I've been using Stack Overflow for years but this is the first time I've not been able to find the answer.
I'm attempting to build a query within MySQL using 4 tables
name, user, admin, actions
the actions table has actions_id, admin_id, user_id and action columns
the user table has user_id and name_id columns
the admin table has admin_id and name_id columns
the name table has name_id, first_name and _last_name columns
what I'd like to do is show the contents of actions replacing the user_id and admin_id with the first_name and last_name for the linking name_id via admin and user
you have to use join to relate all tables together
select t1.action,n.first_name as user_FirstName,n.last_name as user_LastName,
n1.first_name as adminFirstname,n1.last_name as AdminLastName from
(
select a.action,ad.name_id as adnameid,u.name_id as unameid from actions a inner join user u on a.user_id=u.user_id
inner join admin ad on a.admin_id =ad.admin_id
) as t1 inner join name n on t1.unameid =n.name_id
inner join name n1 on t1.adnameid=n1.name_id
Related
I have 3 tables :
Person table stores basic person wise details with ID as primary Key
This person can have relationships (father / mother etc), which are saved in Relationship table, however the users for them are created in Person table (e.g. ID = 2,3 in person table), This way we know that 2,3 are related to user 1 (carry).
We also have 3rd table - address, which store user ID wise addresses.(for both a user and his related persons, who are also users)
I want to find out if an address exists for either a user or for his related users in SQL. How to achieve this ?
You can combine two rules and search on the combined table as below
SELECT * FROM
(
SELECT username,id,Address.Address
FROM Person
INNER JOIN Address ON Person.id = Address.Userid
UNION ALL
SELECT username,id,Address.Address
FROM Person
INNER JOIN Relationship ON Relationship.Relatedid = Person.id
INNER JOIN Address ON Relationship.Userid = Address.Userid
) as RES
WHERE Address = 'xyz road'
Also you can find DBFiddle link to workout
Query:
select p.id,p.username,(case when a.userid is null then 'No' else 'Yes'end) IsAddressAvailable
from Person p
left join Address a on p.id=a.Userid
Output:
id
username
IsAddressAvailable
1
Carry
Yes
2
Carry-Father
No
3
Carry-Mother
Yes
db<fiddle here
I have three tables, chats, users and chat_user, where chat can have mutiple users and users can have multiple chats. I want to get the chat that is common to all the given user ids.
chats (id)
users (id)
chat_user (id, chat_id, user_id)
I want to get chat that belongs to user 1 and 5 or multiple user ids
Edit
I'm using Laravel framework, so it's better if there's a way to get the result through one of parent tables(users, chats).
But any help would be appreciated.
You may need to join the tables chats (the one that contains the informations you want) and the table chat_user (the one that contains the id of the chat and of the user) to apply where clause on the joined table.
In Laravel, I don't know.
SELECT c.*
FROM `chats` c
JOIN `chat_user` cu
ON c.id = cu.chat_id
WHERE cu.chat_id NOT IN (
SELECT cuu.chat_id
FROM chat_user cuu
WHERE cuu.user_id NOT IN (1, 5))
I am guessing that the userId will be an input parameter here? Try the query below:
SELECT
*
from
chats
WHERE
id in (
SELECT
chat_id
from
chat_user
WHERE
user_id = '1'
OR user_id = '5'
group by
chat_id
having
count(*) = 2
)
The count(*)=2 will ensure only those chats where both user 1 and 5 are present.
A user can have many interests.
An interest can be interested to many users.
My database looks like that:
Users table:
id - primary key,
name,
email,
Interests table:
id - primary key,
title
Users_To_Interests table:
id - primary key,
user_id(id from users table)
interest_id(id from interests table)
How can I improve Users_To_Interests table to be able to pick all users who have the same interest efficiently? user_id and interest_id columns don't have indexes or keys. If I need to add them, please show me how can I make that.
Edition 1: For example,
user1 has interests : interest1, interest2, interest3;
user2 has interests : interest3, interest4;
user3 has interests : interest3, interest5;
user4 has interests : interest4;
If I want to get all users who have interest1, I should receive user1;
If I want to get all users who have interest2, I should receive user1;
If I want to get all users who have interest3, I should receive user1, user2, user3;
The query to get users for interest #3 is very simple (use IN or EXISTS). With an index on users_to_interests(interest_id, user_id) this should be very fast.
select *
from users
where id in (select user_id from users_to_interests where interest_id = 3);
Here is a query which would find all users having interests 1 and 2. It should be clear how to generalize this to any number of interets. The subquery aggregates over users and finds those users who have the interests we want. We then join this back to the Users table to get the full information for each user.
SELECT
t1.*
FROM Users t1
INNER JOIN
(
SELECT ui.user_id
FROM Users_To_Interests ui
INNER JOIN Interests i
ON ui.interest_id = i.id
WHERE i.title IN ('interest2', 'interest3')
GROUP BY ui.user_id
HAVING COUNT(DISTINCT i.id) = 2
) t2
ON t1.id = t2.user_id;
i'm running into a complex problem, the data in a db has three tables.
First_DB
-- default_users
id username email password
1 Timbog Timbog#mail.com vads7y3kkjdfa
2 Marta Marta#mail.com vads7y3kkjdfa
-- default_album
album_id album_name default_user_id
1 Name_Tim 1
3 Katarina 2
-- default_album_img
img_id image_file album_id
3 1320229733.jpg 1
4 3320229733.jpg 3
Second_DB
--users
user_id user_name user_email user_pass user_image
1 Timbog Timbog#mail.com vads7y3kkjdfa 1320229733.jpg
2 Marta Marta#mail.com vads7y3kkjdfa 3320229733.jpg
The approach i used to solve this problem is to first fetch all data by inner join, should i use full outer join and insert the required field to my table, the following query is actual by which i'm trying to make it wor:
INSERT INTO bbpin.users ( user_name, user_pin, user_email, user_password, user_img)
SELECT default_users.username, default_users.bb_pin, default_users.email, default_users.password
FROM bbmpins_pins.default_users
INNER JOIN bbmpins_pins.default_album_images
ON default_album_images.album_id = default_users.id;
i miss the thing how do i compare two table's id in this join maybe? or this query is all wrong by approach?
By two tables which are sepearte in First_DB there could be multiple record how do we trunk them to last entry only ?
Thanks
It looks like you are attempting to retrieve all rows from the default_users table. And along with each row, also return the corresponding row(s) from default_album table. And along with that, the corresponding row(s) from default_album_img table.
Given the example data, a query using inner joins would return the specified result:
SELECT u.id AS user_id
, u.username AS user_name
, u.email AS user_email
, u.password AS user_pass
, i.image_file AS user_image
FROM default_users u
JOIN default_album a
ON a.default_user_id = u.id
JOIN default_album_img i
ON i.album_id = a.album_id
That query will work for the example data.
But, if there is a row in default_user which doesn't have a matching row in default_album, then an inner join won't return that row:
-- default_users
id username email password
3 branstark bran#winterfell warg2
Or, if there are two or more rows in default_album that match a given user, then the query will return two copies of the row from default_user...
-- default_album
album_id album_name default_user_id
1 Tim2 1
Without a specification of what is to be returned in those cases, we can't recommend a query.
I don't see anything wrong with your current approach using a JOIN but could modify it a bit to be more readable and also you will have to join the relation table
INSERT INTO bbpin.users (user_id, user_name, user_pin, user_email, user_password, user_img)
SELECT du.id,
du.username,
du.bb_pin,
du.email,
du.password,
dai.image_file
FROM bbmpins_pins.default_users du
JOIN bbmpins_pins.default_album da ON du.id = da.default_user_id
INNER JOIN bbmpins_pins.default_album_images dai
ON dai.album_id = da.album_id;
I have 2 tabes in my database:
users - userID(primary key), username, password
courses - id(primary key), name, text
subscriptions - id(primary key), curso_id, user_id
right in the subscription table I am writing the users UserID inside -> user_id with the id of the course for which he is subscribed curso_id so the results in the subscrption database are like
subscribtions table:
id user_id curso_id
1 12 1
2 5 1
3 12 2
4 6 7
this is the users table:
users table
userID username password
1 user1 passw1
2
3
4
and this is the courses table:
course table:
id course_name descriotion
1 course one text
2
3
My question is how to make a sql Query which first select the course by $row['id'] which indicates the id variable from the courses database, and after that based on the 3th table subscription to list all the users which are subscribed to this course number. ?
and second question is how to list number of the subscribed users for a course selected by
$row['id']
Here is some kind of the alghorytm logic that I have right now
SELECT * FROM users WHERE id=5.courses(select from the database 'courses') AND 5-> SELECT ALL FROM table subscriptions user_id equal to id from table users
Not sure if I understood what you try to achieve, but if you want a list that shows you every user in every course with the name of the course and ordered by course name, this should make the deal.
select t1.*, t2.*, t3.* from users as t1, courses as t2, subscriptions as t3 where t3.user_id = t1.userID and t3.curso_id = t2.id order by t2.id
Not the nicest way to do this and from a performance aspect I would recommend to put this in several statements as joins are usually slow.
okay I found the way and here is the mysql query:
FROM users
INNER JOIN subscriptions
ON users.userID = subscriptions.user_id
WHERE subscriptions.curso_id = $ids"