Hi i'm trying to run some gulp task on netlify for building Hugo web.
I wonder how to run serial gulp task on netlify,
by the way this is my gulpfile.js
var gulp = require('gulp');
var removeEmptyLines = require('gulp-remove-empty-lines');
var prettify = require('gulp-html-prettify');
var rm = require( 'gulp-rm' );
var minifyInline = require('gulp-minify-inline');
gulp.task('tojson', function () {
gulp.src('public/**/*.html')
.pipe(removeEmptyLines())
.pipe(gulp.dest('public/./'));
});
gulp.task('htmlClean', function () {
gulp.src('public/**/*.html')
.pipe(removeEmptyLines({
removeComments: true
}))
.pipe(gulp.dest('public/./'));
});
gulp.task('templates', function() {
gulp.src('public/**/*.html')
.pipe(prettify({indent_char: ' ', indent_size: 2}))
.pipe(gulp.dest('public/./'))
});
gulp.task('minify-inline', function() {
gulp.src('public/**/*.html')
.pipe(minifyInline())
.pipe(gulp.dest('public/./'))
});
where should i put the command to run all my gulps task in Netlify?
There are two places to setup your build commands in Netlify.
Admin Option
Put your commands in the online admin under the Settings section of your site and go to Build & Deploy (Deploy settings) and change the Build command:
Netlify Config file (netlify.toml) Option
Edit/add a netlify.toml file to the root of your repository and put your build commands into the context you want to target.
netlify.toml
# global context
[build]
publish = "public"
command = "gulp build"
# build a preview (optional)
[context.deploy-preview]
command = "gulp build-preview"
# build a branch with debug (optional)
[context.branch-deploy]
command = "gulp build-debug"
NOTE:
The commands can be any valid command string. Serializing gulp commands would work fine if you do not want to create a gulp sequence to run them. In example, gulp htmlClean && hugo && gulp tojson would be a valid command.
Commands in the netlify.toml will overwrite the site admin command.
You can string your tasks together like this:
add another plugin with NPM:
https://www.npmjs.com/package/run-sequence
var runSequence = require('run-sequence');
gulp.task('default', function (callback) {
runSequence(['tojson', 'htmlClean', 'templates', 'minify-inline'],
callback
)
})
Then run $ gulp
There's a section on run-sequence on this page that will help:
https://css-tricks.com/gulp-for-beginners/
Related
(Pertains to Gulp 4.0/ES6)
I would like to create a task file that can be imported by main gulpfile.js and can also be run directly from the command line using gulp (in this case without even referencing the gulpfile.js file on command line). Is this possible?
I can create a gulp task file that can be run directly:
task-a.js:
const log = require('fancy-log');
function taskA(done){
// do stuff
log('Executing task A');
done();
}
exports.default = taskA;
Run from command line:
gulp -f task-a.js
[17:53:21] Using gulpfile C:\app\task-a.js
[17:53:21] Starting 'default'...
[17:53:21] Executing task A
[17:53:21] Finished 'default' after 2.73 ms
OK, looks good.
In order to import into gulpfile.js I need to modify the export in task-a.js to:
task-a.js:
// modified the exports for require()
module.exports taskA;
gulpfile.js:
const taskA = require('./task-a');
gulp.task('default', taskA);
gulp -f gulpfile.js
OK, this also works.
But is it possible to change the exports in task-a.js to allow for both import and to be run from command line using gulp?
One way to export the function in task-a.js as a task:
gulp.task('default', taskA);
module.exports = gulp.series('default');
This ensures that the gulpfile.js can import the function as a composed operation.
How do you get composer to install dependencies correctly whenusing a gulp build?
My build process set up that outputs to a set location, either ../sites/www/public_html or ../sites/dev/public_html dependent on if an environment argument is passed to a gulp task. These locations essentially mirror my remote host.
I'm wanting to automate composer installs, updates and optimisation to output the correct vendor files in either ../sites/www/vendor or ../sites/dev/vendor whenever the build is initially run or to just optimise based on any watched php files being changed.
My build folder has the following structure:
source/
bower.json
composer.json
composer.lock
gulpfile.json
package.json
My example composer.json has the following:
{
"name": "mycomposer/mycomposer",
"version": "1.0.0",
"autoload": {
"psr-4" : {
"mycomposer\\": "public_html/app/mycomposer"
}
},
"require": {
"rollbar/rollbar": "^1.3",
"vlucas/phpdotenv": "^2.4.0"
}
}
I have tried a gulp-compose and task to install the composer libraries and to run dumpautoload for local first party libraries
gulp.task('composer', function() {
var dest = argv.live ? 'www' : 'devsite',
env = '../sites/' + dest + '/public_html';
$.composer('config vendor-dir ' + env.replace('public_html', 'vendor') );
$.composer({
"no-ansi": true,
"no-dev": true,
"no-interaction": true,
"no-progress": true,
"no-scripts": true,
"optimize-autoloader": true
});
$.composer('dumpautoload ', {
optimize: true
});
});
When the task is complete I'm finding is that the $baseDir variable references the build directory
Expected
$vendorDir = dirname(dirname(__FILE__));
$baseDir = dirname($vendorDir);
Output
$vendorDir = dirname(dirname(__FILE__));
$baseDir = dirname(dirname(dirname($vendorDir))).'/mybuild';
Is this something I can achieve, or should I really be running composer separately from my build process?
Thanks
I had a similar problem.
I use gulp-composer package.
gulpfile.js
const composer = require('gulp-composer');
gulp.task('composer-deployed', async function() {
let opts = {
"working-dir": 'my-path-to-composer.json',
"self-install": true, // false for my case
optimize: true,
"classmap-authoritative": true
};
composer("dumpautoload", opts);
});
In my case, I use composer installed globaly but you can choose the bin path with bin: 'path-to-composer.phar' in opts{}.
I am trying to use minimist with gulp like this...
var minimist = require('minimist'),
...
knownOptions = {
string: ['env'],
boolean: ['watch'],
default: {
env: process.env.NODE_ENV || '',
watch: false
}
},
options = minimist(process.argv.slice(2), knownOptions),
install = require("gulp-install");
console.log("The options are "+process.argv.slice(2));
console.log("The watch is "+options.watch);
but when I run gulp clean -watch true I still see...
The options are clean,-watch,true
The watch is false
Why is it still false?
UPDATE
this works gulp clean --watch true but can't I do it with 1 slash instead of 2?
I believe (and tested) that since you are invoking the gulp cli, the flags are parsed from gulp itself which stops the execution and prompts you to the "Usage" cli manual.
Just for the record, all of the following will evaluate watch=true:
gulp clean --watch true
gulp clean --watch
gulp clean --watch=true
I have a gulp script, and when I run it from command line, it does not return to shell.
this is a simple gulp command to delete files from dist directory
'use strict';
var del = require('del');
var gulp = require('gulp');
gulp.task('clean', function (cb) {
return del(['dist/**/*'], cb);
});
run command:
gulp clean
[13:39:10] Using gulpfile gulpfile.js
[13:39:10] Starting 'clean'...
[13:39:11] Finished 'clean' after 6.35 ms
npm WARN package.json abc#0.0.0 No description
npm WARN package.json abc#0.0.0 No repository field.
npm WARN package.json abc#0.0.0 No README data
npm WARN package.json karma-coverage#0.2.7 No README data
npm WARN package.json karma-phantomjs-launcher#0.1.4 No README data
it does not return to shell, I have to do CTRL+C to return back to shell.
I am new to gulp, please let me know what I did wrong, thanks.
Try removing the callback argument.
gulp.task('clean', function () {
return del(['dist/**/*']);
});
I am following this guide to generate junit output from my js tests:
https://github.com/sbrandwoo/grunt-qunit-junit
I have installed grunt-qunit-junit into my local test project:
npm install grunt-contrib-qunit --save-dev
And this is my Gruntfile.js:
module.exports = function(grunt) {
"use:strict";
grunt.initConfig({
pkg: grunt.file.readJSON('package.json'),
qunit_junit: {
options: {
},
all: ["all_tests.html"]
},
})
grunt.loadNpmTasks('grunt-qunit-junit');
};
where all_tests.html is located in the same dir and lists all my *test.js files. But when I run:
user#ubuntu:~/Test$ grunt qunit_junit
Running "qunit_junit" task
>> XML reports will be written to _build/test-reports
Done, without errors.
Why are the tests not executed (the folder _build/test-reports is not created)?
The README states that you should execute both the qunit_junit and qunit tasks: http://github.com/sbrandwoo/grunt-qunit-junit#usage-examples
For example: grunt.registerTask('test', ['qunit_junit', 'qunit']);