I have a table with languages which s_name value looks like this:
'en_UK'
'en_US'
'de_CH'
'de_AT'
I want to get all the distinct languages, without the country part. So for example, in case I just had those of the example, I would need to get:
en
de
What would be the best way of doing so?
I have this right now:
SELECT DISTINCT SUBSTRING(name,1,2)
FROM my_languages
Try this:
SELECT DISTINCT SUBSTRING_INDEX(name, '_', 1) langName
FROM my_languages
OR
SELECT SUBSTRING_INDEX(name, '_', 1) langName
FROM my_languages
GROUP BY langName
Check this link MySQL STRING Functions
Here is a simple way:
select distinct left(s_name, 2)
from t
This assumes the language name is the left two characters.
This will work in Oracle as well as in MySql I think:
SELECT SUBSTR('en_UK',INSTR('en_UK','_')+1) country FROM dual
/
Related
I m trying to get number in between "sims_7009_alaira", i want 7009.
SELECT sno,dbase, SUBSTRING_INDEX(dbase, 'sims_', -1)temp
FROM school
How should i do that in SQL
Give this a try:
select substring_index(SUBSTRING_INDEX(dbase, '_', 2),'_',-1) from school;
Check this here:
SQL Fiddle
Just use substring_index() two times:
SELECT sno, dbase, substring_index(substring_index(dbase, 'sims_', -1), '_alaira', 1) as number FROM school
Do this instead:
SELECT sno,dbase, SUBSTRING_INDEX(SUBSTRING_INDEX(dbase, "_", 2),'_',-1) temp
FROM school;
For more insight see this.
i have in my table places named field. there are space separated values(there are problem to store csv value in one field). now i want to fire query like below. how i can do ??
select * from tablename where variablename in places
i did try this way but it shows syntax error.
select * from tablename where variablename in replace(places,' ',',')
### places ###
bank finance point_of_interest establishment
Use FIND_IN_SET
For comma separated
SELECT *
FROM tablename
WHERE ( FIND_IN_SET( 'bank', variablename ) )
Refer : SQL Fiddle
For space separated
SELECT *
FROM tablename
WHERE ( FIND_IN_SET( 'bank', replace(variablename,' ',',') ) )
Refer : SQL Fiddle
The best solution would be to normalise your data structure and do not have a single field storing multiple values.
You can make a query work without normalisation, but any solutions would be lot less optimal from a performance point of view.
Use patter matching with like operator:
... where fieldname like '% searched_value %'
Use the replace() function and combine it with find_in_set():
... where find_in_set('searched_value',replace(fieldname,' ',','))>0
Hi I think your problem comes from the usage of IN
IN for MySql is used like this
SELECT *
FROM table_name
WHERE column_name IN (bank,finance,point_of_interest, establishment);
In case of you want to select places you need to specify each place into value like
I have data in column which I want to select with substring_index and group by the result of substring. Is it possible to make in one query?:
Example
code:
R0001.10
R0001.20
R0002.10
R0002.30
If use
SELECT SUBSTRING_INDEX(code, '.', 1) FROM products;
It goes like this:
R0001
R0001
R0002
R0002
But when I use
SELECT SUBSTRING_INDEX(code, '.', 1) FROM products GROUP BY code;
It gave some strange result
01
01
010210000
0103020
etc.
There is no issue using GROUP BY clause check SQL Fiddle. Might be other issue.
Consider I am having tow fields in my table
field_profile_first_name_value field_profile_last_name_value
Victor Brecher
Abhi Jass
select field_profile_first_name_value, field_profile_last_name_value
from content_type_profile where field_profile_first_name_value LIKE '%Victor Bre%' OR
field_profile_last_name_value LIKE '%Victor Bre%'
I am having a auto complete text box.
When i enter the keyword as victor it will fetch the result. But if i give the first name and last name in the same time it will not produce the result.
That is if i give the keyword as Victor Brecher it will not produce the result.
How can i make to get the result if i enter first name and last name ?
How can i make it ?
Try :
select * from contracts
where lower(concat_ws(' ', field_profile_first_name_value, field_profile_last_name_value))
like lower('%Victor Bre%')
Well, even you don't need to use lower too. just use it simply.
select * from contracts where concat_ws(' ', field_profile_first_name_value,field_profile_last_name_value)
like '%Victor Bre%'
I would make use of soundex.
select * from contracts where SOUNDEX(concat_ws(' ', field_profile_first_name_value,field_profile_last_name_value)) = SOUNDEX('Victor Bre');
I suggest to use this code, so the search works also if the search input is the lastname before the name
SELECT
*
FROM
contracts
WHERE
CONCAT(firstname, ' ', lastname)) LIKE 'Victor Bre%'
OR CONCAT(lastname, ' ', firstname)) LIKE 'Victor Bre%';
Moreover, I tested this sql code with and without LOWER(), in mysql 5.7+ the search already do that.
I'm trying to list all users beginning with a letter, e.g. D
Would the following be the right method of doing this.
Select concat(firstname, '',lastname) from users where concat(lastname) = "D*"
SELECT concat(firstname, '',lastname) FROM users WHERE lastname LIKE "D%"
If you want to use wildcards, you need the LIKE operator. Also, in your where clause you only have one column (lastname), so you don't need concat.
i would try:
select * from users where lastname like 'D%';
For getting list starting with eg: "D":
SELECT firstname FROM users WHERE LEFT(firstname,1)= 'D';