SUM DISTINCT MYSQL | WHERE CLAUSE - mysql

Question

I would like to get results based on SUM from table (history), where username contains 'red' and grouped by month. here the query :
select month(date),
SUM(CASE WHEN status='success' THEN 1 ELSE 0 END) as total_sucess,
SUM(CASE WHEN status='failed' THEN 1 ELSE 0 END) as total_failed
from history
where date between '201305%' AND '201311%' AND username like '%#red%'
GROUP BY month(history.date);
the results :
+------------+--------------+--------------+
| month(date) | total_sucess | total_failed |
+------------+--------------+--------------+
| 5 | 10960 | 3573 |
| 6 | 2336 | 1202 |
| 7 | 2211 | 1830 |
| 8 | 5312 | 3125 |
| 9 | 9844 | 5407 |
| 10 | 6351 | 3972 |
+------------+--------------+--------------+
the question is , how do I get distinct total_success and total_failed SUM? just in one query ?
I've tried using this
select month(tgl),
SUM(CASE WHEN status='success' THEN 1 ELSE 0 END) as total_sucess,
SUM(DISTINCT (username) CASE WHEN status='success' THEN 1 ELSE 0 END) as distinct_total_sucess,
SUM(CASE WHEN status='failed' THEN 1 ELSE 0 END) as total_failed,
SUM(DISTINCT (username) CASE WHEN status='failed' THEN 1 ELSE 0 END) as distinct_failed_sucess
from history_auth
where tgl between '201305%' AND '201311%' AND username like '%#t.sel%'
GROUP BY month(history_auth.tgl);
but get error sql syntax... i have no idea with this :(

Answer 1

Best I can make out of your requirement is that you want the number of distinct usernames each month that succeeded / failed.
If so I think you need a pair of sub selects to get those figures.
Rejigged the query (adding another sub select to get the 6 months, rather than relying on all months being represented.
SELECT Sub1.aMonth,
SUM(CASE WHEN history.status='success' THEN 1 ELSE 0 END) as total_sucess,
SUM(CASE WHEN history.status='failed' THEN 1 ELSE 0 END) as total_failed,
IFNULL(SuccessCount, 0),
IFNULL(FailedCount, 0)
FROM
(
SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 0 MONTH)) AS aMonth
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 1 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 2 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 3 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 4 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 5 MONTH))
UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 6 MONTH))
) Sub1
LEFT OUTER JOIN history
ON MONTH(history.date) = Sub1.aMonth
AND username LIKE '%#red%'
LEFT OUTER JOIN
(
SELECT MONTH(date) AS aMonth, COUNT(DISTINCT username) AS SuccessCount
FROM history
WHERE status='success'
AND username LIKE '%#red%'
GROUP BY MONTH(date)
) Sub2
ON Sub1.aMonth = Sub2.aMonth
LEFT OUTER JOIN
(
SELECT MONTH(date) AS aMonth, COUNT(DISTINCT username) AS FailedCount
FROM history
WHERE status='failed'
AND username LIKE '%#red%'
GROUP BY MONTH(date)
) Sub3
ON Sub1.aMonth = Sub3.aMonth
GROUP BY Sub1.aMonth, SuccessCount, FailedCount