Python Scraper - Find Data in Column - html

Question

I am working on my first website scraper and am trying to get the number 41,110 that is saved in a column on the webpage https://mcassessor.maricopa.gov/mcs.php?q=14014003N. Below is my code.
How can I get to this number and print it?
from bs4 import BeautifulSoup
import requests
web_page = 'https://mcassessor.maricopa.gov/mcs.php?q=14014003N'
web_header = {'User-Agent':'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36'}
response = requests.get(web_page,headers=web_header)
soup = BeautifulSoup(response.content,'html.parser')
for row in soup.findAll('table')[0].thread.tr.findAll('tr'):
first_column = row.findAll('th')[0].contents
print(first_column)

Answer 1

A straightforward approach would involve getting the "improvements" table, getting the first non-header row and then the last cell in this row:
table = soup.find("table", id="improvements-table")
first_row = table.find_all("tr")[1] # skipping a header
last_cell = first_row.find_all("td")[-1]
print(last_cell.get_text()) # prints 41,110
A more generic approach would involve making a list of dictionaries out of this table where keys are header names:
table = soup.find("table", id="improvements-table")
headers = [th.get_text() for th in table('th')]
data = [dict(zip(headers, [td.get_text() for td in row('td')])) for row in table("tr")[1:]]
print(data)
print(data[0]['Sq Ft.'])
Prints:
[
{u'Imp #': u'000101', u'Description': u'Mini-Warehouse', u'Age': u'1', u'Rank': u'2', u'Sq Ft.': u'41,110', u'CCI': u'C', u'Model': u'386'},
{u'Imp #': u'000201', u'Description': u'Site Improvements', u'Age': u'1', u'Rank': u'2', u'Sq Ft.': u'1', u'CCI': u'D', u'Model': u'163'}
]
41,110