Here is my trigger, I am getting the MySQL syntax error. I wanted to reduce the balance from sms_index table sms_count column value.
CREATE TRIGGER sms_log_update AFTER UPDATE ON sms_index
FOR EACH ROW
BEGIN
IF NEW.approved_status = '1' THEN
UPDATE sms_package SET balance = (balance - OLD.sms_count) WHERE group_id = OLD.ins_group_id;
END IF;
END;
Error Message:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 5
Your code looks correct, except for the possible problem of the delimiter. Try the following:
DELIMITER //
CREATE TRIGGER sms_log_update AFTER UPDATE ON sms_index
FOR EACH ROW
BEGIN
IF NEW.approved_status = '1' THEN
UPDATE sms_package SET balance = (balance - OLD.sms_count)
WHERE group_id = OLD.ins_group_id;
END IF;
END;//
DELIMITER ;
From the documentation:
However, just as for stored routines, if you use the mysql program to define a trigger that executes multiple statements, it is necessary to redefine the mysql statement delimiter so that you can use the ; statement delimiter within the trigger definition.
Related
I need to update the salary of a newly added employee in the same table if condition is satisfied. SQL keeps throwing errors about syntax, if I use delimiter change it looks like this:
delimiter //
CREATE TRIGGER fixSalary
AFTER INSERT ON emp
FOR EACH ROW
BEGIN
IF NEW.salary < 50000 THEN
UPDATE emp
SET salary = 5000
WHERE eno = NEW.eno;
END IF;
END;//
delimiter ;
But it throws an error:
"You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near
'delimiter //
create trigger fixSalary
after insert on emp
for each row
begin
if ' at line 1"
I tried removing the delimiter:
CREATE TRIGGER fixSalary
AFTER INSERT ON emp
FOR EACH ROW
BEGIN
IF NEW.salary < 50000 THEN
UPDATE emp
SET salary = 5000
WHERE eno = NEW.eno;
END IF;
END;
which resulted in another error:
You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near '' at line 8
I've tried all kinds of semicolons combinations with no luck. Can anyone help me to understand what's going on?
I have wrote trigger for my DB.
CREATE TRIGGER executor_type_check BEFORE INSERT ON executors
FOR EACH ROW
BEGIN
IF NEW.points <> 100
SET NEW.points = 0;
END IF;
END
I get the following error upon importing sql file
You have an error in your SQL syntax;
check the manual that corresponds to your MariaDB server version for the right syntax to use near 'SET NEW.points = 0' at line 5
My .sql file has the following structure:
DataBase creation
start transaction
creation of tables
creation of trigger
commit
Without trigger no error is shown.
As per the Comments below your Question.
You are missing THEN after the IF statement. And also need to Add DELIMITER.
Try this:
DELIMITER $$
CREATE TRIGGER executor_type_check BEFORE INSERT ON executors
FOR EACH ROW
BEGIN
IF NEW.points <> 100
THEN
SET NEW.points = 0;
END IF;
END;$$
DELIMITER ;
I'm getting an odd error every time I try to create one UPDATE trigger into one of my tables...
The Trigger:
CREATE TRIGGER upd_data_nascimento BEFORE UPDATE ON pfi_pessoa_fisica
FOR EACH ROW
BEGIN
IF OLD.date_of_birth = '0000-00-00' THEN
SET NEW.date_of_birth = NULL;
END IF;
END;
And the error:
Error SQL (1064): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 5
Any ideas?
Make sure you are using delimiter
CREATE TRIGGER upd_data_nascimento BEFORE UPDATE ON abc_table
FOR EACH ROW
BEGIN
IF OLD.date_of_birth = '0000-00-00' THEN
SET NEW.date_of_birth = NULL;
END IF;
END
If you are executing it in PHPMyAdmin then set the delimiter to # or something else. And then execute it will work fine I have tested it with above code.
I'm writing a trigger in MySQL to take log of table updates. The log table is called individuo_storico and the target table is called individuo. When individuo is updated, I want to check if IDQualifica and IDLivello are changed, if yes a record in individuo_storico is inserted.
I write down this code but I get a #1064 error, where's the syntax error?
use ore;
create trigger individuo_update after update on individuo
for each row
begin
if ( NEW.IDLivello <> OLD.IDLivello or NEW.IDQualifica <> OLD.IDQualifica) then
insert into individuo_storico(IDIndividuo, IDQualifica, IDLivello)
values (NEW.IDIndividuo, NEW.IDQualifica, NEW.IDLivello);
end if;
end;
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 6
Please wrap your trigger creation with the monikers necessary so the db engine does not choke on it. So three areas:
1) line 1
2) right after the end;
3) and then a reset to a default delimiter.
Same concept is typical with stored proc creations.
DELIMITER $$
create trigger individuo_update after update on individuo
for each row
begin
if ( NEW.IDLivello <> OLD.IDLivello or NEW.IDQualifica <> OLD.IDQualifica) then
insert into individuo_storico(IDIndividuo, IDQualifica, IDLivello)
values (NEW.IDIndividuo, NEW.IDQualifica, NEW.IDLivello);
end if;
end;$$
DELIMITER ;
I want to create a trigger on one of the tables, it's very simple, just to set one value - but I always get error 1064
CREATE TRIGGER `trigger_TEST` BEFORE INSERT ON `TEST_table`
FOR EACH ROW
BEGIN
IF NEW.as_src = 13335 THEN
SET NEW.peer_as_src = 13335;
END IF
END
And get this error:
Error SQL (1064): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 5
Any idea why ?
You need to change the default delimiter
delimiter |
CREATE TRIGGER `trigger_TEST` BEFORE INSERT ON `TEST_table`
FOR EACH ROW
BEGIN
IF NEW.as_src = 13335 THEN
SET NEW.peer_as_src = 13335;
END IF;
END
|
delimiter ;
Otherwise the statement will end at the first ; which would make the trigger definition incomplete.