MySql: Count occurrences of values by date - mysql

Question

I'm trying to count the number of occurences based severity level (1-5) on distinct dates. Note I have another table but severity levels are words (High, Medium and Low...not 1 to 5).
Example of DB:
DATE LEVEL COUNT
---- ----- -----
05/11/2018 3 14
05/11/2018 5 11
05/11/2018 5 11
05/12/2018 3 14
05/12/2018 2 14
05/13/2018 2 11
05/13/2018 1 12
Expected output
Date 1 2 3 4 5
--------- -- -- -- -- --
05/11/2018 0 0 14 0 22
05/12/2018 0 14 14 0 0
05/13/2018 12 11 0 0 0
Expected output 2
Level 05/11/2018 05/12/2018 05/13/2018
--------- ---------- ---------- ----------
1 0 0 12
2 0 14 11
3 14 14 0
4 0 0 0
5 22 0 0
I tried
SELECT CONCAT(DAY(`DATE`) ,MONTH(`DATE`) , YEAR(`DATE`)) AS DDMMYYYY ,
COUNT(DISTINCT LEVEL) as NumCount
FROM `myDatabase`
GROUP BY CONCAT(DAY(`DATE`),MONTH(`DATE`), YEAR(`DATE`) )
but I'm getting the number of different counts..
Any guidance would be appreciated! Thx!

Answer 1

You can't really do pivot tables in MySQL. However with a fixed number of columns (such as expected output #1) you can simulate them with CASE statements e.g.
select date_format(date, '%d%m%Y') as Date,
sum(case when level=1 then count else 0 end) as `1`,
sum(case when level=2 then count else 0 end) as `2`,
sum(case when level=3 then count else 0 end) as `3`,
sum(case when level=4 then count else 0 end) as `4`,
sum(case when level=5 then count else 0 end) as `5`
from table1
group by Date
Output:
Date 1 2 3 4 5
11052018 0 0 14 0 22
12052018 0 14 14 0 0
13052018 12 11 0 0 0