I have a table in which i store every 15 minutes result of a cron job, which is nothing more than a timestamp, a population number and an id.
I am trying to query it as following.
SELECT ROUND(AVG(`population`),0) AS population, DATE(`time`) AS date
FROM `swg_servertracker`
WHERE `time` >= DATE(NOW()) - INTERVAL 7 DAY
GROUP BY DATE(`time`)
DESC
LIMIT 7
What it does it creates an daily average, and grabs the last 7 entries. Sadly in was not in the right order, so i flipped it to ascending. My problem is when i inverse (asc) it, it skips today, and goes back an extra day (today is the 3rd of october, which is not taken in the equation when i use the ascending)
I tried to set the where statement to just now - interval 168 hours (which is also 7 days but then relative back) which had no result either on this. Still it skips today and just goes back 7 days from on yesterday.
SELECT ROUND(AVG(`population`),0) AS population, DATE(`time`) AS date
FROM `swg_servertracker`
WHERE `time` >= NOW() - INTERVAL 168 HOUR
GROUP BY DATE(`time`)
ASC
LIMIT 7
So is there a way I can take today in account as well?
You select 8 records instead 7 records. If you want to select 7 latest records, you must use "greater than" sign instead "greater than or equal" sign.
SELECT ROUND(AVG(`population`),0) AS population, DATE(`time`) AS date
FROM `swg_servertracker`
WHERE `time` > NOW() - INTERVAL 7 DAY
GROUP BY DATE(`time`)
ASC
LIMIT 7
You can get the result-set in a Derived table, and do a sorting on the results again.
Note that, in MySQL, Aliases defined in the Select clause can be used in Group By, Having and Order By clauses. So, I have aliased DATE(time) to avoid re-computation in Group by and Order By.
You can do this instead:
SELECT dt.population,
dt.date1 AS date
FROM (
SELECT ROUND(AVG(`population`),0) AS population,
DATE(`time`) AS date1
FROM `swg_servertracker`
WHERE `time` >= DATE(NOW()) - INTERVAL 7 DAY
GROUP BY date1
ORDER BY date1 DESC
LIMIT 7
) AS dt
ORDER BY dt.date1 ASC
Related
I want to display last 12 months sales in a chart. SQL table has year and month field and not a combined date field.
Im not able to give the interval condition of 12months on Year field.
SELECT s_month,s_year,SUM(s_amount) FROM table
WHERE s_month >= Date_add(now(),interval - 12 month)
AND s_year >= Date_add(now(),interval - 12 month)
GROUP BY s_year,s_month
One method is:
select s_year, s_Month, sum(s_amount)
from t
where date(concat_ws('-', s_year, s.month, 1)) >= curdate() - interval 12 month
group by s_year, s_month;
You may want to adjust the date arithmetic, depending on whether you want the date from 12 months ago.
If you want the last 12 months in the data, you can do:
select s_year, s_month, sum(amount)
from t
group by s_year, s_month
order by s_year desc, s_month desc
limit 12;
This is a strong argument against storing date parts (month, year) in separate columns.
The WHERE clause you have does not do what you expect!
It is virtually always better to have a DATE column (or TIMESTAMP or DATETIME) and use date functions as needed to split it apart.
SELECT MONTH(dat), YEAR(dat), SUM(amount)
FROM table
WHERE dat >= CURDATE() - INTERVAL 12 MONTH
GROUP BY LEFT(dat, 7) -- eg, "2017-12"
There is another problem with your query. SUM(amount) will have a partial month at either end. I can't solve that for you without better understanding where the data comes from and when. If it is already a single reading stored on the first of the month, then no problem. If it is daily or hourly amounts, then my point stands.
I am trying to add 5 days to a date in MYSQL in a query. This is what I have done:
SELECT * FROM sales INNER JOIN partner on user_id = idpartner WHERE DATE((end_date) + 5) >= DATE(NOW()) ORDER BY end_date ASC LIMIT 0,50000
But this is not showing the list of sales which has ended. Can someone please tell me where I am making a mistake.
It looks like you want rows where end_date is later than five days ago.
The best way to get that is with
WHERE end_date >= CURDATE() - INTERVAL 5 DAY
The business of adding integers to dates doesn't work in MySQL (it's an Oracle thing). So you need to use the INTERVAL n unit syntax.
You'll notice that my WHERE clause above is functionally equivalent to
WHERE DATE(end_date) + INTERVAL 5 DAY >= DATE(NOW())
But, the first formulation is superior to the second for two reasons.
if you mention end_date in a WHERE clause without wrapping it in computations, your query can exploit an index on that column and can run faster.
DATE(NOW()) and CURDATE() both refer to the first moment of today (midnight). But CURDATE() is a bit simpler.
To fix the original query, you can use DATE_ADD with the INTERVAL keyword:
SELECT
*
FROM
sales
INNER JOIN
partner ON user_id = idpartner
WHERE
DATE_ADD(end_date, INTERVAL 5 DAY) >= DATE(NOW())
ORDER BY end_date ASC
LIMIT 0 , 50000
Said that, I wouldn't recommend applying functions such as DATE_ADD on columns, as it means that the database won't be able to use an index on end_date. Therefore, I would modify the query to:
SELECT
*
FROM
sales
INNER JOIN
partner ON user_id = idpartner
WHERE
end_date <= DATE_ADD(DATE(NOW()), INTERVAL 5 DAY)
ORDER BY end_date ASC
LIMIT 0 , 50000
As you can see, in the second alternative all functions are applied on constants and not on columns (end_date).
You can try
DATE_ADD() here is the
Link
Select DATE_ADD(DATE_FORMAT(NOW(),'%Y-%m-%d'),INTERVAL 1 DAY) FROM DUAL
I have a table name transactions where data rows are stored with a date
Like
`trans_id` `amount` `tdate`
I want to filter that data like last 30 days, last 31st 60 days, last 61-90 days calculate the overall amount also
My queries are
For last 30 days
SELECT SUM(amount) AS amt FROM transactions GROUP BY DATE(tdate) ORDER BY DATE(tdate) DESC LIMIT 30
Working fine and show SUM of amount (last 30days)
But for last 31-60 days not working
SELECT SUM(amount) AS amt FROM transactions GROUP BY DATE(tdate) ORDER BY DATE(tdate) DESC LIMIT 60,31
How to solve it ? I do want to include only 31 to 60 days amount only
Use the following: (It returns data between today and last 30 days)
SELECT DATE_FORMAT(DateCol, '%m/%d/%Y')
FROM Table
WHERE DateCol BETWEEN CURDATE() - INTERVAL
30 DAY AND CURDATE()
Or more precisely, this will do the trick:
DateCol BETWEEN (NOW() - INTERVAL 60 DAY)
AND (NOW() - INTERVAL 30 DAY)
CURDATE() works for only date portion. If you have DateTime column, then NOW() will do.
I have a group of currency quotations that change every hour or so. For the sql results in this particular example, I only need the last available record of each day of the last 30 days in yyyy-mm-dd format.
This is my current query:
SELECT value, DATE(date_quotation) as date_q
FROM quotation
GROUP BY DATE(date_quotation)
ORDER BY date_q DESC LIMIT 30
This is used for a histogram chart, where the x axis shows separated days. The quotations table has these columns:
id_quotation (INT)
date_quotation (DATETIME)
value (DECIMAL)
The problem is that it doesn't necessarily bring the last record of the day. It is grouping the records by day, but it should display the one with the highest hour/minute/second. Any ideas? Thanks!
You can leverage non-standard behavior of MySQL GROUP BY extension and do
SELECT DATE(date_quotation) date_q, value
FROM
(
SELECT value, date_quotation
FROM quotation
WHERE date_quotation >= CURDATE() - INTERVAL 30 DAY
AND date_quotation < CURDATE() + INTERVAL 1 DAY
ORDER BY date_quotation DESC
) q
GROUP BY DATE(date_quotation)
or you can do it by the book by selecting a max value of date_quotation per day (assuming that there is no duplicates) and then join back to quotation to pick up value
SELECT date_q, value
FROM
(
SELECT DATE(date_quotation) date_q, MAX(date_quotation) date_quotation
FROM quotation
WHERE date_quotation >= CURDATE() - INTERVAL 30 DAY
AND date_quotation < CURDATE() + INTERVAL 1 DAY
GROUP BY DATE(date_quotation)
) t JOIN quotation q
ON t.date_quotation = q.date_quotation
Note: that both queries use an index-friendly way to filter for date period. Make sure that you have an index on date_quotation column.
Here is SQLFiddle demo
I have a number of posts saved into a InnoDB table on MySQL. The table has the columns "id", "date", "user", "content". I wanted to make some statistic graphs, so I ended up using the following query to get the amount of posts per hour of yesterday:
SELECT HOUR(FROM_UNIXTIME(`date`)) AS `hour`, COUNT(date) from fb_posts
WHERE DATE(FROM_UNIXTIME(`date`)) = CURDATE() - INTERVAL 1 DAY GROUP BY hour
This outputs the following data:
I can edit this query to get any day I want. But what I want now is the AVERAGE of each hour of every day, so that if on Day 1 at 00 hours I have 20 posts and on Day 2 at 00 hours I have 40, I want the output to be "30". I'd like to be able to pick date periods as well if it's possible.
Thanks in advance!
You can use a sub-query to group the data by day/hour, then take the average by hour across the sub-query.
Here's an example to give you the average count by hour for the past 7 days:
select the_hour,avg(the_count)
from
(
select date(from_unixtime(`date`)) as the_day,
hour(from_unixtime(`date`)) as the_hour,
count(*) as the_count
from fb_posts
where `date` >= unix_timestamp(current_date() - interval 7 day)
and created_on < unix_timestamp(current_date())
group by the_day,the_hour
) s
group by the_hour
Aggregate the information by date and hour, and then take the average by hour:
select hour, avg(numposts)
from (SELECT date(`date`) as day, HOUR(FROM_UNIXTIME(`date`)) AS `hour`,
count(*) as numposts
from fb_posts
WHERE DATE(FROM_UNIXTIME(`date`)) between <date1> and <date2>
GROUP BY date(`date`), hour
) d
group by hour
order by 1
By the way, I prefer including the explicit order by, since most databases do not order the results of a group by. Mysql happens to be one database that does.
SELECT
HOUR(FROM_UNIXTIME(`date`)) AS `hour`
, COUNT(`id`) \ COUNT(DISTINCT TO_DAYS(`date`)) AS avgHourlyPostCount
FROM fb_posts
WHERE `date` > '2012-01-01' -- your optional date criteria
GROUP BY hour
This gives you a count of all the posts, divided by the number of days, by hour.