Print top 5 clips of each year based on their ranking - mysql

I need to print for each year: the title of the movie, year and rank-in-year of top 5 clips, based on their ranking.
So, i need to find the top 5 rated movies of each year.
I've tried a GROUP BY year(releases.date) but i also need the titles and i need to get N-th top rows of each group.
CLIPS [ id, title ]
RELEASES [ id_clip, date ]
RANKS [ id_clip, nr_votes, ranking ]
Any hints ? I am using MySQL.
I also have the year in the clips table.
mysql> select * from clip LIMIT 5;
+--------+-----------------------+------+-----------+
| idclip | title | year | clip_type |
+--------+-----------------------+------+-----------+
| 4 | !Women Art Revolution | 2010 | 0 |
| 7 | #1 | 2005 | 0 |
| 8 | #1 (I) | 2010 | 2 |
| 9 | #1 (II) | 2010 | 2 |
| 12 | #1 Cheerleader Camp | 2010 | 2 |
+--------+-----------------------+------
mysql> select * from releasedates LIMIT 5;
+---------+---------------------+---------+
| id_clip | date | country |
+---------+---------------------+---------+
| 4 | 2010-09-01 00:00:00 | Canada |
| 1773811 | 2006-01-22 00:00:00 | USA |
| 1773815 | 2006-02-12 00:00:00 | USA |
| 1773818 | 2006-02-19 00:00:00 | USA |
| 1773820 | 2006-01-22 00:00:00 | USA |
+---------+---------------------+---------+
5 rows in set (0,00 sec)
mysql> select * from ratings LIMIT 5;
+---------+-------+---------+
| id_clip | votes | ranking |
+---------+-------+---------+
| 4 | 8 | 8.0 |
| 1773811 | 51 | 4.5 |
| 1773839 | 753 | 6.3 |
| 1773843 | 32 | 6.9 |
| 1773844 | 18 | 7.1 |
+---------+-------+---------+
5 rows in set (0,00 sec)

Assuming the id column in Clips is similar to id_clip column in releases, can you try this, I can not test this at the moment, but I think this should work
select Title,Year(date) ,
RANK() OVER(PARTITION BY Year(Date) ORDER BY ranking)
from Clips c
Releases r on c.id=r.id_clip
join Ranks rank on r.id_clip=rank.id_clip

Related

Get Sum, Multiple Group By with Filter

I have a table with the following columns that I am trying to create a view from in order to create a report, I need to get the sum of completed hours for a particular class but with a specific filter:
| PK_CLASS_DAYS_ID | FK_MAIN_ID | FK_CLASS_ID | CLASS_DAY | OUTCOME | CLASS_DATE | HOURS |
|------------------|------------|-------------|-----------|---------|------------|-------|
| 1 | 27452 | 137 | 1 | *15 | 2015-11-15 | 8 |
| 2 | 27452 | 137 | 2 | *15 | 2015-11-16 | 8 |
| 3 | 27452 | 137 | 4 | *15 | 2015-11-18 | 8 |
| 4 | 27452 | 137 | 5 | BS15 | 2015-11-19 | 8 |
| 5 | 27452 | 2 | 1 | *16 | 2001-01-01 | 8 |
| 6 | 27452 | 48 | 1 | *16 | 2016-01-12 | 8 |
| 7 | 27452 | 48 | 2 | *16 | 2016-02-27 | 4 |
| 8 | 27452 | 2 | 1 | *17 | 2017-07-01 | 8 |
| 9 | 27452 | 137 | 1 | *16 | 2016-07-16 | 8 |
I need to find the SUM of hours completed for each class (FK_CLASS_ID) for every student in my table (currently I have filtered it to ID 27452 for testing purposes) while applying the following filter for each class (FK_CLASS_ID):
(1)CLASS_DAY must be distinct
(2)CLASS_OUTCOME must begin with "*"
(3)CLASS_DATE must be the most recent, while still having the previous two conditions. The resulting view should be as follows:
| PK_CLASS_DAYS_ID | FK_MAIN_ID | FK_CLASS_ID | Hrs |
|------------------|-------------|--------------|------|
| 1 | 27452 | 137 | 32 |
| 2 | 27452 | 2 | 8 |
| 3 | 27452 | 48 | 12 |
The furthest I've gotten with trying to accomplish this, is the following select statement:
SELECT
t1.CLASS,
SUM(class_hours) as Hrs,
GROUP_CONCAT('D',classes_days.class_day) as DaysList,
main.FULLNAME
FROM
classes t1
INNER JOIN classes_days ON classes_days.FK_CLASS_ID = t1.CLASS_ID
INNER JOIN main ON main.PK_MAIN_ID = classes_days.FK_MAIN_ID
WHERE
main.PK_MAIN_ID = 27452
GROUP BY FK_CLASS_ID
ORDER BY CLASS
For what you're wanting to accomplish, you would need to filter your joins with the desired summation queries and provide the joining on the desired criteria from the retrieved recordset.
Basing it off your provided query and desired results, it should look like:
SELECT
`t1`.`CLASS`,
SUM(`class_hours`.`HOURS`) AS `Hrs`,
GROUP_CONCAT('D', `class_hours`.`CLASS_DAY` ORDER BY `class_hours`.`CLASS_DAY`) AS `DaysList`,
`main`.`FULLNAME`
FROM `classes` AS `t1`
INNER JOIN (
#Filter the total hours by student, class, and day
SELECT `class_dates`.`FK_MAIN_ID`, `class_dates`.`CLASS_DAY`, `class_dates`.`FK_CLASS_ID`, SUM(`class_dates`.`HOURS`) as `HOURS`
FROM (
#Filter Most Recent Days beginning with star, by most recent date
SELECT `classes_days`.*
FROM `classes_days`
WHERE `classes_days`.`OUTCOME` LIKE '*%'
ORDER BY `CLASS_DATE` DESC
) AS `class_dates`
GROUP BY `class_dates`.`FK_MAIN_ID`, `class_dates`.`CLASS_DAY`, `class_dates`.`FK_CLASS_ID`
) AS `class_hours`
ON `class_hours`.`FK_CLASS_ID` = `t1`.`CLASS_ID`
INNER JOIN `main`
ON `main`.`PK_MAIN_ID` = `class_hours`.`FK_MAIN_ID`
GROUP BY `class_hours`.`FK_MAIN_ID`, `class_hours`.`FK_CLASS_ID`
ORDER BY `FULLNAME`, `CLASS`;
Resulting In:
| CLASS | Hrs | DaysList | FULLNAME |
|---------|-----|-------------|----------|
| History | 8 | D1 | Joe |
| Math | 32 | D1,D2,D4 | Joe |
| Science | 12 | D1,D2 | Joe |
| Math | 10 | D1,D2 | Mike |
Example: http://sqlfiddle.com/#!9/d5828/1
Original query of table is the top query. The subquery join example is the bottom query result. Removed the PK_MAIN_ID criteria to show it working against multiple entries
Do keep in mind that MySQL GROUP BY + ORDER BY does not always yield the desired results, and should be filtered using a subquery, which is demonstrated in the join subquery in order to get the most recent dates that begin with *.

MySQL select a row from a daterange excluding the year

I'm trying to create a MySQL query to select the daily price from a table that is between a date range from another. I only want to use 'starting-ending' months and days from the table "seasons" and I want to pass the year dynamically to the query.
This is my query: (I'm giving it the Year to exclude the one on the table)
SELECT a.season, b.base_price
FROM seasons a
JOIN pricebyseason b ON a.id=b.season_id
WHERE b.prop_id='6' AND '2015-11-29' BETWEEN DATE_FORMAT(a.starting,'2015-%m-%d') AND DATE_FORMAT(a.ending,'2016-%m-%d')
ORDER BY b.base_price DESC
It works but not with all dates.
These are the tables:
seasons (these are static date values)
+----+--------------+------------+------------+
| id | season | starting | ending |
+----+--------------+------------+------------+
| 1 | Peak Season | 2015-12-11 | 2016-01-09 |
| 2 | High Season | 2015-11-27 | 2016-04-15 |
| 3 | Mid Season | 2015-04-16 | 2015-09-01 |
| 4 | Low Season | 2015-09-02 | 2015-11-26 |
| 5 | Spring Break | 2015-03-05 | 2015-03-21 |
+----+--------------+------------+------------+
pricebyseason
+----+---------+-----------+------------+
| id | prop_id | season_id | base_price |
+----+---------+-----------+------------+
| 1 | 6 | 1 | 950 |
| 2 | 6 | 2 | 750 |
| 3 | 6 | 3 | 450 |
| 4 | 6 | 4 | 400 |
| 5 | 6 | 5 | 760 |
+----+---------+-----------+------------+
What I want to achive is query the dialy price between checkin, checkout selection
I create this sqlfiddle: http://sqlfiddle.com/#!9/4a6f4
This is a previuos query that is not working either:
SELECT a.base_price,b.season,b.starting,b.ending
FROM pricebyseason a JOIN seasons b ON a.season_id=b.id
WHERE a.prop_id='6' AND
(DATE_FORMAT(b.starting,'%m-%d') <= '12-27' OR DATE_FORMAT(b.starting,'2016-%m-%d') >= '2015-12-27')
AND
(DATE_FORMAT(b.ending,'%m-%d') >= '12-27' OR DATE_FORMAT(b.ending,'2016-%m-%d') <= '2015-12-27')
ORDER BY base_price DESC
And here are some sample dates for each season: '2016-01-08','2015-12-27','2016-04-14','2015-11-29','2016-04-15','2015-09-01','2016-09-02','2015-11-26','2016-10-10','2016-03-18','2016-06-22','2015-06-15'
Thank a lot

Listing results with unique column

I want to list top 6 race records with unique holder only. I mean a holder gets in the list shouldn't be listed with his another record. I currently use the query below to list top 6 times.
mysql> select * from racerecords order by record_time asc, date asc;
+----+---------+------------+-------------+---------------------+----------+
| id | race_id | holder | record_time | date | position |
+----+---------+------------+-------------+---------------------+----------+
| 2 | 10 | Stav | 15 | 2014-08-11 19:43:49 | 1 |
| 1 | 10 | Jennifer | 15 | 2014-08-13 19:43:19 | 1 |
| 4 | 10 | Jennifer | 16 | 2014-08-02 19:44:27 | 1 |
| 5 | 10 | Osman | 17 | 2014-08-04 19:44:57 | 1 |
| 7 | 10 | Gokhan | 18 | 2014-08-15 19:45:37 | 1 |
| 3 | 10 | MotherLode | 25 | 2014-08-01 19:44:11 | 1 |
+----+---------+------------+-------------+---------------------+----------+
6 rows in set (0.00 sec)
As you can see the holder "Jennifer" is listed twice. I want mySQL to skip her after she got in the list. The result I want to be generated is:
+----+---------+------------+-------------+---------------------+----------+
| id | race_id | holder | record_time | date | position |
+----+---------+------------+-------------+---------------------+----------+
| 2 | 10 | Stav | 15 | 2014-08-11 19:43:49 | 1 |
| 1 | 10 | Jennifer | 15 | 2014-08-13 19:43:19 | 1 |
| 5 | 10 | Osman | 17 | 2014-08-04 19:44:57 | 1 |
| 7 | 10 | Gokhan | 18 | 2014-08-15 19:45:37 | 1 |
| 3 | 10 | MotherLode | 25 | 2014-08-01 19:44:11 | 1 |
+----+---------+------------+-------------+---------------------+----------+
I tried everything. GROUP BY holder generates wrong results. It gets the very first record of the holder, even though is not the best. In this table it generates an output like above because id:1 is the first record I inserted for Jennifer.
How can I generate output a result like above?
Desired result can be achieved through this query but it performance intensive. I have reproduced the result in SQLFilddle http://sqlfiddle.com/#!2/f8ee7/3
select * from racerecords
where
(HOLDER, RECORD_TIME) in (
select HOLDER,min(RECORD_TIME) from racerecords
group by HOLDER)
Seems you have missed to include the Where clause in the sub-query. Try this
select * from racerecords
where
(HOLDER, RECORD_TIME) in (
select HOLDER,min(RECORD_TIME) from racerecords where race_id =17
group by HOLDER )
And race_id =17
Order by RECORD_TIME
you should use distinct clause
SELECT DISTINCT column_name,column_name
FROM table_name;
looks this http://www.w3schools.com/sql/sql_distinct.asp

How to get this specific user rankings query in mysql?

I've got tbl_items in my user database that I want to sort user rankings on a particular item with certain id (514). I have test data on my dev environment with this set of data:
mysql> select * from tbl_items where classid=514;
+---------+---------+----------+
| ownerId | classId | quantity |
+---------+---------+----------+
| 1 | 514 | 3 |
| 2 | 514 | 5 |
| 3 | 514 | 11 |
| 4 | 514 | 46 |
| 5 | 514 | 57 |
| 6 | 514 | 6 |
| 7 | 514 | 3 |
| 8 | 514 | 27 |
| 10 | 514 | 2 |
| 11 | 514 | 73 |
| 12 | 514 | 18 |
| 13 | 514 | 31 |
+---------+---------+----------+
12 rows in set (0.00 sec)
so far so good :) I wrote the following query:
set #row=0;
select a.*, #row:=#row+1 as rank
from (select a.ownerid,a.quantity from tbl_items a
where a.classid=514) a order by quantity desc;
+---------+----------+------+
| ownerid | quantity | rank |
+---------+----------+------+
| 11 | 73 | 1 |
| 5 | 57 | 2 |
| 4 | 46 | 3 |
| 13 | 31 | 4 |
| 8 | 27 | 5 |
| 12 | 18 | 6 |
| 3 | 11 | 7 |
| 6 | 6 | 8 |
| 2 | 5 | 9 |
| 7 | 3 | 10 |
| 1 | 3 | 11 |
| 10 | 2 | 12 |
+---------+----------+------+
12 rows in set (0.00 sec)
that ranks correctly the users. However in a table with lots of records, I need to do the following:
1) be able to get small portion of the list, around where the user ranking actually resides, something that would get me the surrounding records, preserving the overall rank:
I tried to do these things with setting a user variable to the ranking of the current user and by using offset and limit, but couldn't preserve the overall ranking.
This should get me something like the following (for instance ownerId=2 and surroundings limit 5:
+---------+----------+------+
| ownerid | quantity | rank |
+---------+----------+------+
| 3 | 11 | 7 |
| 6 | 6 | 8 |
| 2 | 5 | 9 | --> ownerId=2
| 7 | 3 | 10 |
| 1 | 3 | 11 |
+---------+----------+------+
5 rows in set (0.00 sec)
2) I'd also need another query (preferably single query) that gets me the top 3 places + the ranking of particular user with certain id, preferably with a single query, no matter if he's among the top 3 places or not. I couldn't get this as well
It would look like the following (for instance ownerId=2 again):
+---------+----------+------+
| ownerid | quantity | rank |
+---------+----------+------+
| 11 | 73 | 1 |
| 5 | 57 | 2 |
| 4 | 46 | 3 |
| 2 | 5 | 9 | --> ownerId=2
+---------+----------+------+
4 rows in set (0.00 sec)
Also I'm in a bit of a concern about the performance of the queries on a table with millions of records...
Hope someone helps :)
1) 5 entries around a given id.
set #row=0;
set #rk2=-1;
set #id=2;
select b.* from (
select a.*, #row:=#row+1 as rank, if(a.ownerid=#id, #rk2:=#row, -1) as rank2
from (
select a.ownerid,a.quantity
from tbl_items a
where a.classid=514) a
order by quantity desc) b
where b.rank > #rk2 - 3
limit 5;
Though you'll get an extra column rank2: you probably want to filter it out by explicit list of columns instead of b.*. Maybe it's possible whith a having clause rather than an extra nesting.
2) 3 top ranked entries + 1 specific id
select b.* from (
select a.*, #row:=#row+1 as rank
from (
select a.ownerid,a.quantity
from tbl_items a
where a.classid=514) a
order by quantity desc) b
where b.rank < 4 or b.ownerid=#id

mysql query for rating system

select
user_id,
#pos:=(#pos+1) as new_position,
(coins+total_item_costs) as wealth
from user_ledger
join users using (user_id),(select #pos:=0) p
ORDER BY wealth DESC
limit 10;
+---------+--------------+------------+
| user_id | new_position | wealth |
+---------+--------------+------------+
| 19 | 19 | 1112823871 |
| 11 | 11 | 13318047 |
| 8 | 8 | 7292407 |
| 6 | 6 | 6122746 |
| 27 | 27 | 5271889 |
| 23 | 23 | 5263050 |
| 9 | 9 | 5171734 |
| 3 | 3 | 5136092 |
| 15 | 15 | 5097488 |
| 4 | 4 | 5089487 |
+---------+--------------+------------+
10 rows in set (0.01 sec)
The new_position is incorrect..
What's wrong, guys? :)
ps. pls dont tell me to use temporary table
Should do the ORDER BY beforehand the position.
SELECT user_id,#pos:=(#pos+1) as new_position,wealth FROM (
select user_id,(coins+total_item_costs) as wealth from user_ledger join users
using (user_id) ORDER BY wealth DESC limit 10 ) a,(select #pos:=0) p