XPath doesn't recognize path - html

I'm writing an XSL transformer to convert XML to HTML. Here's my gun.xml:
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="guns.xslt"?>
<guns xsi:noNamespaceSchemaLocation="guns2.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<gun>
<model>revolver</model>
<handy>1</handy>
<origin>Britain</origin>
<ttc>20mm</ttc>
</gun>
</guns>
And guns.xslt here:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match = "/">
<html>
<body>
<h2>Gun Collection</h2>
<table border = "1">
<tr bgcolor = "#9acd32">
<th>Model</th>
<th>Origin</th>
<th>TTC</th>
</tr>
<xsl:for-each select="guns/gun">
<tr>
<td><xsl:value-of select = "model"/></td>
<td><xsl:value-of select = "handy"/></td>
<td><xsl:value-of select = "origin"/></td>
<td><xsl:value-of select = "ttc"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Both files are located in the same package, but XPAth doesn't recognize "guns/gun" in for-each block. What am I missing?

You have declared in xml-stylesheet - type as "text/xsl", please change file extension from "guns.xslt" to "guns.xsl" and also change in your XML as below:
<?xml-stylesheet type="text/xsl" href="guns.xsl"?>
Then your result will be as below:

Related

How to add clickable link to XML?

I am trying to make a URL in my XML file clickable. Below is my XML and XSL files which work fine together.
I've tried using XLink and href in XML file but it didn't work.
How do I make my URL in the XML file clickable?
XML
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="file.xsl" ?>
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="1.xsl" ?>
<catalog>
<cd>
<title>Empire Burlesque</title>
<artist>Johnny</artist>
<country>USA</country>
<company>Columbia</company>
<price>10.90</price>
<url>http://www.yahoo.com</url>
</cd>
</catalog>
XSL
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h2>XSL</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th style="text-align:left">Title</th>
<th style="text-align:left">Artist</th>
<th style="text-align:left">Country</th>
<th style="text-align:left">Company</th>
<th style="text-align:left">Price</th>
<th style="text-align:left">URL</th>
</tr>
<xsl:for-each select="catalog/cd">
<tr>
<td><xsl:value-of select="title"/></td>
<td><xsl:value-of select="artist"/></td>
<td><xsl:value-of select="country"/></td>
<td><xsl:value-of select="company"/></td>
<td><xsl:value-of select="price"/></td>
<td><xsl:value-of select="url"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
Before writing any XSLT, you should really know what output you want. And to make a link clickable in HTML you can do this...
http://www.yahoo.com
So, in your XSLT, instead of doing this....
<td><xsl:value-of select="url"/></td>
Do this...
<td>
<a href="{url}">
<xsl:value-of select="url"/>
</a>
</td>
Note the use of curly braces in the href attribute. This is known as an Attribute Value Template. The curly braces indicate an expression to be evualated, rather than output literally.

XSLT code returns empty rows when converting XML to HTML table

I am trying to convert an XML document to HTML using XSLT 1.0. I aim to display the XML rows in an HTML table. But my XSLT code returns empty rows in the HTML table. Here's what my XML looks like:
<?xml version="1.0" encoding="UTF-8"?>
<people>
<person id="ABCDE1234" firstname="John" lastname="Lewis" sex="male"/>
<person id="XYZWU6789" firstname="Marie" lastname="Claire" sex="female"/>
</people>
Here's my XSLT code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<head>
<title>XML to HTML using XSLT</title>
</head>
<body>
<table border="1" >
<tr>
<th>id</th>
<th>firstname</th>
<th>lastname</th>
<th>sex</th>
</tr>
<xsl:for-each select="people/person">
<tr>
<td><xsl:value-of select="id"/></td>
<td><xsl:value-of select="firstname"/></td>
<td><xsl:value-of select="lastname"/></td>
<td><xsl:value-of select="sex"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
However, my XSLT code runs properly when I reformat the XML file as follows:
<?xml version="1.0" encoding="UTF-8"?>
<people>
<person>
<id>ABCDE1234</id>
<firstname>John</firstname>
<lastname>Lewis</lastname>
<sex>Male</sex>
</person>
<person>
<id>XYZWU6789</id>
<firstname>Mary</firstname>
<lastname>Claire</lastname>
<sex>Female</sex>
</person>
</people>
Why is this happening? Any ideas?
Just add the # sign so that the values will recognize as attributes.
<td><xsl:value-of select="#id"/></td>
<td><xsl:value-of select="#firstname"/></td>
<td><xsl:value-of select="#lastname"/></td>
<td><xsl:value-of select="#sex"/></td>

XML / XSLT - XML Parsing Error: no element found

When i open the xml file with mozilla i get this error:
XML Parsing Error: no element found
Location: file:///D:/PTI/xsl.xsl
Line Number 26, Column 8:
-------^
How can i fix that ?
XML Code:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="xsl.xsl"?>
<books name="List">
<book>
<title>Don Quixote</title>
<author>Miguel de Cervantes</author>
<theme>Adventure</theme>
<price>$120</price>
<year>1605</year>
</book>
<book>
<title>A Tale Of Two Cities</title>
<author>Charles Dickens</author>
<theme>History</theme>
<price>$75</price>
<year>1859</year>
</book>
</books>
XSL Code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h2>Book Catalog</h2>
<table border="1">
<tr>
<th>Title</th>
<th>Author</th>
<th>Theme</th>
<th>Price</th>
<th>Year</th>
</tr>
<xsl:for-each select="books/book">
<tr>
<td><xsl:value-of select="title"/></td>
<td><xsl:value-of select="author"/></td>
<td><xsl:value-of select="theme"/></td>
<td><xsl:value-of select="price"/></td>
<td><xsl:value-of select="year"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
Unless you forget to include a part of your XSLT file you're missing some closing tags (template and stylesheet). Just add them to the end of your xsl.xsl document:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
...your stuff here...
</html>
</xsl:template>
</xsl:stylesheet>

How to process a namespaced XML document using XSLT?

I am trying to process an XML file with XSLT to produce a list or table or (eventually) an SQL INSERT command with some of the values. I have been using the example from w3schools http://www.w3schools.com/xsl/tryxslt.asp?xmlfile=cdcatalog&xsltfile=cdcatalog.
My XML is very simple and I need to extract just the name and the rate of the hotel:
<?xml version="1.0" encoding="utf-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<soapenv:Body>
<getHotelsResponse xmlns="http://hotel.booking.vbooking.com">
<getHotelsReturn>
<address>
<number>589-591</number>
<postcode>08014</postcode>
<region>Catalonia</region>
<street>Carrer Vermell</street>
<town>Barcelona</town>
</address>
<name>Downtown Hotel</name>
<rate>235.0</rate>
</getHotelsReturn>
</getHotelsResponse>
</soapenv:Body>
</soapenv:Envelope>
The best XSLT I could build up from the w3schools was this one:
<?xml version="1.0" encoding="utf-8"?>
<!-- Edited by XMLSpyΠ-->
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/soapenv:Envelope/soapenv:Body/getHotelsResponse">
<html>
<body>
<h2>Hotels in Barcelona</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Hotel name</th>
<th>Rate ($/night)</th>
</tr>
<xsl:for-each select="getHotelsReturn">
<tr>
<td><xsl:value-of select="name"/></td>
<td><xsl:value-of select="rate"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Which should produce a similar result to what I had in the w3schools example, but it comes back as blank.
Can anyone please explain this? Thanks.
As pointed out by #keshlam, if elements in your input XML have namespaces, you must declare them in your XSLT stylesheet as well.
Find more detail on namespaces in a previous answer of mine.
The gist of the information you find there is: as far as the XSLT processor is concerned, a getHotelsReturn element is entirely different from a vb:getHotelsReturn element.
Stylesheet
<?xml version="1.0" encoding="utf-8"?>
<!-- Edited by XMLSpy?-->
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:vb="http://hotel.booking.vbooking.com"
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
exclude-result-prefixes="soapenv vb">
<xsl:template match="/soapenv:Envelope/soapenv:Body/vb:getHotelsResponse">
<html>
<body>
<h2>Hotels in Barcelona</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Hotel name</th>
<th>Rate ($/night)</th>
</tr>
<xsl:for-each select="vb:getHotelsReturn">
<tr>
<td><xsl:value-of select="vb:name"/></td>
<td><xsl:value-of select="vb:rate"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Output
<html>
<body>
<h2>Hotels in Barcelona</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Hotel name</th>
<th>Rate ($/night)</th>
</tr>
<tr>
<td>Downtown Hotel</td>
<td>235.0</td>
</tr>
</table>
</body>
</html>
Rendered HTML
You can use XPaths like this:
/Product1/Product2/Product3[#ValidYN = 'Y' and #ProductType = 'ABC']
/Product1/Product2/Product3[#ValidYN = 'Y' and #ProductType = 'DEF']
/Product1/Product2/Product3[#ValidYN = 'Y' and #ProductType = 'GHI']
Check this other question How to parse XML using XSLT?

XML to HTML using XSL.Unable to read data from node

I have a xml file with one of the nodes as:
<test-case time="0.077" name="TestingNunit.NUnitTestClass.NunitTestMethod1" asserts="1" success="False" result="Failure" executed="True">
<failure>
<message>
<![CDATA[ Expected: not 3.0d But was: 3.0d ]]>
</message>
<stack-trace>
<![CDATA[at TestingNunit.NUnitTestClass.NunitTestMethod1() in z:\UnitTestingSample\UIAutomation\TestingNunit\UnitTest1.cs:line 12 ]]>
</stack-trace>
</failure>
</test-case>
<test-case time="0.003" name="TestingNunit.NUnitTestClass.NunitTestMethod2" asserts="2" success="False" result="Failure" executed="True">
<failure>
<message>
<![CDATA[ Expected: 2.0d But was: 3.0d ]]>
</message>
<stack-trace>
<![CDATA[at TestingNunit.NUnitTestClass.NunitTestMethod2() in z:\UnitTestingSample\UIAutomation\TestingNunit\UnitTest1.cs:line 21 ]]>
</stack-trace>
</failure>
Now I want to read the data of all CDATA's". I am trying to generate a html file using XSL for which I need this data? I am able to generate data for normal nodes and their attributes but for a node written in this way I am unable to figure out a way to read it. This is my xsl file foreach loop
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<html>
<body>
<table border="1">
<tr bgcolor="#9acd32">
<th>Test Method</th>
<th>Execution Time</th>
<th>Asserts Performed</th>
<th>Success</th>
<th>Result</th>
<th>Executed</th>
<th>Failure Message</th>
<th>Stack Trace</th>
</tr>
<xsl:for-each select="test-results/test-suite/results/test-suite/results/test-suite/results/test-case">
<tr>
<td><xsl:value-of select="#name"/></td>
<td><xsl:value-of select="#time"/></td>
<td><xsl:value-of select="#asserts"/></td>
<td><xsl:value-of select="#success"/></td>
<td><xsl:value-of select="#result"/></td>
<td><xsl:value-of select="#executed"/></td>
<td><xsl:value-of select="//failure/message/text()" disable-output-escaping="no"/></td>
<td><xsl:value-of select="//failure/stack-trace/text()" disable-output-escaping="no"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
To read CDATAs (and then transform them) use the text() function in your XPath.
//test-case/failure/message/text()
//test-case/failure/stack-trace/text()
Try select="./failure/message/text()" instead of select="//failure/message/text()" (mind the ./ at the beginning).
Doing this the XPath relates to the node that is currently selected by the for-each loop. When using // it will select all nodes from the document ignoring the currently selected node. Imagine this like a lscommand on Linux: ls /* will select the top level elements regardless of your current work directory, while ls ./* will select the child elements of your current work directory.