MySQL - group by new column - mysql

Question

I'm trying to group by a new columns here - one three counts.
It's a scenario where I want to see open, closed and plan orders for each date.
At the moment, with the code below I'm getting the results however I want to have a column with Main Date and count for each dates.
The results I am getting are as follows:
+------------+----------+------------+--------+------------+--------+
| Closed | ClosedNo | Open | OpenNo | Plan | PlanNo |
+------------+----------+------------+--------+------------+--------+
| NULL | 0 | NULL | 0 | 2018-10-22 | 3 |
| NULL | 0 | NULL | 0 | 2018-10-23 | 1 |
| NULL | 0 | NULL | 0 | 2018-10-24 | 1 |
| NULL | 0 | NULL | 0 | 2018-10-25 | 1 |
| NULL | 0 | 2018-10-25 | 1 | NULL | 0 |
| NULL | 0 | 2018-10-26 | 1 | NULL | 0 |
| NULL | 0 | 2018-10-27 | 2 | NULL | 0 |
| 2018-10-22 | 3 | NULL | 0 | NULL | 0 |
| 2018-10-23 | 1 | NULL | 0 | NULL | 0 |
| 2018-10-25 | 1 | NULL | 0 | NULL | 0 |
+------------+----------+------------+--------+------------+--------+
The desired results are:
Date ClosedNo OpenNo PlanNo
22/10/2018 3 3
23/10/2018 1 1
24/10/2018 1
25/10/2018 1 1 1
26/10/2018 1
27/10/2018 2
This is a code I use.
CREATE TABLE Orders
(Closed DATE,
Open DATE,
Plan DATE);
insert into Orders values ("2018-10-23",NULL,NULL);
insert into Orders values ("2018-10-22",NULL,NULL);
insert into Orders values ("2018-10-22",NULL,NULL);
insert into Orders values ("2018-10-22",NULL,NULL);
insert into Orders values (NULL,NULL,"2018-10-23");
insert into Orders values (NULL,NULL,"2018-10-22");
insert into Orders values (NULL,NULL,"2018-10-22");
insert into Orders values (NULL,NULL,"2018-10-22");
insert into Orders values (NULL,"2018-10-26",NULL);
insert into Orders values (NULL,"2018-10-27",NULL);
insert into Orders values (NULL,"2018-10-27",NULL);
insert into Orders values (NULL,"2018-10-25",NULL);
insert into Orders values (NULL,NULL,"2018-10-24");
insert into Orders values ("2018-10-25",NULL,NULL);
insert into Orders values (NULL,NULL,"2018-10-25");
SELECT
Closed
, COUNT(Closed) AS 'ClosedNo'
,Open
, COUNT(Open) AS 'OpenNo'
,Plan
, COUNT(Plan) AS 'PlanNo'
FROM
Orders
GROUP BY
Closed, Open, Plan;

Answer 1

Firstly, Open and Date are Keyword(s) in MySQL. You should really name your column to something else; or you will have to use backticks around it.
We can use Coalesce() function to get the Date. It will consider the first non-null value.
Using Count() aggregation function, we can count the non-null rows, for a Date group.
Try the following instead:
SELECT
COALESCE(Closed, `Open`, Plan) AS `Date`,
COUNT(Closed) AS ClosedNo,
COUNT(`Open`) AS OpenNo,
COUNT(Plan) AS PlanNo
FROM Orders
GROUP BY `Date`
RESULT
| Date | ClosedNo | OpenNo | PlanNo |
| ---------- | -------- | ------ | ------ |
| 2018-10-22 | 3 | 0 | 3 |
| 2018-10-23 | 1 | 0 | 1 |
| 2018-10-24 | 0 | 0 | 1 |
| 2018-10-25 | 1 | 1 | 1 |
| 2018-10-26 | 0 | 1 | 0 |
| 2018-10-27 | 0 | 2 | 0 |
View on DB Fiddle