I was wondering how I can complete this task by command line jq. I make up a file with similar nested structure as follows:
{
"item": "item1",
"features": [
{
"feature": "feature_a",
"value": ""
},
{
"feature": "feature_b",
"value": ""
}
]
}
Now I have another file that maps the feature to value:
feature_a value_1
feature_b value_2
So I would like to insert the value into the first json file, according to the maps, resulting the following output:
{
"item": "item1";
"features": [
{
"feature": "feature_a",
"value": "value_1"
},
{
"feature": "feature_b",
"value": "value_2"
}
]
}
How I can achieve above operation by jq?
Thanks in advance!
Assuming the text file is in dict.txt and the JSON file is in source.json, the invocation
jq -Rs --argfile target source.json dict.txt '
([ split("\n")[]
| select(length>0)
| split(" ")
| { (.[0]): .[1]} ]
| add) as $dict
| $target
| .features |= map(.value = $dict[.feature])'
would yield the desired output.
The main reason for including select(length>0) is to skip any empty strings that might result from using split("\n") to split an entire file.
Related
I have a GraphQL schema file with deeply nested object metadata that I'd like to extract into arrays of child properties. The original file is over 75000 lines long but I was able to successfully extract the Types & fields for each object using this command:
jq '.data.__schema.types[] | {name: .name, fields: .fields[]?.name?}' schema.json > output.json
Output:
{
"name": "UsersConnection",
"fields": "nodes"
}
{
"name": "UsersConnection",
"fields": "edges"
}
{
"name": "UsersConnection",
"fields": "pageInfo"
}
{
"name": "UsersConnection",
"fields": "totalCount"
}
{
"name": "UsersEdge",
"fields": "cursor"
}
{
"name": "UsersEdge",
"fields": "node"
}
...
But the output I want looks more like this:
[{
"name": "UsersConnection",
"fields": [ "nodes", "edges", "pageInfo", "totalCount" ]
},
{
"name": "UsersEdge",
"fields": [ "cursor", "node" ]
}]
I was able to do this by comma-separating each object, surrounding the output with { "data": [ -OUTPUT- ]} & the command:
jq 'map(. |= (group_by(.name) | map(first + {fields: map(.fields)})))' output.json > output2.json
How can I do this with a single command?
Assuming .data.__schema.types is an array, and so is .fields, you could try map in both cases:
.data.__schema.types | map({name: .name, fields: (.fields | map(.name))})
I totally missed that I put the fields object inside brackets like this:
jq '.data.__schema.types[] | {name: .name, fields: [.fields[]?.name?]}'
Keeping this up for posterity in case someone else is trying to do the same thing
Update: I was able to get a cleaner, comma-separated result like this:
jq 'reduce .data.__schema.types[] as $d (null; .[$d.name] += [$d.fields[]?.name?])'
I have a json file with this content and want to convert it to CSV like below:
{
"fields": [
{
"id": 17,
"name": "Business Division",
"values": [
{
"id": 131,
"name": "Accounting",
"industry": [
"Accounting"
]
}
]
},
{
"id": 16,
"name": "Cancellation Reason",
"values": [
{
"id": 114,
"name": "Forgot"
}
]
}
]
}
CSV File format:
17,Business Division,131,Accounting,Accounting
16,Cancellation Reason,114,Forgot
I ran this command on the terminal:
jq -M -r -f industry.jq source.json |tr -d '"' >source.csv
this is the content of industry.jq file that is used as the filter:
.fields[]
| .values[] as $e
| $e.industry[]? as $s
| [.id, .name, $e.id, $e.name, $s? ]
| #csv
As result, the second line of the CSV file did not print
I think it's because of the .industry[] object that did not available in the second object in my Json
How can I print the above json in the needed format?
.fields[] | [ .id, .name, .values[].id, .values[].name, .values[].industry[]? ] | #csv
Will produce
17,"Business Division",131,"Accounting","Accounting"
16,"Cancellation Reason",114,"Forgot"
When invoked like:
jq --raw-output '.fields[] | [ .id, .name, .values[].id, .values[].name, .values[].industry[]? ] | #csv'
Multiple industries will be added behind
Try it online
I'd use try ... catch ... to make the value of the default explicit, e.g.
(try $e.industry[] catch null) as $s
{
"Users": [
{
"Attributes": [
{
"Name": "sub",
"Value": "1"
},
{
"Name": "phone_number",
"Value": "1234"
},
{
"Name": "referral_code",
"Value": "abc"
}
]
},
{
"Attributes": [
{
"Name": "sub",
"Value": "2"
},
{
"Name": "phone_number",
"Value": "5678"
},
{
"Name": "referral_code",
"Value": "def"
}
]
}
]
}
How can I produce output like below ?
1,1234,abc
2,5678,def
jq '.Users[] .Attributes[] .Value' test.json
produces
1
1234
abc
2
5678
def
Not sure this is the cleanest way to handle this, but the following will get the desired output:
.Users[].Attributes | map(.Value) | #csv
Loop through all the deep Attributes .Users[].Attributes
map() to get all the Value's
Convert to #csv
jqPlay demo
If you don't need the output to be guaranteed to be CSV, and if you're sure the "Name" values are presented in the same order, you could go with:
.Users[].Attributes
| from_entries
| [.[]]
| join(",")
To be safe though it would be better to ensure consistency of ordering:
(.Users[0] | [.Attributes[] | .Name]) as $keys
| .Users[]
| .Attributes
| from_entries
| [.[ $keys[] ]]
| join(",")
Using join(",") will produce the comma-separated values as shown in the Q (without the quotation marks), but is not guaranteed to produce the expected CSV for all valid values of the input. If you don't mind the pesky quotation marks, you could use #csv, or if you want to skip the quotation marks around all numeric values:
map(tonumber? // .) | #csv
I have a response from curl in a format like this:
[
{
"list": [
{
"value": 1,
"id": 12
},
{
"value": 15,
"id": 13
},
{
"value": -4,
"id": 14
}
]
},
...
]
Given a mapping between ids like this:
{
"12": "newId1",
"13": "newId2",
"14": "newId3"
}
I want to make this:
[
{
"list": {
"newId1": 1,
"newId2": 15,
"newId3": -4,
}
},
...
]
Such that I get a mapping from ids to values (and along the way I'd like to remap the ids).
I've been working at this for a while and every time I get a deadend.
Note: I can use Shell or the like to preform loops if necessary.
edit: Here's one version what I've developed so far:
jq '[].list.id = ($mapping.[] | select(.id == key)) | del(.id)' -M --argjson "mapping" "$mapping"
I don't think it's the best one, but I'm looking to see if I can find an old version that was closer to what I need.
[EDIT: The following response was in answer to the question when it described (a) the mapping as shown below, and (b) the input data as having the form:
[
{
"list": [
{
"value": 1,
"id1": 12
},
{
"value": 15,
"id2": 13
},
{
"value": -4,
"id3": 14
}
]
}
]
END OF EDIT]
In the following I'll assume that the mapping is available via the following function, but that is an inessential assumption:
def mapping: {
"id1": "newId1",
"id2": "newId2",
"id3": "newId3"
} ;
The following jq filter will then produce the desired output:
map( .list
|= (map( to_entries[]
| (mapping[.key]) as $mapped
| select($mapped)
| {($mapped|tostring): .value} )
| add) )
There's plenty of ways to skin a cat. I'd do it like this:
.[].list |= reduce .[] as $i ({};
($i.id|tostring) as $k
| (select($mapping | has($k))[$mapping[$k]] = $i.value) // .
)
You would just provide the mapping through a separate file or argument.
$ cat program.jq
.[].list |= reduce .[] as $i ({};
($i.id|tostring) as $k
| (select($mapping | has($k))[$mapping[$k]] = $i.value) // .
)
$ cat mapping.json
{
"12": "newId1",
"13": "newId2",
"14": "newId3"
}
$ jq --argfile mapping mapping.json -f program.jq input.json
[
{
"list": {
"newId1": 1,
"newId2": 15,
"newId3": -4
}
}
]
Here is a reduce-free solution to the revised problem.
In the following I'll assume that the mapping is available via the following function, but that is an inessential assumption:
def mapping:
{
"12": "newId1",
"13": "newId2",
"14": "newId3"
} ;
map( .list
|= (map( mapping[.id|tostring] as $mapped
| select($mapped)
| {($mapped): .value} )
| add) )
The "select" is for safety (i.e., it checks that the .id under consideration is indeed mapped). It might also be appropriate to ensure that $mapped is a string by writing {($mapped|tostring): .value}.
In my JSON document I have a string that I need manipulated and then have the entire document returned with the 'fixed' values.
The input document is:
{
"records" : [
{
"time": "123456789000"
},
{
"time": "123456789000"
}
]
}
I want to find the "time" key and replace the string by dropping off the last 3 chars. The resulting document would be:
{
"records" : [
{
"time": "123456789"
},
{
"time": "123456789"
}
]
}
I've been trying to understand the jq query syntax but I'm not coming right. I'm still struggling to return the whole document when filtering on a specific value. All I have so far is:
.records[] | select(.time | contains("123456789000"))
Here is a solution using |= and string slicing
.records[].time |= .[:-3]
Sample Run (assuming data in data.json)
$ jq -M '.records[].time |= .[:-3]' data.json
{
"records": [
{
"time": "123456789"
},
{
"time": "123456789"
}
]
}
Try it online at jqplay.org
With jq sub() function:
jq '.records[].time |= sub("[0-9]{3}$";"")' file
The output:
{
"records": [
{
"time": "123456789"
},
{
"time": "123456789"
}
]
}
Or even simpler: via dividing the time value by 1000:
jq '.records[].time |= (tonumber / 1000 | tostring)' file
The following works with jq version 1.4 or later:
jq '.records[].time |= .[:-3]' file.json
(The expression .[:-3] is short for .[0:-3]; the negative integer here counts from the right.)
With jq 1.3, the following filter would work in your particular case:
.records[].time |= (tonumber | ./1000 | tostring)