I have a datetime column and I want to select all rows from the previous 2 complete months (Sept and Oct, currently). Manually I could compose this query as:
where date_column between '2018-09-01' and '2018-10-31'
but how can I do this programmatically so the end date is always correct? I was thinking
where date_column between concat(substr(now() - INTERVAL 2 month, 1, 7), '-01') and concat(substr(now() - INTERVAL 1 month, 1, 7), '-31')
but the 31 will be incorrect for November, February, etc.
You could format the date and just hard code the day to be 1:
date_column BETWEEN
DATE_FORMAT(NOW() - INTERVAL 2 MONTH, '%Y-%m-01') AND
DATE_FORMAT(NOW(), '%Y-%m-01')
Related
I have function get day of week and week from current day in mysql
It look like.
select
DATE_FORMAT(now(), '%U') as w,
DATE_FORMAT(now(), '%w') as day_of_w;
It return w is 37 and day_of_week is 1. How to get correct value w is 37 and day_of_week is 1 of previous year.
I using
select
DATE_FORMAT(now() interval 1 year, '%U') as w,
DATE_FORMAT(now() interval 1 year, '%w') as day_of_w;
But SQL cannot execute.
The function to turn a string into a date is STR_TO_DATE. If you want to get the date for week 37, day 1 in 2019, you could use
select str_to_date('37 1 2019', '%U %w %Y')
If you want the date for today's week and day number in last year:
select str_to_date(concat_ws(' ', date_format(current_date, '%U'),
date_format(current_date, '%w'),
year(current_date) - 1),
'%U %w %Y')
Be aware though, that some years have a week 53 while others don't. If you run this query in a year's 53rd week, you don't get a valid result.
select DAYOFWEEK(now()) day_of_week, week(now()) week from dual
your query has syntactical problem. you forgot +/- symbol
select DATE_FORMAT(now() + interval 1 year, '%U') as w
,DATE_FORMAT(now() + interval 1 year, '%w') as day_of_w;
You just need to use DATE_ADD function in MYSQL to change the date to last year.
select DATE_FORMAT(DATE_ADD(now(), INTERVAL -1 YEAR), '%U') as w
,DATE_FORMAT(DATE_ADD(now(), INTERVAL -1 YEAR), '%w') as day_of_w;
Result:
36 6
Current and last year date:
select now() as curr_yr_date, DATE_ADD(now(), INTERVAL -1 YEAR) as last_yr_date;
Result:
2020-09-14 07:13:24 2019-09-14 07:13:24
I am trying to select every record between current month and the next 2 months but I am not able to because the year will be changing from 2016 to 2017.
For ex.
I want to get all the records from November 2016 to January 2017.
The current query (shown below) i have has worked fine until this month because November 2016 + 2 months = Jan 2017.
select * from dateTable
where month(t2.`END_DATE`) between month(curdate()) and
month(DATE_ADD(curdate(), INTERVAL 2 MONTH))
and year(t2.`END_DATE`) = year(curdate());
This returns 0 rows because this cannot handle having two years, 2016 and 2017.
How would I go about doing this?
This should be what you need, although there are probably a number of ways of doing this
select * from dateTable
where `END_DATE` BETWEEN DATE_FORMAT(NOW() ,'%Y-%m-01')
AND LAST_DAY(DATE_ADD(NOW(), INTERVAL 2 MONTH))
The result of this query will demonstrate the dates being generated
SELECT DATE_FORMAT(NOW() ,'%Y-%m-01') as from_date,
LAST_DAY(DATE_ADD(NOW(), INTERVAL 2 MONTH)) as to_date
Today this will generate
from_date to_date
2016-11-01 2017-01-31
Try to use full datetime with DATE_ADD and DATE_DIFF functions.
select * from dateTable where t2.`END_DATE`
between DATEADD(month,
DATEDIFF(month, 0, getdate() -- get difference to first day
), 0)
and DATEADD(month, 2, -- add 3 months interval to get first day of third
DATEADD(month,
DATEDIFF(month, 0, getdate() -- get difference to first day
), 0))
If you have to remove the first day from last month use DATEADD again and remove 1 second to get 23:59:59
I need some help with this.
I have the following SQL statement
SELECT * FROM table
WHERE MONTH(ORDERDATE) = MONTH(NOW() - INTERVAL 1 MONTH)
The problem is that it is returning data from last month but for all years... Am I doing something wrong or is this a normal issue that people face with this function?
The problem I am facing is that if I use the YEAR(NOW()) the report I am writing will not show the data for 2016 when we hit 2017. I'm trying to write a 6 month sales history report.
Any guidance would be appreciated.
Added Information
SELECT * FROM DATA_WH.SALESORD_HDR WHERE MONTH(ORDERDATE) = MONTH(NOW() - INTERVAL 1 MONTH)
RETURNS....
'2015-08-14 00:00:00'
Try using DATE_SUB with BETWEEN:
SELECT *
FROM DATA_WH.SALESORD_HDR
WHERE ORDERDATE BETWEEN DATE_SUB(NOW(), INTERVAL 1 MONTH) AND
DATE_SUB(NOW(), INTERVAL 2 MONTH)
This avoids the problem of having to deal with boundary conditions when using MONTH and YEAR.
Edit:
The above query will return records whose order date is between one and two months old. If you want to identify orders from the previous calendar month, then you will have to do a bit more work. Try this query:
SELECT *
FROM DATA_WH.SALESORD_HDR
WHERE ORDERDATE >= STR_TO_DATE(CONCAT('01-', LPAD(MONTH(DATE_SUB(NOW(), INTERVAL 1 MONTH)), 2, '0'), '-', YEAR(DATE_SUB(NOW(), INTERVAL 1 MONTH))), '%d-%m-%Y') AND
ORDERDATE < STR_TO_DATE(CONCAT('01-', LPAD(MONTH(NOW()), 2, '0'), '-', YEAR(NOW())), '%d-%m-%Y')
The strategy here is to build the date boundaries (August 1 and September 1 of 2016, as of the time of writing this answer), using the ORDERDATE.
Here is a Fiddle showing this logic in action:
SQLFiddle
I think you have to add another condition with AND with YEAR function
SELECT * FROM DATA_WH.SALESORD_HDR WHERE MONTH(ORDERDATE) = MONTH(NOW() - INTERVAL 1 MONTH) AND YEAR(ORDERDATE)= YEAR(NOW());
I have been working on this kind of queries recently:
This query will get the first day of the month and the last day of the month , also if you can carefully check the query you should be able to see that I have add a function from mysql that check the last day if the month "last_day(now())"
SELECT *
FROM DATA_WH.SALESORD_HDR
WHERE ORDERDATE BETWEEN date(concat(year(now()) , '-' ,month(now()) , '-01')) ,AND
date(concat(year(now()) , '-' ,month(now()) , '-' , day(last_day(now()))))
What about this?
SELECT * FROM table
WHERE MONTH(ORDERDATE) = MONTH(NOW() - INTERVAL 1 MONTH) and YEAR(ORDERDATE) = YEAR(NOW() - INTERVAL 1 MONTH)
This should only return rows where the order date is in the previous month.
How would I go about retrieving records from the last three months of the previous year? I was thinking it would be:
Date_add(curdate() , interval '-1 2' year_month)
Try this:
WHERE my_date_column BETWEEN
SUBDATE(CURDATE(), INTERVAL DAYOFYEAR(CURDATE()) + 91 DAY) AND
SUBDATE(CURDATE(), INTERVAL DAYOFYEAR(CURDATE()) DAY)
91 is one less than 31 + 30 + 31, because BETWEEN is inclusive.
Note that if your column is a datetime type, you'll need the end value to be the last second of the day:
SUBDATE(SUBDATE(CURDATE(), INTERVAL DAYOFYEAR(CURDATE()) - 1 DAY), INTERVAL 1 SECOND)
See SQLFiddle of these expressions generating correct values.
Assuming you date column is named "date", something like:
SELECT
*
FROM
table
WHERE
YEAR(date) = YEAR(DATE_SUB(CURDATE(), INTERVAL 1 YEAR))
AND
MONTH(date) BETWEEN 10 AND 12
I have a table with a timestamp field. How do I get data from the last 3 months?
In particular, March is my current month let say, 03/2012. I need to return records from the months March, February, and January only.
3 months before today:
select * from table where timestamp >= now()-interval 3 month;
Start with first of month:
select * from table where timestamp >= last_day(now()) + interval 1 day - interval 3 month;
To get the first day of the current month, you could use this:
DATE_FORMAT(CURDATE(), '%Y-%m-01')
if current date is 2013-03-13, it will return 2013-03-01, and we can just substract 2 months from this date to obtain 2013-01-01. Your query could be like this:
SELECT *
FROM yourtable
WHERE data >= DATE_FORMAT(CURDATE(), '%Y-%m-01') - INTERVAL 2 MONTH
I know this is an old question, but to possibly save others time and to sum the above answers up for the case of needing (1) dates from current month and (2) dates from the prior 2 months (common when displaying data statistics):
WHERE ((timestamp >= NOW() - DATE_FORMAT(CURDATE(), '%Y-%m-01'))
OR (timestamp >= DATE_FORMAT(CURDATE(), '%Y-%m-01') - INTERVAL 2 MONTH))
Assuming you're using SQL Server (Oracle, MySQL and others have similar date functions), you can use the dateadd function to add or subtract an interval to the current date.
If you want a full three months, you can subtract 3 months from today : DATEADD(m,-3,getdate())
But, as you state, you only want data from January, February and March. You have to make some calculation based on today's date: dateadd(m,-2, CONVERT(datetime, CONVERT(VARCHAR(2), MONTH(getdate())) + '/01/' + CONVERT(VARCHAR(4), YEAR(getdate()))))
And in the end, get a query like
SELECT fields
FROM table
WHERE timestampfield > DATEADD(m,-2, CONVERT(datetime, CONVERT(VARCHAR(2), MONTH(getdate())) + '/01/' + CONVERT(VARCHAR(4), YEAR(getdate()))))
--- edit ---
erf, I just noticed the "mysql" tag... you can get more information on MySQL date functions here : https://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
Another possibility would be:
SELECT * WHERE your_date_column > LAST_DAY(CURRENT_DATE - INTERVAL 3 MONTH);
Use this code here to get the previous 3 months from a certain date
SELECT * FROM table WHERE date_column>= DATE_FORMAT(current_date(), '%Y-%m-01') - INTERVAL 3 MONTH and date_column< DATE_FORMAT(current_date(), '%Y-%m-01')
WHERE ((timestamp >= NOW() - DATE_FORMAT(CURDATE(), '%Y-%m-01'))
OR (timestamp >= DATE_FORMAT(CURDATE(), '%Y-%m-01') - INTERVAL 2 MONTH))