I have table as below :-
With help of MySql query, I want result as below:
date total read unread
2018-01-31 8 4 4
2018-02-01 2 2 0
Try this:
SELECT date, COUNT(*) as total,
SUM(CASE WHEN read = 1 THEN 1 ELSE 0) as read
SUM(CASE WHEN read = 0 THEN 1 ELSE 0) as unread
FROM yourtable
GROUP BY date
you can use case for aggregate the filtered value for read
select date
, count(*), sum(case when read=1 then 1 else 0 end ) as read
, sum(case when read=0 then 1 else 0 end ) as unread
from my_table
group by date
Try This we don't need case in the read column as 1 means read so we simply sum the value. It will help in the performance if we are dealing with the huge data:
SELECT date,
COUNT(*) as total,
SUM(read) as read --Case not needed here
SUM(CASE WHEN read = 0 THEN 1 ELSE 0) as unread
FROM yourtable
GROUP BY date
You have to group rows by date using group by, then you can use count to count the total number of rows within each date group (= total column).
In order to obtain the number of read and unread, you can sum read and unread value
SELECT date
, COUNT(*) AS total
, SUM(READ) AS READ
, SUM(CASE WHEN READ = 0 THEN 1 ELSE 0 END) AS unread
FROM mytable
GROUP BY date
Related
I have query like below for get sum of purchase and sold traffic.
SELECT DATE_FORMAT(order_time,'%d')AS date,
SUM(CASE WHEN seller_id = 1 THEN visitor_quantity ELSE 0 END) AS totalSold,
SUM(CASE WHEN buyer_id = 1 THEN visitor_quantity ELSE 0 END) AS totalBought
FROM `tbl_orders`
WHERE buyer_id = 1 OR seller_id = 1
GROUP BY DATE(order_time)
Its working fine and giving me result like below
Since I am looking for get all dates between provided date range with 0 if there no any record for that date.
So I am trying following query
with recursive all_dates(dt) as (
-- anchor
select '2021-12-01' dt
union all
-- recursion with stop condition
select dt + interval 1 day from all_dates where dt + interval 1 day <= '2021-12-31'
)SELECT DATE_FORMAT(order_time,'%d')AS date,SUM(CASE
WHEN seller_id = 1
THEN visitor_quantity
ELSE 0
END) AS totalSold, SUM(CASE
WHEN buyer_id = 1
THEN visitor_quantity
ELSE 0
END) AS totalBought FROM `tbl_orders` WHERE buyer_id = 1 OR seller_id = 1 GROUP BY DATE(order_time)
I have found query tutorial here.
But its giving me error called Unrecognized statement type. (near with) in phpmyadmin and giving same result as above image.
my phpmyadmin and marialdb version information is like this.
Let me know if anyone here can help me for same
Thanks!
This is a PhpMyAdmin bug. You need to upgrade to 5.5.0 to get the fix.
I need to sum the number of visits in march and another column that show me the number of visits in april, how can I do it in one query?
I am running in Metabase and I never really used it before, I don't even know how to use the dashboard correctly so I am just querying as usual.
I want to be able to pull enough information to create a visitation over time graph.
Thanks in advance!
select
sum(case when month='MARCH' then 1 else 0 end) as VisitInMarch,
sum(case when month='APRIL' then 1 else 0 end) as VisitInApril
from your_table
or if some specific sum:
select
sum(case when month='MARCH' then [your_field] else 0 end) as VisitInMarch,
sum(case when month='APRIL' then [your_field] else 0 end) as VisitInApril
from your_table
Assuming each visit has a unique ID:
select
count( distinct case when month = 'March' then visit_ID else NULL end ) as March_Visits
, count( distinct case when month = 'April' then visit_ID else NULL end ) as April_Visits
from visits
Or if you want everything in one column, just group by month:
select
month
, count( distinct visit_ID ) as Visits
from visits
group by month
order by month
I am working with a query where I want to display number of upcoming dates. The following query returns 0 even though there are dates greater than current date. Please help me to solve this problem.
SELECT (case when b.booked_date > cast(now() as date) then sum(1) else sum(0) end) as upcoming_booked_facilities
from svk_apt_book_facilities b
where b.customer_id = 1
and b.association_id = 1
and b.is_active = 1
group by b.facility_id
You need to sum a CASE expression to do conditional aggregation:
SELECT
facility_id,
SUM(CASE WHEN booked_date > CURDATE() THEN 1 ELSE 0 END) AS upcoming_booked_facilities
FROM svk_apt_book_facilities
WHERE
customer_id = 1 AND
association_id = 1 AND
is_active = 1
GROUP BY
facility_id;
You were trying to use the sum as the predicate of the CASE expression, which is probably not what you want. Note that I am also selecting the facility_id, since you are grouping by that column. If you instead want a conditional sum over the entire table, then don't select or group by facility.
I have table with columns: id, name, date, present
Column present have values 0 or 1 or 2 and ... more
I need to count how many 0 valous is in current month 2013-07-01 - 2013-07-31 but count only when there are or more than 10 times.
for example if i have
2013-07-01 to 2013-07-10 valoues 0 it should count it and let me know that is 10 or more consecutives days like 11, 12 or more, but if it was less than 10 should count nothing.
I was trying some examples from stack... but they are different problems... so i need little help with that mysql query.
i have smth like this but need consecutives 10 days like >= 10
$sql = mysql_query("SELECT COUNT(name) as count FROM `table` WHERE (`present` = 0) AND (`date` BETWEEN '2013-07-01' AND '2013-07-31')");
while($row = mysql_fetch_array($sql)){
$result = $row['count'];
}
It counts me every 0 values in date between 2013-07-01 and 2013-07-31 but i need count how many days start from 10 or more consecutives days
column present have 0 and other numbers like 1, 2, 3... so i need count only 0 with 10 or more consecutives days
here is SqlFiddle i was trying to make warking from answer
http://sqlfiddle.com/#!2/1bde8/2
best regards
m.
This approach uses correlated subqueries to calculate two values.
The first value is the date of the previous record where Present = 1. This allows you to get the number of days in a row where Present = 0 by using datediff().
The second is the Present value of tomorrow, which will be NULL on the last day of the month. When today has Present = 0 and tomorrow is either 1 or NULL, then we can use this record. It is the end of a sequence of 0s.
From there is it just a question of adding up the values according to the conditions that you set. The following query assumes that you want to do this for each name:
select name, sum(case when datediff(date, lastPresentDate) >= 10
then datediff(date, lastPresentDate)
else 0 end) as DaysCounted
from (select t.*,
(select coalesce(max(date), '2013-06-30')
from t t2
where t2.name = t.name and
t2.present <> 0 and
t2.date <= t.date and
t2.date between '2013-07-01' and '2013-07-31'
) as lastPresentDate,
(select t2.present
from t t2
where t2.name = t.name and
t2.date = adddate(t.date, 1)
order by t2.date
limit 1
) as TomorrowPresent
from t
where date between '2013-07-01' and '2013-07-31'
) t
where Present = 0 and (TomorrowPresent = 1 and TomorrowPresent is null)
group by name
This query should give you a count only when it is 10 or greater than 10.
SELECT COUNT(`name`) as `count`
FROM `table`
WHERE (`present` = 0)
AND (`date` BETWEEN '2013-07-01' AND '2013-07-31')
HAVING `count` >= 10;
Hope it helps!
Not tested, but you could use user variables like this:-
SELECT SUM(if(ConsCounter=10, 1, 0))
FROM
(
SELECT id, name, date, present, #Counter := IF(#PrevPresent = present AND present = 0, #Counter + 1, 0) AS ConsCounter, #PrevPresent = present
FROM
(
SELECT id, name, date, present
FROM `table`
ORDER BY date
) Sub1
CROSS JOIN (SELECT #PrevPresent:=-99999, #Counter:=0) Sub2
) Sub4
Get all the records in date order and add a sequence number for the count since the present was first 0. Then count the number of times that counter is 10.
I have a table of transactions for purchases. Each transaction has a timestamp and purchase amount (in USD).
I'm trying to create some stats from this. I'd like to extract a row for each year that contains the sum for each month in the year. (I'd like months with no transaction to sum to 0 - not omitted.)
I know I could just do a plain SELECT of everything and process it in PHP, but I was wondering if it was at all possible to make MySQL do the work and extract the data like I want it?
What I'd like to see is rows like:
Year, Total_Jan, Total_Feb, ... Total_Dec, Total_Year
I am able to get the total per year, but I can't work out how to get the total per month into the same row.
SELECT
YEAR(dt) as the_year,
SUM(mc_gross) AS sum_total
FROM
transactions
GROUP BY
the_year
SELECT
YEAR(dt) as the_year,
SUM(CASE WHEN MONTH(dt) = 1 THEN mc_gross ELSE 0 END) AS Total_Jan,
SUM(CASE WHEN MONTH(dt) = 2 THEN mc_gross ELSE 0 END) AS Total_Feb,
...
SUM(CASE WHEN MONTH(dt) = 12 THEN mc_gross ELSE 0 END) AS Total_Dec
FROM
transactions
GROUP BY
the_year;