i have setup a DB and what i want is the following:
In Table a i got the users with infos and his points
In Table b i got more infos about each user and his "level"
in Table c i got basic settings
in Table d i got detailed infos about the levels each user can have
What i would like to do is:
either INSERT ON DUPLICATE KEY UPDATE or IF EXISTS UPDATE (insert would be my fav)
I would like to do the query with multiple users at once (by their id)
The problem right now is how do i get the VALUE into the SELECT Statement ?
My Code so far:
INSERT INTO users (id) VALUES ('12345')
ON DUPLICATE KEY UPDATE
points = (points + (
SELECT (d.multiplier * c.base_points)
FROM b
INNER JOIN d ON b.level = d.id , c
WHERE b.level = d.id AND b.id = '12345'));
i now want to change:
WHERE
b.level = d.id AND
b.id = '12345'));
so that i can use VALUES(id) - but when i do that i get NULL as result
WHERE
b.level = d.id AND
b.id = VALUES(id)));
:(
How can i use the id i have ?
regards
I'm trying to pull from multiple tables to insert into a table to create role assignments in moodle's database based on the categories that are created but I need it to update on duplicate key but I cant use ON DUPLICATE KEY UPDATE because the fields im trying to match on role id, context id, and user id are not primary keys in the mdl_role_assignments table.
insert into vclassmoodle.mdl_role_assignments (roleid,contextid,userid,timemodified,modifierid,itemid,sortorder) select
mdl_role.id as roleid, mdl_context.id as contextid, mdl_user.id as userid, unix_timestamp() as timemodified, 3 as modifierid, 0 as itemid, 0 as sortorder
from
mdl_context
left join
mdl_course_categories ON mdl_context.instanceid = mdl_course_categories.id
left join
mdl_user ON mdl_course_categories.idnumber = mdl_user.idnumber
join
mdl_role ON mdl_role.shortname = 'manager'
where mdl_context.contextlevel = 40 and mdl_course_categories.depth > 1
Let me know if I need to clarify on anything
Thanks
Just been having a look at the function role_assign() in /lib/accesslib.php
If there is a duplicate then it doesn't update, so you could just ignore duplicates.
Although you should really use the role_assign() function rather than insert data directly. In case the role assignment changes in the future, but also because it triggers a role_assigned event which might be used elsewhere.
Still use your query but ignore existing records and create a loop to call role_assign(), something like this
SELECT mdl_role.id as roleid,
mdl_context.id as contextid,
mdl_user.id as userid
FROM mdl_context
JOIN mdl_course_categories ON mdl_context.instanceid = mdl_course_categories.id
JOIN mdl_user ON mdl_course_categories.idnumber = mdl_user.idnumber
JOIN mdl_role ON mdl_role.shortname = 'manager'
WHERE mdl_context.contextlevel = 40
AND mdl_course_categories.depth > 1
AND NOT EXISTS (
SELECT mdl_role_assignments.id
FROM mdl_role_assignments
WHERE mdl_role_assignments.roleid = mdl_role.id
AND mdl_role_assignments.contextid = mdl_context.id
AND mdl_role_assignments.userid = mdl_user.id
AND mdl_role_assignments.itemid = 0
AND mdl_role_assignments.component = '')
Note that a duplicate is a combination of roleid, userid and contextid but also component and itemid. So component = '' needs to be checked too.
I am creating a view for my Database , I am joing 3 tables, Users,personal_info and contact_info, if you notice I have a lot of column names in my Select statement , since i don't want to include primary keys but it seems I have an error here, take a look
CREATE VIEW `payroll`.`new_view` AS
Select employee_id,employee_password,First_Name,Middle_Initial,
Last_Name,Date_Of_Birth,Beneficiaries,Home_Number,Address,Mobile_Number,Email_Address
From USER
LEFT JOIN personal_info on idUser = idPersonal_Info,
FULL JOIN contact_info on idUser = idContact_Info
The error is
ERROR 1146: Table 'payroll.full' doesn't exist
SQL Statement:
CREATE OR REPLACE VIEW `payroll`.`new_view` AS
Select employee_id,employee_password,First_Name,Middle_Initial,
Last_Name,Date_Of_Birth,Beneficiaries,Home_Number,Address,Mobile_Number,Email_Address
From USER
LEFT JOIN personal_info on idUser = idPersonal_Info,
FULL JOIN contact_info on idUser = idContact_Info
quote it with backtics: payroll.new_view
CREATE VIEW `payroll.new_view`
Error on:
LEFT JOIN personal_info on idUser = idPersonal_Info
you need to specify which column on which table equals which one on the other table, like
SELECT a,b,c from table1
LEFT JOIN table2
on table1.a= table2.columnY
in your case:
on USER.idUser = Personal_Info.idPersonalInfo
and the same for the 3rd Join
Another thing is the Comma at the end of the line:
LEFT JOIN personal_info on idUser = idPersonal_Info ,
it doesnt belong there.
I have consolidated a joined table with it's related entity as the relationship was one-to-one.
So now the original ww_staff table holds the ww_contacts details directly.
I wrote the following statement based on what I think is logical from MySQL's perspective
but - its not happy.
Can anyone see a similar solution or a blatent transgression?
INSERT INTO
ww_staff s
(phone, mobile, email, skype)
VALUES
(
SELECT w.phone, w.mobile, w.email, w.skype
FROM ww_contacts w
JOIN ww_staff s
ON s.staff_ID = w.contacts_ID
);
Just remove the VALUES()
INSERT INTO ww_staff s (phone, mobile, email, skype)
SELECT w.phone, w.mobile, w.email, w.skype FROM ww_contacts w
JOIN ww_staff s
ON s.staff_ID = w.contacts_ID;
--UPDATE
Since you are selecting from ww_contacts w JOIN ww_staff - all the records are there already - and you do not want to insert duplicates, use a update with a join:
UPDATE ww_staff s JOIN ww_contacts w ON s.staff_ID = w.contacts_ID
SET s.phone = w.phone, s.mobile = w.mobile, s.email = w.email, s.skype = w.skype;
Next time please explain more in your question what you are trying to do.
You need to do an INSERT ... SELECT ... ON DUPLICATE KEY UPDATE statement. This will insert new rows and update existing ones:
INSERT INTO
ww_staff
(staff_ID, phone, mobile, email, skype)
SELECT w.contacts_ID, w.phone, w.mobile, w.email, w.skype
FROM ww_contacts w
JOIN ww_staff s
ON s.staff_ID = w.contacts_ID
ON DUPLICATE KEY UPDATE
ww_staff.phone = w.phone, ww_staff.mobile = w.mobile, ww_staff.email = w.email, ww_staff.skype = w.skype
I need to check (from the same table) if there is an association between two events based on date-time.
One set of data will contain the ending date-time of certain events and the other set of data will contain the starting date-time for other events.
If the first event completes before the second event then I would like to link them up.
What I have so far is:
SELECT name as name_A, date-time as end_DTS, id as id_A
FROM tableA WHERE criteria = 1
SELECT name as name_B, date-time as start_DTS, id as id_B
FROM tableA WHERE criteria = 2
Then I join them:
SELECT name_A, name_B, id_A, id_B,
if(start_DTS > end_DTS,'VALID','') as validation_check
FROM tableA
LEFT JOIN tableB ON name_A = name_B
Can I then, based on my validation_check field, run a UPDATE query with the SELECT nested?
You can actually do this one of two ways:
MySQL update join syntax:
UPDATE tableA a
INNER JOIN tableB b ON a.name_a = b.name_b
SET validation_check = if(start_dts > end_dts, 'VALID', '')
-- where clause can go here
ANSI SQL syntax:
UPDATE tableA SET validation_check =
(SELECT if(start_DTS > end_DTS, 'VALID', '') AS validation_check
FROM tableA
INNER JOIN tableB ON name_A = name_B
WHERE id_A = tableA.id_A)
Pick whichever one seems most natural to you.
UPDATE
`table1` AS `dest`,
(
SELECT
*
FROM
`table2`
WHERE
`id` = x
) AS `src`
SET
`dest`.`col1` = `src`.`col1`
WHERE
`dest`.`id` = x
;
Hope this works for you.
Easy in MySQL:
UPDATE users AS U1, users AS U2
SET U1.name_one = U2.name_colX
WHERE U2.user_id = U1.user_id
If somebody is seeking to update data from one database to another no matter which table they are targeting, there must be some criteria to do it.
This one is better and clean for all levels:
UPDATE dbname1.content targetTable
LEFT JOIN dbname2.someothertable sourceTable ON
targetTable.compare_field= sourceTable.compare_field
SET
targetTable.col1 = sourceTable.cola,
targetTable.col2 = sourceTable.colb,
targetTable.col3 = sourceTable.colc,
targetTable.col4 = sourceTable.cold
Traaa! It works great!
With the above understanding, you can modify the set fields and "on" criteria to do your work. You can also perform the checks, then pull the data into the temp table(s) and then run the update using the above syntax replacing your table and column names.
Hope it works, if not let me know. I will write an exact query for you.
UPDATE
receipt_invoices dest,
(
SELECT
`receipt_id`,
CAST((net * 100) / 112 AS DECIMAL (11, 2)) witoutvat
FROM
receipt
WHERE CAST((net * 100) / 112 AS DECIMAL (11, 2)) != total
AND vat_percentage = 12
) src
SET
dest.price = src.witoutvat,
dest.amount = src.witoutvat
WHERE col_tobefixed = 1
AND dest.`receipt_id` = src.receipt_id ;
Hope this will help you in a case where you have to match and update between two tables.
I found this question in looking for my own solution to a very complex join. This is an alternative solution, to a more complex version of the problem, which I thought might be useful.
I needed to populate the product_id field in the activities table, where activities are numbered in a unit, and units are numbered in a level (identified using a string ??N), such that one can identify activities using an SKU ie L1U1A1. Those SKUs are then stored in a different table.
I identified the following to get a list of activity_id vs product_id:-
SELECT a.activity_id, w.product_id
FROM activities a
JOIN units USING(unit_id)
JOIN product_types USING(product_type_id)
JOIN web_products w
ON sku=CONCAT('L',SUBSTR(product_type_code,3), 'U',unit_index, 'A',activity_index)
I found that that was too complex to incorporate into a SELECT within mysql, so I created a temporary table, and joined that with the update statement:-
CREATE TEMPORARY TABLE activity_product_ids AS (<the above select statement>);
UPDATE activities a
JOIN activity_product_ids b
ON a.activity_id=b.activity_id
SET a.product_id=b.product_id;
I hope someone finds this useful
UPDATE [table_name] AS T1,
(SELECT [column_name]
FROM [table_name]
WHERE [column_name] = [value]) AS T2
SET T1.[column_name]=T2.[column_name] + 1
WHERE T1.[column_name] = [value];
You can update values from another table using inner join like this
UPDATE [table1_name] AS t1 INNER JOIN [table2_name] AS t2 ON t1.column1_name] = t2.[column1_name] SET t1.[column2_name] = t2.column2_name];
Follow here to know how to use this query http://www.voidtricks.com/mysql-inner-join-update/
or you can use select as subquery to do this
UPDATE [table_name] SET [column_name] = (SELECT [column_name] FROM [table_name] WHERE [column_name] = [value]) WHERE [column_name] = [value];
query explained in details here http://www.voidtricks.com/mysql-update-from-select/
You can use:
UPDATE Station AS st1, StationOld AS st2
SET st1.already_used = 1
WHERE st1.code = st2.code
For same table,
UPDATE PHA_BILL_SEGMENT AS PHA,
(SELECT BILL_ID, COUNT(REGISTRATION_NUMBER) AS REG
FROM PHA_BILL_SEGMENT
GROUP BY REGISTRATION_NUMBER, BILL_DATE, BILL_AMOUNT
HAVING REG > 1) T
SET PHA.BILL_DATE = PHA.BILL_DATE + 2
WHERE PHA.BILL_ID = T.BILL_ID;
I had an issue with duplicate entries in one table itself. Below is the approaches were working for me. It has also been advocated by #sibaz.
Finally I solved it using the below queries:
The select query is saved in a temp table
IF OBJECT_ID(N'tempdb..#New_format_donor_temp', N'U') IS NOT NULL
DROP TABLE #New_format_donor_temp;
select *
into #New_format_donor_temp
from DONOR_EMPLOYMENTS
where DONOR_ID IN (
1, 2
)
-- Test New_format_donor_temp
-- SELECT *
-- FROM #New_format_donor_temp;
The temp table is joined in the update query.
UPDATE de
SET STATUS_CD=de_new.STATUS_CD, STATUS_REASON_CD=de_new.STATUS_REASON_CD, TYPE_CD=de_new.TYPE_CD
FROM DONOR_EMPLOYMENTS AS de
INNER JOIN #New_format_donor_temp AS de_new ON de_new.EMP_NO = de.EMP_NO
WHERE
de.DONOR_ID IN (
3, 4
)
I not very experienced with SQL please advise any better approach you know.
Above queries are for MySql server.
if you are updating from a complex query. The best thing is create temporary table from the query, then use the temporary table to update as one query.
DROP TABLE IF EXISTS cash_sales_sums;
CREATE TEMPORARY TABLE cash_sales_sums as
SELECT tbl_cash_sales_documents.batch_key, COUNT(DISTINCT tbl_cash_sales_documents.cash_sale_number) no_of_docs,
SUM(tbl_cash_sales_documents.paid_amount) paid_amount, SUM(A.amount - tbl_cash_sales_documents.bonus_amount - tbl_cash_sales_documents.discount_given) amount,
SUM(A.recs) no_of_entries FROM
tbl_cash_sales_documents
RIGHT JOIN(
SELECT
SUM(
tbl_cash_sales_transactions.amount
)amount,
tbl_cash_sales_transactions.cash_sale_document_id,
COUNT(transaction_id)recs
FROM
tbl_cash_sales_transactions
GROUP BY
tbl_cash_sales_transactions.cash_sale_document_id
)A ON A.cash_sale_document_id = tbl_cash_sales_documents.cash_sale_id
GROUP BY
tbl_cash_sales_documents.batch_key
ORDER BY batch_key;
UPDATE tbl_cash_sales_batches SET control_totals = (SELECT amount FROM cash_sales_sums WHERE cash_sales_sums.batch_key = tbl_cash_sales_batches.batch_key LIMIT 1),
expected_number_of_documents = (SELECT no_of_docs FROM cash_sales_sums WHERE cash_sales_sums.batch_key = tbl_cash_sales_batches.batch_key),
computer_number_of_documents = expected_number_of_documents, computer_total_amount = control_totals
WHERE batch_key IN (SELECT batch_key FROM cash_sales_sums);
INSERT INTO all_table
SELECT Orders.OrderID,
Orders.CustomerID,
Orders.Amount,
Orders.ProductID,
Orders.Date,
Customer.CustomerName,
Customer.Address
FROM Orders
JOIN Customer ON Orders.CustomerID=Customer.CustomerID
WHERE Orders.OrderID not in (SELECT OrderID FROM all_table)