I have 3 tables, retailer,product and manufacturer.I will pass retailerID to the query and it should return the manufacturer Details.
criteria:
1)from the given input (retailerID) fetch productID from the retailer table.
2)Using productID get the manufacturerID from product table.
3)Get the complete details of manufacturer from manufacturer table using manufacturerID.
Can anyone help me to solve this.Thanks in advance.
Based on the description of your question, I understood that this is your requirement:
select *
from manufacturer
where manufacturerID = (
select manufacturerID
from Product
where productID = (
select productID
from retailer
where retailerID=#retailerID)
)
Above query is written in subquery format, which can easily be converted into join format:
select *
from Manufacturer m
join Product p on m.manufacturerID = p.manufacturerID
join retailer r on r.ProductID = p.ProductID
where r.RetailerID = #retailerID
Related
I have 3 Tables with a n:m Relation
Languages:
ID (primary-key)
name
slug
Products:
ID
name
slug
-productgroup
Table for Relation:
Lang_Prod:
lang_prod_id (composed from lang_id and prod_id)
lang_id
prod_id
Now i want to get all Products with their corresponding Language-Names:
product
productgroup
language-names (multiple values)
I've tried:
SELECT product.*, languages_products.language_id,
GROUP_CONCAT(languages_products.language_id) as languages
FROM product
INNER JOIN languages_products ON id = languages_products.product_id
GROUP BY product.id;
Result is:
productname
product_slug
product_group
String with languages IDs
Instead of the string with the language-IDs, i would like to have a string with language-names
How can i archieve that?
You need to join with language table
SELECT product.id,product.name,product.productgroup,
GROUP_CONCAT(l.name) as languages
FROM product
INNER JOIN languages_products ON id = languages_products.product_id
INNER JOIN languages l ON languages_products.language_id=l.id
GROUP BY product.id,product.name,product.productgroup
You need to add another join with the languages table, and use the name column from it. I'd group it in an inner query though:
SELECT p.*, languages
FROM product p
JOIN (SELECT product_id, GROUP_CONCAT(l.name) as languages
FROM languages_products lp
JOIN languages l ON lp.language_id = l.id
GROUP BY product_id) cl ON cl.product_id = p.id
Process:
When user buy item and check out then there's cart and cart items table to store the transaction.
1 cart_id have many item which stored in cart items table.
After purchase succeed, then will generate a purchase order id and stored in purchase order table .
In purchase order table, id_cart and status will be stored.
From here, i am trying to calculate quantity based on id_product or id branch or etc from the purchase made.
There is receiving and ordered quantity field, which in some cases quantity received field might be null, so i will take ordered quantity value.
This is my query
SELECT id_product,sum(DISTINCT(COALESCE(received_qty, quantity)))
FROM (SELECT C.id_cart,C.received_qty,C.quantity , P.id_product,
PO.id_purchase_order, PO.status
FROM (SELECT * FROM cart_items WHERE id_cart IN (SELECT id_cart FROM purchase_orders)) AS C
LEFT JOIN products as P on p.id_product = c.id_product
LEFT JOIN purchase_orders AS PO ON C.id_cart = PO.id_cart ) AS A
GROUP By A.id_product
Table data
The cart id in will be duplicated based on product's supplier. Because need to track and send separately to supplier.
Result
By right the product id for 1212 should be 1 and 1223 is 2, total qty =3.
What's wrong with my query ?
Your outer joins seem to cause multiplication of your data, but there are so many unnecessary layers of fluff in your query that I cant make it out exactly.
How about just this:
SELECT id_product, sum(COALESCE(received_qty, quantity)) AS Nmbr
FROM cart_items
GROUP BY id_product
If you want to make sure the cart is in your purchase_orders:
SELECT c.id_product, sum(COALESCE(c.received_qty, c.quantity)) AS Nmbr
FROM cart_items c
JOIN (SELECT DISTINCT id_cart FROM purchase_orders) p ON p.id_cart = c.id_cart
GROUP BY c.id_product
I have the following three tables: Product, User and Purchased.
Product contains:
A unique identifier (productID)
A name (productname)
A price
(productprice)
User contains:
A unique identifier (userID)
Purchased contains:
Two identifiers noted as private keys, productID and userID
A date of the record (creationdate)
My query should return a list of unique products that were bought on the retailer’s site since January 1st with most expensive product returned first.
My Query:
SELECT Product.productID, Product.productname, Purchased.creationdate
FROM Product
INNER JOIN Purchased
ON Product.productID = Purchased.productID;
ORDER BY Product.productprice DESC;
If you just want a list of products, I would suggest exists rather than join:
select p.*
from products p
where exists (select 1
from purchased pu
where pu.productId = p.productId and
year(pu.creationdate) = year(now())
)
order by price desc;
Hi I want to get opposite of intersect from two tables.
I have a sale table and purchase table. What I want to do is get all purchases ids where not included in the sales table.
sale table
sale_id (pk)
product_id (fk)
purchase_id (fk)
purchase table
product_id (fk)
purchase_id (pk)
SELECT DISTINCT purchase_id
, product_id
FROM
purchase
INNER JOIN sale
USING (purchase_id, product_id);
Here is an example:
If I run the above code, this will be the result.
purchase_id product id
1 1
1 2
1 4
2 1
2 3
Now I want to get:
purchase_id product id
1 3
2 2
In short I want to get inverse of above code. Thanks in advance.
Okay, I think I understand better now.
This should return any entry in purchase that have no matching entry in sales.
SELECT
`purchase`.`purchase_id`, `purchase`.`product_id`
FROM `purchase`
LEFT JOIN `sale` ON `sale`.`purchase_id` = `purchase`.`purchase_id` AND `sale`.`product_id` = `purchase`.`product_id`
WHERE
`sale`.`sale_id` IS NULL
ORDER BY
`purchase`.`purchase_id`, `purchase`.`product_id`
If you want to get all the purchases that have no related values in the sales table, you can use a LEFT JOIN:
select
p.purchase_id
from
purchase as p
left join sale as s on p.purchase_id = s.purchase_id
where
s.purchase_id is null;
"Unilateral" joins (LEFT JOIN, RIGHT JOIN) are useful when you want to get data from a table even if data in another related table does not exist. Of course, that means that you can filter data from one table when there's no related data in a second table.
Hope this helps.
Looking at your updated question and your comment, I think that you want all the possible combinations not used.
You'll need to split this in two steps:
First you need all the possible combinations of purchase_id and sale_id values (the "cartesian product" of both the sets).
Then you need to get all the combinations already used.
Finally you need to exclude all the combinations already used.
This can be done using subqueries.
Step 1.
select distinct p.purchase_id, s.product_id from purchase as p, sale as s;
Step 2. (Your query)
select distinct
purchase_id, product_id
from
purchase as p
inner join sale as s
on (p.purchase_id = s.purchase_id and p.product_id = s.product_id);
Step 3. Put it all together
select
a.*
from
(select distinct p.purchase_id, s.product_id from purchase as p, sale as s) as a
left join (
select distinct
purchase_id, product_id
from
purchase as p
inner join sale as s
on (p.purchase_id = s.purchase_id and p.product_id = s.product_id)
) as e on (a.purchase_id = e.purchase_id and a.product_id = e.product_id)
where
e.purchase_id is null and e.product_id is null;
I'm asking for an awful lot here - but maybe some SQL guru can show me how to extract the data I want and save me 10+ hours of google-time(tm)?
These are my tables, with only relevant fields displayed:
**event**
id
cust_id
....
.
**art**
id
art_name
...
.
**event_art**
event_id
art_id
...
.
**price**
cust_id
art_id
price
...
Prices in the "price" DB with user ID "0" is standard price, if an entry exists with art_id and cust_id that is customer specific price for that article.
What I have is cust_id and what I have for output now is just the customer specific prices with SQL:
SELECT * FROM price WHERE cust_id='{$custID}'
But I'd like to include prices for previously ordered articles, even if they do not have a customer specific price.
So what I need is to:
1 Get all id's from table event where cust_id = custID
2 Get all distinct article ID's on those orders from table event_art
3 Output "id" and "art_name" of article from "art" and "price" from price table using custID or 0 for standard price if no entry exists.
To me this sounds like a multi-line JOIN that's a bit outside my scope of SQL knowledge. Could somebody help me out, point me to a guide that deals with similar issues or... well, something?
Thanks in advance!
SELECT art_id, price
FROM price
WHERE cust_id = $cust_id
UNION ALL
SELECT art_id, price
FROM (
SELECT DISTINCT art_id
FROM event e
JOIN event_art ea
ON ea.event_id = e.id
WHERE e.cust_id = $cust_id
AND ea.art_id NOT IN
(
SELECT art_id
FROM price
WHERE cust_id = $cust_id
)
) e
JOIN price p
ON p.cust_id = 0
AND p.art_id = e.art_id
Make sure that (cust_id, art_id) (in this order) is a PRIMARY KEY or a UNIQUE INDEX on price.
Had to make some small changes to indicate which table was used where in the SQL, but pretty much copy&paste so not bad at all :P
SELECT price.art_id, price.price
FROM price
WHERE cust_id =114
UNION ALL
SELECT e.art_id, p.price
FROM (
SELECT DISTINCT art_id
FROM event e
JOIN event_art ea ON ea.event_id = e.id
WHERE e.cust_id =114
AND ea.art_id NOT
IN (
SELECT price.art_id
FROM price
WHERE cust_id =114
)
)e
JOIN price p ON p.cust_id =0
AND p.art_id = e.art_id
SELECT DISTINCT
a.id,
a.art_name,
COALESCE(p.price, p0.price) AS price
FROM event e
INNER JOIN event_art ea ON e.id = ea.event_id
INNER JOIN art a ON ea
LEFT JOIN price p ON p.art_id = a.id AND p.cust_id = e.cust_id
LEFT JOIN price p ON p.art_id = a.id AND p.cust_id = 0