Assuming I have a table like the following:
id | assignment | duedate
1 | Math | 2012-01-01
2 | History | 2012-02-02
3 | Science | 2012-01-01
4 | Government | 2012-02-01
5 | Government | 2013-01-13
6 | History | 2013-03-13
Is it possible to make some sql query such that I get a grouping of all the dates by month and year? Is there some possibility that I could get a sorted result of:
duedatemonth | count
January 2012 | 2
Feburary 2012 | 2
January 2013 | 1
March 2013 | 1
I know you can GROUP BY duedate, but that only groups those with the same month, day, and year instead of just month and year.
Would it be then possible to even further group it such that it factors in "assignment" to obtain a resulting table of
id | duedatemonth | count
1 | January 2012 | 2
3 | January 2012 | 2
2 | Feburary 2012 | 2
4 | Feburary 2012 | 2
5 | January 2013 | 1
6 | March 2013 | 1
try this
SELECT DATE_FORMAT(duedate,'%M %Y') duedatemonth, COUNT(*) count
FROM Table1
GROUP BY year(duedate), MONTH(duedate)
DEMO HERE
will output this:
DUEDATEMONTH COUNT
January 2012 2
February 2012 2
January 2013 1
March 2013 1
Use the string functions YEAR and MONTH.
SELECT YEAR(duedate), MONTH(duedate), COUNT(*)
FROM sparkles
GROUP BY YEAR(duedate), MONTH(duedate)
Use MONTHNAME or DATE_FORMAT to get the name of the month.
You can use this query.
SELECT DATE_FORMAT(duedate, '%M %Y') duedatemonth, COUNT(1) `count`
FROM Tbl
GROUP BY DATE_FORMAT(duedate, '%M %Y')
Related
I am trying to convert a MS Access query to mysql query but in the SELECT part I found a DatePart function which selects the year from the table tbl_trade. I understand that we have inbuilt functions in mysql like YEAR(), EXTRACT() etc but it seems that I cannot use them as
SELECT YEAR(tbl_trade.create_date) from tbl_trade;
It gives an error
Unknown table 'tbl_trade' in field list
Also I do not know how to implement the 3rd and 4th parameter of the DatePart function in mysql.
You can find more details about DatePart function from https://www.techonthenet.com/access/functions/date/datepart.php
In the end, I wish to be able to implement this
SELECT DatePart("yyyy", tbl_trade.create_date,1,2) FROM tbl_trade
The closest equivalent is extract. It takes a variety of intervals.
select create_date, extract(year from create_date)
from tbl_trade;
+---------------------+--------------------------------+
| create_date | extract(year from create_date) |
+---------------------+--------------------------------+
| 2019-01-02 00:00:00 | 2019 |
| 2019-01-02 00:00:00 | 2019 |
+---------------------+--------------------------------+
As for changing the definitions of the week and year, you can pass various modes to week.
-- Mode 7: Week starts on Monday. Week 1 is the first with a Monday.
select create_date, week(create_date, 7) from tbl_trade;
+---------------------+----------------------+
| create_date | week(create_date, 7) |
+---------------------+----------------------+
| 2019-01-02 00:00:00 | 53 |
| 2019-01-02 00:00:00 | 53 |
+---------------------+----------------------+
Or do it by setting default_week_format to affect all date functions.
set default_week_format = 7;
select create_date, extract(week from create_date) from tbl_trade;
+---------------------+--------------------------------+
| create_date | extract(week from create_date) |
+---------------------+--------------------------------+
| 2019-01-02 00:00:00 | 53 |
| 2019-01-02 00:00:00 | 53 |
+---------------------+--------------------------------+
And for fine control there is date_format.
-- %v is mode 3. First DOW is Monday. First week is has 4 days or more.
select create_date, date_format(create_date, '%W week %v') from tbl_trade;
+---------------------+----------------------------------------+
| create_date | date_format(create_date, '%W week %v') |
+---------------------+----------------------------------------+
| 2019-01-02 00:00:00 | Wednesday week 01 |
| 2019-01-02 00:00:00 | Wednesday week 01 |
+---------------------+----------------------------------------+
I have a table like this
userID time NoOfVisits
1 2014 50
2 2015 60
3 2016 70
4 2017 80
5 2018 90
6 2019 100
I need to write a sql query which will print time and average of past 3 years NoOfVisits for a particular site.
output should be as
userID time NoOfVisits
1 2014 50.0000
2 2015 55.0000
3 2016 60.0000
4 2017 70.0000
5 2018 80.0000
6 2019 90.0000
Explanation :
For user Id 6 (80+90+100)/3=90.0000
Please help me to solve this problem.
You can use a cumulative average, available in MySQL 8+:
select t.*,
avg(visits) over (order by time rows between 2 preceding and current row) as avg_visits_3
from t;
Assuming there are no gaps between the years (like your sample data), you can self join the table and group by userid, time to get the average:
select
t.userid, t.time, avg(tt.noofvisits) NoOfVisits
from tablename t inner join tablename tt
on tt.time between t.time - 2 and t.time
group by t.userid, t.time
See the demo.
Results:
| userid | time | NoOfVisits |
| ------ | ---- | ---------- |
| 1 | 2014 | 50 |
| 2 | 2015 | 55 |
| 3 | 2016 | 60 |
| 4 | 2017 | 70 |
| 5 | 2018 | 80 |
| 6 | 2019 | 90 |
SELECT COUNT(client_ID) / DAY(LAST_DAY(dateRequested))
FROM `tbl_client`
WHERE dateRequested BETWEEN DATE_FORMAT(dateRequested,'%Y-%m-01') AND LAST_DAY(dateRequested)
I want to show the average of client per day in the month
client_ID | dateRequested
1 | 2018-07-04
2 | 2018-07-05
3 | 2018-07-06
4 | 2018-07-07
5 | 2018-08-04
6 | 2018-08-06
7 | 2018-08-09
i want to show
Average | Month
4 | July 2018
3 | August 2018
Try below query:
SELECT COUNT(client_ID),concat(month(dateRequested),year(dateRequested))
FROM `tbl_client`
WHERE dateRequested BETWEEN DATE_FORMAT(dateRequested,'%Y-%m-01') AND LAST_DAY(dateRequested)
group by concat(month(dateRequested),year(dateRequested))
I have a database with a table containing information on some images, each row containing a createdAt date and a viewCount. The data ranges from September 2014 until today (July 2016). I want to get a monthly sum of the amount of views across all images for the month
When I run the query
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
GROUP BY MONTH(createdAt);
I'm only returned 12 rows with results between September 2014 and August 2015
Year | Month | Views
-------------------
2014 | 9 | 1452
2014 | 10 | 279
2014 | 11 | 34428
2014 | 12 | 4763
2015 | 1 | 2826
2015 | 2 | 777
2015 | 3 | 568
2015 | 4 | 1309
2015 | 5 | 46744
2015 | 6 | 1541
2015 | 7 | 8160
2015 | 8 | 91
If I add a date restraint it will give me the latest data, but again only 12 rows
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images WHERE createdAt > DATE('2015-08-01 00:00:00')
GROUP BY MONTH(createdAt);
Year | Month | Views
--------------------
2015 | 8 | 981
2015 | 9 | 1031
2015 | 10 | 2566
2015 | 11 | 3325
2015 | 12 | 411
2016 | 1 | 2140
2016 | 2 | 710
2016 | 3 | 714
2016 | 4 | 1985
2016 | 5 | 426
2016 | 6 | 119
2016 | 7 | 81
I do realise that since it's July the second query stops there as that's where the data ends, but why does the first query not return all the results?
Group by year/month:
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
--WHERE createdAt > DATE('2015-08-01 00:00:00')
GROUP BY YEAR(createdAt), MONTH(createdAt);
Related Group by clause in mySQL and postgreSQL, why the error in postgreSQL?
Keep in mind that from MySQL 5.7.6+ your initial query may not even work because of only_full_group_by which is set by default.
You can simply add Year to you group by
SELECT YEAR(createdAt), MONTH(createdAt), SUM(viewCount)
FROM Images
GROUP BY YEAR(createdAt), MONTH(createdAt)
ORDER BY YEAR(createdAt), MONTH(createdAt)
I want to develop code that will allow a subset within a query. I have three fields "batchid", "month" and "year". Each batch may have several months and more than one year. The final order I need is the highest month year combination.
The following table I hope illustrates this.
Batch Month Year
5 12 2013
1 2014
6 11 2013
3 2014
4 1 2014
2 2014
The required order is
Batch Month Year
5 12 2013
1 2014
4 1 2014
2 2014
6 11 2013
3 2014
You can see each batch is sorted to the latest date in the batch and each batch is ordered to the latest date in the batch.
I have got it as far as the year is concerned but cannot figure out the month.
The first statement determines the lowest and highest dates.
I am new to this forum and for that matter not experienced using VBA and have not beanpole to get the SQL statement into this post so I apologize na hope this may make sense.
SELECT t1.batch, t1.month, t1.year
FROM tmp t1
JOIN
(SELECT batch, max(year*12+month) mord FROM tmp GROUP BY batch ORDER BY mord) t2
ON t2.batch = t1.batch
ORDER BY t2.mord, t1.year, t1.month
yields
+-------+-------+------+
| batch | month | year |
+-------+-------+------+
| 5 | 12 | 2013 |
| 5 | 1 | 2014 |
| 4 | 1 | 2014 |
| 4 | 2 | 2014 |
| 6 | 11 | 2013 |
| 6 | 3 | 2014 |
+-------+-------+------+