How to make a wavetable with Inverse FFT in web-audio api or any other tool - fft

I would like to know how one could generate a wavetable out of a wav file for example.
I know a wavetable can be used in web audio api with setPerdiodic wave and I know how to use it.
But what do I need to do to create my own wavetables? I read about inverse FFT, but I did find nearly nothing. I don't need any code just an idea or a formula of how to get the wavetable from an wav file to a Buffer.

There are a few constraints here and I'm not sure how good the result will be.
Your wav file source can't be too long; the PeriodicWave object
only supports arrays up to size 8192 or so.
I'm going to assume your waveform is intended to be periodic. If the
last sample and the first aren't reasonably close to each other,
there will be a hard-to-reproduce jump.
The waveform must have zero mean, so if it doesn't you should remove
the mean.
With that taken care of, select a power of two greater than the length
of your wave file (not strictly needed, but most FFTs expect powers of
two). Zero-pad the wave file if the length is not a power of two.
Then compute the the FFT. You'll either get an array of complex
numbers or two arrays. Separate these out to real and imaginary
arrays and use them for contructing the PeriodicWave.

Related

fft: fitting binned data

I want to fit a curve to data obtained from an FFT. While working on this, I remembered that an FFT gives binned data, and therefore I wondered if I should treat this differently with curve-fitting.
If the bins are narrow compared to the structure, I think it should not be necessary to treat the data differently, but for me that is not the case.
I expect the right way to fit binned data is by minimizing not the difference between values of the bin and fit, but between bin area and the area beneath the fitted curve, for each bin, such that the energy in each bin matches the energy in the range of the bin as signified by the curve.
So my question is: am I thinking correctly about this? If not, how should I go about it?
Also, when looking around for information about this subject, I encountered the "Maximum log likelihood" for example, but did not find enough information about it to understand if and how it applied to my situation.
PS: I have no clue if this is the right site for this question, please let me know if there is a better place.
For an unwindowed FFT, the correct interpolation between bins is by using a Sinc (sin(x)/x) or periodic Sinc (Dirichlet) interpolation kernel. For an FFT of samples of a band-limited signal, thus will reconstruct the continuous spectrum.
A very simple and effective way of interpolating the spectrum (from an FFT) is to use zero-padding. It works both with and without windowing prior to the FFT.
Take your input vector of length N and extend it to length M*N, where M is an integer
Set all values beyond the original N values to zeros
Perform an FFT of length (N*M)
Calculate the magnitude of the ouput bins
What you get is the interpolated spectrum.
Best regards,
Jens
This can be done by using maximum log likelihood estimation. This is a method that finds the set of parameters that is most likely to have yielded the measured data - the technique originates in statistics.
I have finally found an understandable source for how to apply this to binned data. Sadly I cannot enter formulas here, so I refer to that source for a full explanation: slide 4 of this slide show.
EDIT:
For noisier signals this method did not seem to work very well. A method that was a bit more robust is a least squares fit, where the difference between the area is minimized, as suggested in the question.
I have not found any literature to defend this method, but it is similar to what happens in the maximum log likelihood estimation, and yields very similar results for noiseless test cases.

Motion Vectors and DCT residuals, are they related or independent?

I am working on a novel technique that uses already encoded H264 motion vectors from a pre-encoded video.
I need to know how the motion vectors and residuals are related. I need some very specific answers that I can't find answered anywhere else:
Are the motion vectors forward, or backward? I mean, does the vector indicate where the current 4x4 or 8x8, 8x4 .... block will be in the next frame (forward). Or is it the opposite? (That in the block it is indicated where that block comes from), (backwards).
In the case a block has multiple references (I don't know if that is even possible). How are those references added together? Mean? Weighted?
How is the residual error being compensated, per block (4x8, 8x4, etc)? Ignoring the sub blocks, and just partitioning the image in 8x8 chunks?
My ultimate goal, is to know from the video feed the "accuracy" of each motion vector. I can only do that with backwards prediction, and if the DCT residuals are per block. In that case I can measure the accuracy of the motion vector estimation by measuring the amount of residual error of that block.
Thanks in advance!!
PD: Reading trough the 800 pages of H264 is not easy task....
The H264 standard is your friend. Also get the books by Ian Richardson, a bit more readable than the standard (but only a bit :)
"Are the motion vectors forward, or backward?" - they are backward. The MV for a block points to where that block came from.
"In the case a block has multiple references (I don't know if that is even possible). How are those references added together?" - it is possible, check out weightb and weightp options for x264. Can have up to two references, the explicit weights are encoded in the stream (I think as deltas from the neighbor weights, so usually zeros - but don't quote me on that; also I think whether weights are used is a flag somewhere, if not used the weights are equal by default)
"How is the residual error being compensated" - depends on the macroblock partitioning mode and transform size. The MVs are for each partition, the residuals are for the transform size tiled into the partition (so if a 16x16 is partitioned into two 16x8 and the transform is 8x8, each partition gets two transforms; if the transform is 4x4 each partition gets (16/4)x(8/4)=8 transforms).
For experiments, you can change encoder settings to turn off B-frames and weighted P-frames, and also restrict the partitioning mode to not partition (ie 16x16 only). This allows much easier way to try different motion vectors :)

understanding getByteTimeDomainData and getByteFrequencyData in web audio

The documentation for both of these methods are both very generic wherever I look. I would like to know what exactly I'm looking at with the returned arrays I'm getting from each method.
For getByteTimeDomainData, what time period is covered with each pass? I believe most oscopes cover a 32 millisecond span for each pass. Is that what is covered here as well? For the actual element values themselves, the range seems to be 0 - 255. Is this equivalent to -1 - +1 volts?
For getByteFrequencyData the frequencies covered is based on the sampling rate, so each index is an actual frequency, but what about the actual element values themselves? Is there a dB range that is equivalent to the values returned in the returned array?
getByteTimeDomainData (and the newer getFloatTimeDomainData) return an array of the size you requested - its frequencyBinCount, which is calculated as half of the requested fftSize. That array is, of course, at the current sampleRate exposed on the AudioContext, so if it's the default 2048 fftSize, frequencyBinCount will be 1024, and if your device is running at 44.1kHz, that will equate to around 23ms of data.
The byte values do range between 0-255, and yes, that maps to -1 to +1, so 128 is zero. (It's not volts, but full-range unitless values.)
If you use getFloatFrequencyData, the values returned are in dB; if you use the Byte version, the values are mapped based on minDecibels/maxDecibels (see the minDecibels/maxDecibels description).
Mozilla 's documentation describes the difference between getFloatTimeDomainData and getFloatFrequencyData, which I summarize below. Mozilla docs reference the Web Audio
experiment ; the voice-change-o-matic. The voice-change-o-matic illustrates the conceptual difference to me (it only works in my Firefox browser; it does not work in my Chrome browser).
TimeDomain/getFloatTimeDomainData
TimeDomain functions are over some span of time.
We often visualize TimeDomain data using oscilloscopes.
In other words:
we visualize TimeDomain data with a line chart,
where the x-axis (aka the "original domain") is time
and the y axis is a measure of a signal (aka the "amplitude").
Change the voice-change-o-matic "visualizer setting" to Sinewave to
see getFloatTimeDomainData(...)
Frequency/getFloatFrequencyData
Frequency functions (GetByteFrequencyData) are at a point in time; i.e. right now; "the current frequency data"
We sometimes see these in mp3 players/ "winamp bargraph style" music players (aka "equalizer" visualizations).
In other words:
we visualize Frequency data with a bar graph
where the x-axis (aka "domain") are frequencies or frequency bands
and the y-axis is the strength of each frequency band
Change the voice-change-o-matic "visualizer setting" to Frequency bars to see getFloatFrequencyData(...)
Fourier Transform (aka Fast Fourier Transform/FFT)
Another way to think about "time domain vs frequency" is shown the diagram below, from Fast Fourier Transform wikipedia
getFloatTimeDomainData gives you the chart on on the top (x-axis is Time)
getFloatFrequencyData gives you the chart on the bottom (x-axis is Frequency)
a Fast Fourier Transform (FFT) converts the Time Domain data into Frequency data, in other words, FFT converts the first chart to the second chart.
cwilso has it backwards.
the time data array is the longer one (fftSize), and the frequency data array is the shorter one (half that, frequencyBinCount).
fftSize of 2048 at the usual sample rate of 44.1kHz means each sample has 1/44100 duration, you have 2048 samples at hand, and thus are covering a duration of 2048/44100 seconds, which 46 milliseconds, not 23 milliseconds. The frequencyBinCount is indeed 1024, but that refers to the frequency domain (as the name suggests), not the time domain, and it the computation 1024/44100, in this context, is about as meaningful as adding your birth date to the fftSize.
A little math illustrating what's happening: Fourier transform is a 'vector space isomorphism', that is, a mapping going bijectively (i.e., reversible) between 2 vector spaces of the same dimension; the 'time domain' and the 'frequency domain.' The vector space dimension we have here (in both cases) is fftSize.
So where does the 'half' come from? The frequency domain coefficients 'count double'. Either because they 'actually are' complex numbers, or because you have the 'sin' and the 'cos' flavor. Or, because you have a 'magnitude' and a 'phase', which you'll understand if you know how complex numbers work. (Those are 3 ways to say the same in a different jargon, so to speak.)
I don't know why the API only gives us half of the relevant numbers when it comes to frequency - I can only guess. And my guess is that those are the 'magnitude' numbers, and the 'phase' numbers are thrown out. The reason that this is my guess is that in applications, magnitude is far more important than phase. Still, I'm quite surprised that the API throws out information, and I'd be glad if some expert who actually knows (and isn't guessing) can confirm that it's indeed the magnitude. Or - even better (I love to learn) - correct me.

How to use FFT for large chunks of data to plot amplitude-frequency response?

I am a programmer and not a good mathematician so FFT is like some black box to me, I would like t throw some data into some FFT library and get out a plottable AFR (amplitude-frequency response) data, like some software like Rightmark audio does:
http://www.ixbt.com/proaudio/behringer/3031a/fr-hf.png
Now I have a system which plays back a logarithmic swept sine (with short fade-in/fade-out to avoid sharp edges) and records the response from the audio system.
As far as I understand, I need to pad the input with zeros to 2^n, use audio samples as a real part of a complex numbers, set imaginary=0, and I'll get back from FFT the frequency bins array whith half length of input data.
But if I do not need as big frequency resolution as some seconds audio buffer give to me, then what is the right way to make, lets say, 1024 size FFT window, feed chunks of audio and get back 512 frequency points which take into account all the data I passed in? Or maybe it is not possible and I need to feed entire swept sine at once to get back all the AFR data I need?
Also is there any smoothing needed? I have seen that the raw output from FFT may be really noisy. What is the right way to avoid the noise as early as possible, so I see the noise only as it comes from the AFR itself and not from FFT calculations (like the image in the link I have given - it seems pretty smooth)?
I am a C++/C# programmer. I would be grateful for any examples which show how to process chunks of swept sine end get back AFR data. For now I have found only examples which process data in small chunks in realtime, and that is not what I need.
Window function should help you reducing the noise
All you need to do is multiply your input data by w(n) :

How to represent stereo audio data for FFT

How should stereo (2 channel) audio data be represented for FFT? Do you
A. Take the average of the two channels and assign it to the real component of a number and leave the imaginary component 0.
B. Assign one channel to the real component and the other channel to the imag component.
Is there a reason to do one or the other? I searched the web but could not find any definite answers on this.
I'm doing some simple spectrum analysis and, not knowing any better, used option A). This gave me an unexpected result, whereas option B) went as expected. Here are some more details:
I have a WAV file of a piano "middle-C". By definition, middle-C is 260Hz, so I would expect the peak frequency to be at 260Hz and smaller peaks at harmonics. I confirmed this by viewing the spectrum via an audio editing software (Sound Forge). But when I took the FFT myself, with option A), the peak was at 520Hz. With option B), the peak was at 260Hz.
Am I missing something? The explanation that I came up with so far is that representing stereo data using a real and imag component implies that the two channels are independent, which, I suppose they're not, and hence the mess-up.
I don't think you're taking the average correctly. :-)
C. Process each channel separately, assigning the amplitude to the real component and leaving the imaginary component as 0.
Option B does not make sense. Option A, which amounts to convert the signal to mono, is OK (if you are interested in a global spectrum).
Your problem (double freq) is surely related to some misunderstanding in the use of your FFT routines.
Once you take the FFT you need to get the Magnitude of the complex frequency spectrum. To get the magnitude you take the absolute of the complex spectrum |X(w)|. If you want to look at the power spectrum you square the magnitude spectrum, |X(w)|^2.
In terms of your frequency shift I think it has to do with you setting the imaginary parts to zero.
If you imagine the complex Frequency spectrum as a series of complex vectors or position vectors in a cartesian space. If you took one discrete frequency bin X(w), there would be one real component representing its direction in the real axis (x -direction), and one imaginary component in the in the imaginary axis (y - direction). There are four important values about this discrete frequency, 1. real value, 2. imaginary value, 3. Magnitude and, 4. phase. If you just take the real value and set imaginary to 0, you are setting Magnitude = real and phase = 0deg or 90deg. You have hence forth modified the resulting spectrum, and applied a bias to every frequency bin. Take a look at the wiki on Magnitude of a vector, also called the Euclidean norm of a vector to brush up on your understanding. Leonbloy was correct, but I hope this was more informative.
Think of the FFT as a way to get information from a single signal. What you are asking is what is the best way to display data from two signals. My answer would be to treat each independently, and display an FFT for each.
If you want a really fast streaming FFT you can read about an algorithm I wrote here: www.depthcharged.us/?p=176