I'm not sure if this is allowed, but my question can actually be splitted into two:
The bottom header should display a bottom box-shadow, but doesn't because of backgrounds and z-index (if I'm correct).
The container should occupy 100% of remaining available screen height. If the content in container right is longer, stretch both container and container right. container left should always be 100% remaining available height, stay on screen, and display a scrollbar if the content is too long for the container.
As you can see in the situation screenshot below, currently I'm not able to do either.
How can I fix both of these issues? I've been messing around trying various solutions, but none of them seem to work 100%.
Do note that there's a certain layering order:
Container > Header(s) + Footer > Sidepanel > Modal
Here's the situation: Codepen example
I've only included the relevant code here for the sake of brevity.
HTML:
<div class="header-box-shadow">Header 1</div>
<div class="header-box-shadow">Header 2</div>
<div class="header-box-shadow">Header 3</div>
<div class="header-box-shadow">Header 4</div>
<div class="container">
<div class="content">
<div class="left">container left</div>
<div class="right">container right</div>
</div>
</div>
<div class="footer">footer</div>
<div class="sidepanel">sidepanel</div>
<div class="modal">modal</div>
SCSS:
.header-box-shadow {
&:last-of-type {
box-shadow: 0 2px 4px rgba(0, 0, 0, .3);
position: relative;
z-index: 100000;
}
}
.container {
display: flex;
flex-direction: column;
.content {
flex: 1 1 auto;
display: flex;
.left {
height: 100%;
}
.right {
flex: 1 1 auto;
}
}
}
.footer {
position: fixed;
bottom: 0;
left: 0;
}
.sidepanel {
height: 100%;
position: fixed;
top: 0;
right: 0;
}
.modal {
position: absolute;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
}
Wrap your complete HTML layout inside another div, which you give display: flex. You can then give this div, let's call it .outer, 100% viewport height. Then, on the container, set flex: 1; - this will make sure that the container stretches and fills remaining vertical space. You can then also remove the footers fixed position. Next, set overflow-y: scroll; on the left container side. It will scroll when the content gets too large.
For your box shadow, :last-of-type will not work, because the last div is not the last of it's type in the parent container. Therefore, add a class .last to the last header item and apply the box shadow to that selector.
Have a demo here: https://codepen.io/NikxDa/pen/vdZbxV?editors=1100
Please let me know if this is the result you were trying to achieve.
One problem is I think that last-of-type selector only works on node-selectors like in this answer is described.
After compiling your scss there is .header-box-shadow:last-of-type { and because of the class it doesn't work.
So if you make an extra class for the element with the shadow, it will work.
.hasShadow{
box-shadow: 0 2px 4px rgba(0, 0, 0, .3);
position: relative;
z-index: 100000;
}
Related
Is it possible with only CSS to have the following effect:
I have two divs. One follows the other.
Now, if the user starts scrolling down the page (to see other content, more divs if you want..) the second div should "go up" (could also stay fixed and the first div goes down, I mean it would look the same) and overlap the first.
But only overlap for let's say 50px. After that, the behaviour is normal again, meaning that if you scroll further, those divs move out of the browser window eventually.
Have I made myself clear? I can add two coloured boxed to showcase if that helps. I played around a bit and tried parallex/position fixed/sticky mixes, but none seem to work with a given height restriction. I just wonder if this is possible without javascript.
You can get this effect by using position: sticky on both elements. There are a few things that can stop this from taking place, like having overflow: hidden or not having a height set on the parent element.
HTML
<div class="container">
<div class="red-box">This is the red box</div>
<div class="blue-box">this is the blue box</div>
</div>
<!-- needs space to be able to actually scroll on the page -->
<div class="container">
<div class=""></div>
<div class=""></div>
</div>
CSS
/* set the height of the container so that the sticky elements know how far they are meant to scroll */
.container{
min-height: 400px;
}
/* set your position sticky and a attribute that tells it when it should become sticky, in this case right at the top */
.red-box{
height: 400px;
background-color: red;
position: sticky;
top: 0px;
}
.blue-box{
height: 400px;
background-color: blue;
position: sticky;
top: 0px;
}
I have done a quick codepen example so that you can see this working. hope that helps.
https://codepen.io/Domnewmarch/pen/NWzqBde
Solution: I used a combination of negative margin, z-index and position: sticky.
Added margin to the 2nd container to make it more visible.
.sticky-wrapper {
height: 310px;
margin-bottom: -60px;
}
.content {
z-index: -1;
position: sticky;
top: 0;
padding: 0 3%;
height: 250px;
background-color: green;
}
.foo {
margin: 0 50px;
background-color: red;
height: 200px;
}
.next-content {
height: 1000px;
background-color: khaki;
}
<div class="sticky-wrapper">
<div class="content"></div>
</div>
<div class="foo"></div>
<div class="next-content"></div>
As you can see in the CSS below, I want child2 to position itself before child1. This is because the site I'm currently developing should also work on mobile devices, on which the child2 should be at the bottom, as it contains the navigation which I want below the content on the mobile devices. - Why not 2 masterpages? This is the only 2 divs which are repositioned in the entire HTML, so 2 masterpages for this minor change is an overkill.
HTML:
<div id="parent">
<div class="child1"></div>
<div class="child2"></div>
</div>
CSS:
parent { position: relative; width: 100%; }
child1 { width: auto; margin-left: 160px; }
child2 { width: 145px; position: absolute; top: 0px; bottom: 0px; }
child2 has dynamic height, as different subsites could have more or less navigation items.
I know that absolute positioned elements are removed from the flow, thus ignored by other elements.
I tried setting overflow:hidden; on the parent div, but that didn't help, neither does the clearfix.
My last resort will be JavaScript to reposition the two divs accordingly, but for now I'll try and see if there exist a non-JavaScript way of doing this.
You answered the question yourself:
I know that absolute positioned elements are removed from the flow, thus ignored by other elements.
So you can't set the parents height according to an absolutely positioned element.
You either use fixed heights or you need to involve JavaScript.
Nowadays one might use CSS flexbox or grid layout to reverse the visual order of HTML elements inside a parent container without using position: absolute;. See also Reverse order of columns in CSS Grid Layout
Although stretching to elements with position: absolute is not possible, there are often solutions where you can avoid the absolute positioning while obtaining the same effect. Look at this fiddle that solves the problem in your particular case http://jsfiddle.net/gS9q7/
The trick is to reverse element order by floating both elements, the first to the right, the second to the left, so the second appears first.
.child1 {
width: calc(100% - 160px);
float: right;
}
.child2 {
width: 145px;
float: left;
}
Finally, add a clearfix to the parent and you're done (see the fiddle for the complete solution).
Generally, as long as the element with absolute position is positioned at the top of the parent element, chances are good that you find a workaround by floating the element.
There is a quite simple way to solve this.
You just have to duplicate the content of child1 and child2 in relative divs with display:none in parent div. Say child1_1 and child2_2. Put child2_2 on top and child1_1 at the bottom.
When your jquery (or whatever) calls the absolute div, just set the according relative div (child1_1 or child2_2) with display:block AND visibility:hidden. The relative child will still be invisible but will make parent's div higher.
Feeela is right but you can get a parent div contracting or expanding to a child element if you reverse your div positioning like this:
.parent {
position: absolute;
/* position it in the browser using the `left`, `top` and `margin`
attributes */
}
.child {
position: relative;
height: 100%;
width: 100%;
overflow: hidden;
/* to pad or move it around using `left` and `top` inside the parent */
}
This should work for you.
This question was asked in 2012 before flexbox. The correct way to solve this problem using modern CSS is with a media query and a flex column reversal for mobile devices. No absolute positioning is needed.
https://jsfiddle.net/tnhsaesop/vjftq198/3/
HTML:
<div class="parent">
<div style="background-color:lightgrey;">
<p>
I stay on top on desktop and I'm on bottom on mobile
</p>
</div>
<div style="background-color:grey;">
<p>
I stay on bottom on desktop and I'm on top on mobile
</p>
</div>
</div>
CSS:
.parent {
display: flex;
flex-direction: column;
}
#media (max-width: 768px) {
.parent {
flex-direction: column-reverse;
}
}
With pure JavaScript, you just need to retrieve the height of your static position child element .child1 using the getComputedStyle() method then set that retrieve value as the padding-top for that same child using the HTMLElement.style property.
Check and run the following Code Snippet for a practical example of what I described above:
/* JavaScript */
var child1 = document.querySelector(".child1");
var parent = document.getElementById("parent");
var childHeight = parseInt(window.getComputedStyle(child1).height) + "px";
child1.style.paddingTop = childHeight;
/* CSS */
#parent { position: relative; width: 100%; }
.child1 { width: auto; }
.child2 { width: 145px; position: absolute; top: 0px; bottom: 0px; }
html, body { width: 100%;height: 100%; margin: 0; padding: 0; }
<!-- HTML -->
<div id="parent">
<div class="child1">STATIC</div>
<div class="child2">ABSOLUTE</div>
</div>
There's a very simple hack that fixes this issue
Here's a codesandbox that illustrates the solution: https://codesandbox.io/s/00w06z1n5l
HTML
<div id="parent">
<div class="hack">
<div class="child">
</div>
</div>
</div>
CSS
.parent { position: relative; width: 100%; }
.hack { position: absolute; left:0; right:0; top:0;}
.child { position: absolute; left: 0; right: 0; bottom:0; }
you can play with the positioning of the hack div to affect where the child positions itself.
Here's a snippet:
html {
font-family: sans-serif;
text-align: center;
}
.container {
border: 2px solid gray;
height: 400px;
display: flex;
flex-direction: column;
}
.stuff-the-middle {
background: papayawhip
url("https://camo.githubusercontent.com/6609e7239d46222bbcbd846155351a8ce06eb11f/687474703a2f2f692e696d6775722e636f6d2f4e577a764a6d6d2e706e67");
flex: 1;
}
.parent {
background: palevioletred;
position: relative;
}
.hack {
position: absolute;
left: 0;
top:0;
right: 0;
}
.child {
height: 40px;
background: rgba(0, 0, 0, 0.5);
position: absolute;
bottom: 0;
left: 0;
right: 0;
}
<div class="container">
<div class="stuff-the-middle">
I have stuff annoyingly in th emiddle
</div>
<div class="parent">
<div class="hack">
<div class="child">
I'm inside of my parent but absolutely on top
</div>
</div>
I'm the parent
<br /> You can modify my height
<br /> and my child is always on top
<br /> absolutely on top
<br /> try removing this text
</div>
</div>
I came up with another solution, which I don't love but gets the job done.
Basically duplicate the child elements in such a way that the duplicates are not visible.
<div id="parent">
<div class="width-calc">
<div class="child1"></div>
<div class="child2"></div>
</div>
<div class="child1"></div>
<div class="child2"></div>
</div>
CSS:
.width-calc {
height: 0;
overflow: hidden;
}
If those child elements contain little markup, then the impact will be small.
I had a similar problem.
To solve this (instead of calculate the iframe's height using the body, document or window) I created a div that wraps the whole page content (a div with an id="page" for example) and then I used its height.
"You either use fixed heights or you need to involve JS."
Here is the JS example:
---------- jQuery JS example--------------------
function findEnvelopSizeOfAbsolutelyPositionedChildren(containerSelector){
var maxX = $(containerSelector).width(), maxY = $(containerSelector).height();
$(containerSelector).children().each(function (i){
if (maxX < parseInt($(this).css('left')) + $(this).width()){
maxX = parseInt($(this).css('left')) + $(this).width();
}
if (maxY < parseInt($(this).css('top')) + $(this).height()){
maxY = parseInt($(this).css('top')) + $(this).height();
}
});
return {
'width': maxX,
'height': maxY
}
}
var specBodySize = findEnvelopSizeOfAbsolutelyPositionedSubDivs("#SpecBody");
$("#SpecBody").width(specBodySize.width);
$("#SpecBody").height(specBodySize.height);
There is a better way to do this now. You can use the bottom property.
.my-element {
position: absolute;
bottom: 30px;
}
This is very similar to what #ChrisC suggested. It is not using an absolute positioned element, but a relative one. Maybe could work for you
<div class="container">
<div class="my-child"></div>
</div>
And your css like this:
.container{
background-color: red;
position: relative;
border: 1px solid black;
width: 100%;
}
.my-child{
position: relative;
top: 0;
left: 100%;
height: 100px;
width: 100px;
margin-left: -100px;
background-color: blue;
}
https://jsfiddle.net/royriojas/dndjwa6t/
Also consider next approach:
CSS:
.parent {
height: 100%;
}
.parent:after {
content: '';
display: block;
}
Also since you are trying to reposition divs consider css grid
Absolute views position themselves against the nearest ancestor that isn't statically positioned (position: static), therefore if you want an absolute view positioned against a given parent, set the parent position to relative and the child to position to absolute
Try this, it was worked for me
.child {
width: 100%;
position: absolute;
top: 0px;
bottom: 0px;
z-index: 1;
}
It will set child height to parent height
I have a div (div1) inside some other divs. Now I want this div to have the same width as the body (take up full width of display), but always have the same height and position as its parent (div2). I've tried using position: absolute; on this div (div1). Then I can either
set body to position: relative; and have div1 take up 100% width, but now I'm having trouble making the height always follow div2.
or set the parent (div2) to position: relative; and have div 1 take up 100% height, but now I can't make it follow the width of body.
It would be cool if CSS had the option of saying:
.div1 {
height: 100%(.div2);
width: 100%(body);
position: 0(.div2);
}
Or something like that
JSFiddle with the relevant bits: https://jsfiddle.net/Hamleyburger/fqe5o46c/1/#&togetherjs=K02DaSO2nR
What I want is the div ".selectable" to have a div (inside?) that shows on hover and fits the heights of ".selectable" (parent) and the entire width of the body.
Extra, maybe relevant info:
I'm using Bootstrap and (Jinja2) templating. All the divs so far are taking their base widths from a wrapper container (.main) in my base template that I've set to be (responsively) narrower than body. If I were to remove .main
div I would have to set width on many individual divs. That would solve it (I could make all the divs that aren't div1 narrower), but it wouldn't be very DRY. I'm using SASS, if that helps.
It's possible to force a div to fill the whole viewport width using vw. It's a bit weird though:
body,
html {
margin: 0;
padding: 0;
}
.outer {
width: 300px;
height: 300px;
background-color: #eeeeee;
margin: 0 auto;
position: relative
}
.inner {
width: 100vw;
height: 100%;
background-color: rgba(0, 0, 0, 0.1);
position: absolute;
left: 50%;
top: 50%;
transform: translate(-50%, -50%);
}
<div class="outer">
<div class="inner"></div>
</div>
I'd recommend to make your outer div full width and give the inner one a specific width:
body,
html {
margin: 0;
padding: 0;
}
.outer {
width: 100%;
background-color: #eeeeee;
position: relative
}
.inner {
width: 300px;
height: 300px;
margin: 0 auto;
background-color: rgba(0, 0, 0, 0.1);
}
<div class="outer">
<div class="inner"></div>
</div>
So I want a div to always be on the bottom of another div it's in.
I've used bottom:0, position: absolute. This works as long as the window is the same size as the main div (which is the size of the windows too), but the main div has a min-height set, when the window gets smaller then this height the div start moving up with the bottom of the window.
vertical-align also doesn't work for this purpose as it glues it to the bottom of the other divs in the main div, but that results in it not being in the bottom of the main div, which is my goal.
How can I achieve this?
You can use flexbox for that:
.parent {
width: 50%;
height: 200px;
border: 1px solid grey;
margin: 1em auto;
display: flex;
flex-direction: column;
align-items: center;
}
.child {
width: 60%;
height: 50px;
background: rebeccapurple;
margin-top: auto;
}
<div class="parent">
<div class="child"></div>
</div>
From my understanding, you want to make sure that a div is always anchored to the bottom of a div, no matter what. In that case, all you need to do is make sure that the parent div has position:relative, while the child has position: absolute and is absolutely positioned to the bottom of the div.
Screen size shouldn't affect this, even if the parent div has a min-height.
But if I'm off, if you post your code, we may be able to better help.
HTML
<div class="parent">
<div class="child"></div>
</div>
CSS:
<style>
.parent {
position: relative;
min-height:--px
}
.child {
position: absolute;
bottom: 0;
}
As you can see in the CSS below, I want child2 to position itself before child1. This is because the site I'm currently developing should also work on mobile devices, on which the child2 should be at the bottom, as it contains the navigation which I want below the content on the mobile devices. - Why not 2 masterpages? This is the only 2 divs which are repositioned in the entire HTML, so 2 masterpages for this minor change is an overkill.
HTML:
<div id="parent">
<div class="child1"></div>
<div class="child2"></div>
</div>
CSS:
parent { position: relative; width: 100%; }
child1 { width: auto; margin-left: 160px; }
child2 { width: 145px; position: absolute; top: 0px; bottom: 0px; }
child2 has dynamic height, as different subsites could have more or less navigation items.
I know that absolute positioned elements are removed from the flow, thus ignored by other elements.
I tried setting overflow:hidden; on the parent div, but that didn't help, neither does the clearfix.
My last resort will be JavaScript to reposition the two divs accordingly, but for now I'll try and see if there exist a non-JavaScript way of doing this.
You answered the question yourself:
I know that absolute positioned elements are removed from the flow, thus ignored by other elements.
So you can't set the parents height according to an absolutely positioned element.
You either use fixed heights or you need to involve JavaScript.
Nowadays one might use CSS flexbox or grid layout to reverse the visual order of HTML elements inside a parent container without using position: absolute;. See also Reverse order of columns in CSS Grid Layout
Although stretching to elements with position: absolute is not possible, there are often solutions where you can avoid the absolute positioning while obtaining the same effect. Look at this fiddle that solves the problem in your particular case http://jsfiddle.net/gS9q7/
The trick is to reverse element order by floating both elements, the first to the right, the second to the left, so the second appears first.
.child1 {
width: calc(100% - 160px);
float: right;
}
.child2 {
width: 145px;
float: left;
}
Finally, add a clearfix to the parent and you're done (see the fiddle for the complete solution).
Generally, as long as the element with absolute position is positioned at the top of the parent element, chances are good that you find a workaround by floating the element.
There is a quite simple way to solve this.
You just have to duplicate the content of child1 and child2 in relative divs with display:none in parent div. Say child1_1 and child2_2. Put child2_2 on top and child1_1 at the bottom.
When your jquery (or whatever) calls the absolute div, just set the according relative div (child1_1 or child2_2) with display:block AND visibility:hidden. The relative child will still be invisible but will make parent's div higher.
Feeela is right but you can get a parent div contracting or expanding to a child element if you reverse your div positioning like this:
.parent {
position: absolute;
/* position it in the browser using the `left`, `top` and `margin`
attributes */
}
.child {
position: relative;
height: 100%;
width: 100%;
overflow: hidden;
/* to pad or move it around using `left` and `top` inside the parent */
}
This should work for you.
This question was asked in 2012 before flexbox. The correct way to solve this problem using modern CSS is with a media query and a flex column reversal for mobile devices. No absolute positioning is needed.
https://jsfiddle.net/tnhsaesop/vjftq198/3/
HTML:
<div class="parent">
<div style="background-color:lightgrey;">
<p>
I stay on top on desktop and I'm on bottom on mobile
</p>
</div>
<div style="background-color:grey;">
<p>
I stay on bottom on desktop and I'm on top on mobile
</p>
</div>
</div>
CSS:
.parent {
display: flex;
flex-direction: column;
}
#media (max-width: 768px) {
.parent {
flex-direction: column-reverse;
}
}
With pure JavaScript, you just need to retrieve the height of your static position child element .child1 using the getComputedStyle() method then set that retrieve value as the padding-top for that same child using the HTMLElement.style property.
Check and run the following Code Snippet for a practical example of what I described above:
/* JavaScript */
var child1 = document.querySelector(".child1");
var parent = document.getElementById("parent");
var childHeight = parseInt(window.getComputedStyle(child1).height) + "px";
child1.style.paddingTop = childHeight;
/* CSS */
#parent { position: relative; width: 100%; }
.child1 { width: auto; }
.child2 { width: 145px; position: absolute; top: 0px; bottom: 0px; }
html, body { width: 100%;height: 100%; margin: 0; padding: 0; }
<!-- HTML -->
<div id="parent">
<div class="child1">STATIC</div>
<div class="child2">ABSOLUTE</div>
</div>
There's a very simple hack that fixes this issue
Here's a codesandbox that illustrates the solution: https://codesandbox.io/s/00w06z1n5l
HTML
<div id="parent">
<div class="hack">
<div class="child">
</div>
</div>
</div>
CSS
.parent { position: relative; width: 100%; }
.hack { position: absolute; left:0; right:0; top:0;}
.child { position: absolute; left: 0; right: 0; bottom:0; }
you can play with the positioning of the hack div to affect where the child positions itself.
Here's a snippet:
html {
font-family: sans-serif;
text-align: center;
}
.container {
border: 2px solid gray;
height: 400px;
display: flex;
flex-direction: column;
}
.stuff-the-middle {
background: papayawhip
url("https://camo.githubusercontent.com/6609e7239d46222bbcbd846155351a8ce06eb11f/687474703a2f2f692e696d6775722e636f6d2f4e577a764a6d6d2e706e67");
flex: 1;
}
.parent {
background: palevioletred;
position: relative;
}
.hack {
position: absolute;
left: 0;
top:0;
right: 0;
}
.child {
height: 40px;
background: rgba(0, 0, 0, 0.5);
position: absolute;
bottom: 0;
left: 0;
right: 0;
}
<div class="container">
<div class="stuff-the-middle">
I have stuff annoyingly in th emiddle
</div>
<div class="parent">
<div class="hack">
<div class="child">
I'm inside of my parent but absolutely on top
</div>
</div>
I'm the parent
<br /> You can modify my height
<br /> and my child is always on top
<br /> absolutely on top
<br /> try removing this text
</div>
</div>
I came up with another solution, which I don't love but gets the job done.
Basically duplicate the child elements in such a way that the duplicates are not visible.
<div id="parent">
<div class="width-calc">
<div class="child1"></div>
<div class="child2"></div>
</div>
<div class="child1"></div>
<div class="child2"></div>
</div>
CSS:
.width-calc {
height: 0;
overflow: hidden;
}
If those child elements contain little markup, then the impact will be small.
I had a similar problem.
To solve this (instead of calculate the iframe's height using the body, document or window) I created a div that wraps the whole page content (a div with an id="page" for example) and then I used its height.
"You either use fixed heights or you need to involve JS."
Here is the JS example:
---------- jQuery JS example--------------------
function findEnvelopSizeOfAbsolutelyPositionedChildren(containerSelector){
var maxX = $(containerSelector).width(), maxY = $(containerSelector).height();
$(containerSelector).children().each(function (i){
if (maxX < parseInt($(this).css('left')) + $(this).width()){
maxX = parseInt($(this).css('left')) + $(this).width();
}
if (maxY < parseInt($(this).css('top')) + $(this).height()){
maxY = parseInt($(this).css('top')) + $(this).height();
}
});
return {
'width': maxX,
'height': maxY
}
}
var specBodySize = findEnvelopSizeOfAbsolutelyPositionedSubDivs("#SpecBody");
$("#SpecBody").width(specBodySize.width);
$("#SpecBody").height(specBodySize.height);
There is a better way to do this now. You can use the bottom property.
.my-element {
position: absolute;
bottom: 30px;
}
This is very similar to what #ChrisC suggested. It is not using an absolute positioned element, but a relative one. Maybe could work for you
<div class="container">
<div class="my-child"></div>
</div>
And your css like this:
.container{
background-color: red;
position: relative;
border: 1px solid black;
width: 100%;
}
.my-child{
position: relative;
top: 0;
left: 100%;
height: 100px;
width: 100px;
margin-left: -100px;
background-color: blue;
}
https://jsfiddle.net/royriojas/dndjwa6t/
Also consider next approach:
CSS:
.parent {
height: 100%;
}
.parent:after {
content: '';
display: block;
}
Also since you are trying to reposition divs consider css grid
Absolute views position themselves against the nearest ancestor that isn't statically positioned (position: static), therefore if you want an absolute view positioned against a given parent, set the parent position to relative and the child to position to absolute
Try this, it was worked for me
.child {
width: 100%;
position: absolute;
top: 0px;
bottom: 0px;
z-index: 1;
}
It will set child height to parent height