I have a log table that stores media requests by act_datetime, app_id, location_id, media_id and media_type_id. What I want is each resultset row to contain type totals for each month. For example, log records contain:
I tried using temp tables to extract records by app_id and grouping by month, but I get multiple rows for each total. I can use sub-queries, but how do I get a total row by type for each month?
Any help is greatly appreciated.
Thanks,
Brandon
EDIT
The follow code works combining shared ideas:
This query takes about 13 seconds parsing about 8.1 million rows. Is that acceptable? Lastly how do you display date as 2018-1 as one column? I'm getting errors when converting to string since the date is also used in the group and order by clauses.
I also want to try code construct sum( case when media_type_id = 1 then 1 else 0 end )... to see if get same results and speed.
Thanks for everyone's help!
Assuming this is SQL Server, and not MySQL:
SELECT DATEPART(MONTH, act_datetime) AS [Month],
COUNT(CASE WHEN app_id = 14 AND media_type_id = 1 AND location_id = 1 THEN act_datetime END) AS MP3_Messages_MO,
COUNT(CASE WHEN app_id = 14 AND media_type_id = 1 AND location_id = 2 THEN act_datetime END) AS MP3_Messages_FL,
COUNT(CASE WHEN app_id = 14 AND media_type_id = 3 AND location_id = 1 THEN act_datetime END) AS MP3_Messages_MO,
COUNT(CASE WHEN app_id = 14 AND media_type_id = 3 AND location_id = 2 THEN act_datetime END) AS MP3_Messages_FL,
COUNT(CASE WHEN app_id = 55 AND media_type_id = 1 THEN act_datetime END) AS MP3_Music,
COUNT(CASE WHEN app_id = 55 AND media_type_id = 9 THEN act_datetime END) AS ZIP_Music
FROM YourTable
GROUP BY DATEPART(MONTH, act_datetime);
Note you have included no logic for differing years, data for each Month will do a count irrespective of year.
This is also completely untested, due to lack of consumable data.
Related
I'm trying to see if it's possible to have several unique columns in a select statement from varying where clause selections. Here is my query.
select org_id, count(org_role) as total
from organization
where org_id = 10 and org_role = 9
group by org_id;
the above works perfectly. It produces:
org_id total
10 19
Id'd like to add another column count named total2 where org_id = 10 and org_role = 7 (the count is 23). So i'd have this result:
org_id total total2
10 19 23
I'm just not sure how to edit the original above query to produce that. Any thoughts would be appreciated.
You can use conditional aggregation. For example:
select
org_id,
sum(case when org_role = 9 then 1 else 0 end) as total,
sum(case when org_role = 7 then 1 else 0 end) as total2
from organization
where org_id = 10 and org_role in (7, 9)
group by org_id;
select org_id, count(org_role) as total, count(total_2)
from organization
where org_id = 10 and org_role = 9
group by org_id;
If it does not work please send your database structure.
I have two tables namely "appointment" and "skills_data".
Structure of appointment table is:
id_ap || ap_meet_date || id_skill || ap_status.
And the value of ap_status are complete, confirm, cancel and missed.
And the skills_data table contains two columns namely:
id_skill || skill
I want to get the count of total number of appointments for each of these conditions
ap_status = ('complete' and 'confirm'),
ap_status = 'cancel' and
ap_status = 'missed'
GROUP BY id_skill and year and
order by year DESC
I tried this query which only gives me count of one condition but I want to get other two based on group by and order by clauses as mentioned.
If there is no record(for example: zero appointments missed in 2018 for a skill) matching for certain conditions, then it should display the output value 0 for zero count.
Could someone please suggest me with a query whether I should implement multiple select query or CASE clause to achieve my expected results. I have lot of records in appointment table and want a efficient way to query my records. Thank you!
SELECT a.id_skill, YEAR(a.ap_meet_date) As year, s.skill,COUNT(*) as count_comp_conf
FROM appointment a,skills_data s WHERE a.id_skill=s.id_skill and a.ap_status IN ('complete', 'confirm')
GROUP BY `id_skill`, `year`
ORDER BY `YEAR` DESC
Output from my query:
id_skill | year | skill | count_comp_conf
-----------------------------------------
1 2018 A 20
2 2018 B 15
1 2019 A 10
2 2019 B 12
3 2019 C 10
My expected output should be like this:
id_skill | year | skill | count_comp_conf | count_cancel | count_missed
------------------------------------------------------------------------
1 2018 A 20 5 1
2 2018 B 15 8 0
1 2019 A 10 4 1
2 2019 B 12 0 5
3 2019 C 10 2 2
You can use conditional aggregation using case when expression
SELECT a.id_skill, YEAR(a.ap_meet_date) As year, s.skill,
COUNT(case when a.ap_status IN ('complete', 'confirm') then 1 end) as count_comp_conf,
COUNT(case when a.ap_status = 'cancel' then 1 end) as count_cancel,
COUNT(case when a.ap_status = 'missed' then 1 end) as count_missed
FROM appointment a inner join skills_data s on a.id_skill=s.id_skill
GROUP BY `id_skill`, `year`
ORDER BY `YEAR` DESC
SELECT a.id_skill,
YEAR(a.ap_meet_date) As year,
s.skill,
SUM(IF(a.ap_status IN ('complete', 'confirm'),1,0)) AS count_comp_conf,
SUM(IF(a.ap_status='cancel',1,0)) AS count_cancel,
SUM(IF(a.ap_status='missed',1,0)) AS count_missed
FROM appointment a,skills_data s WHERE a.id_skill=s.id_skill
GROUP BY `id_skill`, `year`
ORDER BY `YEAR` DESC;
Please try to use if condition along with sum.
With below query you will get output.
select id_skill ,
year ,
skill ,
count_comp_conf ,
count_cancel ,
count_missed ( select id_skill, year, skill, if ap_status ='Completed' then count_comp_conf+1, elseif ap_status ='cancelled' then count_cancel +1 else count_missed+1
from appointment a join skills_data s on (a.id_skill = s.id_skill) group by id_skill, year) group by id_skill,year
order by year desc;
Here is my SQL query:
SELECT
COUNT(CASE WHEN `urgency`='1' THEN 1 END) AS verylow,
COUNT(CASE WHEN `urgency`='2' THEN 1 END) AS low,
COUNT(CASE WHEN `urgency`='3' THEN 1 END) AS standard,
COUNT(CASE WHEN `urgency`='4' THEN 1 END) AS high,
COUNT(CASE WHEN `urgency`='5' THEN 1 END) AS critical,
tbl_users.userName
FROM
notes, tbl_users
WHERE
notes.responsible = tbl_users.userID
AND project_id = '4413'
AND (notes.status = 'Ongoing' OR notes.status = 'Not started')
and the output is:
verylow low standard high critical userName
5 1 2 1 1 Nick
However this is wrong because i have multiple users in the database who have assigned tasks. and it looks like this in my database:
urgency userName
3 Nick
5 Nick
4 Nick
3 James
1 James
1 Nick
2 Nick
1 James
1 Nick
1 Nick
Any idea why it doesn't count the urgency for the other user and how many different urgencies he has?
What you are doing is not entirely correct. If you would turn on MySQL mode ONLY_FULL_GROUP_BY, you'd get a warning, because you are selecting a column that is not in the GROUP BY clause without applying an aggregation function. So you need a GROUP BY clause.
The entire query should look like so:
SELECT
COUNT(CASE WHEN `urgency`='1' THEN 1 END) AS verylow,
COUNT(CASE WHEN `urgency`='2' THEN 1 END) AS low,
COUNT(CASE WHEN `urgency`='3' THEN 1 END) AS standard,
COUNT(CASE WHEN `urgency`='4' THEN 1 END) AS high,
COUNT(CASE WHEN `urgency`='5' THEN 1 END) AS critical,
tbl_users.userName
FROM
notes, tbl_users
WHERE
notes.responsible = tbl_users.userID
AND project_id = '4413'
AND (notes.status = 'Ongoing' OR notes.status = 'Not started')
GROUP BY tbl_users.userName;
With COUNT you aggregate your rows. As there is no GROUP BY clause, you aggregate them to one row (rather than, say a row per user).
You are selecting userName. Which? As you select only one row, the DBMS picks one arbitrarily.
I previously posted a question here: Mysql query with joined tables problems
but didn't get good answers, so I thought I break it down to show only the part that gives me a headache, I might get answers faster to this question, and if I can solve this, I can solve the previous problem too.
The values are referring to an item_id, and I want to get item_id's where the item is referring to (('good' OR 'bad') AND 'fast')
So item_id 1 must be listed, because it is good and also fast
item_id 2 should not listed because it is not fast.
The result i want to get
item_id
1
5
if I have a table like this
id item_id value
1 1 'good'
2 1 'fast'
3 2 'good'
4 2 'slow'
5 3 'good'
6 3 'slow'
7 4 'bad'
8 4 'slow'
9 5 'bad'
10 5 'fast'
11 6 'moderate'
12 6 'fast'
Can someone help me?
One way to see this is: you want a statement per item, so you aggregate and group by item. Criteria come in the HAVING clause.
select item_id
from mytable
group by item_id
having count(case when value = 'fast' then 1 end) >= 1
and count(case when value in ('good','bad') then 1 end) >= 1;
(You can also use sum(case when value = 'fast' then 1 else 0 end) >= 1 or max(case when value = 'fast' then 1 else 0 end) = 1 or some expression along those lines. COUNT(expression) counts expressions that are not null. As I am omitting an ELSE branch, a non-matching record results in null and is thus not counted. Some prefer SUM, some prefer COUNT - it's finally a matter of personal preference.)
One way to do this is with an EXISTS query.
Here's an example:
select t1.item_id
from your_table t1
where t1.value = 'fast'
and exists (
select NULL
from your_table t2
where t2.item_id = t1.item_id
and t2.value in ('good','bad')
);
Considering that a item can be good or bad, not both, I would use the simple way:
select item_id your_table
where value in ('good','bad','fast')
group by item_id
having count(*) = 2
count should be always 2 in those cases.
My Database table is::
attendence date admission number attendence
2013-10-2 LSTM-0008/2013-2014 present
2013-10-19 LSTM-0008/2013-2014 absent
2013-9-20 LSTM-0008/2013-2014 present
above one is my database table.
i want to display table like this based on database table:
MonthName totalWorkingDays Present absent
october 26 1 1
november 26 1 0
i wrote mysql query like this:
SELECT DISTINCT monthname(attendencedate)as monthname , COUNT (*) as totalworking days,
(SELECT COUNT(*) FROM lstms_attendence WHERE attendence='present' AND addmissionno='LSTM-0008/2013-2014') as present,
(SELECT COUNT(*) FROM lstms_attendence WHERE attendence='absent' AND addmissionno='LSTM-0008/2013-2014') as absent
FROM lstms_attendence
WHERE addmissionno='LSTM-0008/2013-2014'
GROUP BY attendencedate;
its not working for me any one give me suggestions.
Try this:
SELECT monthname(attendencedate) AS monthname,
COUNT(*) AS totalworking_days,
SUM(CASE WHEN attendence = 'present' THEN 1 ELSE 0 END) AS present,
SUM(CASE WHEN attendence = 'absent' THEN 1 ELSE 0 END AS absent
FROM lstms_attendence
WHERE addmissionno = 'LSTM-0008/2013-2014'
GROUP BY monthname(attendencedate);
It will SUM 1 for every row that has attendence = 'present' in the present column and 0 otherwise. The same for attendence = 'absent'