UPDATE COALESCE query with null values - mysql

Definitely a basic question, but I couldn't find an example.
I'm writing a procedure which merges two rows into the good row. It moves all child rows' ids to being the correct one, replaces all NULL values with available values in the row being removed before finally deleting the 'bad' row.
What I have so far is this:
CREATE DEFINER=`danielv`#`%`
PROCEDURE `emp_merge`(IN `#core_emp_id` int, IN `#bad_emp_id` int)
BEGIN
UPDATE claim SET employee_id = #core_emp_id
WHERE employee_id = #bad_emp_id;
WITH bad_employee_values AS (
SELECT * FROM employee WHERE employee_id = #bad_emp_id
)
UPDATE employee SET
employee.employment_date = COALESCE(employee.employment_date, bad_employee_values.employment_date),
WHERE employee_id = #core_emp_id;
DELETE FROM employee WHERE employee_id = #bad_emp_id;
END
However, I'm getting non-descript error messages and I'm not sure why. I suspect there's an issue with how I'm handling my CTE and coalesce function, but I'm not sure where the gap in my understanding is.

In this statement :
WITH bad_employee_values AS (SELECT * FROM employee WHERE employee_id = #bad_emp_id)
UPDATE employee SET
employee.employment_date = COALESCE(employee.employment_date, bad_employee_values.employment_date),
WHERE employee_id = #core_emp_id;
You are defining CTE bad_employee_values but you are not using it in the UPDATE part of the query, hence you cannot access its columns : for MySQL, bad_employee_values.employment_date is unknown.
It looks like you could simply avoid a CTE here. You could just self-join the table, like so :
UPDATE employee e_core
INNER JOIN employee e_bad ON e_bad.employee_id = #bad_emp_id
SET e_core.employment_date = e_bad.employment_date,
WHERE employee_id = #core_emp_id AND e_core.employment_date IS NULL
This query will simply select the record identified by #core_emp_id, join it with the corresponding "bad" record, and copy the value of employment_date. The second condition in the WHERE clause prevents records whose employment_date is not null from being selected.

Related

mysql: I want to sum up all the values of credit from table semester and then add to another column total_credit from another table

I have the below code:
UPDATE VIEW
LEFT JOIN sem_view ON (view.semester = sem_view.semester)
SET view.t_credit = SUM(sem_view.credit)
but its not working saying invalid use of group
Data for updating must be perpared previously, in subquery. Updating must use the data which is already aggregated.
Left joining may be errorneous - it will set the value in the destination table to NULL if according data for the semester in interest in sem_view is not present. But if the logic needs this then you may use LEFT JOIN instead of INNER one in the below query.
Totally:
UPDATE `view`
JOIN ( SELECT sem_view.semester, SUM(sem_view.credit) summ
FROM sem_view
GROUP BY sem_view.semester ) data_for_updating
ON `view`.semester = data_for_updating.semester
SET `view`.t_credit = data_for_updating.summ;
PS. The text looks like view is a name of a table to be updated.

Complicated MySql Update Join Query

Have is an example of the problem I'm facing. The database tables are a little different than usual, but needed to be setup this way.
Items: id, order_id, other fields
Items_Drinks: id, drinks, other fields
Orders: id, other fields
Orders_Drinks: id, drinks, other fields
I need to have an update query that will update the Orders_Drinks table with the sum of the Items_Drinks drinks field that have the same order_id as Orders_Drinks id field.
Items: 1 1 ...
Items: 2 1 ...
Items_Drinks: 1 4 ...
Items_Drinks: 2 5 ...
Orders: 1 ...
Orders_Drinks: 1 9 ...
The Orders_Drinks is currently correct, but if I were to update Items_Drinks with id of 1 to 5, I would need an update command to get Orders_Drinks with id 1 to equal 10.
It would be best if the command would update every record of the Orders_Drinks.
I know my database is not typical, but it is needed for my application. This is because the Drinks table is not needed for all entries. The Drinks table has over 5000 fields in it, so if every record had these details the database would grow and slow for no real reason. Please do not tell me to restructure the database, this is needed.
I am currently using for loops in my C# program to do what I need, but having 1 command would save a ton of time!
Here is my best attempt, but it gives an error of "invalid group function".
update Orders_Drinks join Items on Items.order_id=Orders_Drinks.id join Items_Drinks on Items_Drinks.id=Items.id set Orders_Drinks.drinks=sum(Item_Drinks.drinks);
I think this is what you're wanting.
Edited:
UPDATE `Order_Drinks` a
SET a.`drinks` = (SELECT SUM(b.`drinks`) FROM `Items_Drinks` b INNER JOIN `Items` c ON (b.`id` = c.`id`) WHERE a.`id` = c.`order_id`)
That should give you a total of 9 for the Order_Drinks table for the row id of 1.
This is assuming that Orders.id == Orders_Drinks.id and that Items.id == Items_Drinks.id.
You need to do an aggregation. You can do this in the join part of the update statement:
update Orders_Drinks od join
(select i.order_id, sum(id.drinks) as sumdrinks
from Items i join
Items_Drinks id
on id.id = i.id
) iid
on iid.order_id = od.id
set od.drinks = iid.sumdrinks;
Something like this will return the id from the orders_drinks table, along with the current value of the drinks summary field, and a new summary value derived from the related items_drinks tables.
(Absent the name of the foreign key column, I've assumed the foreign key column names are of the pattern: "referenced_table_id" )
SELECT od.id
, od.drinks AS old_drinks
, IFNULL(td.tot_drinks,0) AS new_drinks
FROM orders_drinks od
LEFT
JOIN ( SELECT di.orders_drinks_id
, SUM(di.drinks) AS tot_drinks
FROM items_drinks di
GROUP BY di.orders_drinks_id
) td
ON td.orders_drinks_id = od.id
Once we have SELECT query written that gets the result we want, we can change it into an UPDATE statement. Just replace SELECT ... FROM with the UPDATE keyword, and add a SET clause, to assign/replace the value to the drinks column.
e.g.
UPDATE orders_drinks od
LEFT
JOIN ( SELECT di.orders_drinks_id
, SUM(di.drinks) AS tot_drinks
FROM items_drinks di
GROUP BY di.orders_drinks_id
) td
ON td.orders_drinks_id = od.id
SET od.drinks = IFNULL(td.tot_drinks,0)
(NOTE: the IFNULL function is optional. I just used it to substitute a value of zero whenever there are no matching rows in items_drinks found, or whenever the total is NULL.)
This will update all rows (that need to be updated) in the orders_drinks table. A WHERE clause could be added (after the SET clause), if you only wanted to update particular rows in orders_drinks, rather than all rows:
WHERE od.id = 1
Again, to get to this, first get a SELECT statement working to return the new value to be assigned to the column, along with the key of the table to be updated. Once that is working, convert it into an UPDATE statement, moving the expression that returns the new value down to a SET clause.

MySQL: handle EMPTY SET in UPDATE statement

I have: something like
UPDATE table
SET field = (SELECT field FROM another_table WHERE id = #id);
Problem: SELECT field FROM another_table WHERE id = #id subquery can return one field or EMPTY SET.
Question: How to handle situation when subquery returns empty set?
Updated:
UPDATE table t
SET field = IF((SELECT field FROM another_table WHERE id = #id) IS NOT NULL, -- select field
(SELECT field FROM another_table WHERE id = #id), -- Problem #1: select field AGAIN!
(SELECT field FROM table WHERE id = t.id) -- Problem #2: try to not change value, so select the current field value!!
);
If function can be useful:
UPDATE table
SET field = if((SELECT field FROM another_table WHERE id = #id) IS NULL,true,false);
You can add the conditional:
WHERE (SELECT COUNT(*) FROM another_table WHERE id = #id) > 0
This will make sure that at least one row exists in another_table with the id. See my SQL Fiddle as an example.
Note: this may not be the most efficient because it does a count on another_table, and if it is greater than 1 it will do another SELECT (two sub-queries). Instead, you can do an INNER JOIN:
UPDATE table
INNER JOIN another_table ON table.id=another_table.id
SET table.field = another_table.field
WHERE another_table.id = #id;
See this SQL Fiddle. The reason why I saved this as a second option, is not all SQL languages can UPDATE with joins (MySQL can). Also, you need some way to relate the tables..in this case I said that the table.id we are updating is equal to another_table.id we are taking the data from.
NOTE The UPDATE statement will modify EVERY row in table and assign the same value to every row; that seems a little unusual.
To answer your question:
If you want to handle the "empty set" by not updating any rows in table, then one way to do this is with a JOIN to an inline view:
UPDATE table t
CROSS
JOIN (SELECT a.field
FROM another_table a
WHERE a.id = #id
LIMIT 1
) s
SET t.field = s.field
Note that if the inline view query (aliased as s) return an "empty set", then no rows in table will be updated, because the JOIN operation will also return an "empty set", meaning there are zero rows to be updated.

MySQL sub query select statement inside Update query

I have 2 tables: tbl_taxclasses, tbl_taxclasses_regions
This is a one to many relationship, where the main record ID is classid.
I have a column inside the first table called regionscount
So, I create a Tax Class, in table 1. Then I add regions/states in table 2, assigning the classid to each region.
I perform a SELECT statement to count the regions with that same classid, and then I perform an UPDATE statement on tbl_taxclasses with that number. I update the regionscount column.
This means I'm writing 2 queries. Which is fine, but I was wondering if there was a way to do a SELECT statement inside the UPDATE statement, like this:
UPDATE `tbl_taxclasses` SET `regionscount` = [SELECT COUNT(regionsid) FROM `tbl_taxclasses_regions` WHERE classid = 1] WHERE classid = 1
I'm reaching here, since I'm not sure how robust MySQL is, but I do have the latest version, as of today. (5.5.15)
You could use a non-correlated subquery to do the work for you:
UPDATE
tbl_taxclasses c
INNER JOIN (
SELECT
COUNT(regionsid) AS n
FROM
tbl_taxclasses_regions
GROUP BY
classid
) r USING(classid)
SET
c.regionscount = r.n
WHERE
c.classid = 1
Turns out I was actually guessing right.
This works:
UPDATE `tbl_taxclasses`
SET `regionscount` = (
SELECT COUNT(regionsid) AS `num`
FROM `tbl_taxclasses_regions`
WHERE classid = 1)
WHERE classid = 1 LIMIT 1
I just needed to replace my brackets [] with parenthesis ().

MySQL - How can I update a table with values from another table?

I have the task to repair some invalid data in a mysql-database. In one table there are people with a missing date, which should be filled from a second table, if there is a corresponding entry.
TablePeople: ID, MissingDate, ...
TableEvent: ID, people_id, replacementDate, ...
Update TablePeople
set missingdate = (select replacementDate
from TableEvent
where people_id = TablePeople.ID)
where missingdate is null
and (select count(*)
from TableEvent
where people_id = TablePeople.ID) > 0
Certainly doesn't work. Is there any other way with SQL? Or how can I process single rows in mysql to get it done?
We need details about what's not working, but I think you only need to use:
UPDATE TablePeople
SET missingdate = (SELECT MAX(te.replacementDate)
FROM TABLEEVENT te
WHERE te.people_id = TablePeople.id)
WHERE missingdate IS NULL
Notes
MAX is being used to return the latest replacementdate, out of fear of risk that you're getting multiple values from the subquery
If there's no supporting record in TABLEEVENT, it will return null so there's no change