I want to extract the date as the format 2008-07-06 from this date Sunday 6th July 2008 format.
I have tried as below by using below two functions
select str_to_date('Sunday 6th July 2008','%Y-%m-%d')
select DATE_FORMAT('Sunday 6th July 2008','%Y-%m-%d')
but it will returning null value.
Use STR_TO_DATE:
SELECT STR_TO_DATE('Sunday 6th July 2008', '%W %D %M %Y')
FROM dual;
The default date format in MySQL already is 2008-07-06, so you should not have to make a second call to DATE_FORMAT.
SQLFiddle
Related
I have database which contains string like this
22 Jan 2019 11:03
I would like to convert this string to date so I apply this query
select DATE_FORMAT(STR_TO_DATE('22 Jan 2019 11:03','%d-%m-%Y') ,'%d-%m-%Y');
but I get a null result
All you have to do is change small letter m to big letter M in your str_to_date function.
select STR_TO_DATE('22 Jan 2019 11:03','%d %M %Y');
so the final query would be:
select DATE_FORMAT(STR_TO_DATE('22 Jan 2019 11:03','%d %M %Y') ,'%d-%m-%Y');
Here is a demo
SELECT STR_TO_DATE('22 Jan 2019 11:03','%d,%m,%Y');
Basically you first need to understand the values to pass in STR_TO_DATE() and DATE_FORMAT() functions
STR_TO_DATE(my date string , current format of my date string)
Now what you are not doing right is that in STR_TO_DATE() you are passing the format '%d-%m-%Y' , this format says that the input string has hyphen separated date month and year values which is not true.
Now in your case the actual format of your date string is the following
'%d %M %Y %h:%i'
STR_TO_DATE('22 Jan 2019 11:03','%d %M %Y %h:%i')
%d - day
%M - month
%Y - year
%h - hour
%i - minute
For more info on formats click
Now that we have a complete valid value from string to date including hour and minutes, we can convert this date into any of our required format using correct parameters
SELECT DATE_FORMAT(STR_TO_DATE('22 Jan 2019 11:03','%d %M %Y %h:%i') ,'%d-%m-%y %h:%i');
You can try out various examples here
https://www.mysqltutorial.org/tryit/query/mysql-str_to_date/#1
How can we insert date in in '17-DEC-80' format ?
How to find the last day of this month ?
like this I want to insert 10 dates in the given format and find the last day of the months specified in the date.
This can be acheived through the STR_TO_DATE and DATE_FORMAT internal functions.
You can insert a date so long as you accompany it with the format you are providing it in.
INSERT INTO DateFormats (DF_DATE_FIELD) VALUES (STR_TO_DATE('17-Dec-80', '%d-%b-%y'));
You can also SELECT a that same format date value with the DATE_FORMAT() function. To return the value you want from the table you would use
SELECT
DF_ID,
DF_DATE_FIELD,
DATE_FORMAT(DF_DATE_FIELD, '%d-%b-%y')
FROM DateFormats;
Assuming that DF_DATE_FIELD is in fact a DATE or DATETIME field. Also beware that this is case sensitive
The formatting is as follows
%d = Day of Month for 2 places (i.e 05, 12, 23)
%b = Abbreviated Month (i.e JAN, FEB, DEC)
%y = 2 digit year code (i.e 18, 80, 99)
Read more about formatting At this handy W3 Schools page
And use this DBFiddle for reference
To follow your desired format, use below;
select STR_TO_DATE('17-Dec-80', '%d-%b-%y');
To get last day of the month
select LAST_DAY(STR_TO_DATE('17-Dec-80', '%d-%b-%y'));
I am using MySQL, I have a column value like this 08th August 2017.
I want to convert it into a date like 8-8-2017. I have tried MySQL date_formate() function, STR_TO_DATE() function but it return a null value.
How can do this task ?
SELECT STR_TO_DATE('08th August 2017', '%D %M %Y') works fine for me
You need to use the %D %M %Y format for STR_TO_DATE
SELECT STR_TO_DATE(datefield,'%D %M %Y')
FROM yourtable
Input
08th August 2017
Output
2017-08-08
SQL Fiddle: http://sqlfiddle.com/#!9/701e66/5/0
First convert your date string into a DATETIME value and then use that in a DATE_FORMAT() to get the date into whatever format you want
SELECT DATE_FORMAT(STR_TO_DATE('08th August 2017', '%D %M %Y'),'%d-%m-%Y') AS
test;
You can use this code in mysql.
I am just giving example how to use.
select STR_TO_DATE("08th August 2017", "%d %m %y") from demo
where demo is the demo table.
my mysql database tb_date (varchar 20):
16 November 2014
06 December 2014
01 April 2014
12 April 2015
I want select between 01 January 2014 until 31 December 2014, how the query is with date conversion?
thanks..
This is an anti-pattern, storing date values in VARCHAR columns, rather than using datatypes specifically designed and implemented for storing date values... DATE, DATETIME or TIMESTAMP.
To answer your question, before it gets closed, you could use the STR_TO_DATE function to convert the strings into DATE datatype, and then do the comparison. MySQL won't be able to make use of an index range scan operation, it will need to evaluate that function on every flipping row in the table.
As an example:
SELECT t.mycol
FROM mytable t
WHERE STR_TO_DATE(t.mycol,'%d %M %Y') >= '2014-01-01'
AND STR_TO_DATE(t.mycol,'%d %M %Y') < '2015-01-01'
We'll need to check the MySQL Reference Manual to verify that '%M' is the right format specifier for the full month name...
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
Yes, it looks like I guessed right. M is the month name.
As I already commented, you should store your date as Timestamp or Data format then you could simply compare.
However, there is still a solution.. You can convert the varchar to a date directly in your query :
select * from yourTable
where (str_to_date(tb_date, '%d %M %Y') between '2014-01-01' and '2014-12-31');
But please don't use this hack and change your date format...
Edit : If you are really willing to use varchar to store your date, change it to varchar(17) which is the max character possible using your string format.
How to query data in specific time like: I want to select all records stored between 1 pm and 5 pm during a month , when the time stored in datetime column in Unix timestamp format like so "1403830861".
The FROM_UNIXTIME function can convert a unix timestamp to a date. The %k format (hour represented as an in 0..23) seems to fit the bill nicely. The month could be easily extracted in the same fashion, using the %m format and the year using %Y. E.g., the following query would return only results from November 2014:
SELECT *
FROM my_table
WHERE FROM_UNIXTIME (timestamp_column, '%k') BETWEEN 13 AND 17 AND
FROM_UNIXTIME (timestamp_column, '%m') = 11 AND
FROM_UNIXTIME (timestamp_column, '%Y') = 2014