How to define an index, within a Sequelize model? - mysql

Question

I'm trying to create a simple non-unique index for one of my SQL columns, inside a Sequelize model. I tried to follow this post :How to define unique index on multiple columns in sequelize .
This is my code:
module.exports = (sequelize, DataTypes) => {
const Item = sequelize.define('Item', {
itemId: DataTypes.STRING,
ownerId: DataTypes.INTEGER,
status: DataTypes.STRING,
type: DataTypes.STRING,
nature: DataTypes.STRING,
content: DataTypes.STRING,
moment: DataTypes.BIGINT,
indexes:[
{
unique: 'false',
fields:['ownerId']
}
]
});
return Item;
};
I get this error:
Unhandled rejection SequelizeDatabaseError: You have an error in your
SQL syntax; check the manual that corresponds to your MariaDB server
version for the right syntax to use near '[object Object], createdAt
DATETIME NOT NULL, updatedAt DATETIME NOT NULL, P' at line 1
The code that i have in my server.js file is this:
models.sequelize.sync().then(function () {
server.listen(port, () => {
console.log('server ready')
})
});
What is wrong with my setup? Is there any other way this can be done with Sequelize?

Answer 1

Almost there. You should add indexes in a new object like this:
module.exports = (sequelize, DataTypes) => {
const Item = sequelize.define('Item', {
itemId: DataTypes.STRING,
ownerId: DataTypes.INTEGER,
status: DataTypes.STRING,
type: DataTypes.STRING,
nature: DataTypes.STRING,
content: DataTypes.STRING,
moment: DataTypes.BIGINT
},
{
indexes:[
{
unique: false,
fields:['ownerId']
}
]
});
return Item;
};

Answer 2

It can work in single migration also.
In my case, just perform the addIndex after createTable method in the migration file
Migration:
return queryInterface.createTable('Item', {
// columns...
}).then(() => queryInterface.addIndex('Item', ['OwnerId']))
.then(() => {
// perform further operations if needed
});
it's work for me in the migration file.