How to write a Laravel query to group duplicate records - mysql

Question

This is my current query getting data from tables corporations, jobs, corp_networks and candidates.
$sqlCandSkills = DB::table('corporations')
->join('jobs', 'corporations.corp_id', '=', 'jobs.corp_id')
->join('corp_logos', 'corp_logos.corp_id', '=', 'corporations.corp_id')
->join('candidates', 'corporations.corp_id', '=', 'candidates.corp_id')
->join('corp_networks', 'corporations.corp_id', '=', 'corp_networks.participation_corp_id')
->where([
'corp_networks.owning_corp_id' => $this->corp->corp_id,
'corp_networks.status' => "Accepted"
])
->orwhere([
'corporations.corp_id' => $this->corp->corp_id
])
->where('candidates.is_available', '=', 0)->get();
I need to add a validation query into this because I'm getting multiple rows of same data from above query.
for($i=0 ; $i<sizeof($skillsArray); $i++){
$value= $skillsArray[$i];
echo($value);
$jobDetails = DB::select(
'SELECT * FROM jobs WHERE job_technical_requirements LIKE "%'.$value.'%" AND job_status = 1 INNER JOIN '
);
}
Above query gives all data but I also need to perform above checks.
I'm doing this second query to compare array of values to a csv values in column.
Now I need to achieve all this into a single result.
I need ways to do it either in sql query or laravel query.

Answer 1

you can use groupBy
$sqlCandSkills = DB::table('corporations')
->distinct()
->join('candidates', 'corporations.corp_id', '=', 'candidates.corp_id')
->join('corp_networks', 'corporations.corp_id', '=', 'corp_networks.participation_corp_id')
->where([
'corp_networks.owning_corp_id' => $this->corp->corp_id,
'corp_networks.status' => "Accepted"
])
->orwhere([
'corporations.corp_id' => $this->corp->corp_id
])
->where('candidates.is_available', '=', 0)
->groupBy(array(
'corporations.corp_id',
'corp_networks.participation_corp_id',
'corp_networks.owning_corp_id'
))
->get('corporations.corp_id');