I try to create a trigger but I get this error after executing the SQL:
# 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'DECLARE temp INT' at line 4
Here is my trigger:
CREATE TRIGGER hesap
AFTER INSERT ON uber
DECLARE temp INT;
BEGIN IF uber.il='ANKARA' THEN
temp=5+(uber.mesafe*0.5);
ELSEIF uber.il='ISTANBUL' THEN
temp=10+(uber.mesafe*0.5);
ELSEIF uber.il='IZMIR' THEN
temp=3+(uber.mesafe*0.5);
END IF;
INSERT INTO fatura VALUES(uber.uid,temp)
END;
There is some syntax error as I identified check out the below code:
delimiter $$
CREATE TRIGGER hesap
AFTER INSERT ON uber FOR EACH ROW
BEGIN
DECLARE temp integer;
IF new.il = 'ANKARA' THEN
temp= 5+(uber.mesafe*0.5);
ELSEIF new.il='ISTANBUL' THEN
temp=10+(uber.mesafe*0.5);
ELSEIF new.il='IZMIR' THEN
temp=3+(uber.mesafe*0.5);
END IF;
INSERT INTO fatura VALUES(new.uid,temp);
END
delimiter ;
Related
I just want to create trigger in my sql but some error happened
this is the code
CREATE TRIGGER delete_santri_in_kamar
AFTER UPDATE ON
santri
FOR EACH ROW
BEGIN
DECLARE stat INT
SET stat = select status FROM santri WHERE id_santri=new.id_santri
IF (stat = 0) THEN
DELETE FROM santri_kamar_asrama WHERE id_santri=new.id_santri
END IF
END
and this is the error message
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'SET stat = select status FROM santri WHERE id_santri=new.id_santri
IF (stat =' at line 7
please help me
Add semicolons after the statements and change default delimiter(;) before the code of create trigger. Otherwise it will give
SQL Error(1064): You have an error in your SQL Syntax;
After the create trigger code make ; as default delimiter
DELIMITER $$
CREATE TRIGGER delete_santri_in_kamar
AFTER UPDATE ON
santri
FOR EACH ROW
BEGIN
DECLARE stat INT;
SET stat = (select status FROM santri WHERE id_santri=new.id_santri);
IF (stat = 0) THEN
DELETE FROM santri_kamar_asrama WHERE id_santri=new.id_santri;
END IF;
END
$$
DELIMITER ;
this is my trigger
CREATE TRIGGER `proximo_pago` BEFORE INSERT ON `pago`
FOR EACH ROW BEGIN
declare num_orden integer;
select max(orden) from pago where lote=NEW.lote into num_orden;
if(num_orden is NULL)
then
set NEW.orden=1;
else
set NEW.orden=num_orden+1;
end if;
END
and the ERROR
SQL query:
CREATE TRIGGER `proximo_pago` BEFORE INSERT ON `pago`
FOR EACH ROW BEGIN
declare num_orden integer;
MySQL said: Documentation
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 3
I've tried to use DELIMITER but it isn´t works, please help me , thanks
My answer is based only on the necessity of your question which is declaration of the variable.. if the Delimiter doesn't do the trick maybe its an error in your syntax because you didn't SET your SELECT query in a variable. try this first.
DELIMITER $$
CREATE
TRIGGER `proximo_pago` BEFORE INSERT
on `pago`
FOR EACH ROW
BEGIN
DECLARE num_orden int;
SET num_orden = select max(orden) from pago where lote=NEW.lote;
if(num_orden is NULL)
then
set NEW.orden=1;
else
set NEW.orden=num_orden+1;
end if;
END$$
DELIMITER ;
I have faced this problem when I created an after insert trigger. I know this is an syntax error, but I don't know how to fix it in my SQL.
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '' at line 5
Here is my trigger:
CREATE TRIGGER insert_to_student_table
AFTER INSERT ON user
FOR EACH ROW
BEGIN
DECLARE v_UserID INTEGER;
SET #v_UserID := (Select Max(UserID) from user where Type="Student");
INSERT INTO student (StudentID,TutorID)VALUES (v_UserID, NULL);
END
You need to have a delimiter
delimiter //
CREATE TRIGGER insert_to_student_table
AFTER INSERT ON user
FOR EACH ROW
BEGIN
DECLARE v_UserID INTEGER;
SET v_UserID = (Select Max(UserID) from user where Type="Student");
INSERT INTO student (StudentID,TutorID)VALUES (v_UserID, NULL);
END;//
delimiter ;
I am trying this trigger but it keeps giving me this error:
Trigger
DELIMITER $$
CREATE
TRIGGER entries_limit_trigger
BEFORE INSERT ON Feed
FOR EACH ROW
BEGIN
Set #counts=(SELECT count(*) from Feed);
IF (#counts > 10000)
THEN
PRINT 'INSERTED SUCCESS';
END IF;
END
$$
DELIMITER ;
Error
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''INSERTED SUCCESS'; END IF; END' at line 9
If you want the trigger to exit with a message you can do:
CREATE
TRIGGER entries_limit_trigger
BEFORE INSERT ON Feed
FOR EACH ROW
BEGIN
Set #counts=(SELECT count(*) from Feed);
IF #counts > 10000 THEN
set #msg = "Reached the limit";
SIGNAL SQLSTATE '45000' SET MESSAGE_TEXT = #msg;
END IF;
END;
sqlfiddle demo
To make it exit with a message, just add another insert to the fiddle.
The sql i wrote
**delimiter |
CREATE
DEFINER=CURRENT_USER
TRIGGER set_profiletype_after_insert BEFORE INSERT ON trl_translator FOR EACH ROW
BEGIN
UPDATE trl_profile SET trl_profile.type = 'translator' WHERE trl_profile.profile_id = NEW.translator_id
END
|
delimiter ;**
The error given
[SQL]
**CREATE
DEFINER=CURRENT_USER
TRIGGER set_profiletype_after_insert BEFORE INSERT ON trl_translator FOR EACH ROW
BEGIN
UPDATE trl_profile SET trl_profile.type = 'translator' WHERE trl_profile.profile_id = NEW.translator_id
END
;
[Err] 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'END' at line 6**
How to solve this ? where is the mistake i do ?
It looks like you simply need to terminate your UPDATE statement with a semicolon.
Try this code
delimiter |
CREATE
DEFINER=CURRENT_USER
TRIGGER set_profiletype_after_insert BEFORE INSERT ON trl_translator FOR EACH ROW
BEGIN
UPDATE trl_profile SET trl_profile.type = 'translator' WHERE trl_profile.profile_id = NEW.translator_id;
END;|
delimiter ;