Scale Caffe weights - deep-learning

I have trained lenet network.
When I extract weights for model I have small values like this:
[[ 0.06115171 -0.12328118 -0.05160818 -0.10334936 -0.01025871 -0.0503762
-0.07576288]]
I need integer values for a specific application,Is there a way to train caffe with integer values or there are any scale factor due all values are near 0?.
Im looking for filters like this:
(1 2 1)
(0 0 0)
(-1 -2 -1)
Kind regards

Although i don't use caffe it seems like your output is l2 normolized. I.e. your last layer is L2 normalization.
If you want to get integers you can apply sigmoid function to the output that currently goes into your L2 norm layer. You are still going to get float values, but they will be very close to either zero or 1. But in order for these integer values to make any sense you also need to use this output in some kind of an objective function and train with it. E.g. crossentropy with logits.
if you want to get distinct integers you can add another channel to your output with the dimension equal to the total possible unique integers you want. That way you still getting 0s and 1s but they will one-hot encode the integer values you need. Also if you going to do this you will need to apply softmax across this additional channel instead of sigmoid.

Related

what's the meaning of 'parameterize' in deep learning?

no
13
what's the meaning of 'parameterize' in deep learning? As shown in the photo, does it means the matrix 'A' can be changed by the optimization during training?
Yes, when something can be parameterized it means that gradients can be calculated.
This means that the (dE/dw) which means the derivative of Error with respect to weight can be calculated (i.e it must be differentiable) and subtracted from the model weights along with obviously a learning_rate and other params being included depending on the optimizer.
What the paper is saying is that if you make a binary matrix a weight and then find the gradient (dE/dw) of that weight with respect to a loss and then make an update on the binary matrix through backpropagation, there is not really an activation function (which by requirement must be differentiable) that can keep the values discrete (like 0 and 1) but rather you will end up with continous values (like these decimal values).
Therefore it is saying since the idea of having binary values be weights and for them to be back-propagated in a way where the weights + activation function also yields an updated weight matrix that is also binary is difficult, another solution like the Bernoulli Distribution is used instead to initialize parameters of a model.
Hope this helps,

PyTorch - Neural Network - Output single scalar value

Let's say we have the following neural network in PyTorch
seq_model = nn.Sequential(
nn.Linear(1, 13),
nn.Tanh(),
nn.Linear(13, 1))
With the following input tensor
input = torch.tensor([1.0, 1.0, 5.0], dtype=torch.float32).unsqueeze(1)
I can run forward through the net and get
seq_model(input)
tensor([[-0.0165],
[-0.0165],
[-0.2289]], grad_fn=<TanhBackward0>)
Probably I also can get a single scalar value as an output, but I'm not sure how.
Thank you. I'm trying to use such an network for reinforcment learning, and use it
as an value function approximator for game board state evaluation.
The first dimension of input represents the number of observations in your minibatch (3), the second dimension represents instead the number of features (1).
If you want to forward a single 3d input, the network must be modified (nn.Linear(1, 13) becomes nn.Linear(3, 13)), and you must remove unsqueeze(1) on input. Otherwise, you can merge the three outputs by using a loss to compute a single scalar from them.

Predicting continuous valued output

I am working on predicting Semantic Textual Similarity (SemEval 2017 Task-1) between a pair of texts. The similarity score (output) is a continuous value between [0,5]. The neural network model (link below), therefore, has 6 units in the final layer for prediction between values [0,5]. The objective function used is the Pearson correlation coefficient and softmax activation is used. Now, in order to train the model, how can I give the target output values to the model? Since there are 6 output classes, I should probably send one-hot-encoded vectors of the output. In that case, how can we convert the output (which might be a float value such as 2.33) to a one-hot vector of length 6? Or is there any other way of specifying the target output and training the model?
Paper: http://nlp.arizona.edu/SemEval-2017/pdf/SemEval016.pdf
If the value you're trying to predict is continuously-defined, you might be better off configuring this as a regression architecture. This will be simpler to train and interpret and will give you non-integer predictions (which you can then bucket or threshold however you please).
In order to do this, replace your softmax layer with a layer containing a single neuron with a linear activation function. Then you can simply train this network using your real-valued similarity numbers at the output. For loss function, you can use MSE / L2 unless you have a reason to do otherwise.

Why Caffe's Accuracy layer's bottoms consist of InnerProduct and Label?

I'm new to caffe, in the MNIST example, I was thought that label should compared with softmax layers, but it was not the situation in lenet.prototxt.
I wonder why use InnerProduct result and label to get the accuracy, it seems unreasonable. Was it because I missed something in the layers?
The output dimension of the last inner product layer is 10, which corresponds to the number of classes (digits 0~9) of your problem.
The loss layer, takes two blobs, the first one being the prediction(ip2) and the second one being the label provided by the data layer.
loss_layer = SoftmaxLossLayer(name="loss", bottoms=[:ip2,:label])
It does not produce any outputs - all it does is to compute the loss function value, report it when backpropagation starts, and initiates the gradient with respect to ip2. This is where all magic starts.
After training ( in TEST phase), In the last layer desire results come from multiply weights and ip1( that are computed in last layer ); And each of class( one of 10 neurons) has max value is choosen.

Loss function for ordinal target on SoftMax over Logistic Regression

I am using Pylearn2 OR Caffe to build a deep network. My target is ordered nominal. I am trying to find a proper loss function but cannot find any in Pylearn2 or Caffe.
I read a paper "Loss Functions for Preference Levels: Regression with Discrete Ordered Labels" . I get the general idea - but I am not sure I understand what will the thresholds be, if my final layer is a SoftMax over Logistic Regression (outputting probabilities).
Can some help me by pointing to any implementation of such a loss function ?
Thanks
Regards
For both pylearn2 and caffe, your labels will need to be 0-4 instead of 1-5...it's just the way they work. The output layer will be 5 units, each is a essentially a logistic unit...and the softmax can be thought of as an adaptor that normalizes the final outputs. But "softmax" is commonly used as an output type. When training, the value of any individual unit is rarely ever exactly 0.0 or 1.0...it's always a distribution across your units - which log-loss can be calculated on. This loss is used to compare against the "perfect" case and the error is back-propped to update your network weights. Note that a raw output from PL2 or Caffe is not a specific digit 0,1,2,3, or 5...it's 5 number, each associated to the likelihood of each of the 5 classes. When classifying, one just takes the class with the highest value as the 'winner'.
I'll try to give an example...
say I have a 3 class problem, I train a network with a 3 unit softmax.
the first unit represents the first class, second the second and third, third.
Say I feed a test case through and get...
0.25, 0.5, 0.25 ...0.5 is the highest, so a classifier would say "2". this is the softmax output...it makes sure the sum of the output units is one.
You should have a look at ordinal (logistic) regression. This is the formal solution to the problem setup you describe ( do not use plain regression as the distance measures of errors are wrong).
https://stats.stackexchange.com/questions/140061/how-to-set-up-neural-network-to-output-ordinal-data
In particular I recommend looking at Coral ordinal regression implementation at
https://github.com/ck37/coral-ordinal/issues.