Counting between dates - mysql

Question

I need the count of all dates including the nonexistent
SELECT ifnull(COUNT(*),0) as num , date_format(c.dataCupo,"%d/%m/%Y") as data
FROM cupons c
WHERE c.dataCupo between "2017-02-02" AND "2018-05-04" AND c.proveidor!="VINCULADO" and c.empresa=1
group by date_format(c.dataCupo,"%Y-%m-%d")
//And I need to count all months including the nonexistent
SELECT ifnull(COUNT(*),0) as num , date_format(c.dataCupo,"%m/%Y") as data
FROM cupons c
WHERE c.dataCupo between "2017-02-02" AND "2018-05-04" AND c.proveidor!="VINCULADO" and c.empresa=1
group by date_format(c.dataCupo,"%Y-%m")
//And I need to count of all years including the nonexistent
SELECT ifnull(COUNT(*),0) as num , date_format(c.dataCupo,"%Y") as data
FROM cupons c
WHERE c.dataCupo between "2015-02-02" AND "2018-05-04" AND c.proveidor!="VINCULADO" and c.empresa=1
group by date_format(c.dataCupo,"%Y")
The result i want its:
02/02/2017 | 10
03/02/2017 | 0
04/02/2017 | 2
05/02/2017 | 0
....
AND
02/2017 | 50
03/2017 | 0
04/2017 | 10
AND
2015 | 0
2016 | 10
2017 | 15
2018 | 0

Answer 1

Easiest way to do this is with a Calendar table. This table will have a datetime column that you can join to and is really useful for reporting. Here goes an example of how to make one in MySQL.
https://gist.github.com/bryhal/4129042
Now that you have the Calendar table, you can join to it to find counts of all dates in a date range.
All days example:
select num, td.db_date
FROM
time_dimension td
left join
(SELECT ifnull(COUNT(*),0) as num , c.dataCupo as data
FROM cupons c
WHERE c.dataCupo between "2017-02-02" AND "2018-05-04" AND
c.proveidor!="VINCULADO" and c.empresa=1
group by c.dataCupo) t
on t.data = td.db_date
WHERE td.db_date between "2017-02-02" AND "2018-05-04"
All months example:
select
sum(t.num),
CONCAT(month(td.db_date),"-",year(td.db_date))
FROM
time_dimension td
left join
(SELECT
ifnull(COUNT(*),0) as num ,
c.dataCupo as data
FROM cupons c
WHERE c.dataCupo between "2017-02-02" AND "2018-05-04" AND
c.proveidor!="VINCULADO" and c.empresa=1) t
on c.data = t.data
WHERE td.db_date between "2017-02-02" AND "2018-05-04"
group by CONCAT(month(td.db_date),"-",year(td.db_date))

Answer 2

You should create A Temporary Table To Store All The Date Ranges Between Your Date Ranges
CREATE TEMPORARY TABLE IF NOT EXISTS AllDateRange engine=memory
SELECT DATE(cal.date) Date
FROM (
SELECT ( case when #prmToDate = #prmFromDate then #prmFromDate else
SUBDATE( #prmFromDate, INTERVAL (DATEDIFF(#prmToDate,#prmFromDate)) DAY) + INTERVAL xc DAY end ) AS Date
FROM (
SELECT #xi:=#xi+1 as xc from
(SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4) xc1,
(SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4) xc2,
(SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4) xc3,
(SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4) xc4,
(SELECT #xi:=+1) xc0
) xxc1
) cal WHERE DATE( cal.date) >= DATE(#prmFromDate) and DATE( cal.date) <= DATE(#prmToDate) ;
And Then Join It With Your Table As.
SELECT count(COALESCE(c.empresa, 0)) as num , date_format(a.Date,"%d/%m/%Y") as data from AllDateTimeRange a
left join cupons c on a.Date=date_format(c.dataCupo,"%Y-%m-%d")
WHERE c.dataCupo between #prmFromDate AND #prmToDate AND c.proveidor!="VINCULADO" and c.empresa=1
group by date_format(c.dataCupo,"%Y-%m-%d");
Similarly Create Temp Tables For Month & Year And Then Join With Your Primary Table, as above in order to get your required results for month and year respectively.