Hi i have a table regd like this
name | year | month
james| 2017 | 2
stacy| 2017 | 4
josh | 2017 | 8
june | 2017 | 9
mary | 2018 | 1
hawk | 2018 | 2
sim | 2018 | 3
How can I select all the people between month 8 of year 2017 to month 3 of year 2018.
Thank you for your help and suggestions.
You can write condition like below
year * 100 + month between 201708 and 201803
where 201708 = 2017 * 100 + 8
and 201803 = 2018 * 100 + 3
Related
I have a table
id | due_at | status
1 | 15 April 2021 | successful
1 | 14 May 2021 | successful
1 | 13 June 2021 | successful
How can i change the due_at column to be a fixed day for every month; Such that
id | due_at | status
1 | 15 April 2021 | successful
1 | 15 May 2021 | successful
1 | 15 June 2021 | successful
I have tried this concept
update tablename set due_at = now() + interval 1 month
UPDATE table
SET due_at = CONCAT('15', SUBSTRING(due_at FROM 3));
I have a table like this
userID time NoOfVisits
1 2014 50
2 2015 60
3 2016 70
4 2017 80
5 2018 90
6 2019 100
I need to write a sql query which will print time and average of past 3 years NoOfVisits for a particular site.
output should be as
userID time NoOfVisits
1 2014 50.0000
2 2015 55.0000
3 2016 60.0000
4 2017 70.0000
5 2018 80.0000
6 2019 90.0000
Explanation :
For user Id 6 (80+90+100)/3=90.0000
Please help me to solve this problem.
You can use a cumulative average, available in MySQL 8+:
select t.*,
avg(visits) over (order by time rows between 2 preceding and current row) as avg_visits_3
from t;
Assuming there are no gaps between the years (like your sample data), you can self join the table and group by userid, time to get the average:
select
t.userid, t.time, avg(tt.noofvisits) NoOfVisits
from tablename t inner join tablename tt
on tt.time between t.time - 2 and t.time
group by t.userid, t.time
See the demo.
Results:
| userid | time | NoOfVisits |
| ------ | ---- | ---------- |
| 1 | 2014 | 50 |
| 2 | 2015 | 55 |
| 3 | 2016 | 60 |
| 4 | 2017 | 70 |
| 5 | 2018 | 80 |
| 6 | 2019 | 90 |
I have a table called Offers in which I have several offers:
ID | List Name | Arrival | Depart | Price
1 | Plus | 12 August | 18 August | $ 100.00
2 | Plus | 19 August | 25 August | $ 120.00
3 | Plus | 26 August | 1 September | $ 80.00
4 | Weekend | 11 August | 13 August | $ 50.00
5 | Weekend | 18 August | 20 August | $ 60.00
6 | Weekend | 25 August | 27 August | $ 40.00
Then I have a guest in my hotel which has a check-in and check-out date.
In need to find all the offers with the same List Name that cover all the days of my vacation's guest (from check-in date to check-out date).
Example
If my guest spends his time in my hotel from the 13th of August to the 20th of August I need to be returned only ids 1 and 2.
If my guest spends his time in my hotel from the 13th of August to the 27th of August I need to be returned only ids 1, 2, and 3. That's because the ids 6 and 7 cover only weekend and not all the days between check-in and check-out dates.
If my guest spends his time in my hotel from the 18th of August to the 20th of August I need to be returned only ids 1, 2 and 5.
You are looking for logic like this:
select o.*
from offers o
where o.arrival <= $arrival and o.depart >= $depart;
$arrival and $depart are the dates for your guest.
You need to do something like this :
SQL Fiddle
MySQL 5.6 Schema Setup:
CREATE TABLE offers
(`ID` int, `Arrival` date, `Depart` date, `Price` float)
;
INSERT INTO offers
(`ID`, `Arrival`, `Depart`, `Price`)
VALUES
(1, '2016-08-12', '2016-08-18', 100.00),
(2, '2016-08-19', '2016-08-25', 120.00),
(3, '2016-08-26', '2016-09-01', 80.00),
(4, '2016-08-11', '2016-08-13', 50.00),
(5, '2016-08-18', '2016-08-20', 60.00),
(6, '2016-08-25', '2016-08-27', 40.00)
;
Query 1:
select *
from offers
where (((arrival >= '2016-08-13' and arrival <= '2016-08-20') or
(depart >= '2016-08-13' and depart <= '2016-08-20'))
and datediff(depart,arrival) = 6)
or
(arrival = '2016-08-13' and depart = '2016-08-20'
and datediff(depart,arrival) = 2)
Results:
| ID | Arrival | Depart | Price |
|----|--------------------------|--------------------------|-------|
| 1 | August, 12 2016 00:00:00 | August, 18 2016 00:00:00 | 100 |
| 2 | August, 19 2016 00:00:00 | August, 25 2016 00:00:00 | 120 |
Query 2:
select *
from offers
where (((arrival >= '2016-08-13' and arrival <= '2016-08-27') or
(depart >= '2016-08-13' and depart <= '2016-08-27'))
and datediff(depart,arrival) = 6)
or
(arrival = '2016-08-13' and depart = '2016-08-27'
and datediff(depart,arrival) = 2)
Results:
| ID | Arrival | Depart | Price |
|----|--------------------------|-----------------------------|-------|
| 1 | August, 12 2016 00:00:00 | August, 18 2016 00:00:00 | 100 |
| 2 | August, 19 2016 00:00:00 | August, 25 2016 00:00:00 | 120 |
| 3 | August, 26 2016 00:00:00 | September, 01 2016 00:00:00 | 80 |
Query 3:
select *
from offers
where (((arrival >= '2016-08-18' and arrival <= '2016-08-20') or
(depart >= '2016-08-18' and depart <= '2016-08-20'))
and datediff(depart,arrival) = 6)
or
(arrival = '2016-08-18' and depart = '2016-08-20'
and datediff(depart,arrival) = 2)
Results:
| ID | Arrival | Depart | Price |
|----|--------------------------|--------------------------|-------|
| 1 | August, 12 2016 00:00:00 | August, 18 2016 00:00:00 | 100 |
| 2 | August, 19 2016 00:00:00 | August, 25 2016 00:00:00 | 120 |
| 5 | August, 18 2016 00:00:00 | August, 20 2016 00:00:00 | 60 |
I have a database with a table containing information on some images, each row containing a createdAt date and a viewCount. The data ranges from September 2014 until today (July 2016). I want to get a monthly sum of the amount of views across all images for the month
When I run the query
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
GROUP BY MONTH(createdAt);
I'm only returned 12 rows with results between September 2014 and August 2015
Year | Month | Views
-------------------
2014 | 9 | 1452
2014 | 10 | 279
2014 | 11 | 34428
2014 | 12 | 4763
2015 | 1 | 2826
2015 | 2 | 777
2015 | 3 | 568
2015 | 4 | 1309
2015 | 5 | 46744
2015 | 6 | 1541
2015 | 7 | 8160
2015 | 8 | 91
If I add a date restraint it will give me the latest data, but again only 12 rows
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images WHERE createdAt > DATE('2015-08-01 00:00:00')
GROUP BY MONTH(createdAt);
Year | Month | Views
--------------------
2015 | 8 | 981
2015 | 9 | 1031
2015 | 10 | 2566
2015 | 11 | 3325
2015 | 12 | 411
2016 | 1 | 2140
2016 | 2 | 710
2016 | 3 | 714
2016 | 4 | 1985
2016 | 5 | 426
2016 | 6 | 119
2016 | 7 | 81
I do realise that since it's July the second query stops there as that's where the data ends, but why does the first query not return all the results?
Group by year/month:
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
--WHERE createdAt > DATE('2015-08-01 00:00:00')
GROUP BY YEAR(createdAt), MONTH(createdAt);
Related Group by clause in mySQL and postgreSQL, why the error in postgreSQL?
Keep in mind that from MySQL 5.7.6+ your initial query may not even work because of only_full_group_by which is set by default.
You can simply add Year to you group by
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
GROUP BY YEAR(createdAt), MONTH(createdAt)
ORDER BY YEAR(createdAt), MONTH(createdAt)
Assuming I have a table like the following:
id | assignment | duedate
1 | Math | 2012-01-01
2 | History | 2012-02-02
3 | Science | 2012-01-01
4 | Government | 2012-02-01
5 | Government | 2013-01-13
6 | History | 2013-03-13
Is it possible to make some sql query such that I get a grouping of all the dates by month and year? Is there some possibility that I could get a sorted result of:
duedatemonth | count
January 2012 | 2
Feburary 2012 | 2
January 2013 | 1
March 2013 | 1
I know you can GROUP BY duedate, but that only groups those with the same month, day, and year instead of just month and year.
Would it be then possible to even further group it such that it factors in "assignment" to obtain a resulting table of
id | duedatemonth | count
1 | January 2012 | 2
3 | January 2012 | 2
2 | Feburary 2012 | 2
4 | Feburary 2012 | 2
5 | January 2013 | 1
6 | March 2013 | 1
try this
SELECT DATE_FORMAT(duedate,'%M %Y') duedatemonth, COUNT(*) count
FROM Table1
GROUP BY year(duedate), MONTH(duedate)
DEMO HERE
will output this:
DUEDATEMONTH COUNT
January 2012 2
February 2012 2
January 2013 1
March 2013 1
Use the string functions YEAR and MONTH.
SELECT YEAR(duedate), MONTH(duedate), COUNT(*)
FROM sparkles
GROUP BY YEAR(duedate), MONTH(duedate)
Use MONTHNAME or DATE_FORMAT to get the name of the month.
You can use this query.
SELECT DATE_FORMAT(duedate, '%M %Y') duedatemonth, COUNT(1) `count`
FROM Tbl
GROUP BY DATE_FORMAT(duedate, '%M %Y')