Using LIKE operator in MySQL with comma s issue - mysql

This is my query:
SELECT
store_id as `initial`,
CONCAT(',', store_id, ',') AS store_id
FROM `mytable` AS `main_table`
WHERE (`store_id` LIKE '%,13,%');
These are the results without the where conditions:
When I executed my query , I got no results. Same for WHERE (store_idLIKE '%,3,%'); Is it some kind of rule or exception for the , and like operator ?
Thank you :)


Using FIND_IN_SET fixed my problem. More Info:
https://www.w3resource.com/mysql/string-functions/mysql-find_in_set-function.php .
Credit goes to #Jens
SELECT
store_id as `store_id`,
FROM `ffm_nonpayment_actiontemplate` AS `main_table`
WHERE FIND_IN_SET('13', store_id);


The problem is that field store_id in WHERE has initial value and not the value you calculate with CONCAT(',', store_id, ',') AS store_id
If you want filter you can use HAVING keyword

Related

Need regex expression in mysql select query

I am writing the mysql query where I need to compare data entered by user with the sku column in database tab
Query is like
SELECT *
FROM `is_product_info`
WHERE REPLACE( '-', '', sku ) LIKE '%ETI2006%'
so that if sku in database contains "-" in sku, I am replacing all hyphens with "" before comparing.
so whether sju no contains ETI2006 or ETI-2006, it will come in output

I think you may just like this
SELECT * FROM is_product_info WHERE REPLACE( sku , '-', '' ) LIKE '%ETI2006%'

I didn't try on a running MySQL but this should work:
SELECT *
FROM `is_product_info`
WHERE sku REGEXP REPLACE('ETI-2006','-','-?');

I made the mistake in replace syntax, it works with the below one:
SELECT * FROM is_product_info WHERE REPLACE( sku , '-', '' ) LIKE '%ETI2006%'

Using replace() on every row is what's slowing it down.
All of these approaches should be faster - see which one works best for you:
Option 1 - use LIKE twice:
WHERE sku LIKE '%ETI-2006%'
OR sku LIKE '%ETI2006%'
Option 2 - Use RLIKE once:
WHERE sku RLIKE 'ETI-?2006'

Select substring group by

I have data in column which I want to select with substring_index and group by the result of substring. Is it possible to make in one query?:
Example
code:
R0001.10
R0001.20
R0002.10
R0002.30
If use
SELECT SUBSTRING_INDEX(code, '.', 1) FROM products;
It goes like this:
R0001
R0001
R0002
R0002
But when I use
SELECT SUBSTRING_INDEX(code, '.', 1) FROM products GROUP BY code;
It gave some strange result
01
01
010210000
0103020
etc.

There is no issue using GROUP BY clause check SQL Fiddle. Might be other issue.

Finding language in string (doing substring?) with MySQL

I have a table with languages which s_name value looks like this:
'en_UK'
'en_US'
'de_CH'
'de_AT'
I want to get all the distinct languages, without the country part. So for example, in case I just had those of the example, I would need to get:
en
de
What would be the best way of doing so?
I have this right now:
SELECT DISTINCT SUBSTRING(name,1,2)
FROM my_languages

Try this:
SELECT DISTINCT SUBSTRING_INDEX(name, '_', 1) langName
FROM my_languages
OR
SELECT SUBSTRING_INDEX(name, '_', 1) langName
FROM my_languages
GROUP BY langName
Check this link MySQL STRING Functions

Here is a simple way:
select distinct left(s_name, 2)
from t
This assumes the language name is the left two characters.

This will work in Oracle as well as in MySql I think:
SELECT SUBSTR('en_UK',INSTR('en_UK','_')+1) country FROM dual
/

MySQL GROUP_CONCAT multiple fields

I'm probably having a no-brain moment.
I want to return a series of numbers using GROUP_CONCAT from two fields in my database. I have done this so far using the following:
SELECT t_id,
CONCAT(GROUP_CONCAT(DISTINCT s_id),',',IFNULL(GROUP_CONCAT(DISTINCT i_id),'')) AS all_ids
FROM mytable GROUP BY t_id
This works fine but if i_id is NULL then of course I get an unnecessary comma. Is there a better way to do this so I don't end up with a comma at the end if i_id is NULL?

You need to use CONCAT_WS to avoid extra comma for NULL values, try this:
SELECT t_id,
CONCAT_WS(',', GROUP_CONCAT(DISTINCT s_id),
GROUP_CONCAT(DISTINCT i_id)) AS all_ids
FROM mytable
GROUP BY t_id;

SQL: Eliminate chains of duplicate in a GROUP_CONCAT

I'm running a query to analyse variations in Group_member_ID for some users.
What I would like to identify is the key variations in group_member_ids (eg Group1 on 01/08/2011, Group5 on 05/08/2011).
I came up with this command:
select id,
CAST(group_concat(concat('[',group_member_id,'-',from_unixtime(obs_time),']') order by obs_time) as CHAR(10000) CHARACTER SET utf8)
from Table1
where id=1
RESULT:
imei group/date
1[178-2011-06-13 18:58:31],[0-2011-06-13 19:20:56],[0-2011-06-17 17:21:57],[0-2011-06-19 16:53:29],[0-2011-06-22 16:41:11],[178-2011-09-30 16:43:11],[179-2011-10-01 18:43:11]
How can I eliminate the Group/date [0-2011-06-17 17:21:57],[0-2011-06-19 16:53:29],[0-2011-06-22 16:41:11] from this query as I already identified the first record for group_member_id=0 and the others do not matter for me...
In other words, I would like my final result to look like:
imei group/date
1[178-2011-06-13 18:58:31],[0-2011-06-13 19:20:56],[178-2011-09-30 16:43:11],[179-2011-10-01 18:43:11]
I'm stuck. I was thinking of using LIMIT in my group_concat but apparently it's not possible. Or is it?
Thanks for your answers.

TRY with GROUP BY
SELECT id, CAST( GROUP_CONCAT (
CONCAT('[',group_member_id,'-',from_unixtime(obs_time),']')
ORDER BY obs_time ) as CHAR(10000) CHARACTER SET utf8)
AS group_set
FROM table1
WHERE id=1
GROUP BY group_member_id