Sum distinct values in SSRS - reporting-services

I need some help in achieving a functionality. The idea is to calculate the sum of duration for all distinct activities which the query is bringing. A couple of considerations
The query is not SQL, its FetchXML (Microsoft Dynamics 365).
Grouping is not done on Activity IDs instead Contact ID, and it has to be that way only.
Here is how the data looks like
| Contact ID | a.activityid | b.activityid | b.duration |
|------------|--------------|--------------|------------|
| A | a1 | act_1 | 15 |
| A | b1 | act_1 | 15 |
| A | c1 | act_1 | 15 |
Now, I'm trying to Sum(b.duration) and it gives me result as 45, but I want the sum as 15 because b.activityid is getting duplicated in the resultset.
In short Sum of duration for distinct b.activityid.
Can anyone help me out a little here?

Related

laravel group by date in join query to find sum of values

I am looking for laravel developer to solve a simple issue. I have 3 tables that I am joining to get data. Model data is like this:
date | order number | amount
I need to group by date and find the sum of amount. Like this:
date | order number | amount
12/06/2022 | ask20 | 150
12/06/2022 | ask20 | 50
13/06/2022 | ask21 | 120
15/06/2022 | ask20 | 110
15/06/2022 | ask23 | 10
16/06/2022 | ask20 | 30
Now, I need to group by date to get the value like this:
date | order number | amount
12/06/2022 | ask20 | 200 (added value)
13/06/2022 | ask21 | 120
15/06/2022 | ask20 | 110 (not added as the order number is different)
15/06/2022 | ask23 | 10
16/06/2022 | ask20 | 30
Remember, I am getting this data by joining 3 tables, Can anyone help solve this?
This seems a simple SUM function -
SELECT date, order_number, SUM(amount)
FROM <YOUR BIGGER QUERY..>
GROUP BY date, order_number

Get sum() in two columns in Laravel 5.4

I have this table (Pickups):
+-----------+------------+-------------+------------+
| worker_id | box_weight | bag_weight | date |
+-----------+------------+-------------+------------+
| 1 | 2 | 5 | 11-07-2018 |
| 1 | 7 | 9 | 11-07-2018 |
| 2 | 8 | 11 | 11-07-2018 |
| 2 | 7 | 12 | 11-07-2018 |
+-----------+------------+-------------+------------+
and I want in Laravel 5.4 Eloquent database engine get the sum of the box_weight and the bag_weight like this:
+-----------+-----------------+-----------------+------------+
| worker_id | sum(box_weight) | sum(bag_weight) | date |
+-----------+-----------------+-----------------+------------+
| 1 | 9 | 14 | 11-07-2018 |
| 2 | 15 | 23 | 11-07-2018 |
+-----------+-----------------+-----------------+------------+
Until now I could only retrieve the sum of a single column not the both in the same call.
Please find the answer bellow, since you didn't mention you want sum of same date per worker id or all dates, I assume only same date, if you want sum of all dates per worker id, remove date from groupBy
Eloquent Query
Pickup::select(['worker_id ','date',DB::raw('sum(box_weight)'),DB::raw('sum(bag_weight)')])
->groupBy('worker_id','date')
->get();
or in Query Builder Approach
DB::table('pickups')
->select(['worker_id ','date',DB::raw('sum(box_weight)'),DB::raw('sum(bag_weight)')])
->groupBy('worker_id','date')
->get();
You're looking for the MySql query or Laravel's QueryBuilder/Eloquent?
I'm assuming you want it grouped by worker_id and not by date, if it's by date, just add date to the groupBy
In the future, show us what you've tried and you're trying to accomplish in more detail
If you're looking for the MySqlQuery, Rom's answer will do just fine
SELECT worker_id, sum(box_weight), sum(bag_weight), date
FROM pickups
GROUP BY worker_id
If you're going from the Eloquent model:
//Assuming Pickup is your model name
Pickup::selectRaw('worker_id, sum(box_weight), sum(bag_weight), date')
->groupBy('worker_id')->get();
Using DB
DB::table('pickups')->selectRaw('worker_id, sum(box_weight), sum(bag_weight), date')
->groupBy('worker_id')->get();
//Or even
DB::select(DB::raw('SELECT worker_id, sum(box_weight), sum(bag_weight), date
FROM pickups
GROUP BY worker_id');
This will give you a collection of pickups, place toArray() at the end of the query if you wish to convert it to an array
The reason behind selectRaw is due to not being able to use ->sum() with ->select(). It works just fine for the sum of a column, not for multiple output and the same goes for select, as it can't relate sum(column) as a column

Joining 2 row of data into 1 row of data

I have a table which looks like this
|Application No | Status | Amount | Type |
==========================================
|90909090 | Null | 3,000 | Null |
|90909090 | Forfeit| Null | A |
What I want to achieve is to combine the values together and end with a result like
|Application No | Status | Amount | Type |
==========================================
|90909090 | Forfeit| 3,000 | A |
I am new to SQL Query and have no idea how to do this
Thanks in advance
No need to join, use max() aggregate function and group by:
select applicationno, max(status), max(amount), max(type)
from yourtable
group by applicationno
However, if you have several non-null values for an application number in a field, then you may have to define a more granular rule than a simple aggregation via max.

Grouping MySQL results buy times

I'm having trouble getting my SQL results to do what I need them to. I've been reading for awhile and I'm still having a little snag. I have a database with times in it. What I'm trying to do is return the amount of calls that fall within each hour. I'm trying to avoid doing 24 different queries for each hour and was hoping the group function might be something I can work with. Is it possible to do one query on this table and be able to group them into one hour increments, or do I need to do individual queries for each hour. My end result will have the number of calls that happened in each of the 24 hours.
+----------+---------+
| calltime | time |
+----------+---------+
| 160523 | 4:05pm |
| 150259 | 3:02pm |
| 025942 | 2:59am |
| 024729 | 2:47am |
| 072419 | 7:24am |
| 142450 | 2:24pm |
| 201937 | 8:19pm |
| 190428 | 7:04pm |
+----------+---------+
Is this possible?
Answer:
SELECT COUNT(*) FROM table GROUP BY HOUR(calltime)
And then looping through results.
You can try this:
SELECT HOUR(STR_TO_DATE( time, '%l:%i:%S %p' )), COUNT(calltime) FROM table GROUP BY HOUR(STR_TO_DATE( time, '%l:%i:%S %p' ));
You can read more here.

Returning multiple results from one row

I have a set of MySQL data similar to the following:
| id | type | start | end |
===============================================================
| 1 | event | 2011-11-01T00:00:00 | 2012-01-02T00:00:00 |
| 2 | showing | 2012-11-04T00:00:00 | 2012-11-04T00:00:00 |
| 3 | conference | 2012-12-01T00:00:00 | 2012-12-04T00:00:00 |
| 4 | event2 | 2012-01-01T00:00:00 | 2012-01-01T00:00:00 |
I want to retrieve events within a certain date range, but I also want to return individual results for each row that has a time span of more than one day. What's the best way to achieve this?
EDIT: In other words, I want to return two results from the event row, four results from the conference row and a single result for all the others.
Any ideas would be greatly appreciated.
Try this statement:
SELECT * FROM table
WHERE START BETWEEN '2012-01-01' AND '2012-01-03'
OR END BETWEEN '2012-01-01' AND '2012-01-03'
OR TO_DAYS(end) - TO_DAYS(start) > 1
I have created it for testing on SQL Fiddle