Laravel count with where on Query Builder with joins - mysql

Good day all, I am trying to count all records in a table but only if the table does not contain data in a specific column (deleted_at). It is a join table the table names are companies and employees. I am currently counting the records with a DB::raw but it should only count it if the deleted_at column is null. Please understand that i am a beginner.
public function index()
{
$user = Auth::user()->id;
$companies = DB::table('companies AS c')
->select([
'c.id',
'c.logo',
'c.company_name',
'c.created_at',
'c.sector',
'c.deleted_at',
DB::raw('COUNT(e.id) AS employee_count')
])
->leftJoin('employees AS e', 'e.company_id', '=', 'c.id' )
->leftJoin('company_user AS cu', 'cu.company_id', '=', 'c.id')
->where('cu.user_id', '=', $user)
->where('c.deleted_at', '=', null)
->groupBy('c.id')
->get();
return view('account.companies.index')
->with('companies', $companies);
}

If you are using Mysql then you could use conditional aggregation
$companies = DB::table('companies AS c')
->select([
'c.id',
'c.logo',
'c.company_name',
'c.created_at',
'c.sector',
'c.deleted_at',
DB::raw('SUM(c.deleted_at IS NULL) AS employee_count')
])
->leftJoin('employees AS e', 'e.company_id', '=', 'c.id' )
->leftJoin('company_user AS cu', 'cu.company_id', '=', 'c.id')
->where('cu.user_id', '=', $user)
->groupBy('c.id')
->get();
In mysql when an expression is used inside sum(a= b) it will result as a boolean 0/1 so you can get your conditional count using above
Or you could use whereNull() method in your query
->whereNull('c.deleted_at')

Use this code:
$employeeCount = DB::table('employees')
->select('companies.name', DB::raw('count(employees.id) as employee_count'))
->join('companies', 'employees.company','=','companies.id')
->groupBy('companies.id')
->get();

Related

MySql group by with where condition not working

I have 2 tables, groups and questions. I need the result in such a way that it contains group name and corresponding non-deleted question count.
The structure and data for the two tables are as afollows.
My expected Result is as follows
I tried the following code, but it gives the entire row including the deleted questions.
$groupname = DB::table('groups as d')
->select([
'd.id','d.group_name',DB::raw("count(dtls.survey_group_id) as count")
])
->leftJoin('questions as dtls','d.id', '=', 'dtls.survey_group_id')
->whereNotExists( function ($query) {
$query->select(DB::raw(1))
->from('questions')
->where('id', 'd.id')
->where('dtls.is_deleted', 1);
})
->groupBy('d.id','d.group_name')
->get()
->toArray();
A problem here is that ->where('id', 'd.id') mathches id with the literal string d.id which obviously is not what you want. In addition, inner query tables should be aliased to prevent ambiguity. You can try changing it to:
$groupname = DB::table('groups as d')
->select([
'd.id','d.group_name',DB::raw("count(dtls.survey_group_id) as count")
])
->leftJoin('questions as dtls','d.id', '=', 'dtls.survey_group_id')
->whereNotExists( function ($query) {
$query->select(DB::raw(1))
->from('questions as innerDtls')
->whereRaw('innerDtls.id = d.id')
->where('dtls.is_deleted', 1);
})
->groupBy('d.id','d.group_name')
->get()
->toArray();
Alternatively your current query can be simplified to:
$groupname = DB::table('groups as d')
->select([
'd.id','d.group_name',DB::raw("count(dtls.survey_group_id) as count")
])
->leftJoin('questions as dtls','d.id', '=', 'dtls.survey_group_id')
->where('dtls.is_deleted', 0)
->groupBy('d.id','d.group_name')
->get()
->toArray();

Join 3 table with query builder in laravel

I have a 3 table questions,registrations,ssi_tracks i need to get details from the registraions table by corresponding to other two tables
i need to get details from registrations based on
questions.question_schedul=0 ,ssi_tracks.track_first_status
i have wrote query but it says the column is not found here is my query
$register = DB::table('registrations')
->join('questions', 'registrations.registration_id', '=', 'questions.question_id')
->join('ssi_tracks','registrations.registration_id','=','ssi_tracks.registration_id')
->select('address', 'model', 'chassis', 'delivery_date','ssi_tracks.track_first_status')
->where([["questions.question_schedul", "=", $dropselected] and ['ssi_tracks.track_first_status',0]])
->get();
Try this:
$register = DB::table('registrations as R')
->select('R.address', 'R.model', 'R.chassis', 'R.delivery_date','S.track_first_status')
->join('questions as Q', 'R.registration_id', '=', 'Q.question_id')
->join('ssi_tracks as S','R.registration_id','=','S.registration_id')
->where('Q.question_schedul', '=', $dropselected)
->where('S.track_first_status', '=', 0)
->get();
Make sure you have used the right column here from question table for matching registration id:
->join('questions as Q', 'R.registration_id', '=', 'Q.question_id')
try this query :
$register = DB::table('registrations')
->leftJoin('questions', 'registrations.registration_id', '=', 'questions.question_id')
->leftJoin('ssi_tracks','registrations.registration_id','=','ssi_tracks.registration_id')
->select('registrations.address', 'registrations.model', 'registrations.chassis', 'registrations.delivery_date','ssi_tracks.track_first_status')
->where(['questions.question_schedul'=>$dropselected,'ssi_tracks.track_first_status'=>0])
->get();

Join the same table with two different column laravel

I try these code in MySQl:
SELECT
A.*,
B.name,
C.name
FROM
eventlog_tbl as A
LEFT JOIN users B ON A.byuser=B.email
LEFT JOIN users C ON A.affectiveuser=C.email;
I try these in Laravel
return DB::table('eventlog_tbl')
->leftjoin('users', 'users.email', '=', 'eventlog_tbl.byuser')
->leftjoin('users', 'users.email', '=', 'eventlog_tbl.affectiveuser')
->select('eventlog_tbl.*','users.name','users.name')
->get();
How can i convert it to Laravel?
Try below code:
$res = DB::table('eventlog_tbl')
->leftjoin('users AS A', 'A.email', '=', 'eventlog_tbl.byuser')
->leftjoin('users AS B', 'B.email', '=', 'eventlog_tbl.affectiveuser')
->select('eventlog_tbl.*','A.name as byuser_name','B.name as affectiveuser_name')
->get();
print_r($res);
This is your query written using the Laravel query builder.
$events = DB::table('eventlog_tbl')
->select('eventlog_tbl.*', 'users_1.name', 'users_2.name')
->leftJoin('users AS users_1', 'users_1.email', '=', 'eventlog_tbl.byuser')
->leftJoin('users AS users_2', 'users_2.email', '=', 'eventlog_tbl.affectiveuser')
->get();
Edit:
$events = DB::table('eventlog_tbl')
->select('eventlog_tbl.*', 'users_1.name AS user_1', 'users_2.name AS user_2')
->leftJoin('users AS users_1', 'users_1.email', '=', 'eventlog_tbl.byuser')
->leftJoin('users AS users_2', 'users_2.email', '=', 'eventlog_tbl.affectiveuser')
->get();
The problem is that both name columns are called the same thing. As per the accepted answer, these will need to be aliased differently too.
Why don't you convert this to use relationships? I have probably got the relationships wrong, something like this:
class EventLog extends Model
{
public function byUser()
{
return $this->hasOne(User::class, 'byuser', 'id');
}
public function affectiveUser()
{
return $this->hasOne(User::class, 'affectiveuser', 'id');
}
}
And then
$event_log = EventLog::with(['byUser', 'affectiveUser')->all();
foreach ($event_log as $item) {
echo $item->byUser->email();
}

How to write a Laravel query to group duplicate records

This is my current query getting data from tables corporations, jobs, corp_networks and candidates.
$sqlCandSkills = DB::table('corporations')
->join('jobs', 'corporations.corp_id', '=', 'jobs.corp_id')
->join('corp_logos', 'corp_logos.corp_id', '=', 'corporations.corp_id')
->join('candidates', 'corporations.corp_id', '=', 'candidates.corp_id')
->join('corp_networks', 'corporations.corp_id', '=', 'corp_networks.participation_corp_id')
->where([
'corp_networks.owning_corp_id' => $this->corp->corp_id,
'corp_networks.status' => "Accepted"
])
->orwhere([
'corporations.corp_id' => $this->corp->corp_id
])
->where('candidates.is_available', '=', 0)->get();
I need to add a validation query into this because I'm getting multiple rows of same data from above query.
for($i=0 ; $i<sizeof($skillsArray); $i++){
$value= $skillsArray[$i];
echo($value);
$jobDetails = DB::select(
'SELECT * FROM jobs WHERE job_technical_requirements LIKE "%'.$value.'%" AND job_status = 1 INNER JOIN '
);
}
Above query gives all data but I also need to perform above checks.
I'm doing this second query to compare array of values to a csv values in column.
Now I need to achieve all this into a single result.
I need ways to do it either in sql query or laravel query.
you can use groupBy
$sqlCandSkills = DB::table('corporations')
->distinct()
->join('candidates', 'corporations.corp_id', '=', 'candidates.corp_id')
->join('corp_networks', 'corporations.corp_id', '=', 'corp_networks.participation_corp_id')
->where([
'corp_networks.owning_corp_id' => $this->corp->corp_id,
'corp_networks.status' => "Accepted"
])
->orwhere([
'corporations.corp_id' => $this->corp->corp_id
])
->where('candidates.is_available', '=', 0)
->groupBy(array(
'corporations.corp_id',
'corp_networks.participation_corp_id',
'corp_networks.owning_corp_id'
))
->get('corporations.corp_id');

WhereNotIn Subquery

What i'm trying to achieve is the following:
I want to check if there is a record with the same client_code but with a lower/different campaign id. I'm using a sub-query for now and i tried to do it with a join as well but I couldn't get the logic working
This is what i got now:
$oDB = DB::table('campaigns AS c')
->select(
'c.id AS campaign_id',
'cc.id AS campaign_customer_id'
)
->join('campaign_customers AS cc', 'cc.campaign_id', '=', 'c.id')
->where('c.status', '=', ModelCampaign::STATUS_PLANNED)
->where('c.scheduled', '=', 1)
->whereRaw('c.scheduled_at <= NOW()')
->where('cc.status', '=', ModelCampaignCustomer::STATUS_INVITE_EMAIL_SCHEDULED)
->whereNotIn('cc.client_code', '=', function ($query){
$query ->select(DB::raw(1))
->from('campaign_customers')
->whereRaw('campaign_id', '!=', 'c.id');
})
->where('cc.active', '=', 1)
;
any tips on how to work the logic would be great
You can use the ->toSql(); method to see the SQL so you can refactorize your query.
The whereNotIn probably shouldn't have an = in it
->whereNotIn('cc.client_code', function ($query){
....
edit
Try:
->whereNotIn('cc.client_code', function ($query){
$query->select(DB::raw('client_code'))
->from('campaign_customers')
->whereRaw('campaign_id != c.id');
})
I think the whereRaw should be a single text string or maybe you can use where here (looking at this for reference https://laravel.com/docs/5.2/queries#advanced-where-clauses). Also DB::raw(1) is going to return a 1 for each subquery result but you want an id for the whereNotIn.