I have a table with lunch effective date and its rate.
I need to display rate from its nearest lesser effective date (created_on) for each date column.
lunch_rate table:
created_on | rate
-----------+-------
2018-06-01 | 30
2018-06-04 | 60
Here's what I tried to do:
SELECT userId,
SUM(CASE WHEN date= '2018-06-01' AND lunchStatus = 1 THEN (SELECT MAX(rate) FROM lunch_rate WHERE DATE(created_on) <= date LIMIT 1) ELSE 0 END) '2018-06-01',
SUM(CASE WHEN date= '2018-06-02' AND lunchStatus = 1 THEN (SELECT MAX(rate) FROM lunch_rate WHERE DATE(created_on) <= date LIMIT 1) ELSE 0 END) '2018-06-02',
SUM(CASE WHEN date= '2018-06-03' AND lunchStatus = 1 THEN (SELECT MAX(rate) FROM lunch_rate WHERE DATE(created_on) <= date LIMIT 1) ELSE 0 END) '2018-06-03',
SUM(CASE WHEN date= '2018-06-04' AND lunchStatus = 1 THEN (SELECT MAX(rate) FROM lunch_rate WHERE DATE(created_on) <= date LIMIT 1) ELSE 0 END) '2018-06-04'
FROM
(
SELECT userId, lunchStatus, DATE(issuedDateTime) as date
FROM `lunch_status`
WHERE DATE(issuedDateTime) BETWEEN '2018-06-01' AND '2018-06-04'
) as a
GROUP BY userId;
But this query only gives maximum rate of all, without considering the nearest effective date.
Here's the outcome:
userId | 2018-06-01 | 2018-06-02 | 2018-06-03 | 2018-06-04
------------------------------------------------------------------------
131 | 60 | 60 | 0 | 60
132 | 60 | 60 | 60 | 0
133 | 0 | 0 | 0 | 60
134 | 0 | 0 | 0 | 60
Expected outcome:
userId | 2018-06-01 | 2018-06-02 | 2018-06-03 | 2018-06-04
------------------------------------------------------------------------
131 | 30 | 30 | 0 | 60
132 | 30 | 30 | 30 | 0
133 | 0 | 0 | 0 | 60
134 | 0 | 0 | 0 | 60
SUM(CASE WHEN ... THEN (SELECT MAX(rate) FROM lunch_rate WHERE DATE(created_on) <= date LIMIT 1) ELSE 0 END) ....',
How can I select lunch rate that was effective on that date?
If I understand correctly, you want the calculation in the subquery:
SELECT userId,
SUM(CASE WHEN date = '2018-06-01' AND lunchStatus = 1
THEN rate ELSE 0
END) as `2018-06-01`,
SUM(CASE WHEN date = '2018-06-02' AND lunchStatus = 1
THEN rate ELSE 0
END) as `2018-06-02`,
SUM(CASE WHEN date = '2018-06-03' AND lunchStatus = 1
THEN rate ELSE 0
END) as `2018-06-03`,
SUM(CASE WHEN date = '2018-06-04' AND lunchStatus = 1
THEN rate ELSE 0
END) as `2018-06-04`
FROM (SELECT ls.*, DATE(ls.issuedDateTime) as date
(SELECT lr.rate
FROM lunch_rate lr
WHERE DATE(lr.created_on) <= DATE(ls.issuedDateTime)
ORDER BY lr.created_on DESC
LIMIT 1
) as rate
FROM lunch_status ls
WHERE DATE(issuedDateTime) BETWEEN '2018-06-01' AND '2018-06-04'
) lr
GROUP BY lr.userId;
Note the other changes:
The subquery for lunch_rate does not use MAX(). Instead, it uses ORDER BY.
The column aliases are surrounded by backticks, not single quotes. I don't approve of the names (because they need to be escaped). But if you want them, use proper escape characters.
The tables are given reasonable aliases and column names are qualified.
You could try something like this:
SELECT lr1.rate
FROM lunch_rate lr1
WHERE lr1.created_on <= my_date
AND NOT EXISTS (SELECT *
FROM lunch_rate lr2
WHERE lr2.created_on > lr1.created_on
AND lr2.created_on <= my_date);
Related
I have this table: "sales"
+-------------+---------+
| date | total |
+-------------+---------+
| 2018-12-04 | 269.10 |
| 2018-12-05 | 29.00 |
| 2018-12-06 | 107.10 |
| 2018-12-06 | 34.00 |
| 2018-12-08 | 69.50 |
| 2018-12-08 | 223.00 |
| 2018-12-08 | 68.00 |
| 2018-12-09 | 99.00 |
| 2018-12-10 | 59.50 |
| ... | ... |
+-------------+---------+
I'm trying this query
SELECT DAY(date) AS Days,
SUM(CASE WHEN MONTH(date) = 12 THEN total ELSE NULL END) AS December
FROM sales WHERE YEAR(date) = 2018 GROUP BY date
And I get
+-------+----------+
| Days | December |
+-------+----------+
| 4 | 269.10 |
| 5 | 29.00 |
| 6 | 141.10 |
| 8 | 360.50 |
| 9 | 99.00 |
| 10 | 59.50 |
| ... | ... |
+-------+----------+
But I want consecutive days like this:
+-------+----------+
| Days | December |
+-------+----------+
| 1 | NULL |
| 2 | NULL |
| 3 | NULL |
| 4 | 269.10 |
| 5 | 29.00 |
| 6 | 141.10 |
| 7 | NULL |
| 8 | 360.50 |
| 9 | 99.00 |
| 10 | 59.50 |
| ... | ... |
| 31 | 123.00 |
+-------+----------+
Can you help me plss..
PS: I have several months and years in "date" column from "sales" table.
This recursive CTE generates a list of dates corresponding to the month and year specified in the doi CTE, and then LEFT JOINs that to the sales table to get the sales for that month. It will work for any month/year, just change the values in the doi CTE, and the title of the SUM column (currently December) to suit.
WITH RECURSIVE doi AS (
SELECT 12 AS month,
2018 AS year
),
cte AS (
SELECT DATE(CONCAT_WS('-', year, month, 1)) AS date
FROM doi
UNION ALL
SELECT date + INTERVAL 1 DAY
FROM cte
WHERE date < LAST_DAY(date)
)
SELECT DAY(cte.date) AS Days,
ROUND(SUM(s.total),2) AS December
FROM cte
LEFT JOIN sales s ON s.date = cte.date
GROUP BY cte.date
ORDER BY cte.date
Output is too long to show here but can be seen at this demo on dbfiddle
Update
To expand this query to cover an entire year requires changing the approach slightly in terms of generating an entire year's worth of dates, and then using conditional aggregation to get the sums for each day of each month:
WITH RECURSIVE doi AS (
SELECT 2018 AS year
),
cte AS (
SELECT DATE(CONCAT_WS('-', year, 1, 1)) AS date
FROM doi
UNION ALL
SELECT date + INTERVAL 1 DAY
FROM cte
CROSS JOIN doi
WHERE date < DATE(CONCAT_WS('-', doi.year, 12, 31))
)
SELECT DAY(cte.date) AS Days,
ROUND(SUM(CASE WHEN MONTH(s.date) = 1 THEN s.total END),2) AS January,
ROUND(SUM(CASE WHEN MONTH(s.date) = 2 THEN s.total END),2) AS February,
ROUND(SUM(CASE WHEN MONTH(s.date) = 3 THEN s.total END),2) AS March,
ROUND(SUM(CASE WHEN MONTH(s.date) = 4 THEN s.total END),2) AS April,
ROUND(SUM(CASE WHEN MONTH(s.date) = 5 THEN s.total END),2) AS May,
ROUND(SUM(CASE WHEN MONTH(s.date) = 6 THEN s.total END),2) AS June,
ROUND(SUM(CASE WHEN MONTH(s.date) = 7 THEN s.total END),2) AS July,
ROUND(SUM(CASE WHEN MONTH(s.date) = 8 THEN s.total END),2) AS August,
ROUND(SUM(CASE WHEN MONTH(s.date) = 9 THEN s.total END),2) AS September,
ROUND(SUM(CASE WHEN MONTH(s.date) = 10 THEN s.total END),2) AS October,
ROUND(SUM(CASE WHEN MONTH(s.date) = 11 THEN s.total END),2) AS November,
ROUND(SUM(CASE WHEN MONTH(s.date) = 12 THEN s.total END),2) AS December
FROM cte
LEFT JOIN sales s ON s.date = cte.date
GROUP BY DAY(cte.date)
ORDER BY DAY(cte.date)
Demo on dbfiddle
generate your months using union and do right join
select t1.d as Days
, sum(iif(month(date) = 12, total, null) as December
from sales
right join (select 1 as d
union select 2 union select 3 union select 4 union select 5 union select 6
union select 7 union select 8 union select 9 union select 10 union select 11
.... ) as t1 on t1.d = day(date)
where year(date) = 2012
group by date
if you are using mysql v8.0, you can use recursive queries.
with recursive cte as(
select 1 as d
union all
select d + 1 from cte where d < day(last_day('2019-12-01'))
)
select coalesce(day(s.date), t1.d) as Days
, sum(iif(month(s.date) = 12, total, null) as December
from sales s
right join cte as t1 on t1.d = day(s.date)
where year(date) = 2012
group by coalesce(day(s.date), t1.d)
My source table (wplott_wpkl_winner) contains the field "lottery_number" that carries 1 to 6 digit numbers and the corresponding "draw_date".
lottery_number | draw_date
==================================
0024 | 2018-11-10
4456 | 2018-11-10
3895 | 2018-11-10
4557 | 2018-11-10
4225 | 2018-11-10
2896 | 2018-11-10
3354 | 2018-11-10
1895 | 2018-11-10
78466 | 2018-11-10
998556 | 2018-11-10
My current MYSQL query is as below (I am trying to group the data into ranges)
select
count(case when wplott_wpkl_winner.lottery_number between 0 and 999 then 1 end) `0-999`,
count(case when wplott_wpkl_winner.lottery_number between 1000 and 1999 then 1 end) `1000-1999`,
count(case when wplott_wpkl_winner.lottery_number between 2000 and 2999 then 1 end) `2000-2999`,
count(case when wplott_wpkl_winner.lottery_number between 3000 and 3999 then 1 end) `3000-3999`,
count(case when wplott_wpkl_winner.lottery_number between 4000 and 4999 then 1 end) `4000-4999`,
count(case when wplott_wpkl_winner.lottery_number between 5000 and 5999 then 1 end) `5000-5999`,
count(case when wplott_wpkl_winner.lottery_number between 6000 and 6999 then 1 end) `6000-6999`,
count(case when wplott_wpkl_winner.lottery_number between 7000 and 7999 then 1 end) `7000-7999`,
count(case when wplott_wpkl_winner.lottery_number between 8000 and 8999 then 1 end) `8000-8999`,
count(case when wplott_wpkl_winner.lottery_number between 9000 and 9999 then 1 end) `9000-9999`
from wplott_wpkl_winner
where CHAR_LENGTH(wplott_wpkl_winner.lottery_number) = 4 AND wplott_wpkl_winner.draw_date > '2013-06-30'
It provides the below output
0-999 | 1000-1999 | 2000-2999 | 3000-3999 | 4000- 4999 .... etc
=====================================================================
1 | 1 | 1 | 2 | 3
However, I would like to get the output in the below format.
Range | Count
=======================
0-999 | 1
1000-1999 | 1
2000-2999 | 1
3000-3999 | 2
4000-4999 | 3
.
.
.
Any help is highly appreciated. I did search in SO for a similar answer but none of the answers helped my particular case.
Thanks in advance!
One approach uses a series of unions:
SELECT
`range`,
count
FROM
(
SELECT 1 AS pos, '0-999' AS `range`, COUNT(*) AS count
FROM wplott_wpkl_winner
WHERE draw_date > '2013-06-30' AND lottery_number BETWEEN 0 AND 999
UNION ALL
SELECT 2, '1000-1999', COUNT(*)
FROM wplott_wpkl_winner
WHERE draw_date > '2013-06-30' AND lottery_number BETWEEN 1000 AND 1999
UNION ALL
... -- fill in remaining ranges here
) t
ORDER BY pos;
Note that I introduce a computed column pos so that we may maintain the desired ordering of the ranges in the final output. Also, I removed the check on the CHAR_LENGTH of the lottery_number, since the conditional sums already handle this logic.
I am trying to learn SQL and am wondering how to write this query for multiple dates. I tried using CASE but it is not outputting the correct totals. This query works.
I am trying to total the dailyrate for each reservation which is the effectively the daily sales.
SELECT SUM(dailyrate) AS 1June
FROM reservations
WHERE start_date < '2018-06-02' AND end_date > '2018-06-01';
This was my attempt using CASE but it does not produce the correct totals.
select dailyrate,
sum(case when start_date < '2018-06-02' AND end_date > '2018-06-01' then 1 else 0 end) as 1june,
sum(case when start_date < '2018-06-03' AND end_date > '2018-06-02' then 1 else 0 end) as 2june,
sum(case when start_date < '2018-06-04' AND end_date > '2018-06-03' then 1 else 0 end) as 3june
FROM reservations;
+------------------+------------------+----------+-
| start_date | end_date | dailyrate |
+------------------+------------------+----------+--
| 2018-06-01 05:00 | 2018-06-01 15:00 | 22 |
| 2018-05-21 05:00 | 2018-06-04 19:00 | 11.5 |
| 2018-06-01 15:00 | 2018-06-07 05:00 | 24 |
| 2018-06-03 05:00 | 2018-06-02 22:00 | 9.5 |
| 2018-05-21 12:00 | 2018-06-11 05:00 | 31 |
+------------------+------------------+----------+-
Are you looking for the COUNT of each daily_rate on each day?
If so, this may be the query you're after:
SELECT dailyrate,
COUNT(CASE WHEN start_date < '2018-06-02' AND end_date > '2018-06-01' THEN 1 ELSE 0 end) AS 1june,
COUNT(CASE WHEN start_date < '2018-06-03' AND end_date > '2018-06-02' THEN 1 ELSE 0 end) AS 2june,
COUNT(CASE WHEN start_date < '2018-06-04' AND end_date > '2018-06-03' THEN 1 ELSE 0 end) AS 3june
FROM reservations
GROUP BY dailyrate;
If you're looking for the SUM of the daily rates for each table, then this query may work for you:
SELECT dailyrate,
SUM(CASE WHEN start_date < '2018-06-02' AND end_date > '2018-06-01' THEN dailyrate ELSE 0 end) AS 1june,
SUM(CASE WHEN start_date < '2018-06-03' AND end_date > '2018-06-02' THEN dailyrate ELSE 0 end) AS 2june,
SUM(CASE WHEN start_date < '2018-06-04' AND end_date > '2018-06-03' THEN dailyrate ELSE 0 end) AS 3june
SUM reservations
GROUP BY dailyrate;
I think you were missing the GROUP BY, as both the SUM and COUNT functions are aggregate functions and need a GROUP BY to show the correct data.
I have table assessment as given below-
SLNO EID Period_From Period_To
1 101 2017-06-01 2017-11-14
2 102 2017-07-01 2017-09-30
3 103 2017-05-01 2017-07-31
If Period_To and currentdate is equal to 75 days then row should return 1 else 0 I used below query-
SELECT SLNO,EID, Period_From,Period_To,(CASE WHEN (PERIOD_TO = (select DATE_ADD(PERIOD_TO,INTERVAL 75 DAY))) THEN 1 ELSE 0 END) AS ASSESSMENT_ENABLE from assessment;
I got result as
SLNO EID Period_From Period_To ASSESSMENT_ENABLE
1 101 2017-06-01 2017-11-14 0
2 102 2017-07-01 2017-09-30 0
3 103 2017-05-01 2017-07-31 0
I am getting wrong result. Please help me.
i don't think you need sub query. try this it works for me
SELECT SLNO,EID, Period_From,Period_To,
(CASE WHEN (PERIOD_TO = DATE_FORMAT(CURDATE(), '%Y-%m-%d') - INTERVAL 75 DAY) THEN 1 ELSE 0 END)
AS ASSESSMENT_ENABLE
Short solution using CURRENT_DATE and DATEDIFF functions:
SELECT
SLNO, EID, Period_From, Period_To,
IF(DATEDIFF(CURRENT_DATE(), date_to) = 75, 1, 0) AS ASSESSMENT_ENABLE
FROM
ASSESSMENT
https://dev.mysql.com/doc/refman/5.7/en/date-and-time-functions.html
You can try this-
select
SLNO,
EID,
Period_From,
Period_To,
case when (DATEDIFF(now(),PERIOD_TO)=75) then 1 else 0 end as ASSESSMENT_ENABLE
from
assessment;
I would like to get results based on SUM from table (history), where username contains 'red' and grouped by month. here the query :
select month(date),
SUM(CASE WHEN status='success' THEN 1 ELSE 0 END) as total_sucess,
SUM(CASE WHEN status='failed' THEN 1 ELSE 0 END) as total_failed
from history
where date between '201305%' AND '201311%' AND username like '%#red%'
GROUP BY month(history.date);
the results :
+------------+--------------+--------------+
| month(date) | total_sucess | total_failed |
+------------+--------------+--------------+
| 5 | 10960 | 3573 |
| 6 | 2336 | 1202 |
| 7 | 2211 | 1830 |
| 8 | 5312 | 3125 |
| 9 | 9844 | 5407 |
| 10 | 6351 | 3972 |
+------------+--------------+--------------+
the question is , how do I get distinct total_success and total_failed SUM? just in one query ?
I've tried using this
select month(tgl),
SUM(CASE WHEN status='success' THEN 1 ELSE 0 END) as total_sucess,
SUM(DISTINCT (username) CASE WHEN status='success' THEN 1 ELSE 0 END) as distinct_total_sucess,
SUM(CASE WHEN status='failed' THEN 1 ELSE 0 END) as total_failed,
SUM(DISTINCT (username) CASE WHEN status='failed' THEN 1 ELSE 0 END) as distinct_failed_sucess
from history_auth
where tgl between '201305%' AND '201311%' AND username like '%#t.sel%'
GROUP BY month(history_auth.tgl);
but get error sql syntax... i have no idea with this :(
Best I can make out of your requirement is that you want the number of distinct usernames each month that succeeded / failed.
If so I think you need a pair of sub selects to get those figures.
Rejigged the query (adding another sub select to get the 6 months, rather than relying on all months being represented.
SELECT Sub1.aMonth,
SUM(CASE WHEN history.status='success' THEN 1 ELSE 0 END) as total_sucess,
SUM(CASE WHEN history.status='failed' THEN 1 ELSE 0 END) as total_failed,
IFNULL(SuccessCount, 0),
IFNULL(FailedCount, 0)
FROM
(
SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 0 MONTH)) AS aMonth
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 1 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 2 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 3 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 4 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 5 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 6 MONTH))
) Sub1
LEFT OUTER JOIN history
ON MONTH(history.date) = Sub1.aMonth
AND username LIKE '%#red%'
LEFT OUTER JOIN
(
SELECT MONTH(date) AS aMonth, COUNT(DISTINCT username) AS SuccessCount
FROM history
WHERE status='success'
AND username LIKE '%#red%'
GROUP BY MONTH(date)
) Sub2
ON Sub1.aMonth = Sub2.aMonth
LEFT OUTER JOIN
(
SELECT MONTH(date) AS aMonth, COUNT(DISTINCT username) AS FailedCount
FROM history
WHERE status='failed'
AND username LIKE '%#red%'
GROUP BY MONTH(date)
) Sub3
ON Sub1.aMonth = Sub3.aMonth
GROUP BY Sub1.aMonth, SuccessCount, FailedCount