Multiple Select Count in Different Condition - mysql

Question

I have table that contain clients_status, and my query just like these:
SELECT ROUND((SUM(client_status='BAD DEBT')/COUNT(*))*100) AS BAD,
ROUND((SUM(client_status='ALERT')/COUNT(*))*100) AS ALERT,
ROUND((SUM(client_status='REMIND BAYAR')/COUNT(*))*100) AS REMIND,
ROUND((SUM(client_status='RUTIN BAYAR')/COUNT(*))*100) AS RUTIN,
ROUND((SUM(client_status='POTENSI KOREKSI')/COUNT(*))*100) AS POTENSI,
ROUND((SUM(client_status='TOP 10')/COUNT(*))*100) AS TOP FROM clients
And the output of my query just like this:
What should i do, to make my output like this:
Data value
===============
Bad 29
Alert 29
Remind 14
Rutin 14
Potensi 0
Top 15
Please help guys... thanks,

Answer 1

Aggregate grouping by the status and cross join a subquery getting the total count to calculate the percentage. For the renaming and the custom order you can use CASEs.
SELECT cs.s data,
cs.c / ca.c * 100 value
FROM (SELECT CASE client_status
WHEN 'BAD DEPT' THEN
1
WHEN 'ALERT' THEN
2
WHEN 'REMIND BAYAR' THEN
2
WHEN 'RUTIN BAYAR' THEN
4
WHEN 'POTENSI KOREKSI' THEN
5
WHEN 'TOP 10' THEN
6
END o,
CASE client_status
WHEN 'BAD DEPT' THEN
'Bad'
WHEN 'ALERT' THEN
'Alert'
WHEN 'REMIND BAYAR' THEN
'Remind'
WHEN 'RUTIN BAYAR' THEN
'Rutin'
WHEN 'POTENSI KOREKSI' THEN
'Potensi'
WHEN 'TOP 10' THEN
'Top'
END s,
count(*) c
FROM clients
GROUP BY client_status) cs
CROSS JOIN (SELECT count(*) c
FROM clients) ca
ORDER BY cs.o;