In this Database I want to count the number of orders that contain only products of a certain category.
I know how to count all orders that also contain items of a certain category, i.e. category 1:
SELECT Count(DISTINCT orderdetails.orderid) AS "AllCat1"
FROM orderdetails
INNER JOIN orders
ON orderdetails.orderid = orders.orderid
AND orderdetails.productid IN (SELECT DISTINCT productid
FROM products
WHERE categoryid = 1)
WHERE orderdate BETWEEN "1996-12-01" AND "1996-12-31";
I am having trouble finding an elegant way to get all orders that contain only category 1 items. I tried selecting all OrderIDs and grouping them by OrderID AND CategoryID:
SELECT *
FROM orderdetails
INNER JOIN orders
ON orderdetails.orderid = orders.orderid
AND orderdate BETWEEN "1996-12-01" AND "1996-12-31"
INNER JOIN products
ON orderdetails.productid = products.productid
GROUP BY orderdetails.orderid,
categoryid;
But I have no idea how to count all OrderIDs that contain category 1 items exclusively. Is my approach right? Or is there a better way to do it (Which I am sure there is)
You can use group by and having . . . but you need two levels. To get the orders that are all in one (or a set of categories) by doing:
SELECT o.orderId
FROM orders o JOIN
orderdetails od
ON od.orderid = o.orderid JOIN
products p
ON p.productid = od.productid
WHERE o.orderdate BETWEEN '1996-12-01' AND '1996-12-31'
GROUP BY o.orderId
HAVING SUM(CASE WHEN p.categoryid IN (1) THEN 1 ELSE 0 END) = COUNT(*);
The count needs a subquery:
SELECT COUNT(*)
FROM (SELECT o.orderId
FROM orders o JOIN
orderdetails od
ON od.orderid = o.orderid JOIN
products p
ON p.productid = od.productid
WHERE o.orderdate BETWEEN '1996-12-01' AND '1996-12-31'
GROUP BY o.orderId
HAVING SUM(CASE WHEN p.categoryid IN (1) THEN 1 ELSE 0 END) = COUNT(*)
) o;
You can do filtering using HAVING clause. We basically Count the order details rows where category is 1 for an order. It should be equal to the total count of rows for that order. This would ensure that all the categories in an order is 1 only.
SELECT od.orderid
FROM orderdetails AS od
INNER JOIN orders AS o
ON od.orderid = o.orderid
AND o.orderdate BETWEEN "1996-12-01" AND "1996-12-31"
INNER JOIN products AS p
ON od.productid = p.productid
GROUP BY od.orderid
HAVING COUNT(CASE WHEN p.categoryid = 1 THEN 1 END) = COUNT(*)
It is advisable to use Aliasing in case of multi-table queries for Code clarity and readability
Related
I'm pretty new to sql.
I have the following db schema:
Customers
CustomerID number
Name string
Address string
Country string
OrderDetails
OrderDetailID number
OrderID number
ProductID number
Quantity number
Orders
OrderID number
CustomerID number
OrderDate string
OrderValue string
Products
ProductID number
ProductName string
Price number
I need to get the CustomerID and Quantity for all those that have ordered a particular product name = "oil"
So far I can get the quantity by
select OrderDetails.Quantity
FROM Products
INNER JOIN OrderDetails ON OrderDetails.ProductID = Products.ProductID
where Products.ProductName = 'oil'
I can get the CustomerID by following Products.ProductID -> OrderDetails.ProductID -> OrderDetails.OrderID -> Orders.OrderID -> Orders.CustomerID but I am unsure how to express this in sql.
EDIT:
I'm looking for a single table like:
CustomerID | Quantity
-----------------------
1 10
4 40
5 1
Testing:
I'm using the SQL to regular expression calculator here using the gist here
select customers.name,sum(OrderDetails.Quantity) as tot_qty
FROM Products
INNER JOIN OrderDetails ON OrderDetails.ProductID = Products.ProductID
inner join orders on orderdetails.orderid=orders.orderid
inner join customers on orders.customerid=customers.customerid
where Products.ProductName = 'oil'
group by customers.name
What you need is to aggregate the quantities per CustomerId.
Since you only require the customerId there's no need to join to the Customer table.
Note also the use of short meaningful aliases makes the query less verbose:
select o.CustomerId, Sum(od.Quantity) Quantity
from Products p
join OrderDetails od on od.ProductID = p.ProductID
join orders o on o.orderid = od.orderid
where p.ProductName = 'oil'
group by o.CustomerId;
Forget about the distinct, use group by instead.
Use sum() aggregated function to consolidate all orders
select sum(OrderDetails.Quantity) as total, OrderDetails.CustomerID
FROM Products
INNER JOIN OrderDetails ON OrderDetails.ProductID = Products.ProductID
INNER JOIN Orders O ON O.OrderId = ON.OrderId
where Products.ProductName = 'oil'
group by Order.CustomerID
I am trying to solve the following query, there's a few additional parameters, but these are the main attributes required:
Provide the product details, which vendors supply these products, and what was the last date these products were ordered by customers.
I have my original query below which gets me 90% of the way. I just can't seem to figure out how to display the last order date by customer per individual product. I've tried embedding (select max(o.OrderDate) from orders as o) into my select statement, but it only displays the latest order date of all of the products, not the individual per product last order date (e.g., all dates listed are 01/01/2020 when I know other products' last order date was before this date).
Apologies, I do not have enough rep to post pictures in line with text, therefore I have attached pictures of table structure and my query.
SQL Query
Table structure
Query:
select distinct p.ProductNumber, p.ProductName, p.RetailPrice, p.QuantityOnHand, v.VendName,
(select max(o.OrderDate)
from orders as o)
as LastOrderDateByCust
from ((((orders as o
inner join order_details as od
on od.OrderNumber = o.OrderNumber)
inner join products as p
on p.ProductNumber = od.ProductNumber)
inner join product_vendors as pv
on p.ProductNumber = pv.ProductNumber)
inner join vendors as v
on pv.VendorID = v.VendorID)
where p.QuantityOnHand < '10'
order by LastOrderDateByCust DESC;`
figured it out on my own I believe:
select distinct p.ProductNumber, p.ProductName, c.CategoryDescription, p.RetailPrice, pv.WholesalePrice, p.QuantityOnHand, v.VendName, pv.DaysToDeliver, (select max(o.OrderDate)
from orders as o
inner join order_details as od
on o.OrderNumber = od.OrderNumber
where od.ProductNumber = p.ProductNumber)
as LastOrderDateByCust
from (((((orders as o
inner join order_details as od
on o.OrderNumber = od.OrderNumber)
inner join products as p
on p.ProductNumber = od.ProductNumber)
inner join product_vendors as pv
on p.ProductNumber = pv.ProductNumber)
inner join vendors as v
on pv.VendorID = v.VendorID)
inner join categories as c
on p.CategoryID = c.CategoryID)
where od.ProductNumber = p.ProductNumber and p.QuantityOnHand < '10'
order by p.ProductNumber;`
I'm trying to calculate the total purchase amount of each customer from the database available online on W3 Schools
The tables I'm using are:
Customers
Orders
Products
OrderDetails
My current query gives me the product wise purchase amount for the customer. What I need is the total purchase amount.
SELECT c.CustomerID,o.OrderID,(ord.Quantity*p.Price) as
Total_Amount
from Customers c inner join Orders o
inner join Products p
inner join OrderDetails ord
on c.CustomerID = o.CustomerID
and o.OrderID = ord.OrderID
and ord.ProductID = p.ProductID;
My Output:
I need the sum for the values with the same order id and customer id.
I tried out group-by and sum but it gives me the overall sum of all the products.
You simply want a GROUP BY:
SELECT c.CustomerID, SUM(ord.Quantity*p.Price) as
Total_Amount
FROM Customers c inner join Orders o
on c.CustomerID = o.CustomerID join
OrderDetails ord
on o.OrderID = ord.OrderID join
Products p
on ord.ProductID = p.ProductID
GROUP BY CustomerID;
Note that this orders the JOINs so the ON clauses are interleaved. This is how JOINs are normally written.
If you need the sum for the values with the same order id and customer id, then you need to group the rows based on both customer id and order id.
SELECT c.CustomerID,o.OrderID,SUM(ord.Quantity*p.Price) as Total_Amount
from Customers c inner join Orders o
inner join Products p
inner join OrderDetails ord
on c.CustomerID = o.CustomerID
and o.OrderID = ord.OrderID
and ord.ProductID = p.ProductID
Group By c.CustomerID,o.OrderID
I've a setup with the following tables (using MySQL):
orders, which have many:
a join table order_items, which have one from the:
products table
I've written a query to select orders where all their products are of a certain type:
SELECT orders.* FROM orders
INNER JOIN order_items ON order_items.order_id = orders.id
INNER JOIN products ON products.id = order_items.product_id
WHERE products.type = 'FooProduct'
AND (
NOT EXISTS (
SELECT null
FROM products
INNER JOIN order_items ON order_items.product_id = products.id
WHERE order_items.order_id = orders.id
AND products.type != 'FooProduct'
)
)
I run similar a couple of times: firstly to get orders comprised of all FooProducts, and again to get orders with all BarProducts.
My sticking point has been generating a third query to get all other orders, i.e. where all their products' types are not exclusively FooProducts, or exclusively BarProducts (aka a mix of the two, or other product types).
So, my question is how can I get all records where all product types aren't exclusively FooProducts or exclusively BarProduct.
Here's a little example data, from which I'd like to return the orders with the IDs 3 and 4:
- orders
id
1
2
3
4
-- order_items
id order_id product_id
1 1 1
2 1 1
3 2 2
4 2 2
5 3 3
6 3 4
7 4 1
8 4 2
-- products
id type
1 'FooProduct'
2 'BarProduct'
3 'OtherProduct'
4 'YetAnotherProduct'
I've attempted this, awfully so placing as a subtext, with the following in place of the existing AND (even the syntax is way off):
NOT HAVING COUNT(order_items.*) = (
SELECT null
FROM products
INNER JOIN order_items ON order_items.product_id = products.id
WHERE order_items.order_id = orders.id
AND products.type IN ('FooProduct', 'BarProduct')
)
Instead of using Correlated subqueries, you can use Having and conditional aggregation function based filtering.
products.type IN ('FooProduct', 'BarProduct') will return 0 if a product type is none of them. We can use Sum() function on it, for further filtering.
Try the following instead:
SELECT orders.order_id
FROM orders
INNER JOIN order_items ON order_items.order_id = orders.id
INNER JOIN products ON products.id = order_items.product_id
GROUP BY orders.order_id
HAVING SUM(products.type IN ('FooProduct', 'BarProduct')) < COUNT(*)
For the case, where you are looking for orders which has only FooProduct type, you can use the following instead:
SELECT orders.order_id
FROM orders
INNER JOIN order_items ON order_items.order_id = orders.id
INNER JOIN products ON products.id = order_items.product_id
GROUP BY orders.order_id
HAVING SUM(products.type <> 'FooProduct') = 0
Another possible approach is:
SELECT orders.order_id
FROM orders
INNER JOIN order_items ON order_items.order_id = orders.id
INNER JOIN products ON products.id = order_items.product_id
GROUP BY orders.order_id
HAVING SUM(products.type = 'FooProduct') = COUNT(*)
You can use aggregation and a having clause for this:
SELECT o.*
FROM orders o INNER JOIN
order_items oi
ON oi.order_id = o.id INNER JOIN
products p
ON p.id = oi.product_id
GROUP BY o.id -- OK assuming `id` is the primary key
HAVING SUM(p.type NOT IN ('FooProduct', 'BarProduct')) > 0; -- at least one other product
Actually, that is not quite right. This gets orders that have some other product, but it doesn't pick up orders that are mixes only of foo and bar. I think this gets the others:
HAVING SUM(p.type = 'FooProduct') < COUNT(*) AND
SUM(p.type = 'BarProduct') < COUNT(*)
This is a basic solution, not so efficient but easy:
SELECT * FROM orders WHERE id NOT IN (
SELECT orders.id FROM orders
INNER JOIN order_items ON order_items.order_id = orders.id
INNER JOIN products ON products.id = order_items.product_id
WHERE products.type = 'FooProduct'
AND (
NOT EXISTS (
SELECT null
FROM products
INNER JOIN order_items ON order_items.product_id = products.id
WHERE order_items.order_id = orders.id
AND products.type != 'FooProduct'
)
)
) AND id NOT IN (
SELECT orders.id FROM orders
INNER JOIN order_items ON order_items.order_id = orders.id
INNER JOIN products ON products.id = order_items.product_id
WHERE products.type = 'BarProduct'
AND (
NOT EXISTS (
SELECT null
FROM products
INNER JOIN order_items ON order_items.product_id = products.id
WHERE order_items.order_id = orders.id
AND products.type != 'BarProduct'
)
)
)
I would suggest using count(distinct) in joined subselect like this:
SELECT orders.*
FROM orders
inner join (
SELECT orderid, max(products.type) as products_type
FROM order_items
INNER JOIN products ON products.id = order_items.product_id
GROUP BY orderid
-- distinct count of different products = 1
-- -> all order items are for the same product type
HAVING COUNT(distinct products.type ) = 1
-- alternative is:
-- min(products.type )=max(products.type )
) as tmp on tmp.orderid=orders.orderid
WHERE 1=1
-- if you want only single type product orders for some specific product
and tmp.products_type = 'FooProduct'
This is a relational division problem.
One solution to find orders where all products are of a given type is this:
SELECT *
FROM orders
INNER JOIN order_items ON order_items.order_id = orders.id
INNER JOIN products ON products.id = order_items.product_id
WHERE orders.id IN (
SELECT order_items.order_id
FROM order_items
INNER JOIN products ON products.id = order_items.product_id
GROUP BY order_items.order_id
HAVING COUNT(CASE WHEN products.type = 'FooProduct' THEN 1 END) = COUNT(*)
)
Tweak the above just a little to find orders where all products are from a list of given types is this:
HAVING COUNT(CASE WHEN products.type IN ('FooProduct', 'BarProduct') THEN 1 END) = COUNT(*)
And to find all orders where all products match all types from a given list is this:
HAVING COUNT(CASE WHEN products.type IN ('FooProduct', 'BarProduct') THEN 1 END) = COUNT(*)
AND COUNT(DISTINCT products.type) = 2
DB Fiddle with tests
i need little help in writing the MYSQL Query.
i want to retreive the data from 3 tables, but i want to retreive the data from 3rd table only if the count() value is equals to 1.
please see the below query.
SELECT count(orderdetails.orderId) as total,gadgets.*,orders.* FROM orders
JOIN orderdetails ON orders.orderId = orderdetails.orderId
CASE total WHEN 1 THEN (JOIN gadgets ON gadgets.gadgetId = orders.gadgetId)
GROUP BY orders.orderId
ORDER BY orders.orderId DESC;
mysql always gives me an error, and i couldnt find any solution over internet.
Just add a Simple Condition in Join, and it would work (Of course you have make it Left Join).
SELECT count(orderdetails.orderId) as total,gadgets.*,orders.* FROM orders
JOIN orderdetails ON orders.orderId = orderdetails.orderId
LEFT JOIN gadgets ON gadgets.gadgetId = orders.gadgetId
and total=1 --Simple Logic
GROUP BY orders.orderId
ORDER BY orders.orderId DESC;
SELECT
g.*, o.*
FROM
orders AS o
JOIN
( SELECT orderId
FROM orderdetails
GROUP BY orderId
HAVING COUNT(*) = 1
) AS od
ON o.orderId = od.orderId
JOIN gadgets AS g
ON g.gadgetId = o.gadgetId
ORDER BY
o.orderId DESC ;
You can join the table and get only results having total = 1
SELECT count(orderdetails.orderId) as total,gadgets.*,orders.* FROM orders
JOIN orderdetails ON orders.orderId = orderdetails.orderId
JOIN gadgets ON gadgets.gadgetId = orders.gadgetId
GROUP BY orders.orderId
HAVING total = 1
ORDER BY orders.orderId DESC;
HTH