I'm having trouble with this website I am creating.
Basically I'm trying to create news articles on a page that once you click on the article you'd be taken to a page that would load the content for that article. Is it possible to set it up in a way that I can load the content on a new page depending on the SQL primary key of the article selected?
I can load the articles on the page from the sql database no problem its just determining what data is loaded on a new page that is beating me.
Thanks in advance for any advice anyone can offer in this, even if its just pointing me in the right direction.
I have tried searching online first with no luck so far.
You can use $_GET to create a dynamic content using one page only
EXAMPLE:
article.php?news_id=1:
<?php
if(isset($_GET['news_id'])){
$newsID = $_GET['news_id'];
//query all the data you need using that $newsID
}
?>
you can pass the news-id as variable in url and get that variable using $_GET method,then execute the sql query.
<?php
$id =$_GET['id];
?>
mysql-"Select * from Table where id =$id"
Related
I am new in yii2 and i am using wbraganca/yii2-dynamicform widget in my view. My question is that I have to use more than two dynamic form in a single view. For single dynamic widget it works fine while saving from controller but others are saving just the last data of dynamic widget, while inspecting the post data in network array index for others except first dynamic form are not increasing (there index is only zero). Would you please suggest how should I have to do. How can I use multiple dynamic-form widget in single view. Thank you in advance.
I believe the problem must be in your view. You should ensure that each control has a unique name and then loop through the post variables in the controller.
<?= $form->field($modelx, "[{$i}]MyVariableName", ['labelOptions' => ['label' => false]])->textInput(['name' =>'myClassNameHere'."{$block}[$i][MyVariableName]"]) ?>
See the 'name' option in the code above. It gives a unique name to each field. Here the $block variable is a unique code I append to each widgetItem class in the DynamicFormWidget.
If I now look at my POST data, I see something like the following:
myClassNameHere0[0][MyVariableName]:1
myClassNameHere1[0][MyVariableName]:11
If this does not help - post a simply example that you cannot get working and I will have a look at it.
I'm displaying the contents of a database on a particular page(recipe names).
I'd like each recipe to be a link which opens to another page. I understand I would have to obtain the recipe id for that particular recipe, pass the id to another page and print the recipe contents onto that page. I would like to know how to retrieve the unique recipe id of a particular recipe ON BEING CLICKED upon mainly.
If you are displaying the contents of a database on a particular page, then definitely you are using a server side scripting like like ASP or PHP or some JavaScript + AJAX. I am quite unclear about that. But for your question, I can tell you one thing that, if, suppose you are using PHP, then you may display the link as;
echo ''.$recipiename.'';
where $recipeid is the variable carrying recipe id and $recipiename is the name of your recipe. In your PHP file (yourpage.php), you may catch this data like $_GET["recipeid"]
You may try a Google search for tutorials.
Use;
$strLink = ''.$strName.'';
echo "<li>".$strLink."</li>";
Don't use spaces.
You just make the id part auf the URL the recipe link points to.
Iced Water
Would be a link pointing to the recipe with ID 23. Since the url is available on the server side you are all set.
i'm working in a symfony project and using sfPropelPager to show a paged list of elements.
The problem is that with a great amount of data to list (i.e. thousands of registers) it makes a query to the database for each page to show!!!! That means about 100 extra queries in my case, and that is unacceptable.
Showing some of my code: the function that returns the pager object
$pager = new sfPropelPager('MyTable',sfConfig::get('sfPropelPagerLines'));
$c = new Criteria();
$c->add('my_table_field',$value);
$c->addDescendingOrderByColumn('date');
$pager->setCriteria($c);
$pager->init();
return $pager;
So, please, if you know a way to get all the results with only one query, it would be a great solution for my problem. Otherwise i must implement that list with an ajax call for every page the user wants to see
Thank you very much for your time.
I'm not sure to get your problem but, anyway, avoid the use of Criteria. Try to make queries with the ModelCriteria API: http://www.propelorm.org/reference/model-criteria.html.
For each paginated page, a query to the database will be done, this is the standard behavior for all pagers I know. If it's related to related objects (assuming you want to display information from relations), you may want to create a query that links those objects before to paginate, that way you'll get one query per page for all your data to display.
Read this doc for instance: http://www.propelorm.org/documentation/03-basic-crud.html#query_termination_methods
At last i did'nt get a solution for the problem, i had to implement the list via AJAX call, calling to a function that returns the requested page, so at the load of the page, no query for this list is slowing the user experience.
Thank you anyway to help me :)
I am absolute beginner to drupal.
I have added a contact form (using Webform module).
Now I want to save the data entered in the form. But I am lost. I have searched over internet, found db_query() is used to query database.
But I dont know where to write the php code. Please help me or if you know any link,please give me.
The tables you'll be most interested in are webform, webform_submissions, webform_submitted_data and webform_component. Have a look at those tables and it becomes very obvious how they're linked together.
You'll want to look at the Drupal 7 Database API to learn how to use the query system but here's an example to get you going:
/* Get a list of all submissions from webform for the node with ID (`nid`) of 1 */
$nid = 1;
$submissions = db_select('webform_submissions', 'ws')
->fields('ws')
->condition('nid', $nid)
->execute();
/* If you want to use db_query and a plain old SQL statement instead you'd do it like this:
$submissions = db_query('SELECT * FROM webform_submissions WHERE nid = :nid', array('nid' => $nid)); */
/* Loop through the submissions and load up the submitted data for each */
$submission_data = array();
foreach ($submissions as $submission) {
$query = db_select('webform_submitted_data', 'wsa')
->fields('wc', array('name'))
->fields('wsa', array('data'))
->condition('sid', $submission->sid);
/* Join in the component table to get the element label */
$query->join('webform_component', 'wc', 'wc.nid = wsa.nid AND wc.sid = wsa.cid');
$submission_data[] = $query->execute()->fetchAllKeyed();
}
At the end of that code you'll have an array ($submission_data), which contains a list of arrays of submission data for the provided node. Each of those arrays' items has a key of the component label, and a value of the submitted user value.
Hope that helps
It's worth noting that for most normal use cases you'll never need to look at the databases or do any kind of coding. The UI allows you to view submissions of a form (and see what was submitted). You can also configure the Webform to send you a copy of each submission (via email)... There is a lot you can do without "looking under the hood" or messing with the database in any way.
If you are really new to Drupal and Webforms, I just thought I'd point that out. There are a lot of tabs in the UI which might easily be overlooked.
Webform has Views support, so you probably don't really need to write database queries to generate the report you want.
I have an HTML TABLE that displays my records from mySQL.
I need to edit various records (rows). Is it possible to click on a table row and edit the values in the row inside the HTML table?
I was wondering if there are any PHP scripts out there to guide me?
Yes, it's possible. While I am very convinced PHP is involved, Javascript is involved also.
I think you can have something like this:
1.Click once, javascript increases a counter variable
2. Click twice, javascript checks if var = 2 after increasing, resets counter, and changes innerHTML of the td to something like this:
form action ='yourphpscript.php' method = 'getorpost'>
.....What you want to change....
</form>
3. So then it sends your values to the PHP script, PHP script changes values in database, and you get redirected back to the main page. Or, better yet, use AJAX.
Hope this helped :)