How to Remove Whole Index of List in a JSON - mysql

Question

I have a JSON Values Like This.
{
"CHEQUE":[
{
"Cheque_No":"1",
"Cheque_Date":"2018-05-30",
"Cheque_Amount":"10000",
"Bank_Name":"ICICI"
},
{
"Cheque_No":"2",
"Cheque_Date":"2018-05-30",
"Cheque_Amount":"20000",
"Bank_Name":"ICICI"
},
{
"Cheque_No":"2",
"Cheque_Date":"2018-05-30",
"Cheque_Amount":"20000",
"Bank_Name":"SBI"
}
]
}'
How can i Remove Entire Index of 2 in a CHEQUE list using the search key SBI for Bank name?.
I need to Do this is in Mysql Stored Procedure without Store Values in DB. This is what I have tried:
CREATE DEFINER = root # PROCEDURE SP_TEST(
IN ls_json JSON,
OUT Message VARCHAR(1000)
)
BEGIN
SELECT
JSON_REMOVE(
ls_json,
CONCAT('$.CHEQUE[0].Bank_Name[0]')
)
INTO ls_json;
#SELECT JSON_REMOVE(ls_json,JSON_SEARCH(ls_json,'ALL',
CONCAT('$.CHEQUE[0].Cheque_No[*]')))
INTO ls_json; #select
JSON_SEARCH(ls_json, 'one', 10000);
SELECT
ls_json;
END

Answer 1

One option:
DELIMITER //
CREATE PROCEDURE `SP_TEST` (
IN `_ls_json` JSON,
IN `_bank_name` VARCHAR(64)
)
BEGIN
DECLARE `_base` CHAR(11) DEFAULT '$.CHEQUE[*]';
DECLARE `_base_attr` CHAR(10) DEFAULT '.Bank_Name';
DECLARE `_element` VARCHAR(1024);
`_loop`: LOOP
SET `_element` :=
JSON_SEARCH(
`_ls_json`,
'one',
`_bank_name`,
NULL,
CONCAT(`_base`, `_base_attr`)
);
IF (`_element` IS NOT NULL) THEN
SET `_ls_json` :=
JSON_REMOVE(
`_ls_json`,
JSON_UNQUOTE(
REPLACE(`_element`, `_base_attr`, '')
)
);
ELSE
LEAVE `_loop`;
END IF;
END LOOP `_loop`;
SELECT JSON_PRETTY(`_ls_json`);
END//
DELIMITER ;
See db-fiddle.