->whereIn('date', [$startDate, $endDate])
->whereRaw("course_1 IS NULL OR course_1 NOT IN('ABCD')")
->whereNull('deleted')
->where('type', 'LIKE', "%".'Professor'."%")
->where('action', '=', 'submit')
->groupBy('file', 'roleId', 'page', 'type', 'userType')
->get();

Related

Convert Raw SQL query to Laravel DB Query

I have the following raw SQL query:
select a.id user_id, a.email_address, a.name_first, a.name_last, count(b.id) number_of_videos, sum(b.vimeo_duration) total_duration, sum(b.count_watched) total_playbacks
from users a,
videos b
where a.id = b.tutor_id
and a.email_address in ('candace_rennie#yahoo.com', 'tjm#hiltoncollege.com', 'matthewjameshenshall#gmail.com', 'nkululeko#syafunda.co.za', 'khulile#syafunda.co.za', 'nzakheni#syafunda.co.za')
group by a.id;
This correctly gets 6 rows from the database. I'm trying to convert this to a Laravel database query like so:
$totals = DB::table('users')
->select(DB::Raw('users.id as user_id'), 'users.email_address', 'users.name_first', 'users.name_last', DB::Raw('count(videos.id) as number_of_videos'), DB::Raw('sum(videos.vimeo_duration) as total_duration'), DB::Raw('sum(videos.count_watched) as total_playbacks'))
->join('videos', 'users.id', '=', 'videos.tutor_id')
->where('users.id', 'videos.tutor_id')
->whereIn('users.email_address', array('candace_rennie#yahoo.com', 'tjm#hiltoncollege.com', 'matthewjameshenshall#gmail.com', 'nkululeko#syafunda.co.za', 'khulile#syafunda.co.za', 'nzakheni#syafunda.co.za'))
->groupBy('users.id')
->get();
This however return 0 rows. Is there anything I'm missing?
It should be smth like below even tho groupBy user id does not help much as id is unique.
$aggregates = [
DB::raw('count(b.id) as number_of_videos'),
DB::raw('sum(b.vimeo_duration) as total_duration'),
DB::raw('sum(b.count_watched) as total_playbacks'),
];
$simpleSelects = ['users.email_address', users.id, 'users.name_first', 'users.name_last'];
$emails = ['candace_rennie#yahoo.com', 'tjm#hiltoncollege.com'....]
$users = Users::select(array_merge($simpleSelects, $aggregates))
->leftJoin('videos as b', function ($join) use ($emails) {
$join->on('b.tutor_id', 'a.id')
->whereIn('users.email_address', $emails);
})
->groupBy('users.id')
->get();
Try to remove this line:
->where('users.id', 'videos.tutor_id')
List item
after sql code convert into laravel
DB::select('posts.id','posts.title','posts.body')
->from('posts')
->where('posts.author_id', '=', 1)
->orderBy('posts.published_at', 'DESC')
->limit(10)
->get();

Laravel count with where on Query Builder with joins

Good day all, I am trying to count all records in a table but only if the table does not contain data in a specific column (deleted_at). It is a join table the table names are companies and employees. I am currently counting the records with a DB::raw but it should only count it if the deleted_at column is null. Please understand that i am a beginner.
public function index()
{
$user = Auth::user()->id;
$companies = DB::table('companies AS c')
->select([
'c.id',
'c.logo',
'c.company_name',
'c.created_at',
'c.sector',
'c.deleted_at',
DB::raw('COUNT(e.id) AS employee_count')
])
->leftJoin('employees AS e', 'e.company_id', '=', 'c.id' )
->leftJoin('company_user AS cu', 'cu.company_id', '=', 'c.id')
->where('cu.user_id', '=', $user)
->where('c.deleted_at', '=', null)
->groupBy('c.id')
->get();
return view('account.companies.index')
->with('companies', $companies);
}
If you are using Mysql then you could use conditional aggregation
$companies = DB::table('companies AS c')
->select([
'c.id',
'c.logo',
'c.company_name',
'c.created_at',
'c.sector',
'c.deleted_at',
DB::raw('SUM(c.deleted_at IS NULL) AS employee_count')
])
->leftJoin('employees AS e', 'e.company_id', '=', 'c.id' )
->leftJoin('company_user AS cu', 'cu.company_id', '=', 'c.id')
->where('cu.user_id', '=', $user)
->groupBy('c.id')
->get();
In mysql when an expression is used inside sum(a= b) it will result as a boolean 0/1 so you can get your conditional count using above
Or you could use whereNull() method in your query
->whereNull('c.deleted_at')
Use this code:
$employeeCount = DB::table('employees')
->select('companies.name', DB::raw('count(employees.id) as employee_count'))
->join('companies', 'employees.company','=','companies.id')
->groupBy('companies.id')
->get();

Sql leftJoin query using laravel syntax showing error

This is my query that i used for left join, it is working fine but something is missing when I convert it to laravel syntax.
Query to convert is
$result = DB::select("select amenities.name as
name,amenities.type_id,amenities.id as id, amenities.icon, rooms.id as status
from amenities left join rooms on find_in_set(amenities.id, rooms.amenities)
and rooms.id = $room_id and type_id !=4");
and the I am doing this
$result = DB::table('amenities')
->select('amenities.name as name', 'amenities.type_id' , 'amenities.id as id'
, 'amenities.icon', 'rooms.id as status' )
->leftJoin('rooms', function ($join) {
$join->on('FIND_IN_SET(amenities.id, rooms.amenities)')
->where('rooms.id' , '=', '$room_id')
->where('type_id','!=', 4);
})->get();
The error is
InvalidArgumentException in
F:\xampp\htdocs\arheb\Arheb\vendor\laravel\framework\src\Illuminate\Database\Query\JoinClause.php
line 79: Not enough arguments for the on clause.
Your query is wrong. I assume that amenities.id and rooms.amenities are attributes of amenities and rooms table respectively.
MySQL FIND_IN_SET() returns the position of a string if it is present (as a substring) within a list of strings.
You need to pass column names in first and second parameter of on() function.
$result = DB::table('amenities')
->select('amenities.name as name', 'amenities.type_id' , 'amenities.id as id'
, 'amenities.icon', 'rooms.id as status' )
->leftJoin('rooms', function ($join) {
$join->on('amenities.id', '=', 'rooms.amenities')
->where('rooms.id' , '=', '$room_id')
->where('type_id','!=', 4);
})->get();
I think you can try this:
$result = DB::table('amenities')
->select('amenities.name as name', 'amenities.type_id' , 'amenities.id as id'
, 'amenities.icon', 'rooms.id as status' )
->leftJoin('rooms', function ($join) {
$join->on(DB::raw("find_in_set(amenities.id, rooms.amenities)"))
->where('rooms.id' , '=', '$room_id')
->where('type_id','!=', 4);
})->get();
Hope this work for you!

WhereNotIn Subquery

What i'm trying to achieve is the following:
I want to check if there is a record with the same client_code but with a lower/different campaign id. I'm using a sub-query for now and i tried to do it with a join as well but I couldn't get the logic working
This is what i got now:
$oDB = DB::table('campaigns AS c')
->select(
'c.id AS campaign_id',
'cc.id AS campaign_customer_id'
)
->join('campaign_customers AS cc', 'cc.campaign_id', '=', 'c.id')
->where('c.status', '=', ModelCampaign::STATUS_PLANNED)
->where('c.scheduled', '=', 1)
->whereRaw('c.scheduled_at <= NOW()')
->where('cc.status', '=', ModelCampaignCustomer::STATUS_INVITE_EMAIL_SCHEDULED)
->whereNotIn('cc.client_code', '=', function ($query){
$query ->select(DB::raw(1))
->from('campaign_customers')
->whereRaw('campaign_id', '!=', 'c.id');
})
->where('cc.active', '=', 1)
;
any tips on how to work the logic would be great
You can use the ->toSql(); method to see the SQL so you can refactorize your query.
The whereNotIn probably shouldn't have an = in it
->whereNotIn('cc.client_code', function ($query){
....
edit
Try:
->whereNotIn('cc.client_code', function ($query){
$query->select(DB::raw('client_code'))
->from('campaign_customers')
->whereRaw('campaign_id != c.id');
})
I think the whereRaw should be a single text string or maybe you can use where here (looking at this for reference https://laravel.com/docs/5.2/queries#advanced-where-clauses). Also DB::raw(1) is going to return a 1 for each subquery result but you want an id for the whereNotIn.

mysql join ON and AND to laravel eloquent

I've been able to get the query result I need using the following raw sql:
select `person`.`id`, `full_name`, count(actions.user_id) as total
from `persons`
left join `actions`
on `actions`.`person_id` = `persons`.`id`
and `actions`.`user_id` = $user
where `type` = 'mp'
group by `persons`.`id`
But I haven't been able to get it working in eloquent yet.
Based on some similar answers, I'd tried functions within ->where() or leftJoin(), but the count of each person's actions isn't yet being filtered by $user. As it stands:
$query = Person::leftJoin('actions', function($q) use ($user)
{
$q->on('actions.person_id', 'persons.id')
->where('actions.user_id', $user);
})
->groupBy('persons.id')
->where('type', 'foo')
//->where('actions.user_id', '=', $user)
->get(['persons.id', 'full_name', DB::raw('count(actions.id) as total')]);
I'm at least heading in roughly the right direction, right...?
If it's relevant, the Persons.php model has two actions relationships:
public function actions()
{
return $this->hasMany('Action');
}
public function actionsUser($id)
{
return $this->hasMany('Action')->where('user_id', $id);
}
So, for reference, I solved it like so:
$query = Person::leftJoin('actions', function($q) use ($user)
{
$q->on('actions.person_id', '=', 'persons.id')
->where('actions.user_id', '=', "$user");
})
->groupBy('persons.id')
->where('type', 'foo')
->get(['persons.id', 'full_name', DB::raw('count(actions.id) as total')]);
The ->where() clause within leftJoin, oddly, needs the speech marks for the variable to be passed through the sql query correctly (likewise, '2' doesn't seem to work while "2" does).
I found that the where doesn't always work on the leftJoin clause
If in the future you get any trouble with it, I'd suggest you using this:
$query = Person::leftJoin('actions', function($q) use ($user)
{
$q->on('actions.person_id', '=', 'persons.id')
->on('actions.user_id', '=', "$user");
})
->groupBy('persons.id')
->where('type', 'foo')
->get(['persons.id', 'full_name', DB::raw('count(actions.id) as total')]);
Hope it helps someone.
When laravel eloquent just start getting complex like this
For more flexibility and readability I'll just use plain sql statement then hydrate the results.
$sql = "
SELECT `person`.`id`,
`full_name`,
count(actions.user_id) AS total
FROM `persons`
LEFT JOIN `actions`
ON `actions`.`person_id` = `persons`.`id`
AND `actions`.`user_id` = $user
WHERE `type` = 'mp'
GROUP by `persons`.`id`
";
$query = Person::hydrate(
DB::select( $sql )
);