How do I get the next pagination 'href'? - html

Question

So I am having trouble obtaining the href link for the next pages of the url. I got up to obtaining all the text and what not that the tag contains but I can't seem to wrap my head around to removing the text that I don't need and just obtaining the href and navigating through the pages.
Here is my code:
import requests
from bs4 import BeautifulSoup
import webbrowser
import time
jobsearch = input("What type of job?: ")
location = input("What is your location: ")
url = ("https://ca.indeed.com/jobs?q=" + jobsearch + "&l=" + location)
base_url = 'https://ca.indeed.com/'
r = requests.get(url)
rcontent = r.content
prettify = BeautifulSoup(rcontent, "html.parser")
filter_words = ['engineering', 'instrumentation', 'QA']
all_job_url = []
nextpages = []
filtered_job_links = []
http_flinks = []
flinks = []
def all_next_pages():
pages = prettify.find_all('div', {'class':'pagination'})
for next_page in pages:
next_page.find_all('a')
nextpages.append(next_page)
print(next_page)
all_next_pages()

Answer 1

Here is a way to get the links of the search result items. Find row result class and then find a tag, it contains all the information you need.
import requests
from bs4 import BeautifulSoup
import webbrowser
import time
jobsearch = input("What type of job?: ")
location = input("What is your location: ")
url = ("https://ca.indeed.com/jobs?q=" + jobsearch + "&l=" + location)
base_url = 'https://ca.indeed.com/'
r = requests.get(url)
rcontent = r.text
prettify = BeautifulSoup(rcontent, "lxml")
filter_words = ['engineering', 'instrumentation', 'QA']
all_job_url = []
nextpages = []
filtered_job_links = []
http_flinks = []
flinks = []
def all_next_pages():
pages = prettify.find_all('div', {'class':' row result'})
for next_page in pages:
info = next_page.find('a')
url = info.get('href')
title = info.get('title')
print(title,url)
all_next_pages()