I am absolute beginner to drupal.
I have added a contact form (using Webform module).
Now I want to save the data entered in the form. But I am lost. I have searched over internet, found db_query() is used to query database.
But I dont know where to write the php code. Please help me or if you know any link,please give me.
The tables you'll be most interested in are webform, webform_submissions, webform_submitted_data and webform_component. Have a look at those tables and it becomes very obvious how they're linked together.
You'll want to look at the Drupal 7 Database API to learn how to use the query system but here's an example to get you going:
/* Get a list of all submissions from webform for the node with ID (`nid`) of 1 */
$nid = 1;
$submissions = db_select('webform_submissions', 'ws')
->fields('ws')
->condition('nid', $nid)
->execute();
/* If you want to use db_query and a plain old SQL statement instead you'd do it like this:
$submissions = db_query('SELECT * FROM webform_submissions WHERE nid = :nid', array('nid' => $nid)); */
/* Loop through the submissions and load up the submitted data for each */
$submission_data = array();
foreach ($submissions as $submission) {
$query = db_select('webform_submitted_data', 'wsa')
->fields('wc', array('name'))
->fields('wsa', array('data'))
->condition('sid', $submission->sid);
/* Join in the component table to get the element label */
$query->join('webform_component', 'wc', 'wc.nid = wsa.nid AND wc.sid = wsa.cid');
$submission_data[] = $query->execute()->fetchAllKeyed();
}
At the end of that code you'll have an array ($submission_data), which contains a list of arrays of submission data for the provided node. Each of those arrays' items has a key of the component label, and a value of the submitted user value.
Hope that helps
It's worth noting that for most normal use cases you'll never need to look at the databases or do any kind of coding. The UI allows you to view submissions of a form (and see what was submitted). You can also configure the Webform to send you a copy of each submission (via email)... There is a lot you can do without "looking under the hood" or messing with the database in any way.
If you are really new to Drupal and Webforms, I just thought I'd point that out. There are a lot of tabs in the UI which might easily be overlooked.
Webform has Views support, so you probably don't really need to write database queries to generate the report you want.
Related
My goal is very simple and I would guess it is a very common goal among web developers.
I am creating a Rails (5.1) application, and I simply want to use AJAX to get the value of a specific cell in a specific row of a specific table in my database (later I am going to use that value to highlight some text on the current page in the user's browser).
I have not been able to find any documentation online explaining how to do this. As I said, it seems like a basic task to ask of jquery and ajax, so I'm confused as to why I'm having so much trouble figuring it out.
For concreteness, say I have a table called 'animals', and I want to get the value of the column 'species' for the animal with 'id' = 99.
How can I construct an AJAX call to query the database for the value of 'species' for the 'animal' with 'id' = 99 .
Though some DBs provide a REST API, what we commonly do is define a route in the app to pull and return data from the DB.
So:
Add a route
Add a controller/action for that route
In that action, fetch the data from the DB and render it in your preferred format
On the client-side, make the AJAX call to that controller/action and do something with the response.
In Perl, I have script that creates a dropdown list based on a database that contains a list of vendors. I would like to use the selection of the first list to populate the second list with values of different contacts given that specific vendor.
ie. Haliburton is vendor....once this is chosen contact Jim, Paul, George are available in contact list that is next to it.
Currently I am getting the list of vendors and the list of contacts separately. How do I get the list of contacts based on the vendor in the database to be populated in the CGI popup_menu?
The following is my current code:
#!c:\perl\bin\perl.exe
use CGI;
use strict;
use warnings;
require ("data_eXchangeSubs.pm");
$query = new CGI;
print $query->header(-expires=>'-1d');
print $query->start_html(-title=>'Dex Vendor Testing',
-bgcolor=>'white'
);
my $dataX = ${ConnectToDatabase($main::DB1, $main::DBEnv)};
$resultSet = $dataX->Execute("select vendor from vendor_info group by vendor");
my #list_of_vendors;
while(!$resultSet->EOF) {
push #list_of_vendors, $resultSet->Fields("vendor")->Value;
$resultSet->MoveNext;
}
From here, I would like to populate another dropdown list with contacts from the vendor_info data table. Currently I'm making a separate query execution but I would like to take a given vendor from the previous array and populate only those contacts specific to the chosen vendor.
I know I have to change the values of the contacts but don't know how to :(
$resultContact = $dataX->Execute("select contact from vendor_info");
my #list_of_contacts;
while(!$resultContact->EOF) {
push #list_of_contacts, $resultContact->Fields("contact")->Value;
$resultContact->MoveNext;
}
print $query->popup_menu(
-name => 'vendors'
, -values =>\#list_of_vendors
, -default => $default_vendor
, -style=> 'width:200px'
);
print $query->popup_menu(
-name => 'contacts'
, -values => \#list_of_contacts
, -default => $default_vendor
);
print $query->end_html;
This is a very broad question. You have a couple of simple options.
1) Create an HTML form with the list of vendors, take (and sanitize!) the user's selection, and return the list of contacts. This is a traditional dynamic CGI form.
2) Use JavaScript. This only works for a reasonable amount of data. There are several ways to do it but the gist of the idea is: a) associate each contact with the correct vendor, b) hide all the contacts initially, c) when a vendor is selected, display the correct contacts.
JQuery is a handy JavaScript tool for this kind of manipulation and magically hides many browser incompatibility problems.
3) You could create a fancy, modern AJAX-ified form, but from your question, this is probably overkill.
Sorry there is no quick-and-dirty solution but I'm hoping to give you enough here to start Googling in the right direction! Best!
With CGI, you need to use CGI::param method.
# I know the name of the select is "vendors",
# but it makes more sense calling it here with 'vendor'
# *you would have to change the name of the element*
my $vendor_name = $query->param( 'vendor' );
And I'm not sure how your database object works (kind of looks like the Microsoft iteration model), but using the proper way of parameterized queries in DBI, it looks like this:
my $stmt = $dbh->prepare( 'select contact from vendor_info where vendor_name=?' );
$stmt->execute( $vendor_name ); # binds the variable to the query.
Then you step through the rows of the query and build your list of contacts. Of course, you'd mostly likely use fetchrow_array or fetchrow_arrayref methods to walk through them.
Although this might be better off utilizing a more modern strategy by getting a combined list of vendors and contacts for JavaScript or using Ajax to query the contacts for a vendor.
There is no "connecting" structure in basic Perl CGI. You would have to use a more modern web framework for that.
OK, in good old fashioned PHP MVC, I might use a model to hit the DB, send info to my PHP controller that I pass on to the View. In the View, I might take that info (say i ajax'ed my controller for the info) and create a table or ul to display the data returned.
I've had trouble finding any modern (ver 6.1 is what i'm on) tutorial to show me how to preform this action in typo3.
Can anyone just "steer" me in the right direction? Perhaps provide an example via answer, or some links to further information that may compare it down to "old fashioned MVC"?
Extension has been suggested, but I'd like to know the very base process of what I'm asking before I try writing some extension, unless the extension is the only way. Although, my table is now on the SAME DB my typo3 is on, so shouldn't there be some command to just simply call my table and get the rows? Maybe send them to a ###sub-part###?
You can use a typoscript cObj content and the select option together with the function render_obj when your table name is like the typo3 nameing convention. The select pulls the record from the table and pass it to the render_obj function. It's a function that can apply to all cObj and iterate over the entire selection. stdWrap works only on the entire cObj. When you need to work through each record you need the render_obj function. For example:
10 = CONTENT
10 {
select {
pidInList = 1
where = colpos=1
orderBy = sorting
}
table = tt_content
renderObj.stdWrap.wrap = <li>|</li>
renderObj.stdWrap.required = 1
}
10.stdWrap.wrap = <ul>|</ul>
This gives you an unorderd list from the tt_content table with pid=1 and the content from the far left column.
So I already have a database setup with a few columns and a few rows already inserted in. I'm trying to create a view that you would just input information into a form and press Submit, then a row would be added to the MySQL database with the information you just typed in.
I believe you can do this with admin, but I would like to try without admin and I'm not sure if this is possible? I've been using the MySQL commandline to add rows as of now..
Of coures this is possible this is a building block for data driven websites. You can use a ModelForm as Daniel suggested (they offer built in validation and HTML markup for FREE) to easily map your model to a front end form. It would probably be beneficial to start with django tutorial or documentation first.
At the the very basic, all you have to do is instantiate your model
new_entry = YourModel(name='me', age='222', about='stackoverflow')
then save it
new_entry.save()
This adds it as a new row to your db.
https://docs.djangoproject.com/en/dev/topics/db/models/
Why would it not be possible?
You probably want a modelform (but see the general form introduction first).
Try out this example of Generic Views: http://postneo.com/2005/08/17/django-generic-views-crud (assumes a model named Task)
With Generic Views you get Insert, Update and Delete for free without any real work. give it a try and let me know what you think.
from django.conf.urls.defaults import *
info_dict = {
'app_label': 'tasks',
'module_name': 'tasks',
}
urlpatterns = patterns('',
(r'^tasks/create/?$', 'django.views.generic.create_update.create_object', info_dict ),
(r'^tasks/update/(?P<object_id>\d+)/?$', 'django.views.generic.create_update.update_object', info_dict),
(r'^tasks/delete/(?P<object_id>\d+)/?$', 'django.views.generic.create_update.delete_object', info_dict ),
)
Django Docs: https://docs.djangoproject.com/en/1.2/ref/generic-views/#create-update-delete-generic-views
i'm working in a symfony project and using sfPropelPager to show a paged list of elements.
The problem is that with a great amount of data to list (i.e. thousands of registers) it makes a query to the database for each page to show!!!! That means about 100 extra queries in my case, and that is unacceptable.
Showing some of my code: the function that returns the pager object
$pager = new sfPropelPager('MyTable',sfConfig::get('sfPropelPagerLines'));
$c = new Criteria();
$c->add('my_table_field',$value);
$c->addDescendingOrderByColumn('date');
$pager->setCriteria($c);
$pager->init();
return $pager;
So, please, if you know a way to get all the results with only one query, it would be a great solution for my problem. Otherwise i must implement that list with an ajax call for every page the user wants to see
Thank you very much for your time.
I'm not sure to get your problem but, anyway, avoid the use of Criteria. Try to make queries with the ModelCriteria API: http://www.propelorm.org/reference/model-criteria.html.
For each paginated page, a query to the database will be done, this is the standard behavior for all pagers I know. If it's related to related objects (assuming you want to display information from relations), you may want to create a query that links those objects before to paginate, that way you'll get one query per page for all your data to display.
Read this doc for instance: http://www.propelorm.org/documentation/03-basic-crud.html#query_termination_methods
At last i did'nt get a solution for the problem, i had to implement the list via AJAX call, calling to a function that returns the requested page, so at the load of the page, no query for this list is slowing the user experience.
Thank you anyway to help me :)